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JEE • PHYSICS • MOTION IN A STRAIGHT LINE

Motion in a straight line practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 333 questions
31 Easy
31 of 333
Application +4 | -1
The motion of a particle along a straight line is described by equation x=2+12t−t2x=2+12 t-t^2, where xx is in metre and tt is in second. The retardation of the particle when its velocity becomes zero is
View answer and explanation
Correct option: A
2 m/s22 \mathrm{~m} / \mathrm{s}^2
Option A (2 m/s22 \mathrm{~m} / \mathrm{s}^2) is correct because the retardation is the magnitude of the acceleration when the velocity is zero.
32 Medium
32 of 333
Analyzing +4 | -1
In a race for 100m dash, the first and the second runners have a gap of one metre at the mid way stage. Assuming the first runner goes steady, by what percentage should the second runner increases his speed just to win the race.
View answer and explanation
Correct option: C
More than 4%4\%
Option C (More than 4%) is correct because the second runner needs to increase his speed by approximately 4.1% to win, which is more than 4%.
33 Medium
33 of 333
Understanding +4 | -1
Speed is in general _____ in magnitude than that of the velocity.
View answer and explanation
Correct option: B
Greater or equal
Option B (Greater or equal) is correct because speed is the magnitude of velocity, and it can be equal to or greater than the magnitude of the velocity.
34 Medium
34 of 333
Application +4 | -1
A body starts from rest, the ratio of distances travelled by the body during 3rd 3^{\text {rd }} and 4th 4^{\text {th }} second is:
View answer and explanation
Correct option: D
5/75 / 7
Option D (5/75 / 7) is correct because the ratio of distances travelled during the 3rd and 4th seconds is calculated using the formula Sn=u+12a(2n−1)S_n = u + \frac{1}{2}a(2n-1).
35 Medium
35 of 333
Analyzing +4 | -1
Assertion: A negative acceleration of a body can be associated with a ‘speeding up’ of the body.

Reason: Increase in speed of a moving body is independent of its direction of motion.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of the assertion.
Option B is correct because both the assertion and reason are true, but the reason does not correctly explain the assertion. A negative acceleration can indeed be associated with speeding up, but the reason provided is not the direct cause.
36 Medium
36 of 333
Understanding +4 | -1
Choose the wrong statement from the following.
View answer and explanation
Correct option: B
The speed in general is less than the magnitude of the velocity
Option B (The speed in general is less than the magnitude of the velocity) is the wrong statement because speed is always greater than or equal to the magnitude of velocity.
37 Medium
37 of 333
Application +4 | -1
A 150 m long train is moving with a uniform velocity of 45 kmph. The time taken by the train to cross a bridge of length 850 m is
View answer and explanation
Correct option: C
80 sec
Option C (80 sec) is correct because it correctly calculates the total distance and uses the correct velocity to find the time.
38 Medium
38 of 333
Application +4 | -1
A juggler throws balls into air. The throws one whenever the previous one is at its highest point. If the throws n balls each second, the height to which each ball will rise is
View answer and explanation
Correct option: A
g2n2\frac{\mathrm{g}}{{2{n^2}}}
Option A (g2n2\frac{\mathrm{g}}{{2{{n^2}}}}) is correct because it is derived from kinematic equations relating to projectile motion, considering the time to reach the highest point.
39 Medium
39 of 333
Application +4 | -1
If a particle travels nn equal distances with speeds v1,v2,…,vnv_1, v_2, \ldots, v_n then the average speed Vˉ\bar{V} of the particle will be such that
View answer and explanation
Correct option: C
1Vˉ=1n(1v1+1v2+⋯+1vn)\frac{1}{\bar{V}}=\frac{1}{n}\left(\frac{1}{v_1}+\frac{1}{v_2}+\cdots+\frac{1}{v_n}\right)
Option C (1Vˉ=1n(1v1+1v2+⋯+1vn)\frac{1}{\bar{V}}=\frac{1}{n}\left(\frac{1}{v_1}+\frac{1}{v_2}+\cdots+\frac{1}{v_n}\right)) is correct because it represents the harmonic mean of the speeds when distances are equal.
40 Medium
40 of 333
Application +4 | -1
A scooter accelerates from rest for time t1{t_1} at constant rate a1{a_1} and then retards at constant rate a2{a_2} for time t2{t_2} and comes to rest. The correct value t1t2\frac{{{t_1}}}{{{t_2}}} of will be
View answer and explanation
Correct option: B
a2a1\frac{{{a_2}}}{{{a_1}}}
Option B (a2a1\frac{{{a_2}}}{{{a_1}}}) is correct because the ratio of times is inversely proportional to the ratio of accelerations.
