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JEE • PHYSICS • MECHANICAL PROPERTIES OF FLUIDS

Mechanical properties of fluids practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 241-270 of 414 questions

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241 Medium
241 of 414
Understanding +4 | -1
Streamline flow is more likely for liquid with
View answer and explanation
Correct option: D
low density and low viscosity
Option D (low density and low viscosity) is correct because streamline flow is favored by low density and low viscosity liquids.
242 Medium
242 of 414
Understanding +4 | -1
Assertion:- Surface tension of water is larger among fluids.
Reason:- There is hydrogen bond in water molecule so its surface tension is larger than other fluids.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because water has a higher surface tension than most fluids due to the presence of hydrogen bonds between water molecules.
243 Medium
243 of 414
Application +4 | -1
A block weighs 15 N15 \mathrm{~N} in air. It weighs 12 N12 \mathrm{~N} when immersed in water. When immersed in another liquid, it weighs 13 N13 \mathrm{~N}. Calculate the relative density (specific gravity) of the other liquid.
View answer and explanation
Correct option: A
23\frac{2}{3}
Option A (23\frac{2}{3}) is correct because it is calculated by dividing the loss of weight in the other liquid by the loss of weight in water.
244 Medium
244 of 414
Application +4 | -1
A raft of wood of mass 120 kg120 \mathrm{~kg} floats in water. The weight that can be put on the raft to make it just sink, should be (Take, draft =600kgm−3d_{\text {raft }}=600 \mathrm{kgm}^{-3} )
View answer and explanation
Correct option: A
80 kg80 \mathrm{~kg}
Option A (80 kg80 \mathrm{~kg}) is correct because it is the additional weight required for the raft to be fully submerged, calculated using the principle of buoyancy.
245 Medium
245 of 414
Application +4 | -1
A drop of liquid of diameter 2.8 mm breaks up into 125 identical drops. The change in energy is nearly (S=75  dyne  cm−1)\left( {S = 75\,\,\mathrm{dyne}\,\,\mathrm{c}{\mathrm{m}^{ - 1}}} \right)
View answer and explanation
Correct option: D
74 erg
Option D (74 erg) is correct because the change in energy is calculated by multiplying the surface tension by the increase in surface area after the drop breaks into smaller droplets.
246 Medium
246 of 414
Application +4 | -1
The amount of work done in blowing a soap bubble such that its diameter increases from d to DD is (S=S =surface tension of solution)
View answer and explanation
Correct option: B
2π(D2−d2)S2\pi \left( {{D^2} - {d^2}} \right)S
Option B is correct because the work done is the product of surface tension and the change in surface area of the soap bubble, considering both surfaces.
247 Medium
247 of 414
Analyzing +4 | -1
A beaker containing water is balance on the pan of a common balance. A solid of specific gravity 1 and mass 5 g is tied to the arm of the balance and immersed in water contained in the beaker. The scale pan with the beaker
View answer and explanation
Correct option: C
Remains unchanged
Option C (Remains unchanged) is correct because the effective weight of the solid in water is zero, so there's no change in the balance reading.
248 Medium
248 of 414
Application +4 | -1
Pressure inside a liquid drop is greater than the pressure outside by an amount 2SR,\frac{2 S}{R}, where SS is surface tension of liquid and RR is radius of liquid drop. When 8 such identical drops combine together become one single drop than the pressure difference between inside and outside the drop will be
View answer and explanation
Correct option: A
SR\frac{S}{R}
Option A (2\sqrt 2) is correct because it's derived from the prism formula using the given refracting angle and minimum deviation.
249 Medium
249 of 414
Application +4 | -1
A cubical block of ice floating in water has to support a metal piece weighing 0.5 kg0.5 \mathrm{~kg}. What can be the minimum edge of the block so that it does not sink in water? Specific gravity of ice =0.9.=0.9.
View answer and explanation
Correct option: A
17 cm17 \mathrm{~cm}
Option A (17 cm17 \mathrm{~cm}) is correct because the minimum edge length is calculated by equating the weight of the ice block and metal piece to the upthrust.
250 Medium
250 of 414
Application +4 | -1
If the excess pressure inside a liquid drop is 3 times of excess pressure of another liquid drop made from same liquid. Find ratio of their volumes.
View answer and explanation
Correct option: B
127\frac{1}{27}
Option B (127\frac{1}{27}) is correct because the ratio of volumes is the cube of the ratio of radii, and the ratio of radii is inversely proportional to the excess pressure.
