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JEE • PHYSICS • MECHANICAL PROPERTIES OF SOLIDS

Mechanical properties of solids practice · Medium

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Showing 121-150 of 251 questions

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121 Medium
121 of 251
Application +4 | -1
A rubber cord catapult has cross-sectional area 25  mm225\,\,m{m^2} and initial length of rubber cord is 10  cm10\,\,cm. It is stretched to 5  cm5\,\,cm and then released to project a missile of mass 5  gm5\,\,gm. Taking Yrubber=5  ×108 N/m2{Y_{rubber}} = 5\,\, \times {10^8}\,N/{m^2} velocity of projected missile is
View answer and explanation
Correct option: C
250  ms−1250\,\,m{s^{ - 1}}
Option A (6) is correct because the number of spectral lines is calculated using the formula n(n−1)2\frac{n(n-1)}{2} where n is the energy level.
122 Medium
122 of 251
Understanding +4 | -1
Which one of the following quantities does not have the unit of force per unit area
View answer and explanation
Correct option: B
Strain
Option B (Strain) is correct because strain is a dimensionless quantity, while stress, Young's modulus, and pressure all have units of force per unit area.
123 Medium
123 of 251
Understanding +4 | -1
Statement-I: We cannot define Young's modulus and rigidity modulus for liquids and gases.
Statement-II: The theoretical limits of Poisson's ratio are −1-1 to 0.50.5
View answer and explanation
Correct option: C
Statement I is false and statement II is true
Option C (Statement I is false and statement II is true) is correct because liquids and gases have bulk modulus but not Young's modulus, and the theoretical limits of Poisson's ratio are -1 to 0.5.
124 Medium
124 of 251
Understanding +4 | -1
In materials like aluminium and copper, the correct order of magnitude of various elastic modulii is:
View answer and explanation
Correct option: C
Shear modulii << Young's modulii << bulk modulii
Statement-I is true and statement-II is true. Joule's law relates heat and work, and 1 calorie is approximately 4.186 Joules.
125 Medium
125 of 251
Understanding +4 | -1
Longitudinal strain is possible in
View answer and explanation
Correct option: C
Solids
Option C (Solids) is correct because longitudinal strain, which involves a change in length, is primarily applicable to solid materials.
126 Medium
126 of 251
Application +4 | -1
A structural steel rod has a radius of 10 mm10 \mathrm{~mm} and length of 1.0 m1.0 \mathrm{~m}. A 100kN100 \mathrm{kN} force stretches it along its length. Young's modulus of structural steel is 2×1011Nm−22 \times 10^{11} \mathrm{Nm}^{-2}. The percentage strain is about
View answer and explanation
Correct option: A
0.16%0.16 \%
The correct answer is A (0.16%0.16 \%) because the percentage strain is calculated using Young's modulus, force, area, and original length.
127 Medium
127 of 251
Understanding +4 | -1
A cable that can support a load ww is cut into two equal parts. The maximum load that can be supported by either part is
View answer and explanation
Correct option: C
ww
Option C (ww) is correct because the maximum load a cable can support depends on its cross-sectional area and material strength, not its length.
128 Medium
128 of 251
Understanding +4 | -1
Which of the following elastic moduli is used to describe the elastic behaviour of object as they respond to the deforming forces acting on them?
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Correct option: D
All of these
Option D (All of these) is correct because Young's modulus, shear modulus, and bulk modulus all describe different aspects of an object's elastic behavior under deforming forces.
129 Medium
129 of 251
Application +4 | -1
A copper rod of length 0.19 m is moving with a uniform velocity 10 m/s parallel to a long straight wire carrying current of 5.0 A. The rod itself is perpendicular to wire with its ends at distance 0.01 m and 0.2 m from it. The e.m.f induced in rod is (approximately)
View answer and explanation
Correct option: B
30  μV30\,\,\mu V
Option B (30,μV30 \\,\mu V) is correct because the induced EMF is calculated by integrating the product of the velocity and magnetic field over the length of the rod.
130 Medium
130 of 251
Application +4 | -1
If the interatomic spacing in a steel wire is 3 Ao   and   ysteel=20×1010N/m23\,{A^\mathrm{o}}\,\,\,\mathrm{ and}\,\,\,\mathrm{ }{y_{\mathrm{steel}}} = 20 \times {10^{10}}N/{m^2} then force constant is
View answer and explanation
Correct option: B
6×10−9NAo6 \times {10^{ - 9}}\frac{N}{{{A^\mathrm{o}}}}
Option B (6×10−9NAo6 \times {10^{ - 9}}\frac{N}{{{A^\mathrm{o}}}}) is correct because it correctly calculates the force constant using the Young's modulus and interatomic spacing.
131 Medium
131 of 251
Understanding +4 | -1
Longitudinal stress depends on:
View answer and explanation
Correct option: A
Area
Option A (Area) is correct because longitudinal stress is defined as force per unit area, thus directly depending on the area.
132 Medium
132 of 251
Remembering +4 | -1
The Young’s modulus of the material of a wire is equal to the
View answer and explanation
Correct option: B
Stress required to produce unit strain
Option B (Stress required to produce unit strain) is correct because Young's modulus is defined as the ratio of stress to strain, so it's the stress needed for a unit strain.
133 Medium
133 of 251
Application +4 | -1
Two bars AA and BB of circular cross-section and of same volume and made of the same material are subjected to tension. If the diameter of AA is half that of BB and if the force applied to both the rods is the same and it is in the elastic limit, the ratio of extension of AA to that of BB will be
View answer and explanation
Correct option: A
16
Option A (16) is correct because the extension is inversely proportional to the fourth power of the diameter, so halving the diameter increases the extension by a factor of 16.
134 Medium
134 of 251
Application +4 | -1
If energy acquired per one radian of twist is 16πJ\frac{1}{6}\pi J. The energy acquired by the wire on twisting it for three complete rotations is
View answer and explanation
Correct option: B
π2J{\pi ^2}J
Option B (π2J{\pi ^2}J) is correct because the total energy is calculated by multiplying the energy per radian by the total angle in radians.
135 Medium
135 of 251
Understanding +4 | -1
Statement I: Ductile metals are used to prepare thin wires.
Statement II: In the stress-strain curve of ductile metals, the length between the points representing elastic limit and breaking point is very small.
View answer and explanation
Correct option: B
Statement I is true and statement II is false
Statement I is true and statement II is false because ductile metals can be drawn into thin wires, and their stress-strain curve exhibits a large plastic region between the elastic limit and breaking point.
136 Medium
136 of 251
Understanding +4 | -1
Mark the wrong statement
View answer and explanation
Correct option: C
It is difficult to twist a long rod as compared to small rod
Option D is the wrong statement because a hollow shaft is stronger than a solid rod of the same length and mass due to its greater resistance to torsion.
137 Medium
137 of 251
Understanding +4 | -1
For most materials the Young&rsquo;s modulus is n times the rigidity modulus, where nn is
View answer and explanation
Correct option: B
3
Option B (3) is correct because Young's modulus is typically three times the rigidity modulus for most materials.
138 Medium
138 of 251
Understanding +4 | -1
A) The stretching of a coil is determined by its shear modulus.

