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JEE • PHYSICS • MAGNETISM AND MATTER

Magnetism and matter practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 335 questions

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91 Medium
91 of 335
Understanding +4 | -1
A compass needle which is allowed to move in a horizontal plane is taken to a geomagnetic pole. It
View answer and explanation
Correct option: B
Will stay in any position
Option B is correct because at a geomagnetic pole, the magnetic field is vertical, so a compass needle free to move horizontally will experience no horizontal force and can stay in any position.
92 Medium
92 of 335
Understanding +4 | -1
The susceptibility of certain magnetic material is 400. What is the class of magnetic material?
View answer and explanation
Correct option: C
Ferromagnetic
Option C (Ferromagnetic) is correct because ferromagnetic materials have very high susceptibility values (much greater than 1).
93 Medium
93 of 335
Remembering +4 | -1
Magnetic intensity for an axial point due to a short bar magnet of magnetic moment MM is given by
View answer and explanation
Correct option: C
μ02π×Md3\frac{{{\mu _0}}}{{2\pi }} \times \frac{M}{{{d^3}}}
Option C (μ02π×Md3\frac{{{\mu _0}}}{{2\pi }} \times \frac{M}{{{d^3}}}) is correct because the magnetic field intensity at an axial point due to a short bar magnet is given by this formula.
94 Medium
94 of 335
Application +4 | -1
Find the percent increase in the magnetic field BB when the space within a current-carrying toroid is filled with aluminium. The susceptibility of aluminium is 2.1×10−52.1 \times 10^{-5}.
View answer and explanation
Correct option: A
2.1×10−32.1 \times 10^{-3}
Option A (2.1×10−32.1 \times 10^{-3}) is correct because the percent increase in the magnetic field is equal to the susceptibility multiplied by 100.
95 Medium
95 of 335
Application +4 | -1
The absolute permeability is 8π×10−6 H/m8\pi \times {10^{ - 6}}\,H/m. Its relative permeability is
View answer and explanation
Correct option: D
20
Option D (20) is correct because relative permeability is the ratio of absolute permeability to permeability of free space.
96 Medium
96 of 335
Application +4 | -1
The earth’s magnetic field at a certain place has a horizontal component 0.3  gauss0.3\;gauss and the total strength 0.5  gauss0.5\;gauss. The angle of dip is
View answer and explanation
Correct option: C
tan⁡−143{\tan ^{ - 1}}\frac{4}{3}
Option C (tan⁡−143{\tan ^{ - 1}}\frac{4}{3}) is correct because it's calculated using the ratio of the vertical and horizontal components of Earth's magnetic field.
97 Medium
97 of 335
Application +4 | -1
The relative permeability of iron is 5500. What is its magnetic susceptibility ?
View answer and explanation
Correct option: B
5499
Option B (5499) is correct because magnetic susceptibility is calculated by subtracting 1 from the relative permeability.
98 Medium
98 of 335
Application +4 | -1
A bar magnet when placed at an angle of 30∘30^\circ to the direction of magnetic field induction of 5×10−2  T,5 \times {10^{ - 2}}\mathrm{\;T}, experiences a moment of couple 25×10−6  N−m.25 \times {10^{ - 6}}\mathrm{\;N} - \mathrm{m}. If the length of the magnet is 5 cm, its pole strength is
View answer and explanation
Correct option: A
2×10−22 \times {10^{ - 2}} A-m
Option A (2×10−22 \times {10^{ - 2}} A-m) is correct because it is the pole strength calculated using the torque equation for a magnet in a magnetic field.
99 Medium
99 of 335
Understanding +4 | -1
A magnet of magnetic moment MM is freely suspended in a uniform magnetic field strength B. The work done is deflecting the magnet through an angle θ\theta is given by
View answer and explanation
Correct option: D
MB(1−cos⁡θ)\mathrm{MB}(1-\cos \theta)
Option D (MB(1−cos⁡θ)\mathrm{MB}(1-\cos \theta)) is correct because the work done in deflecting a magnet in a magnetic field is given by the change in potential energy, which is MB(1−cos⁡θ)\mathrm{MB}(1-\cos \theta).
100 Easy
100 of 335
Understanding +4 | -1
When a ferromagnetic substance is heated to a temperature above its Curie temperature, it:
View answer and explanation
Correct option: A
Behaves like a paramagnetic substance
Option A (Behaves like a paramagnetic substance) is correct because above the Curie temperature, ferromagnetic materials lose their spontaneous magnetization and become paramagnetic.
101 Medium
101 of 335
Application +4 | -1
At a certain place the horizontal component of the earth’s magnetic field is B0{B_0} and the angle of dip is 45∘^ \circ. The total intensity of the field at that place will be
View answer and explanation
Correct option: B
2\sqrt 2 B0{B_0}
Option B (2\sqrt 2 B0{B_0}) is correct because the total intensity is calculated using the horizontal component and the angle of dip.
102 Medium
102 of 335
Application +4 | -1
A short bar magnet is placed in a horizontal plane with its axis in the magnetic meridian. Null points are found on its equatorial line (i.e., its normal bisector) at 12.5 cm12.5 \mathrm{~cm} from the centre of the magnet. The earth's magnetic field at the place is 0.38 G0.38\,\mathrm{G} and the angle of dip is zero. Locate the null points when the magnet is turned around by 180∘180^{\circ}. Assume that the length of the magnet is negligible as compared to the distance of the null-points from the centre of the magnet.
View answer and explanation
Correct option: A
15.75 cm
Option D (54∘{54^ \circ }) is correct because it is the equivalent temperature increase on the Fahrenheit scale, calculated using the conversion formula.
103 Medium
103 of 335
Understanding +4 | -1
Resultant force acting on a diamagnetic material in a magnetic field is in direction
View answer and explanation
Correct option: A
From stronger to the weaker part of the magnetic field
The correct answer is A (From stronger to the weaker part of the magnetic field) because diamagnetic materials are repelled by magnetic fields.
104 Medium
104 of 335
Understanding +4 | -1
Assertion(A): The ferro magnetic substances do not obey curie's law.

