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JEE • PHYSICS • MECHANICAL PROPERTIES OF SOLIDS

Mechanical properties of solids practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 151-180 of 251 questions

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151 Medium
151 of 251
Understanding +4 | -1
The bulk modulus of an ideal gas at constant temperature
View answer and explanation
Correct option: C
Is equal to its pressure pp
Option C (Is equal to its pressure pp) is correct because the bulk modulus at constant temperature (isothermal process) is equal to the pressure of the gas.
152 Medium
152 of 251
Understanding +4 | -1
Assertion: Ratio of stress and strain is always constant for a substance.

Reason: This ratio is called modulus of elasticity.
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true
Option D is correct because the ratio of stress and strain is not always constant; it's only constant within the elastic limit, and the ratio is called the modulus of elasticity.
153 Medium
153 of 251
Application +4 | -1
A man grows into a giant such that his linear dimensions increase by a factor of 9. Assuming that his density remains same, the stress in the leg will change by a factor of
View answer and explanation
Correct option: D
9
Option D (9) is correct because the stress is proportional to the linear dimension when density is constant.
154 Medium
154 of 251
Analyzing +4 | -1
A: Increase in temperature of a substance decreases the modulus of elasticity.
R: The graph between potential energy of molecules and separation between them is asymmetric
View answer and explanation
Correct option: A
If both A &\& R are true and the R is the correct explanation of the A
Option A (If both A & R are true and the R is the correct explanation of the A) is correct because increasing temperature weakens intermolecular forces, decreasing the modulus of elasticity, and the asymmetric potential energy curve explains thermal expansion.
155 Medium
155 of 251
Understanding +4 | -1
Assertion: For small deformations, the stress and strain are proportional to each other.
Reason: A class of solids called elastomers does not obey Hooke’s law.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of assertion
Option B (If both assertion and reason are true but reason is not the correct explanation of assertion) is correct because Hooke's law applies to small deformations, and elastomers are an exception, but the reason doesn't explain the assertion.
156 Medium
156 of 251
Understanding +4 | -1
The Poisson’s ratio cannot have the value
View answer and explanation
Correct option: A
0.7\mathrm{0}\mathrm{.7}
Option A (0.7) is correct because Poisson's ratio must lie between -1 and 0.5 theoretically, and practically between 0 and 0.5. 0.7 exceeds this limit.
157 Medium
157 of 251
Remembering +4 | -1
What is the phenomenon of temporary delay in regaining the original configuration by an elastic body, after the removal of a deforming force?
View answer and explanation
Correct option: D
Elastic after effect
Option D (Elastic after effect) is correct because it specifically describes the temporary delay in regaining the original configuration after removing a deforming force.
158 Medium
158 of 251
Understanding +4 | -1
A wire fixed at the upper end stretches by length ll by applying a force FF. The work done in stretching is
View answer and explanation
Correct option: D
Fl2\frac{{Fl}}{2}
Option D (Fl2\frac{{Fl}}{2}) is correct because the work done in stretching a wire is equal to the potential energy stored, which is half the product of the force and the extension.
159 Medium
159 of 251
Understanding +4 | -1
The maximum load a wire can withstand without breaking, when its length is reduced to half of its original length, will
View answer and explanation
Correct option: D
Remain same
Option D is correct because the maximum load a wire can withstand depends on its cross-sectional area and material properties, not its length.
160 Medium
160 of 251
Understanding +4 | -1
Liquids have no Poisson's ratio, because
View answer and explanation
Correct option: A
They have no definite shape
The correct answer is that liquids have no definite shape, which prevents them from having a Poisson's ratio.
161 Medium
161 of 251
Application +4 | -1
A metal wire 4m4 \mathrm{m} long and 2×10−7m22 \times 10^{-7} \mathrm{m}^{2} in cross section is stretched by a force of 30N30 \mathrm{N}. If the work done in stretching that wire is 4.5×10−2J4.5 \times 10^{-2} \mathrm{J}, the young's modulus of the wire is [pa]
View answer and explanation
Correct option: A
2×10112 \times 10^{11}
Option A (2×10112 \times 10^{11}) is correct because it is calculated using the formula for Young's modulus in terms of work done, force, length, and area.
