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JEE • PHYSICS • MECHANICAL PROPERTIES OF FLUIDS

Mechanical properties of fluids practice · Mixed difficulty

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Showing 271-300 of 414 questions

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271 Medium
271 of 414
Application +4 | -1
16cm316c{m^3}Of water flows per sec through a capillary tube of radius a cm and of length ll cm when connected to a pressure head of hh cm of water. If a tube of the same length and radius a/2a/2 cm is connected to the same pressure head, the quantity of water flowing through the tube per second will be
View answer and explanation
Correct option: B
1cm31\mathrm{c}{\mathrm{m}^3}
Option B (1cm31\mathrm{c}{\mathrm{m}^3}) is correct because the volume flow rate is proportional to the fourth power of the radius, so halving the radius reduces the flow rate by a factor of 16.
272 Medium
272 of 414
Understanding +4 | -1
Bernoulli’s principle applies to streamline flow for which Reynold’s number:
View answer and explanation
Correct option: B
Is between 0 and 2000
Option B is correct because Bernoulli's principle applies to streamline flow, which occurs when the Reynolds number is between 0 and 2000.
273 Medium
273 of 414
Analyzing +4 | -1
An object is floating in a liquid, kept in a container. The container is placed in a lift. Choose the correct option.
View answer and explanation
Correct option: A
Buoyant force increases as the lift accelerates up
Option A (Buoyant force increases as the lift accelerates up) is correct because the effective weight of the liquid increases, leading to a higher pressure gradient and thus a greater buoyant force.
274 Medium
274 of 414
Analyzing +4 | -1
A box filled with water has a small hole on its side near the bottom. It is dropped from the top of a tower. As it falls, a camera attached on the side of the box records the shape of the water stream coming out of the hole. The resulting video will show
View answer and explanation
Correct option: D
No water coming out
The correct answer is D because in free fall, the water and the box accelerate equally, resulting in no relative motion and thus no water coming out.
275 Medium
275 of 414
Application +4 | -1
A block of wood floats in water with (4/5) th of its volume submerged. If the same block just floats in a liquid, the density of the liquid is (in kgm−3\mathrm{kgm}^{-3} )
View answer and explanation
Correct option: D
800
Option D (800) is correct because the density of the liquid is calculated using the principle of buoyancy.
276 Medium
276 of 414
Understanding +4 | -1
Statement A: A piece of ice floats in water. The level of water remains unchanged when the ice melts completely.
Statement B: According to Archimedes' principle, the loss in weight of the body in the liquid is equal to the weight of the liquid displaced by the immersed part of the body.
View answer and explanation
Correct option: B
Statement A is true and statement B is false
Option B is correct. Statement A is true because the water level remains unchanged when ice melts completely, and statement B is false because Archimedes' principle states the loss in weight is equal to the weight of the liquid displaced by the *entire* body, not just the immersed part.
277 Medium
277 of 414
Application +4 | -1
Six identical small liquid drops are mixed together to form a bigger drop. The terminal velocity of bigger drop if terminal velocity of small drop is 10 m/s, will be
View answer and explanation
Correct option: B
10×(6)23 m/s10 \times {\left( 6 \right)^{\frac{2}{3}}}\,m/s
Option B (10×(6)23 m/s10 \times {\left( 6 \right)^{\frac{2}{3}}}\,m/s) is correct because the terminal velocity is proportional to the square of the radius, and the radius of the bigger drop is related to the radius of the smaller drops by a factor of 6136^{\frac{1}{3}}.
278 Medium
278 of 414
Application +4 | -1
The work done in blowing a soap bubble of surface tension 0.06Nm−10.06 \mathrm{Nm}^{-1} from 2 cm2 \mathrm{~cm} radius to 5 cm5 \mathrm{~cm} radius is
View answer and explanation
Correct option: B
0.003168 J0.003168 \mathrm{~J}
Option B (0.003168 J0.003168 \mathrm{~J}) is correct because it is the work done calculated using the formula for the increase in surface area of a soap bubble.
279 Medium
279 of 414
Understanding +4 | -1
If FCF_C and FAF_A denote cohesive and adhesive forces on a liquid molecule near the surface of a solid, then the surface of liquid is concave, when
View answer and explanation
Correct option: C
FA>FC2F_A > \frac{F_C}{\sqrt{2}}
Option C is correct because for a concave liquid surface, the adhesive forces must be strong enough to overcome the cohesive forces, specifically FA>FC2F_A > \frac{F_C}{\sqrt{2}}.
280 Medium
280 of 414
Understanding +4 | -1
A tank filled with non-viscous, incompressible, temperature-independent liquid has a hole in its bottom and water is flowing out of it. If the size of the hole is increased, then:
View answer and explanation
Correct option: B
The velocity of outflow of water remains unchanged
The correct answer is B (The velocity of outflow of water remains unchanged) because the velocity of outflow depends on the height of the liquid level, not the size of the hole.
