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JEE • PHYSICS • MAGNETIC EFFECT OF CURRENT

Magnetic effect of current practice · Mixed difficulty

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151 Medium
151 of 418
Understanding +4 | -1
An electron enters a magnetic field along perpendicular direction. Following quantity will remain constant
View answer and explanation
Correct option: B
Kinetic energy
Option B (Kinetic energy) is correct because the magnetic force does no work on the electron, so its speed and kinetic energy remain constant.
152 Medium
152 of 418
Application +4 | -1
The electric current in a circular coil of four turns produces a magnetic induction 32 T32 \mathrm{~T} at its centre. The coil is unwound and is rewound into a circular coil of single turn, the magnetic induction at the centre of the coil by the same current will be
View answer and explanation
Correct option: D
2 T2 \mathrm{~T}
Option D (2 T2 \mathrm{~T}) is correct because when the coil is rewound into a single turn, the radius increases, and the magnetic field decreases proportionally.
153 Medium
153 of 418
Application +4 | -1
When 3  ampere\sqrt 3 \;ampere current is passed in a tangent galvanometer, there is a deflection of 30∘30^\circ in it. The deflection obtained when 3  amperes3\;amperes current is passed, is
View answer and explanation
Correct option: B
45
Option B (45) is correct because the tangent of the deflection angle is directly proportional to the current in a tangent galvanometer.
154 Medium
154 of 418
Application +4 | -1
At the mid-point along the length of a long solenoid, the magnetic field is equal to XX. If the length of the solenoid is doubled and the current is reduced to half the field at the new mid-point will be nearest to
View answer and explanation
Correct option: B
X2\frac{X}{2}
Option B (X2\frac{X}{2}) is correct because the magnetic field inside a long solenoid is proportional to the number of turns per unit length and the current. Doubling the length halves the turns per unit length, and halving the current halves the magnetic field.
155 Medium
155 of 418
Application +4 | -1
An electron, a proton and an alpha particle having the same kinetic energy are moving in circular orbits of radii re,rp,rα{r_e},{r_p},{r_\alpha } respectively, in a uniform magnetic field B. the relation between re,rp,rα{r_e},{r_p},{r_\alpha } is
View answer and explanation
Correct option: B
re<rp=rα{r_e} < {r_p} = {r_\alpha }
Option B (re<rp=rα{r_e} < {r_p} = {r_\alpha }) is correct because the radius of the circular path is proportional to the square root of mass divided by charge.
156 Medium
156 of 418
Application +4 | -1
If a shunt of 15  Ω15\,\,\Omega is connected with a galvanometer of resistance 60  Ω60\,\,\Omega, then the resistance necessary to be connected in series with circuit for keeping the main current constant.
View answer and explanation
Correct option: D
48  Ω48\,\,\Omega
Option D (48  Ω48\,\,\Omega) is correct because it ensures the total current in the circuit remains constant after adding the shunt resistor.
157 Medium
157 of 418
Understanding +4 | -1
An electrically charged particle enters into a uniform magnetic induction field in a direction perpendicular to the field with a velocity v.\mathrm{v}. Then, it travels
View answer and explanation
Correct option: D
In a circular path with a radius directly proportional to its velocity
Option D (In a circular path with a radius directly proportional to its velocity) is correct because the magnetic force provides the centripetal force, resulting in circular motion with radius r=mvqBr = \frac{mv}{qB}.
158 Medium
158 of 418
Analyzing +4 | -1
Assertion (A) : An electron and a proton are accelerated by same potential difference and then enter in uniform transverse magnetic field. The radii of the two will be different.

Reason (R) : Charges on them are different.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are true but Reason is not the correct explanation of Assertion) is correct because the radii are different due to the mass-to-charge ratio, not just the charge.
159 Medium
159 of 418
Understanding +4 | -1
Assertion: Cyclotron does not accelerate electron.