41 Medium
41 of 333
Application +4 | -1
A burglar's car had a start with an acceleration of 2 ms−2.2 \mathrm{~ms}^{-2}. A police vigilant party came after 5 seconds and continued to chase the burglar's car with a uniform velocity of 20 ms−1.20 \mathrm{~ms}^{-1}. Find the time in which the police van overtakes the burglar's car.
View answer and explanation
Correct option: A
5 s5 \mathrm{~s}
Option A (5 s) is correct because it is the time when the distance traveled by the police van equals the distance traveled by the burglar's car.
42 Medium
42 of 333
Analyzing +4 | -1
Which of the following are true?
(i) A body having constant speed can have verying velocity.
(ii) Position-time graphs for two objects with zero relative velocity are parallel.
(iii) The numerical ration of velocity to speed of an object can never be more than one.
View answer and explanation
Correct option: C
All
Option C (All) is correct because all three statements are true regarding motion and relative velocity.
43 Medium
43 of 333
Understanding +4 | -1
A graph is shown between velocity an time for the motion of a particle. The area under the curve between the time intervals t1 and t2{t_1}\,and\,{t_2} gives
View answer and explanation
Correct option: B
Displacement of the particle
Option B (Displacement of the particle) is correct because the area under a velocity-time graph represents the displacement of the particle.
44 Hard
44 of 333
Application +4 | -1
The relation 3t=3x+63t = \sqrt 3 x + 6 describes the displacement of a particle in one direction, where x is in meter and t in second. The displacement when velocity is zero
View answer and explanation
Correct option: D
zero
Option D (zero) is correct because when the velocity is zero, the displacement is also zero based on the given equation.
45 Medium
45 of 333
Application +4 | -1
From a height, 3 balls are thrown with speed uu, one vertically upward, second horizontally, third downward with times of fall be t1,t2t_1, t_2 and t3t_3 respectively, then
View answer and explanation
Correct option: B
t2=t1t3t_2=\sqrt{t_1 t_3}
Option B (t2=t1t3t_2=\sqrt{t_1 t_3}) is correct because it relates the times of fall based on kinematic equations of motion.
46 Medium
46 of 333
Understanding +4 | -1
What is the numerical ratio of velocity to speed of an object?
View answer and explanation
Correct option: D
Either less than or equal to one.
Option D (Either less than or equal to one) is correct because the magnitude of velocity (speed) is always greater than or equal to the magnitude of the velocity, so the ratio is less than or equal to one.
47 Medium
47 of 333
Analyzing +4 | -1
Assertion: If two particles are moving with same speed but their velocity vectors are opposite, then the distance between the particles must be changing.
Reason: If the velocity of one particle w.r.t. other is zero, then separation between the particle must be constant.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.
Option B is correct because while both statements are true, the reason doesn't explain the assertion; the changing distance is due to the opposite velocity vectors, not zero relative velocity.
48 Medium
48 of 333
Application +4 | -1
The distance traveled by a falling body in the last second of its motion, to that in the last but one second is 7:5. The velocity with which body strikes the ground is
View answer and explanation
Correct option: B
39.2 m/s
Option B (39.2 m/s) is correct because it is calculated using the ratio of distances traveled in the last two seconds to find the total time of fall and then the final velocity.
49 Medium
49 of 333
Analyzing +4 | -1
Assertion: The position-time graph of a body moving uniformly in a straight line is parallel to position axis.
Reason: The position-time graph in a non-uniform motion gives constant velocity at all instants of time.
View answer and explanation
Correct option: D
If both assertion and reason are false
Option D (If both assertion and reason are false) is correct because a uniform motion's position-time graph is a straight line with a constant slope, and non-uniform motion does not give constant velocity at all times.
50 Medium
50 of 333
Understanding +4 | -1
Assertion: Magnitude of average velocity is equal to average speed, if velocity is constant.
Reason: If velocity is constant, then there in no change in the direction of motion.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and Reason is correct explanation of Assertion.
Option A (If both Assertion and Reason are true and Reason is correct explanation of Assertion) is correct because if velocity is constant, the magnitude of average velocity equals average speed, and this is because there's no change in direction.