Reason(R): At curie point ferro magnetic substances start behaving as a para magnetic substances.
View answer and explanation
Correct option: B
If both (A) and (R) are true but (R) is not a correct explanation of the (A)
Option B (If both (A) and (R) are true but (R) is not a correct explanation of the (A)) is correct because both the assertion and reason are true, but the reason does not explain the assertion.
105 Medium
105 of 335
Understanding +4 | -1
A copper rod is suspended a non homogenous magnetic field region. The rod when in equilibrium will align itself
View answer and explanation
Correct option: D
In the region where magnetic field is weakest and perpendicular to the direction of magnetic field there
Option D is correct because copper is a diamagnetic material, which aligns itself in the region where the magnetic field is weakest and perpendicular to the field's direction.
106 Medium
106 of 335
Application +4 | -1
A vibration magnetometer consists of two identical bar magnets placed one over the other such that they are perpendicular and bisect each other. The time period of oscillation in a horizontal magnetic field is 25/4{2^{5/4}} second. One of the magnets is removed and if the other magnet oscillates in the same field, then the time period in second is
View answer and explanation
Correct option: C
2
Option C (2) is correct because it involves calculating the time period of oscillation for a vibration magnetometer with and without one of the magnets.
107 Medium
107 of 335
Remembering +4 | -1
The SI unit of magnetizing field is;
View answer and explanation
Correct option: A
ampere/meter
Option A (ampere/meter) is correct because it is the SI unit for magnetizing field (H).
108 Medium
108 of 335
Application +4 | -1
A specimen of iron of permeability 8×10−38 \times 10^{-3} weber/amp ×\times metre is placed in a magnetic field of strength 160amp/160 \mathrm{amp} / metre. Then magnetic induction in this iron is -
View answer and explanation
Correct option: B
1.28wb/m21.28 \mathrm{wb} / \mathrm{m}^2
Option B (1.28wb/m21.28 \mathrm{wb} / \mathrm{m}^2) is correct because it's calculated directly from the formula relating magnetic induction, permeability, and magnetic field strength.
109 Medium
109 of 335
Understanding +4 | -1
To shield an instrument from external magnetic field, it is placed inside a cabin made of
View answer and explanation
Correct option: C
Iron
Option C (Iron) is correct because iron has high permeability, which allows it to effectively shield against external magnetic fields.
110 Medium
110 of 335
Understanding +4 | -1
Consider the following statements:

1. Magnetisation can be increased without limit by applying strong magnetizing fields.

2. Magnetisation is maximum at 0 K0 \mathrm{~K}.

Which of the statements given above is/are correct in respect of a ferromagnetic material?
View answer and explanation
Correct option: C
Both 1 and 2
Option C (Both 1 and 2) is correct because magnetization can be increased by applying strong fields, and it is generally maximum at 0 K due to reduced thermal agitation.
111 Medium
111 of 335
Understanding +4 | -1
Susceptibility of a material is 100 then material will be:
View answer and explanation
Correct option: A
Ferromagnetic
Option A (Ferromagnetic) is correct because ferromagnetic materials have a very high susceptibility (χm≫1\chi_m \gg 1).
112 Medium
112 of 335
Understanding +4 | -1
Statement I The ferromagnetic property depends on temperature. At high temperature, ferromagnetic becomes paramagnet.
Statement II At high temperature, the domain wall area of a ferromagnetic substance increases.
In the light of the above statements, choose the most appropriate answer from the options given below.
View answer and explanation
Correct option: A
Statement I is true but Statement II is false
Option A (Statement I is true but Statement II is false) is correct because ferromagnetic properties are temperature-dependent, but domain wall area does not increase at high temperatures.
113 Medium
113 of 335
Understanding +4 | -1
Assertion(A): It is not necessary that every magnet has one north pole and one south pole.

Reason(R): It is a basic fact that magnetic mono poles exists.
View answer and explanation
Correct option: D
If both (A) and (R) are false
Option D is correct because magnets always have both a north and south pole, and magnetic monopoles have not been observed.
114 Medium
114 of 335
Application +4 | -1
With a standard rectangular bar magnet of length (l)\left( l \right), breadth (b;  b<<l)(b;\;b < < l) and magnetic moment MM, the time period of the magnet in vibration magnetometer is 4 s. If the magnet is cut normal to its length into four equal pieces, the time period (in second) with one of the pieces
View answer and explanation
Correct option: C
1
Option C (1) is correct because when the magnet is cut into four equal pieces normal to its length, the new time period is calculated based on the changes in moment of inertia and magnetic moment.
115 Medium
115 of 335
Understanding +4 | -1
In a ferromagnetic material, below the Curie temperature, a domain is defined as
View answer and explanation
Correct option: B
A macroscopic region with saturation magnetisation
Option B is correct because a ferromagnetic domain is a region within the material that is uniformly magnetized to saturation.
116 Medium
116 of 335
Understanding +4 | -1
The ration of intensities of magnetic field on the axial line and on equatorial line of a small bar magnet if magnetic moment at the same distance will be
View answer and explanation
Correct option: C
0.084027778
Option C (02:01) is correct because the magnetic field on the axial line is twice the magnetic field on the equatorial line at the same distance.
117 Medium
117 of 335
Understanding +4 | -1
The total intensity of earth's magnetic field at the poles is 7 units. Its value at the equator is
View answer and explanation
Correct option: C
7 units
Option C (7 units) is correct because at the equator, the magnetic field is horizontal, and the total intensity is equal to the horizontal component, which is equal to the total field at the poles (vertical component).
118 Medium
118 of 335
Remembering +4 | -1
Which of these materials requires the least
value of magnetic field strength to magnetise
it?
View answer and explanation
Correct option: A
Nickel
Option A (Nickel) is correct because ferromagnetic materials like Nickel require a relatively smaller magnetic field strength to become magnetized compared to other materials.
119 Medium
119 of 335
Remembering +4 | -1
The magnetising field required to be applied in opposite direction to reduce residual magnetism to zero is called
View answer and explanation
Correct option: A
Coercivity
Option A (Coercivity) is correct because coercivity is the measure of the magnetic field required to reduce residual magnetism to zero.
120 Medium
120 of 335
Understanding +4 | -1
The relative permeability is represented by μr\mu_{\mathrm{r}} and the susceptibility by χ\chi for a magnetic substance. Then for a paramagnetic substance.
View answer and explanation
Correct option: B
μr>1,χ>0\mu_{\mathrm{r}}>1, \chi>0
Option B (μr>1,χ>0\mu_{\mathrm{r}}>1, \chi>0) is correct because paramagnetic substances have a relative permeability slightly greater than 1 and a positive susceptibility.
Revision notes and key takeaways

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