Reason: Mass of the electron is very small.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is correct explanation of assertion.
Option A (Zero) is correct because a conducting medium placed between two charges will redistribute the charges, effectively canceling the electric field and force between them.
160 Medium
160 of 418
Application +4 | -1
A circular coil of 200 turns has a radius of 10 cm10 \mathrm{~cm} and carries a current of 2.0 A2.0 \mathrm{~A}. (a) Find the magnitude of the magnetic field B⃗\vec{B} at the centre of the coil. (b) At what distance from the centre along the axis of the coil will the field BB drop to half its value at the centre? (43=1.5874…)(\sqrt[3]{4}=1.5874 \ldots)
View answer and explanation
Correct option: A
2.512 mT; 7.66 cm
Option A (2.512 mT; 7.66 cm) is correct because it accurately calculates the magnetic field at the center of the coil and the distance at which the field drops to half its value.
161 Medium
161 of 418
Application +4 | -1
Two straight parallel wires carry currents of&nbsp;200   mA   and    1A200\,\,{\mkern 1mu} mA\,\,{\mkern 1mu} \mathrm{and}\,\,\,{\mkern 1mu} 1A in opposite directions. If the wires are 20 cm apart, the distance of the neutral point from the&nbsp;1A1A wire is (in cm)
View answer and explanation
Correct option: D
25
Option A (5) is incorrect. Option B (15) is incorrect. Option C (20) is incorrect. Option D (25) is correct because the neutral point is located at a distance where the magnetic fields due to both wires cancel each other out. The distance from the smaller current wire is calculated, then added to the distance between the wires to find the distance from the 1A wire.
162 Medium
162 of 418
Application +4 | -1
A long cylindrical wire kept along Z{Z}-axis carries a current of density Jˉ=J0rk^\bar{J}=J_0 r \hat{k} where J0J_0 is a constant and r{r} is the radial distance from the axis of the cylinder. The magnetic induction B{B} inside the conductor at a distance d{d} from the axis of the cylinder is
View answer and explanation
Correct option: C
μ0J0d23\frac{\mu_0 J_0 d^2}{3}
Option C (μ0J0d23\frac{\mu_0 J_0 d^2}{3}) is correct because it is the magnetic induction calculated using Ampere's law and the given current density.
163 Medium
163 of 418
Application +4 | -1
A solenoid, of length 1.5 m1.5 \mathrm{~m}, has a radius of 1.5 cm1.5 \mathrm{~cm} and has a total of 1500 turns wound on it. It carries a current of 3 A3 \mathrm{~A}. Calculate the magnitude of the axial magnetic field inside the solenoid. If an electron were to move with a speed of 2×104 ms−12 \times 10^4 \mathrm{~ms}^{-1} along the axis of this current carrying solenoid, what would be the force experienced by this electron?
View answer and explanation
Correct option: A
0.38 T,00.38 \mathrm{~T}, 0
Option A (0.38 T,00.38 \mathrm{~T}, 0) is correct because the magnetic field inside the solenoid is calculated using B=μ0NIlB=\frac{\mu_0 N I}{l}, and the force on the electron moving along the axis is zero.
164 Medium
164 of 418
Understanding +4 | -1
Given the fact that
A) Magnetic field exerts force only on a moving
charge
B) Electric field exerts force on both stationary
and moving charge
C) Magnetic field exerts force on charge moving
parallel to the direction of the field.
Which of the following is true?
View answer and explanation
Correct option: B
A and B
Option B is correct because magnetic fields exert force only on moving charges, and electric fields exert force on both stationary and moving charges.
165 Medium
165 of 418
Understanding +4 | -1
Given below are two statements:

Statement I: If the number of turns in the coil of a moving coil galvanometer is doubled then the current sensitivity becomes double.

