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JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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A particle moves as such whose acceleration is given by a=3sin⁡4ta=3 \sin 4 t, then
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Correct option: B
the acceleration of the particle becomes zero after each interval of π4\frac{\pi}{4} second.
Option B is correct because the acceleration becomes zero when sin⁡4t=0\sin 4t = 0, which occurs at intervals of π4\frac{\pi}{4} seconds.

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