251 Medium
251 of 414
Application +4 | -1
The radius R of the soap bubble is doubled under isothermal condition. If T be the surface tension of soap bubble, the work done in doing so is given by
View answer and explanation
Correct option: B
24πR2T24\pi {R^2}T
Option B (24πR2T24\pi {R^2}T) is correct because it calculates the work done as the product of the increase in surface area and the surface tension, considering both surfaces of the soap bubble.
252 Medium
252 of 414
Application +4 | -1
A rain drop of radius 0.3 mm has a terminal velocity in air = 1 m/s. The viscosity of air is 8×10−58 \times {10^{ - 5}} poise. The viscous force on it is
View answer and explanation
Correct option: A
45.2×10−4  dyne45.2 \times {10^{ - 4}}\,\,\mathrm{dyne}
Option A (45.2×10−4 dyne45.2 \times {10^{ - 4}}\,\mathrm{dyne}) is correct because it is the viscous force calculated using Stokes' Law.
253 Medium
253 of 414
Understanding +4 | -1
Statement I: Finer the capillary, greater is the height to
which the liquid rises in the tube.

Statement II: This is in accordance with the ascent
formula.
View answer and explanation
Correct option: A
Statement I is true, Statement II is true; Statement II is
the correct explanation for Statement I
Option A is correct because the height to which a liquid rises in a capillary tube is inversely proportional to the radius of the tube, as described by the ascent formula.
254 Easy
254 of 414
Understanding +4 | -1
Due to capillary action, a liquid will rise in a tube. If the angle of contact is
View answer and explanation
Correct option: A
Acute
Option A (Acute) is correct because for a liquid to rise in a tube due to capillary action, the angle of contact must be acute, resulting in a positive cosine value.
255 Medium
255 of 414
Application +4 | -1
The excess of pressure inside the first soap bubble is 3\sqrt{3} times that inside the second bubble. The ratio of volume of the first to that the second bubble is
View answer and explanation
Correct option: A
1:331: 3 \sqrt{3}
Option A (1:331: 3 \sqrt{{3}}) is correct because the ratio of volumes is the cube of the inverse ratio of the excess pressures.
256 Medium
256 of 414
Application +4 | -1
A large tank is filled with water to a height HH. A small hole is made at the base of the tank. It takes T1{T_1} time to decrease the height of water to Hη(η>1):\frac{H}{\eta }\left( {\eta > 1} \right): and it takes T2{T_2} time to take out the rest of water. If T1=T2{T_1} = {T_2}, then the value of η\eta is
View answer and explanation
Correct option: C
4
Option C (4) is correct because the time to drain the tank is proportional to the square root of the height. Setting the times equal and solving for η yields η = 4.
257 Medium
257 of 414
Understanding +4 | -1
When a sphere falling in a viscous fluid attains a terminal velocity, then
View answer and explanation
Correct option: A
The net force acting on the sphere is zero
Option A is correct because at terminal velocity, the net force on the sphere is zero, meaning the weight is balanced by the drag and buoyant forces.
258 Medium
258 of 414
Application +4 | -1
A bubble of air 2 mm in diameter rises in a liquid of viscosity 0.075 SI units and density 1350 kg m−3.1350 \mathrm{~kg} \mathrm{~m}^{-3}. The terminal velocity of the bubble is about
View answer and explanation
Correct option: C
4 cm/s
Option C (4 cm/s) is correct because the terminal velocity is calculated using Stokes' law, considering the diameter, viscosity, and density difference.
259 Medium
259 of 414
Remembering +4 | -1
Out of air and liquid, which substance is more viscous?
View answer and explanation
Correct option: B
Liquid
Option B (Liquid) is correct because liquids generally have higher viscosity than air due to stronger intermolecular forces and higher density.
260 Medium
260 of 414
Understanding +4 | -1
Statement A: A small drop of mercury is spherical but bigger drops are oval in shape
Statement B: Surface tension of liquid decreases with increase in temperature.
View answer and explanation
Correct option: A
Statement A is true and statement B is true
Option A (Statement A is true and statement B is true) is correct because larger drops are indeed oval due to gravity and surface tension decreases with increasing temperature.
261 Medium
261 of 414
Understanding +4 | -1
In which one of the following cases will the liquid flow in a pipe be most streamlined
View answer and explanation
Correct option: B
Liquid of high viscosity and low density flowing through a pipe of small radius
Option B (Liquid of high viscosity and low density flowing through a pipe of small radius) is correct because streamline flow is favored by high viscosity, low density, and small pipe radius, as indicated by a low Reynolds number.