Statement II: Increasing current sensitivity of a moving coil galvanometer by only increasing the number of turns in the coil will also increase its voltage sensitivity in the same ratio

In the light of the above statements, choose the correct answer from the options given below:
View answer and explanation
Correct option: A
Statement I is true but Statement II is false
Option A is correct because while current sensitivity doubles with the number of turns, voltage sensitivity does not increase in the same ratio due to the increase in resistance.
166 Medium
166 of 418
Understanding +4 | -1
A charged particle moving in a magnetic field
is increased in its velocity, then its radius of the
circle
View answer and explanation
Correct option: B
increases
Option B is correct because the radius of the circular path is directly proportional to the velocity of the charged particle.
167 Medium
167 of 418
Analyzing +4 | -1
Statement-1: Net force on a current carrying loop in a non-uniform magnetic field must be non-zero.
Statement-2: Force on a current carrying wire of length dl⃗\vec{dl} placed in magnetic field B→\overrightarrow{{B}} is given by dF→=idl⃗×B→\overrightarrow{d {F}}=i \vec{dl} \times \overrightarrow{{B}}
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D is correct because Statement-1 is false, as the net force can be zero if the loop is oriented in a specific way in a non-uniform field, and Statement-2 is true, providing the correct formula for the force on a current-carrying wire.
168 Medium
168 of 418
Application +4 | -1
A particle of charge qq moves in a circle of radius rr with speed vv. Treating the circular path as a current loop with an average current, find the maximum torque exerted on the loop by a uniform field of magnitude BB.
View answer and explanation
Correct option: A
12qvrB\frac{1}{2} q v r B
Option A (12qvrB\frac{1}{2} q v r B) is correct because it's the maximum torque exerted on the loop, calculated by finding the magnetic moment and using τ=MB\tau = MB.
169 Medium
169 of 418
Application +4 | -1
Magnetic fields at two points on the axis of a circular coil at a distance of 0.05m and 0.2m from the centre are in the ratio 8 : 1. The radius of coil is
View answer and explanation
Correct option: B
0.1 m
Option B (0.1 m) is correct because the radius of the coil is calculated using the magnetic field formula for a circular coil on its axis.
170 Medium
170 of 418
Application +4 | -1
A long straight solenoid with cross sectional radius ' aa ' and number of turns per unit length ' nn ' has a current varying width time as I(As−1)I\left(\mathrm{As}^{-1}\right). The magnitude of the electric field as a function of distance ' rr ' from the solenoid axis is
View answer and explanation
Correct option: A
nμ0a2I2r\frac{\mathrm{n} \mu_0 \mathrm{a}^2 \mathrm{I}}{2 \mathrm{r}}
Option A (nμ0a2I2r\frac{\mathrm{n} \mu_0 \mathrm{a}^2 \mathrm{I}}{2 \mathrm{r}}) is correct because the electric field outside the solenoid is derived using Faraday's law and Ampere's law.
171 Medium
171 of 418
Understanding +4 | -1
A cyclotron is used to accelerate :
View answer and explanation
Correct option: D
only positively charged particles
Option D is correct because cyclotrons are designed to accelerate positively charged particles due to the direction of the magnetic force.
172 Medium
172 of 418
Understanding +4 | -1
A current carrying circular coil, suspended
freely in a uniform external magnetic field
orients to a position of stable equilibrium. In
this state:
View answer and explanation
Correct option: A
the plane of the coil is normal to the external
magnetic field
Option A (the plane of the coil is normal to the external magnetic field) is correct because in stable equilibrium, the magnetic moment aligns with the magnetic field, making the plane of the coil perpendicular to the field.
173 Medium
173 of 418
Application +4 | -1
A wire of length 2 m2 \mathrm{~m} carrying a current of 1 A1 \mathrm{~A} is bent to form a circle, the magnetic moment of the coil is
View answer and explanation
Correct option: B
1πAm2\frac{1}{\pi} \mathrm{Am}^2