162 Medium
162 of 251
Analyzing +4 | -1
Assertion: If pressure is increased, bulk modulus of gases will increase.

Reason: With increase in pressure, temperature of gas also increases.
View answer and explanation
Correct option: C
If Assertion is true, but the Reason is false
Option C (If Assertion is true, but the Reason is false) is correct because the bulk modulus of gases increases with pressure, but the reason provided about temperature increase is not always true and not the primary explanation.
163 Medium
163 of 251
Application +4 | -1
A material has poisson's ratio 0.3 if a uniform rod suffer's a longitudinal strain of x. If the percentage increase in its volume is 1% then x =
View answer and explanation
Correct option: A
2.5
Option A (2.5) is correct because the longitudinal strain is calculated using Poisson's ratio and the percentage increase in volume.
164 Medium
164 of 251
Understanding +4 | -1
Which one of the following statement(s) is/are incorrect?
View answer and explanation
Correct option: A
Young’s modulus for a perfectly rigid body is zero
Option A (Young’s modulus for a perfectly rigid body is zero) is correct because Young's modulus for a perfectly rigid body is infinite, not zero.
165 Medium
165 of 251
Application +4 | -1
A metal rod of Young’s modulus 2  ×1010 Nm−22\,\, \times {10^{10}}\,\mathrm{N}{\mathrm{m}^{ - 2}} undergoes an elastic strain of 0.06  %\mathrm{0}\mathrm{.06}\,\,\mathrm{\% }. The energy per unit volume stored in JJ m−3 {\mathrm{m}^{ - 3}}\, is
View answer and explanation
Correct option: A
3600
Option A (3600) is correct because it is the energy per unit volume calculated using the formula with Young's modulus and strain.
166 Medium
166 of 251
Understanding +4 | -1
Statement I: Stress is restoring force per unit area.
Statement II: Interatomic forces in solids are responsible for the property of elasticity
View answer and explanation
Correct option: A
Statement I is true and statement II is true
Option A (Statement I is true and statement II is true) is correct because both statements accurately describe stress and the origin of elasticity in solids.
167 Medium
167 of 251
Understanding +4 | -1
Statement-I: Young's modulus for a perfectly plastic body is zero.
Statement-II: For a perfectly plastic body, restoring force is zero.
View answer and explanation
Correct option: A
Statement I is true and statement II is true
Option A (Statement I is true and statement II is true) is correct because a perfectly plastic body has zero restoring force and therefore zero Young's modulus.
168 Medium
168 of 251
Understanding +4 | -1
A: Modulus of elasticity is independent of dimensions of the body.
R: Modulus of elasticity depends on the material of the body.
View answer and explanation
Correct option: B
If both A &\& R are true but the R is not the correct explanation of the A
Option B (If both A &R\& R are true but the R is not the correct explanation of the A) is correct because both the assertion and the reason are true statements, but the reason does not explain why the modulus of elasticity is independent of the dimensions of the body.
169 Medium
169 of 251
Understanding +4 | -1
If Poisson’s ratio σ\sigma is −12- \frac{1}{2} for a material, then the material is
View answer and explanation
Correct option: A
Uncompressible
Option A (Uncompressible) is correct because if Poisson's ratio is -1/2, the bulk modulus becomes infinite, indicating an incompressible material.
170 Medium
170 of 251
Application +4 | -1
A tensile force FF is needed to break a copper wire having radius R.R. The tensile force required to break a wire of radius 3R3 R made of the same material will be:
View answer and explanation
Correct option: C
9F9 F
Option C (9F9 F) is correct because the tensile force required to break a wire is proportional to the cross-sectional area, which is proportional to the square of the radius.
171 Medium
171 of 251
Application +4 | -1
Two steel wires have equal volumes, their diameters are in the ratio 2:12:1. When same force is applied on them, the elongation produced will be in the ratio of
View answer and explanation
Correct option: C
1:161:16
Option C is correct because the elongation is inversely proportional to the fourth power of the radius when the volume and force are constant.