281 Medium
281 of 414
Understanding +4 | -1
Statement-A: If the angle of contact is equal to π/2\pi / 2 then the level of liquid in capillary is same as outside the capillary.
Statement-B: If the angle of contact is less than π/2\pi / 2 then the liquid rises in the capillary.
View answer and explanation
Correct option: A
Statement A is true and statement B is true
Option A (Statement A is true and statement B is true) is correct because an angle of contact of π/2\pi/2 implies no capillary action, and an angle less than π/2\pi/2 results in capillary rise.
282 Medium
282 of 414
Application +4 | -1
Two mercury drop (each of radius r)r) merge to form a bigger drop, if T is the surface tension is
View answer and explanation
Correct option: D
28/3πr2T{2^{8/3}}\pi {r^2}T
Option D (28/3πr2T{2^{8/3}}\pi {r^2}T) is correct because it represents the change in surface energy when two smaller drops merge into a larger one.
283 Medium
283 of 414
Analyzing +4 | -1
A spring balance reads w1w_1 when a ball of mass mm is suspended from it. A weighing machine reads w2w_2 when a beaker of liquid is kept on the pan of balance. When the ball is immersed in liquid, the spring balance reads w3w_3 and the weighing machine reads w4w_4. The two balances are now so arranged that the suspended mass is inside the liquid in a beaker. Then,
View answer and explanation
Correct option: B
w4>w2w_4>w_2
Option B (w4>w2w_4>w_2) is correct because when the ball is immersed, it displaces liquid, increasing the weight measured by the weighing machine.
284 Medium
284 of 414
Application +4 | -1
A small hole is made at the bottom of a hollow sphere. The water enters into it when it is taken to a depth of 40 cm under water. If the surface tension of water is 0.07 Nm−1,0.07\,N{m^{ - 1}}, diameter of the hole is
View answer and explanation
Correct option: D
114 mm\frac{{1}}{14}\,mm
Option D (114 mm\frac{{1}}{{14}}\,mm) is correct because it is calculated by equating the pressure due to the water column with the pressure due to surface tension and solving for the diameter.
285 Medium
285 of 414
Analyzing +4 | -1
Assertion: Oil spreads on cold water.
Reason: The surface tension of oil is greater than that of cold water.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C (If assertion is true but reason is false) is correct because oil spreads due to lower surface tension than water, not higher.
286 Medium
286 of 414
Application +4 | -1
The terminal speed of a sphere of gold (density=19.5kgm−3)\left( {\mathrm{density} = 19.5\mathrm{kg}{\mathrm{m}^{ - 3}}} \right) is 0.2ms−10.2\mathrm{m}{\mathrm{s}^{ - 1}} in a viscous liquid (density=1.5kgm−3)\left( {\mathrm{density} = 1.5\mathrm{kg}{\mathrm{m}^{ - 3}}} \right). Then the terminal speed of a sphere of silver (density=10.5kgm−3)\left( {\mathrm{density} = 10.5\mathrm{kg}{\mathrm{m}^{ - 3}}} \right) of the same size in the same liquid is
View answer and explanation
Correct option: A
0.1ms−10.1\mathrm{m}{\mathrm{s}^{ - 1}}
Option A (0.1ms−10.1\mathrm{m}{\mathrm{s}^{ - 1}}) is correct because the terminal velocity is proportional to the difference in densities between the sphere and the liquid.
287 Medium
287 of 414
Application +4 | -1
A large tank is filled with water to a height HH. A small hole is made at the base of the tank. It takes T1{T_1} time to decrease the height of water to Hη(η>1):\frac{H}{\eta }\left( {\eta > 1} \right): and it takes T2{T_2} time to take out the rest of water. If T1=T2{T_1} = {T_2}, then the value of η\eta is
View answer and explanation
Correct option: C
4
Option C (4) is correct because the time to drain the tank is proportional to the square root of the height. Setting the times equal and solving for η yields η = 4.
288 Medium
288 of 414
Application +4 | -1
10 min10 \mathrm{~min} are taken to empty a rectangular vessel of height hh through an orifice in its bottom. How much time will it take to be emptied the vessel when half filled?
View answer and explanation
Correct option: C
7 min7 \mathrm{~min}
Option C (7 min) is correct because the time taken to empty the vessel is proportional to the square root of the height.
289 Medium
289 of 414
Remembering +4 | -1
Dimensions of coefficient of viscosity are
View answer and explanation
Correct option: C
[ML−1 T−1]\left[\mathrm{ML}^{-1} \mathrm{~T}^{-1}\right]
Option C ([ML−1 T−1]\left[\mathrm{ML}^{-1} \mathrm{~T}^{-1}\right]) is correct because it represents the correct dimensional formula for the coefficient of viscosity.
