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JEE • PHYSICS • MOTION IN A STRAIGHT LINE

Motion in a straight line practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 333 questions

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211 Medium
211 of 333
Application +4 | -1
A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1{S_1} and that covered in the first 20 seconds is S2{S_2} , then
View answer and explanation
Correct option: C
S2=4S1{S_2} = 4{S_1}
Option C (S2=4S1{S_2} = 4{S_1}) is correct because the distance covered under constant acceleration is proportional to the square of the time.
212 Medium
212 of 333
Application +4 | -1
A body throws a ball in air in such a manner that when the ball is at its maximum heights he throws another ball. If the balls are thrown with the time difference 1 second, the maximum height attained by each ball is
View answer and explanation
Correct option: A
4.9 m
Option A (4.9 m) is correct because the maximum height is calculated using the time of flight and the acceleration due to gravity.
213 Medium
213 of 333
Understanding +4 | -1
Free fall of an object (in vacuum) is a case of motion with
View answer and explanation
Correct option: B
Uniform acceleration
Option B (Uniform acceleration) is correct because in free fall (in vacuum), the only force acting on the object is gravity, resulting in constant acceleration.
214 Medium
214 of 333
Understanding +4 | -1
A train is moving towards north. At one place, it turns towards north-east. Here, we observe that
View answer and explanation
Correct option: A
the radius of curvature of outer rail will be greater than that of the inner rail.
Option A (the radius of curvature of outer rail will be greater than that of the inner rail) is correct because the outer rail has to cover a longer distance in the same amount of time.
215 Medium
215 of 333
Understanding +4 | -1
The acceleration of a moving body can be found from
View answer and explanation
Correct option: C
Slope of the velocity- time graph
Option C (Slope of the velocity- time graph) is correct because acceleration is defined as the rate of change of velocity with respect to time, which is represented by the slope of the velocity-time graph.
216 Medium
216 of 333
Application +4 | -1
The initial velocity of a particle is uu and acceleration is given by at. Which of the following relations for the final velocity v\mathrm{v} is valid?
View answer and explanation
Correct option: B
v=u+12at2v=u+\frac{1}{2} a t^2
The correct answer is B (v=u+12at2v=u+\frac{1}{2} a t^2) because the acceleration is given as a function of time, so integration is required to find the final velocity.
217 Medium
217 of 333
Application +4 | -1
A ball is thrown horizontally from a height of 100 m100 \mathrm{~m} with an initial speed of 15 m s−115 \mathrm{~m} \mathrm{~s}^{-1}. How far does it travel horizontally in the first 2 seconds?
View answer and explanation
Correct option: C
30 m
Option C (30 m) is correct because the horizontal distance is calculated by multiplying the horizontal velocity by the time.
218 Medium
218 of 333
Understanding +4 | -1
Assertion : The speedometer of an automobile measure the average speed of the automobile.

Reason : Average velocity is equal to total displacement per total time taken.
View answer and explanation
Correct option: D
Assertion is incorrect, reason is correct.
The assertion is incorrect because a speedometer measures instantaneous speed. The reason is correct as average velocity is total displacement divided by total time.
219 Easy
219 of 333
Application +4 | -1
An automobile travels on a straight road for 40 km40 \mathrm{~km} at 30 km30 \mathrm{~km} h−1\mathrm{h}^{-1}. It then continues in the same direction for another 40km40 \mathrm{km} at 60 km h−160 \mathrm{~km} \mathrm{~h}^{-1}. What is the average velocity of the car during its 80 km80 \mathrm{~km} trip?
View answer and explanation
Correct option: C
40 km h−140 \mathrm{~km} \mathrm{~h}^{-1}
Option C (40 km/h) is correct because the average velocity is calculated by dividing the total displacement by the total time taken for the entire trip.
220 Medium
220 of 333
Understanding +4 | -1
Assertion: When the initial velocity is zero; then the final velocity value depends upon the acceleration and time taken by the particle