172 Medium
172 of 251
Understanding +4 | -1
Breaking stress of a steel wire of radius 1 mm1 \mathrm{~mm} and length 1 m1 \mathrm{~m} is 1012 N/m210^{12} \mathrm{~N} / \mathrm{m}^2. Breaking stress of another steel wire of radius 2 mm2 \mathrm{~mm} and length 0.5 m0.5 \mathrm{~m} will be
View answer and explanation
Correct option: B
1012 N/m210^{12} \mathrm{~N} / \mathrm{m}^2
1012 N/m210^{12} \mathrm{~N} / \mathrm{m}^2 is the correct answer because breaking stress is a material property and is independent of the dimensions of the wire.
173 Medium
173 of 251
Application +4 | -1
The ratio of two specific heats of gas Cp/Cv{C_p}/{C_v} for argon is 1.6\mathrm{1}\mathrm{.6} and for hydrogen is 1.4\mathrm{1}\mathrm{.4}. Adiabatic elasticity of argon at pressure PP is EE. Adiabatic elasticity of hydrogen will also be equal to EE at the pressure
View answer and explanation
Correct option: B
87P\frac{8}{7}P
Option B (87P\frac{8}{7}P) is correct because it equates the adiabatic elasticity of argon and hydrogen, using the given ratio of specific heats to find the pressure at which their elasticities are equal.
174 Medium
174 of 251
Understanding +4 | -1
A: When a beam is bent only tensile strain is produced.
R: The depression produced in a rectangular beam is directly proportional to its width.
View answer and explanation
Correct option: D
If both A and R are false
Option D (If both A and R are false) is correct because bending a beam produces both tensile and compressive strain, and the depression is inversely proportional to the width.
175 Medium
175 of 251
Remembering +4 | -1
Under elastic limit the stress is
View answer and explanation
Correct option: B
Directly proportional to strain
Option B (Directly proportional to strain) is correct because Hooke's Law states that stress is directly proportional to strain within the elastic limit.
176 Medium
176 of 251
Application +4 | -1
A copper bar of length LL and area of cross-section AA is placed in a chamber at atmospheric pressure. If the chamber is evacuated, the percentage change in its volume will be (compressibility of copper is 8  × 1012 m 2N−1and  1  atm=105  Nm2)8\,\, \times \,{10^{12}}\,\mathrm{m}{\,^2}{\mathrm{N}^{ - 1}}\mathrm{and}\,\,1\,\,\mathrm{atm} = {10^5}\,\,\mathrm{N}{\mathrm{m}^2})
View answer and explanation
Correct option: B
8  ×  10−58\,\, \times \,\,{10^{ - 5}}
Option B (8×10−58 \times 10^{-5}) is correct because it represents the percentage change in volume calculated using the compressibility of copper and the change in pressure.
177 Medium
177 of 251
Understanding +4 | -1
What is the nature of intermolecular forces?
View answer and explanation
Correct option: C
Attractive and repulsive both depend on the intermolecular separation
The correct answer is C (Attractive and repulsive both depend on the intermolecular separation) because intermolecular forces can be attractive at larger distances and repulsive at very short distances.
178 Medium
178 of 251
Application +4 | -1
KK is the force constant of a spring. The work done in increasing its extension from l1{l_1} to l2{l_2} will be
View answer and explanation
Correct option: D
K2(l22−l12)\frac{K}{2}\left( {l_2^2 - l_1^2} \right)
Option D (K2(l22−l12)\frac{K}{2}\left( {l_2^2 - l_1^2} \right)) is correct because it represents the difference in potential energy stored in the spring at the two extensions.
179 Medium
179 of 251
Remembering +4 | -1
The value of Poisson’s ratio lies between
View answer and explanation
Correct option: A
−1  to  12- 1\,\,\mathrm{to}\,\,\frac{1}{2}
Option A (−1,,to 12- 1\\,\\,\mathrm{to}\\\,\frac{1}{2}) is correct because Poisson's ratio is theoretically limited to this range due to thermodynamic considerations.
180 Medium
180 of 251
Understanding +4 | -1
Assertion: The stretching of a coil is determined by its Shear modulus.
Reason: Shear modulus changes only shape of a body keeping its dimensions unchanged.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion) is correct because the stretching of a coil primarily involves changing its shape without significantly altering the length of the wire, which is related to the shear modulus.
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