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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

1 Medium

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Application +4 | -1

A drop of radius

R

is split under isothermal conditions into

n

droplets, each of radius

r

the ratio of surface energies of big and each small drop is

View answer and explanation

Correct option: B

{n^{2/3}}:1

Option B (

{n^{2/3}}:1

) is correct because the ratio of surface energies is proportional to the ratio of surface areas, which depends on the number of droplets.

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