Option B (1πAm2\frac{1}{\pi} \mathrm{Am}^2) is correct because the magnetic moment is calculated using M=IAM = IA, where A is the area of the circular loop.
174 Medium
174 of 418
Application +4 | -1
For a long current carrying solenoid having inside magnetic field is 0.6 T0.6 \mathrm{~T}. Then find the magnetic energy per unit volume is
View answer and explanation
Correct option: A
1.43×105 J/m31.43 \times 10^5 \mathrm{~J} / \mathrm{m}^3
Option A (1.43×105 J/m31.43 \times 10^5 \mathrm{~J} / \mathrm{m}^3) is correct because it is the result of calculating magnetic energy per unit volume using the given magnetic field and permeability of free space.
175 Medium
175 of 418
Analyzing +4 | -1
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason
R.
Assertion A: For measuring the potential difference across a resistance of 600 Ω600 \,\Omega, the
voltmeter with resistance 1000 Ω1000 \,\Omega will be preferred over voltmeter with resistance 4000 Ω.4000\,\Omega.
Reason R: Voltmeter with higher resistance will draw smaller current than voltmeter with lower resistance.
In the light of the above statements, choose the most appropriate answer from the options given below:
View answer and explanation
Correct option: C
A is not correct but R is correct
Option C (A is not correct but R is correct) is correct because a voltmeter with higher resistance is preferred, and a voltmeter with higher resistance draws smaller current.
176 Medium
176 of 418
Application +4 | -1
An electron is moving with velocity 107 m/s10^7 \mathrm{~m} / \mathrm{s} on a circular path of radius 0.57 cm0.57 \mathrm{~cm} in a magnetic field of 10−2 Wb/m210^{-2} \mathrm{~Wb} / \mathrm{m}^2. Find the value of e/m for electron in  coulomb /kg\text { coulomb } / \mathrm{kg}.
View answer and explanation
Correct option: A
1.76×10111.76 \times 10^{11}
Option A (1.76×10111.76 \times 10^{11}) is correct because the e/m ratio is calculated using the formula e/m = v/Br.
177 Medium
177 of 418
Application +4 | -1
A +6μC+6 \mu \mathrm{C} point charge is moving at a constant velocity of 8×106 ms−18 \times 10^6 \mathrm{~ms}^{-1} in the +y+y direction, relative to a reference frame. At the instant when the point charge is at the origin of this reference frame, what is the magnetic field vector it produces at the following points?
(a) x=0.500 m,y=0,z=0x=0.500 \mathrm{~m}, y=0, z=0, and
(b) x=0,y=−0.500 m,z=0x=0, y=-0.500 \mathrm{~m}, z=0.
View answer and explanation
Correct option: A
−(1.92×10−5 T)k^;0-\left(1.92 \times 10^{-5} \mathrm{~T}\right) \hat{k}; 0
Option A (−(1.92×10−5 T)k^;0-(1.92 \times 10^{-5} \mathrm{~T}) \hat{{k}}; 0) is correct because it correctly calculates the magnetic field using the Biot-Savart law for a moving point charge.
178 Hard
178 of 418
Application +4 | -1
The magnetic field due to current carrying a circular loop of radius 5 cm5 \mathrm{~cm} at a point on the axis at a distance of 12 cm12 \mathrm{~cm} from the center is 250μT250 \mu \mathrm{T}. The magnetic field at the center of the loop is
View answer and explanation
Correct option: B
4394μT4394 \mu \mathrm{T}
Option B (4394 μ T) is correct because it is the calculated magnetic field at the center of the loop, based on the given magnetic field at a point on the axis.
179 Medium
179 of 418
Analyzing +4 | -1
Consider a wire carrying a steady current, ii placed in a uniform magnetic field B{B} perpendicular to its length. Consider the charges inside the wire. It is known that magnetic forces do no work. This implies that,
View answer and explanation
Correct option: B
Some charges inside the wire move to the surface as a result of B{B}
Option B is correct because the magnetic force causes charges to redistribute within the wire, leading to a surface charge accumulation.
180 Medium
180 of 418
Understanding +4 | -1
Inside a cyclotron, a charged particle is
subjected to both an electric field and a
magnetic field. It gains kinetic energy due to
View answer and explanation
Correct option: A
only the electric field
Option A (only the electric field) is correct because the electric field accelerates the charged particle, increasing its kinetic energy, while the magnetic field only changes its direction.
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