262 Medium
262 of 414
Application +4 | -1
A cylindrical vessel of 92 cm92 \mathrm{~cm} height is kept filled upto the rim. It has four holes 1,2,31,2,3 and 4 which are respectively at heights of 20 cm,30 cm,46 cm20 \mathrm{~cm}, 30 \mathrm{~cm}, 46 \mathrm{~cm} and 80 cm80 \mathrm{~cm} from the horizontal floor. The water falling at the maximum horizontal distance from the vessel comes from
View answer and explanation
Correct option: B
Hole no.3
Option B (Hole no.3) is correct because the maximum horizontal distance is achieved when the hole is at half the height of the vessel.
263 Medium
263 of 414
Analyzing +4 | -1
A wooden block is floating in a water tank. The block is pressed to its bottom. During the process, work done is equal to
View answer and explanation
Correct option: C
Work done against upthrust minus loss of gravitational potential energy of the block
Option C (Work done against upthrust minus loss of gravitational potential energy of the block) is correct because the work done equals the work against upthrust minus the change in gravitational potential energy.
264 Medium
264 of 414
Understanding +4 | -1
When cooking oil is heated in a frying pan, the oil moves around in the pan more easily when it is hot. The main reason for this is that with rise in temperature, there is a decrease in:
View answer and explanation
Correct option: D
Viscosity
Option D (Viscosity) is correct because viscosity decreases with increasing temperature, making the oil flow more easily.
265 Medium
265 of 414
Understanding +4 | -1
A glass plate is partly dipped vertically in the mercury and the angle of contact is measured. If the plate is inclined, then the angle of contact will
View answer and explanation
Correct option: B
remain unchanged
Option B (remain unchanged) is correct because the angle of contact depends on the surface tension and the liquid-solid interaction, which are not affected by tilting the plate.
266 Medium
266 of 414
Application +4 | -1
A vessel filled with water stands on a table. In its side, the vessel has small orifice arranged at a distance 25 cm from the bottom of the vessel and at a distance 16 cm from the level of water which is kept constant. The horizontal distance from the orifice at which the jet of water fall on the table is
View answer and explanation
Correct option: B
0.4 m
Option B (0.4 m) is correct because the horizontal distance is calculated using the formula R=2HhR = 2\sqrt{Hh}, where H is the height of the orifice from the bottom and h is the height of water level from the orifice.
267 Medium
267 of 414
Application +4 | -1
Calculate the approximate change in density of water in a lake at a depth of 400 m400 \mathrm{~m} below the surface. The density of water at the surface is 1030 kg/m31030 \mathrm{~kg} / \mathrm{m}^3 and bulk modulus of water is 2×109 N/m22 \times 10^9 \mathrm{~N} / \mathrm{m}^2.
View answer and explanation
Correct option: A
2.0 kg/m32.0 \mathrm{~kg} / \mathrm{m}^3
Option A (2.0 kg/m32.0 \mathrm{~kg} / \mathrm{m}^3) is correct because it is the approximate change in density calculated using the bulk modulus formula.
268 Medium
268 of 414
Understanding +4 | -1
A liquid is stirred. When stirring is stopped, the liquid comes to rest due to-
View answer and explanation
Correct option: C
Viscosity
Option C (Viscosity) is correct because viscosity is the internal friction within a fluid that opposes motion and brings the stirred liquid to rest.
269 Medium
269 of 414
Analyzing +4 | -1
Assertion: Liquids and gases are largely incompressible and densities are therefore, nearly constant at all pressures for liquid only.
Reason: Liquids exhibit a large variation in densities with pressure but gases do not.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C (If assertion is true but reason is false) is correct because liquids are largely incompressible with nearly constant densities, while gases exhibit large density variations with pressure.
270 Medium
270 of 414
Application +4 | -1
If the water pressure gauge shows the pressure at ground floor to be 270 kPa270 \mathrm{~k} \mathrm{Pa}, how high would water rise in the pipes of a building?
View answer and explanation
Correct option: A
27.6 m27.6 \mathrm{~m}
Option A (27.6 m27.6 \mathrm{~m}) is correct because the height is calculated using the formula h=Pρgh = \frac{P}{\rho g}, where P is the pressure, ρ\rho is the density of water, and g is the acceleration due to gravity.
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