Reason: The kinematical equation of motion relating initial velocity, final velocity, acceleration and time taken by the particle is v=u+atv=u+a t
View answer and explanation
Correct option: A
Both Assertion and Reason are true, and Reason is the correct explanation for Assertion
Option A (Both Assertion and Reason are true, and Reason is the correct explanation for Assertion) is correct because the reason correctly explains why the final velocity depends on acceleration and time when the initial velocity is zero.
221 Easy
221 of 333
Understanding +4 | -1
A ball of mass m1{m_1} and another ball of mass m2{m_2} are dropped from equal height. If time taken by the balls are t1{t_1} and t2{t_2} respectively, then
View answer and explanation
Correct option: B
t1=t2{t_1} = {t_2}
Option B (t1=t2{t_1} = {t_2}) is correct because the time taken for an object to fall from a certain height is independent of its mass, assuming no air resistance.
222 Medium
222 of 333
Analyzing +4 | -1
A train accelerates from rest at a constant rate α for distance x1{x_1} and time t1{t_1}. After that it retards to rest at constant rate β\beta for distance x2{x_2} and time t2{t_2}. Then it is found that
View answer and explanation
Correct option: B
x1x2=βα=t1t2\frac{{{x_1}}}{{{x_2}}} = \frac{\beta }{\alpha } = \frac{{{t_1}}}{{{t_2}}}
Option C is correct because the ratio of distances is equal to the inverse ratio of accelerations, and the ratio of times is also equal to the inverse ratio of accelerations.
223 Hard
223 of 333
Application +4 | -1
Amongst the following equation of motion, which represents uniformly accelerated motion?
View answer and explanation
Correct option: C
t=x+abt=\sqrt{\frac{x+a}{b}}
Option C (t=x+abt=\sqrt{\frac{x+a}{b}}) is correct because it can be rearranged to show that displacement x is proportional to the square of time t, which is the characteristic of uniformly accelerated motion.
224 Medium
224 of 333
Analyzing +4 | -1
A particle is moving such that s=t3−6t2+18t+9s=t^3-6 t^2+18 t+9, where ss is in metre and tt is in second. The minimum velocity attained by the particle is
View answer and explanation
Correct option: C
6 ms−16 \mathrm{~ms}^{-1}
Option C (6 m/s⁻¹) is correct because it is the minimum velocity obtained by finding the critical point of the velocity function and verifying it is a minimum.
225 Medium
225 of 333
Application +4 | -1
A rocket is fired upward from the earth’s surface such that it creates an acceleration of 19.6  m/sec⁡2.19.6\;m/{\sec ^2}.⁡. If after 5 sec⁡ its engine is switched off, the maximum height of the rocket from earth’s surface would be
View answer and explanation
Correct option: D
735 m
Option D (735 m) is correct because it is the sum of the height achieved during acceleration and the height achieved after the engine is switched off.
226 Medium
226 of 333
Understanding +4 | -1
The ratio of the numerical values of the average velocity and average speed of a body is always
View answer and explanation
Correct option: B
Unity or less
Option B (Unity or less) is correct because the magnitude of displacement is always less than or equal to the distance traveled.
227 Medium
227 of 333
Application +4 | -1
Two cars A and B are moving with same speed of 45 km/hr along same direction. If a third car C coming from the opposite direction with a speed of 36 km/hr meets two cars in an interval of 5 minutes, the distance of separation of two cars A and B should be (in km)
View answer and explanation
Correct option: A
6.75
Option A (6.75) is correct because it is calculated by finding the relative speed of car C with respect to cars A and B and then multiplying by the time interval.
228 Medium
228 of 333
Analyzing +4 | -1
A body covers 26, 28, 30, 32 meters in 10th, 11th, 12th and
13th seconds respectively. The body starts
View answer and explanation
Correct option: C
with an initial velocity and moves with uniform
acceleration
Option C is correct because the body has an initial velocity and moves with uniform acceleration, which is determined by analyzing the given distances covered in consecutive seconds.
229 Easy
229 of 333
Understanding +4 | -1
Let v⃗\vec{v} and a⃗\vec{a} denote the velocity and acceleration respectively of a body in one dimensional motion. Then correct option is
View answer and explanation
Correct option: C
Speed will decrease when V⃗\vec{V} and a⃗\vec{a} anti-parallel
Option C is correct because speed decreases when velocity and acceleration are anti-parallel, meaning they are in opposite directions.
230 Hard
230 of 333
Application +4 | -1
The deceleration experienced by a moving motorboat after its engine is cut off, is given by dv/dt=−kv3\mathrm{dv} / \mathrm{dt}=-\mathrm{kv}^3 where k\mathrm{k} is constant. If v0\mathrm{v}_0 is the magnitude of the velocity at cut-off, the magnitude of the velocity at a time tt after the cut-off is
View answer and explanation
Correct option: A
v0(2v02kt+1)\frac{\mathrm{v}_0}{\sqrt{\left(2 \mathrm{v}_0{ }^2 \mathrm{kt}+1\right)}}
Option A (v0(2v02kt+1)\frac{{\mathrm{v}_0}}{{\sqrt{{\left(2 \mathrm{v}_0{ }^2 \mathrm{kt}+1\right)}}}}) is correct because it is derived by solving the given differential equation with the initial condition.
231 Hard
231 of 333
Application +4 | -1
The velocity vector of a particle moving over a horizontal plane is given by v⃗=2ti^\vec{v}=2 t \hat{i}. The ratio of the magnitude of instantaneous acceleration of the particle at t=2sec{t}=2 \mathrm{sec} to the magnitude of displacement of the particle during the interval of first 2sec2 \mathrm{sec} is
View answer and explanation
Correct option: A
3/43/4
Option A (3/4) is correct because it represents the ratio of the magnitude of instantaneous acceleration to the magnitude of displacement, calculated using the given velocity vector.
232 Medium
232 of 333
Analyzing +4 | -1
Statement-I: The average velocity of a particle is zero in a time interval. It is possible that the instantaneous acceleration is never zero in the interval.
Statement-II: The magnitude of average velocity in an interval is equal to its average speed in that interval.
View answer and explanation
Correct option: B
Statement-I is true, statement-II is false
Option B is correct. Statement-I can be true if the object changes direction, resulting in zero average velocity but non-zero instantaneous acceleration. Statement-II is false because average speed and average velocity magnitudes are only equal for unidirectional motion.
233 Medium
233 of 333
Understanding +4 | -1
The numerical ratio of displacement to the distance covered is always
View answer and explanation
Correct option: C
Equal to or less than one
Option C (Equal to or less than one) is correct because the magnitude of displacement is always less than or equal to the distance covered.
234 Medium
234 of 333
Understanding +4 | -1
Statement-I: The speed of a body can be negative.
Statement-II: If the body is moving in the opposite direction of positive motion, then its speed is negative.
View answer and explanation
Correct option: D
Both statements are false
Option D (Both statements are false) is correct because speed is always a non-negative quantity.
235 Easy
235 of 333
Application +4 | -1
Two particles are moving with velocities 17 m/sec and 14 m/sec along positive X-axis. Their initial positions are at x = 24 m, x = 120 m respectively. find time taken by first particle to cross second one
View answer and explanation
Correct option: B
32 sec
Option B (32 sec) is correct because it is the time when both particles have the same position, calculated by equating their position equations.
236 Medium
236 of 333
Understanding +4 | -1
Assertion: For unidirectional movement of an object, displacement > distance.