51 Medium
51 of 333
Analyzing +4 | -1
A truck and a car are moving with equal velocity. On applying the brakes both will stop after certain distance, then
View answer and explanation
Correct option: C
Both will cover equal distance
Option C (Both will cover equal distance) is correct because stopping distance depends on initial velocity and coefficient of friction, which are equal for both.
52 Medium
52 of 333
Understanding +4 | -1
When particle moves in straight line increasing speed the correct sign of acceleration 'aa' and velocity 'vv' can be
View answer and explanation
Correct option: D
Both 2 and 3
Option D (Both 2 and 3) is correct because when the signs of velocity and acceleration are the same, the speed of the particle increases.
53 Medium
53 of 333
Understanding +4 | -1
Assertion: The speed of an object can never be negative.
Reason: Speed is a scalar quantity.
View answer and explanation
Correct option: B
If both assertion and reason are true, but reason is not correct explanation of the assertion.
Option B (If both assertion and reason are true, but reason is not correct explanation of the assertion) is correct because speed is always non-negative, and speed being a scalar is true but doesn't explain why speed cannot be negative.
54 Easy
54 of 333
Understanding +4 | -1
Which of the following statements is true for a car moving on the road?
View answer and explanation
Correct option: B
With respect to the frame of reference attached to the person sitting in the car, the car is at rest.
Option B (With respect to the frame of reference attached to the person sitting in the car, the car is at rest) is correct because the car's position doesn't change relative to the person inside.
55 Medium
55 of 333
Understanding +4 | -1
If a particle moves with an acceleration, then which of the following can remain constant
View answer and explanation
Correct option: D
only the speed
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because dipoles in a dielectric are not perfectly aligned due to thermal energy disrupting the alignment.
56 Medium
56 of 333
Analyzing +4 | -1
If a particle is moving along a straight line and its velocity varies with time, as v=2t−t2v=2 t-t^2, ( vv and tt are in SI\mathrm{SI} units) then choose the incorrect option.
View answer and explanation
Correct option: D
Average speed from t=0t=0 to t=2 st=2 \mathrm{~s} is 512 m/s\frac{5}{12} \mathrm{~m} / \mathrm{s}
Option D is correct because the average speed from t=0 to t=2 s is calculated as 2/3 m/s, not 5/12 m/s, due to the particle changing direction.
57 Medium
57 of 333
Application +4 | -1
A body A moves with uniform acceleration A and Zero initial velocity, Another body B, starts from the same point moves in the same direction with a constant velocity V.
The two bodies meet after a time t. The value of t is
View answer and explanation
Correct option: A
2Va\frac{{2V}}{a}
Option A (2Va\frac{{2V}}{a}) is correct because the time is calculated by equating the distances traveled by both bodies when they meet.
58 Medium
58 of 333
Application +4 | -1
The displacement of a particle undergoing rectilinear motion along the x-axis is given by x=(2t3+21t2+60t+6)x = \left( {2{t^3} + 21{t^2} + 60t + 6} \right). The acceleration of the particle when its velocity is zero is
View answer and explanation
Correct option: D
−18  ms−2- \mathrm{18}\,\,\mathrm{m}{\mathrm{s}^{ - 2}}
Option C (03:00 AM) is incorrect. The correct answer should be 3A, not a time. The question asks for the current required, and the calculation yields 3A.
59 Medium
59 of 333
Analyzing +4 | -1
Assertion: A body moving with constant acceleration, always travels equal distance in equal time intervals.
Reason: Motion of the body with constant acceleration is a uniform motion.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because a body moving with constant acceleration does NOT always travel equal distances in equal time intervals, and motion with constant acceleration is NOT uniform motion.
60 Medium
60 of 333
Analyzing +4 | -1
A passenger is standing on the platform at the beginning of the nth (=3rd )n^{\text {th }}\left(=3^{\text {rd }}\right) coach of a train. The train starts moving with constant acceleration. The third coach passes by the passenger in Δt1=5.0 s\Delta t_1=5.0 \mathrm{~s} and rest of the train (including the 3rd 3^{\text {rd }} coach) in Δt2=20 s\Delta t_2=20 \mathrm{~s}. In what time interval Δt\Delta t (in sec) did the last coach passed by the passenger?
View answer and explanation
Correct option: A
0.64 s
The correct answer is A (0.64 s) because it is calculated by finding the time taken for the last coach to pass using kinematic equations and the given information.
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