B) Of the three states of matter the bulk modulus of elasticity is maximum for gases.
View answer and explanation
Correct option: B
A is true, B is false
Option B (A is true, B is false) is correct because the stretching of a coil is related to its shear modulus, and the bulk modulus is maximum for solids, not gases.
139 Medium
139 of 251
Remembering +4 | -1
Young's modulus for rigid material is
View answer and explanation
Correct option: B
Infinite
Option B (Infinite) is correct because a rigid material does not deform under stress, resulting in infinite Young's modulus.
140 Medium
140 of 251
Understanding +4 | -1
Statement-1: In general if we apply larger force on a wire in relaxed length it will have larger extension.
Statement-2: Stress is directly proportional to strain if the wire follows Hooke's Law.
View answer and explanation
Correct option: B
Statement-1 is true, Statement-2 is true, Statement-2 is not the correct explanation for Statement-1
Option B (Statement-1 is true, Statement-2 is true, Statement-2 is not the correct explanation for Statement-1) is correct because both statements are true, but the stress-strain relationship doesn't directly explain the extension due to a larger force.
141 Medium
141 of 251
Application +4 | -1
The length of a metal wire is l1{l_1}, when the tension in it is T1{T_1} and is l2{l_2} when the tension is T2.{T_{2.}} The natural length of the wire is
View answer and explanation
Correct option: B
l1T2−l2T1T2−T1\frac{{{l_1}{T_2} - {l_2}{T_1}}}{{{T_2} - {T_1}}}
The correct answer is B (l1T2−l2T1T2−T1\frac{{{l_1}{T_2} - {l_2}{T_1}}}{{{T_2} - {T_1}}}) because it represents the natural length derived from the relationship between tension, length, and Young's modulus.
142 Medium
142 of 251
Understanding +4 | -1
Identify the incorrect statement.
View answer and explanation
Correct option: D
Metals have larger values of Young’s modulus than elastomers
Option D (Metals have larger values of Young’s modulus than elastomers) is the incorrect statement because metals are generally stiffer than elastomers, meaning they have a higher Young's modulus.
143 Medium
143 of 251
Understanding +4 | -1
A steel wire is stretched with a definite load. If the Young’s modulus of the wire is YY. For decreasing the value of YY
View answer and explanation
Correct option: D
None of the above
Option D (None of the above) is correct because Young's modulus is a material property and is not affected by the dimensions of the wire.
144 Medium
144 of 251
Understanding +4 | -1
On stretching a wire, the elastic energy stored per unit volume is
View answer and explanation
Correct option: A
Fl/2ALFl/2AL
Option A (Fl/2ALFl/2AL) is correct because the elastic energy stored per unit volume is given by 12×stress×strain\frac{1}{2} \times \text{{stress}} \times \text{{strain}}.
145 Medium
145 of 251
Application +4 | -1
A steel wire having a radius of 2.0 mm, carrying a load of 4 kg, is hanging from a ceiling. Given that g=3.1 π ms−2,g = 3.1\,\pi \,m{s^{ - 2}}, What will be the tensile stress that would be developed in the wire?
View answer and explanation
Correct option: C
3.1 × 106 Nm−23.1\, \times \,{10^6}\,N{m^{ - 2}}
Option C (3.1 × 106 Nm−23.1\, \times \,{10^6}\,N{m^{ - 2}}) is correct because the tensile stress is calculated by dividing the force (weight) by the area of the wire.
146 Medium
146 of 251
Application +4 | -1
A material has Poisson's ratio 0.5. If a uniform rod of it suffers a longitudinal strain of 2×1032 \times 10^3, the percentage increase in its volume is :
View answer and explanation
Correct option: A
0%0 \%
Option A (0%) is correct because a Poisson's ratio of 0.5 implies that the volume remains constant under longitudinal strain.
147 Medium
147 of 251
Understanding +4 | -1
Assertion: Steel is more elastic than rubber.