Reason: For unidirectional movement of an object, displacement == distance.
View answer and explanation
Correct option: D
Assertion is false, but Reason is true
Option D (Assertion is false, but Reason is true) is correct because for unidirectional movement, displacement equals distance, making the assertion incorrect.
237 Medium
237 of 333
Application +4 | -1
A train has a speed of 60 km/h. for the first one hour and 40 km/h for the next half hour. Its average speed in km/h is
View answer and explanation
Correct option: B
53.33
Option B (53.33) is correct because it's the average speed calculated by dividing the total distance traveled by the total time taken.
238 Medium
238 of 333
Understanding +4 | -1
If magnitude of average speed and average velocity over an interval of time are same, then
View answer and explanation
Correct option: D
Particle must move in a straight line without turning back
Option D is correct because if the magnitude of average speed and average velocity are the same, the particle must move in a straight line without changing direction.
239 Medium
239 of 333
Understanding +4 | -1
Assertion: The displacement-time graph of a body moving with uniform acceleration is a straight line.

Reason: The displacement is proportional to time for uniformly accelerated motion.
View answer and explanation
Correct option: D
If the assertion and reason both are false.
Option D (If the assertion and reason both are false) is correct because the displacement-time graph for uniform acceleration is a parabola, and displacement is proportional to the square of time, not time itself.
240 Medium
240 of 333
Application +4 | -1
Two trains 101 m and 99 m in length are running in opposite direction with velocities 54 km/h and 36 km/h. In what time they will completely cross each other ?
View answer and explanation
Correct option: B
8 s
Option B (8 s) is correct because it is the time calculated using the relative velocity of the two trains and the sum of their lengths.
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