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JEE • PHYSICS • MECHANICAL PROPERTIES OF SOLIDS
Mechanical properties of solids practice · Medium
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 181-210 of 251 questions
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181
Medium
181 of 251
Application
+4 | -1
Equal torsional torques act on two rods having equal length. The diameter of rod is twice the diameter of rod are the angles of twist, then
View answer and explanation
Correct option: D
16
Option D (16) is correct because the angle of twist is inversely proportional to the fourth power of the diameter, so doubling the diameter reduces the twist by a factor of 16.
182
Medium
182 of 251
Application
+4 | -1
The upper end of a wire of diameter and length is clamped and its other end is twisted through an angle of . The angle of shear is
View answer and explanation
Correct option: B
Option B () is correct because it is calculated using the formula relating the angle of twist, radius, length, and angle of shear.
183
Medium
183 of 251
Application
+4 | -1
The upper end of a wire of radius and length is clamped and its other end is twisted through and angle of . Then angle of shear is
View answer and explanation
Correct option: B
Option B () is correct because the angle of shear is calculated using the formula , where r is the radius, l is the length, and is the angle of twist.
184
Medium
184 of 251
Application
+4 | -1
The bulk modulus of a spherical object is If it is subjected to uniform pressure the fractional decreases in radius is
View answer and explanation
Correct option: A
Option A () is correct because it is derived from the definition of bulk modulus and the relationship between volume and radius for a sphere.
185
Medium
185 of 251
Application
+4 | -1
If a bar is made of copper whose coefficient of linear expansion is one and a half times that of iron, the ratio of the force developed in the copper bar to the iron bar of identical lengths and cross-sections, when heated through the same temperature range (Young’s modulus for copper may be taken equal to that of iron) is
View answer and explanation
Correct option: A
Option A () is correct because the force developed is proportional to the coefficient of linear expansion, and the coefficient for copper is 1.5 times that of iron.
186
Medium
186 of 251
Application
+4 | -1
A wire of length , area of cross section is hanging from a fixed support. The length of the wire changes to when mass is suspended from its free end. The expression for Young’s modulus is:
View answer and explanation
Correct option: D
Option D () is correct because it is the correct formula for Young's modulus, which is stress divided by strain.
187
Medium
187 of 251
Understanding
+4 | -1
The general form of potential energy curve for atoms or molecules can be represented by the following equation . Here, R is the interatomic or molecular distance, A and B are coefficients, and are the exponents. In the above equation
View answer and explanation
Correct option: B
Second term represents the attractive part of the potential
Option B (Second term represents the attractive part of the potential) is correct because the negative sign in front of the second term indicates an attractive potential, as the potential energy decreases with increasing distance.
188
Medium
188 of 251
Analyzing
+4 | -1
Which of the following relations is true
View answer and explanation
Correct option: D
Option D is correct because the correct relation between Young's modulus (Y), shear modulus (), bulk modulus (K), and Poisson's ratio () is which can be rearranged to .
189
Medium
189 of 251
Application
+4 | -1
Find the density of the metal under a pressure of . Given density of the metal , bulk modulus of the metal .
View answer and explanation
Correct option: A
Option A () is correct because it is calculated by considering the bulk modulus and the pressure applied to the metal.
190
Medium
190 of 251
Understanding
+4 | -1
If the tension on a wire is removed at once, then:
View answer and explanation
Correct option: D
Its temperature increases
Option D (Its temperature increases) is correct because the potential energy stored in the wire due to tension is converted into heat when the tension is released.
191
Medium
191 of 251
Application
+4 | -1
A wire of length is hanged vertically from ceiling if it is stretched due to its own weight, then find out the energy stored per unit volume. and ]
View answer and explanation
Correct option: D
Option D (10 J/m³) is correct because it is calculated using the formula for potential energy density in terms of Young's modulus, density, gravity, and length.
192
Medium
192 of 251
Application
+4 | -1
When change in volume of a cube under a pressure at atm of 10 is 1% ; compressibility of material of black in is (Take 1atm )
View answer and explanation
Correct option: B
Option B () is correct because compressibility is the reciprocal of the bulk modulus, which relates pressure to the fractional change in volume.
193
Medium
193 of 251
Application
+4 | -1
Two exactly similar wires of steel and copper are stretched by equal forces. If the difference in their elongations is , the elongation of each wire is ,
View answer and explanation
Correct option: A
Option A () is correct because it satisfies both the elongation ratio based on Young's modulus and the given difference in elongations.
194
Medium
194 of 251
Analyzing
+4 | -1
Assertion: If length of a rod is doubled, the breaking load remains the same.
Reason: Breaking load is equal to the elastic limit.
Reason: Breaking load is equal to the elastic limit.
View answer and explanation
Correct option: C
If assertion is true but reason is false
The correct answer is C (If assertion is true but reason is false) because breaking load depends on the cross-sectional area, not the length, and it's related to breaking stress, not the elastic limit.
195
Medium
195 of 251
Understanding
+4 | -1
Young’s modulus of perfectly rigid body material is
View answer and explanation
Correct option: A
Infinite
Option A (Infinite) is correct because a perfectly rigid body experiences no deformation under stress, resulting in an infinite Young's modulus.
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196
Medium
196 of 251
Application
+4 | -1
A wire of Young’s modulus is stretched by a force so as to produce a strain of The energy stored per unit volume is
View answer and explanation
Correct option: D
Option D () is correct because it is the energy stored per unit volume calculated using the given Young's modulus and strain.