290 Medium
290 of 414
Understanding +4 | -1
Why the blood pressure in humans is greater at the feet than at the brain:
View answer and explanation
Correct option: A
Liquid pressure increases downward
Option A (Liquid pressure increases downward) is correct because the pressure in a liquid increases with depth due to the weight of the liquid column above.
291 Medium
291 of 414
Application +4 | -1
An aeroplane of mass 3×104 kg3 \times 10^4 \mathrm{~kg} and total wing area 120 m2120 \mathrm{~m}^2 is in level flight at some height. The difference in pressure between upper and lower surfaces in kilopascal is (g=10 m/s2)\left(g=10 \mathrm{~m} / \mathrm{s}^2\right)
View answer and explanation
Correct option: A
2.52.5
Option A (2.5) is correct because the pressure difference is calculated using the weight of the airplane and the wing area.
292 Medium
292 of 414
Analyzing +4 | -1
Ice pieces are floating in beaker A containing water also in a beaker B containing miscible liquid of specific gravity 1.2. When ice melts, the level of
View answer and explanation
Correct option: D
liquid in B increases
Option D (liquid in B increases) is correct because the volume of liquid displaced by the ice is less than the volume occupied by the melted ice in the liquid, due to the liquid's higher density.
293 Medium
293 of 414
Understanding +4 | -1
Bernoulli’s principle is not involved in the working/explanation of
View answer and explanation
Correct option: C
Blades of a kitchen mixer
Option C (Blades of a kitchen mixer) is correct because the blades of a kitchen mixer rely on mechanical force and do not directly involve Bernoulli's principle.
294 Medium
294 of 414
Understanding +4 | -1
Water rises in plant fibres due to
View answer and explanation
Correct option: A
Capillarity
Option A (Capillarity) is correct because water rises in plant fibers due to capillary action, which is the ability of a liquid to flow in narrow spaces against the force of gravity.
295 Medium
295 of 414
Understanding +4 | -1
Assertion: A rain drop after falling through some height attains a constant velocity.
Reason: At constant velocity, the viscous drag is just equal to its weight.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion) is correct because the constant velocity is achieved when the viscous drag balances the weight of the raindrop.
296 Medium
296 of 414
Understanding +4 | -1
A large ship can float but a steel needle sinks because of
View answer and explanation
Correct option: D
none of these.
Option D (none of these) is correct because the floating/sinking behavior is determined by the relationship between the object's density and the fluid's density, as described by Archimedes' principle.
297 Medium
297 of 414
Application +4 | -1
Typical silt(hard mud) particle of radius 20μm20\mathrm{\mu m} is on the top of lake water, its density is 2000kgm−32000\mathrm{kg}{\mathrm{m}^{ - 3}} and the viscosity of lake water is 1.0 mPa, density is 1000kgm−31000\mathrm{kg}{\mathrm{m}^{ - 3}}. If the lake is still(has no internal fluid motion). The terminal speed with which the particle hits the bottom of the lake is ………. mms−1\mathrm{mm}{\mathrm{s}^{ - 1}}
View answer and explanation
Correct option: C
0.87
Option C (0.87) is correct because it is the terminal speed calculated using Stokes' Law, considering the density difference and viscosity.
298 Hard
298 of 414
Understanding +4 | -1
When two capillary tubes of different diameters are dipped vertically, the rise of the liquid is
View answer and explanation
Correct option: D
more in the tube of smaller diameter
Option D is correct because the height of the liquid rise in a capillary tube is inversely proportional to the radius of the tube, meaning a smaller diameter tube will have a greater liquid rise.
299 Medium
299 of 414
Application +4 | -1
A piston of cross-sectional area 100 cm2100 \mathrm{~cm}^2 is used in a hydraulic pressure to exert a force of 10710^7 dyne on the water. The cross-sectional area of the other piston which supports an object having a mass of 2000 kg2000 \mathrm{~kg} is
View answer and explanation
Correct option: D
1.96×104 cm21.96 \times 10^4 \mathrm{~cm}^2
Option D (1.96×104 cm21.96 \times 10^4 \text{ cm}^2) is correct because it is the area required on the second piston to support the given mass, calculated using Pascal's law.
300 Medium
300 of 414
Understanding +4 | -1
Why the dam of water reservoir is thick at the bottom
View answer and explanation
Correct option: C
Pressure of water increases with depth
Option C (Pressure of water increases with depth) is correct because the pressure exerted by water increases linearly with depth, requiring a thicker dam at the bottom to withstand the force.
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