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JEE PHYSICS MCQ: MAGNETISM AND MATTER

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Application +4 | -1
The coil in a tangent galvanometer is 16 cm in radius. If a current of 20 mA is to produce a deflection of 45∘45^\circ then the number of turns wound on it, is (Take horizontal component of earth’s magnetic field=0.36×10−4  T  and  μ0=4π×10−7  Wb  A−1  m−1= 0.36 \times {10^{ - 4}}\mathrm{\;T\;and\;}{\mathrm{\mu }_0} = 4\pi \times {10^{ - 7}}\;\mathrm{Wb\;}{\mathrm{A}^{ - 1}}\mathrm{\;}{\mathrm{m}^{ - 1}}
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Correct option: B
458
Option B (458) is correct because the number of turns is calculated using the tangent galvanometer formula, relating current, radius, magnetic field, and deflection angle.

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