197
Medium
197 of 251
Remembering
+4 | -1
Which is the most elastic
View answer and explanation
Correct option: C
Quartz
Option C (Quartz) is correct because quartz exhibits a higher resistance to deformation under stress compared to the other options, making it more elastic.
198
Medium
198 of 251
Application
+4 | -1
If longitudinal strain for a wire is and its Poisson’s ratio is , then its lateral strain is
View answer and explanation
Correct option: C
0.015
Option C (0.015) is correct because lateral strain is calculated by multiplying Poisson's ratio by longitudinal strain.
199
Medium
199 of 251
Application
+4 | -1
If a spring extends by on loading, then the energy stored by the spring is (if is tension in the spring and is spring constant)
View answer and explanation
Correct option: B
Option B () is correct because the energy stored in a spring is related to the tension and spring constant by this formula.
200
Medium
200 of 251
Application
+4 | -1
A kg mass is suspended from a wire of negligible mass. The length of the wire is and its cross-sectional area is If the mass is pulled a little in the vertically downward direction and released, it performs simple harmonic motion of angular frequency . If the Young’s modulus of the material of the wire is , the value of is
View answer and explanation
Correct option: A
4
Option A (4) is correct because the Young's modulus is calculated using the formula for the angular frequency of SHM in a wire, and solving for n.
201
Medium
201 of 251
Understanding
+4 | -1
What happens when the applied load increases and upto breaking stress in the experiment to determine the Young's modulus of elasticity?
View answer and explanation
Correct option: A
The area of wire goes on decreasing and wire extends and breaks.
Option A is correct because as the load increases, the wire stretches (extends), and its cross-sectional area decreases until it reaches the breaking stress and fractures.
202
Medium
202 of 251
Understanding
+4 | -1
A: Strain is a dimensionless quantity.
R: Strain is internal force per unit area of a body
R: Strain is internal force per unit area of a body
View answer and explanation
Correct option: C
If A is true but R is false
Option C is correct because strain is dimensionless (change in dimension/original dimension), and the reason is false as strain is not internal force per unit area.
203
Medium
203 of 251
Understanding
+4 | -1
In Searle's apparatus, used for study of extension of wires verses load, we have two wires. During the experiment, we study the extension in one wire. The use of second wire is
View answer and explanation
Correct option: B
To compensate for the change in length caused by changes in temperature of atmosphere during experimentation.
Option B is correct. The second wire in Searle's apparatus compensates for length changes due to temperature variations during the experiment.
204
Medium
204 of 251
Understanding
+4 | -1
If shear modulus and Young's modulus, then in general:
View answer and explanation
Correct option: A
Option A () is correct because Young's modulus (Y) typically represents resistance to tensile stress, while shear modulus (G) represents resistance to shear stress, and Y is generally larger than G for most materials.
205
Medium
205 of 251
Understanding
+4 | -1
Statement I: With increase of temperature, elastic property of a substance decreases.
Statement II: Elasticity is due to intermolecular forces which decreases with the increase of inter molecular distance.
Statement II: Elasticity is due to intermolecular forces which decreases with the increase of inter molecular distance.
View answer and explanation
Correct option: A
Statement I is true and statement II is true
Option A (Statement I is true and statement II is true) is correct because increased temperature weakens intermolecular forces, thus decreasing elasticity.
206
Medium
206 of 251
Application
+4 | -1
A 5 m long aluminium wire of diameter 3 mm supports a 40 kg mass. In order to have the same elongation in the copper wire of the same length under the same weight, the diameter should now be (in mm)
View answer and explanation
Correct option: C
2.3
Option C (2.3) is correct because the diameter is inversely proportional to the square root of Young's modulus for the same elongation, length, and weight. Calculating the new diameter using the given Young's moduli results in approximately 2.3 mm.
207
Medium
207 of 251
Understanding
+4 | -1
An elastic metal rod will change its length when it
View answer and explanation
Correct option: D
Both (2) and (3)
Option D (Both (2) and (3)) is correct because stress is developed in both cases when the metal rod is pulled or stretched.
208
Medium
208 of 251
Analyzing
+4 | -1
A: It is the breaking stress and not the breaking strength which depends on the material
R: Breaking strength
R: Breaking strength
View answer and explanation
Correct option: D
If both A and R are false
Option D (If both A and R are false) is correct because both the assertion and the reason are incorrect statements about breaking stress and breaking strength.
209
Medium
209 of 251
Understanding
+4 | -1
A: Adiabatic elasticity of a gas is greater than isothermal elasticity
R:
R:
View answer and explanation
Correct option: A
If both A R are true and the R is the correct explanation of the A
Option A is correct. Adiabatic elasticity is greater than isothermal elasticity because the ratio is \, which is always greater than 1, and the reason correctly explains the assertion.
210
Medium
210 of 251
Application
+4 | -1
The breaking stress of a wire is and density is . What should be the maximum length of the wire so that it may not break under its own weight?
View answer and explanation
Correct option: A
Option A (20 km) is correct because it is the maximum length calculated using the breaking stress, density, and gravity.
Revision notes and key takeaways
Review MECHANICAL PROPERTIES OF SOLIDS in your textbook or class notes, then use this set to check your understanding.
Showing 181-210 of 251 questions
