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JEE PHYSICS MCQ: MAGNETISM AND MATTER

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Application +4 | -1

The area of hysteresis loop of a material is equivalent to

250\;joule

. When

10\;kg

material is magnetized by an alternating field of

50\;Hz

then energy lost in one hour will be (density of material is

7.5\;gm/c{m^3}

)

View answer and explanation

Correct option: A

6 \times {10^4}J

Option A (

6 \times {10^4}J

) is correct because it is calculated by multiplying the area of the hysteresis loop, frequency, mass, and time, then dividing by the density.

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