Reason: For same strain, steel requires more stress to be produced in it.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and the Reason is correct explanation of the Assertion
Option A is correct because steel is more elastic than rubber, and this is because for the same strain, steel requires more stress.
148 Medium
148 of 251
Understanding +4 | -1
Assertion: Every wire is like a spring, whose spring constant, K∝1lK \propto \frac{1}{l} where ll is length of wire.

Reason: It follows from the relation K=YAlK=\frac{Y A}{l}
View answer and explanation
Correct option: A
If both Assertion and Reason are true and the Reason is correct explanation of the Assertion
Option A (If both Assertion and Reason are true and the Reason is correct explanation of the Assertion) is correct because the spring constant is inversely proportional to the length of the wire, as derived from the given relation.
149 Medium
149 of 251
Remembering +4 | -1
The modulus of elasticity is dimensionally equivalent to
View answer and explanation
Correct option: B
Stress
Option B (Stress) is correct because the modulus of elasticity is defined as the ratio of stress to strain, making it dimensionally equivalent to stress.
150 Medium
150 of 251
Understanding +4 | -1
The possible value of Poisson&rsquo;s ratio is
View answer and explanation
Correct option: D
0.4
Option D (0.4) is correct because Poisson's ratio typically ranges from -1 to 0.5 for most materials.
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