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JEE • PHYSICS • MAGNETIC EFFECT OF CURRENT

Magnetic effect of current practice · Mixed difficulty

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Showing 181-210 of 418 questions

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181 Medium
181 of 418
Understanding +4 | -1
A straight wire of diameter 0.5 mm0.5 \mathrm{~mm} carrying a current of 1 A1 \mathrm{~A} is replaced by another wire of 1 mm1 \mathrm{~mm} diameter carrying the same current. The strength of the magnetic field far away is
View answer and explanation
Correct option: B
Same as the earlier value
Option B (Same as the earlier value) is correct because the magnetic field strength depends on the current, not the diameter of the wire.
182 Medium
182 of 418
Understanding +4 | -1
A proton is projected with a uniform velocity v along the axis of a current - carrying solenoid, then :
View answer and explanation
Correct option: D
the proton will continue to move with velocity v along the axis
Option D (the proton will continue to move with velocity v along the axis) is correct because the magnetic force on a charge moving parallel to a magnetic field is zero.
183 Medium
183 of 418
Application +4 | -1
A horizontal wire, of length 5 cm5 \mathrm{~cm} and carrying a current of 2A2\mathrm{A} placed in the middle of a long solenoid and right angles to its axis. The solenoid has 1000 turns per metre and carries a steady current I. Calculate I if the force on the wire is vertically downwards and equal to 10−4 N10^{-4} \mathrm{~N}.
View answer and explanation
Correct option: A
0.8 A0.8 \mathrm{~A}
Option A (0.8 A0.8 \mathrm{~A}) is correct because it is calculated by equating the magnetic force on the wire to the given force and solving for the current I in the solenoid.
184 Medium
184 of 418
Understanding +4 | -1
A circuit to verify Ohm’s law uses ammeter and voltmeter in series or parallel connected correctly to the resistor. In the circuit
View answer and explanation
Correct option: C
Ammeter is always connected in series and voltmeter in parallel
Option C is correct because an ammeter must be connected in series to measure current, and a voltmeter must be connected in parallel to measure potential difference.
185 Medium
185 of 418
Understanding +4 | -1
The relation between voltage sensitivity (σV)({\sigma _V}) and current sensitivity (σi)\left( {{\sigma _i}} \right) of a moving coil galvanometer is (resistance of galvanometer is G).
View answer and explanation
Correct option: A
σiG=σv\frac{{{\sigma _i}}}{G} = {\sigma _\mathrm{v}}
Option A (σiG=σv\frac{{{\sigma _i}}}{G} = {\sigma _\mathrm{v}}) is correct because voltage sensitivity is current sensitivity divided by the galvanometer resistance.
186 Medium
186 of 418
Application +4 | -1
A circular loop of radius 0.0157 m carries a current of 2 Amperes. The magnetic field at the centre of the loop is [μ∘=4π×10−7  wb/A−m] [in  wb/m2]\left[ {{\mu _ \circ } = 4\pi \times {{10}^{ - 7}}\,\,wb/A - m} \right]\,\left[ {in\,\,wb/{m^2}} \right]
View answer and explanation
Correct option: B
8×10−58 \times {10^{ - 5}}
Option B (8×10−58 \times {10^{ - 5}}) is correct because the magnetic field at the center of a circular loop is directly proportional to the current and inversely proportional to the radius.
187 Medium
187 of 418
Application +4 | -1
A long solenoid with 2000 turns per meter has a small loop of radius 3 cm3 \mathrm{~cm} placed inside the solenoid normal to its axis. If the current through the solenoid increases steadily from 1.5 A to 5.5 A5.5 \mathrm{~A} in π2100 s\frac{\pi^2}{100} \mathrm{~s}, the induced emf in the loop is
View answer and explanation
Correct option: B
0.288mV0.288 \mathrm{mV}
Option B (0.288mV0.288 \mathrm{mV}) is correct because it is the induced emf calculated using Faraday's law of induction, considering the changing magnetic field due to the solenoid's current variation.
188 Medium
188 of 418
Application +4 | -1
A particle of mass mm and charge qq enters a magnetic field BB perpendicularly with a velocity vv, the radius of the circular path described by it will be
View answer and explanation
Correct option: D
mvqB\frac{\mathrm{mv}}{\mathrm{qB}}
Option D (mvqB\frac{\mathrm{mv}}{\mathrm{qB}}) is correct because it represents the radius of the circular path derived from equating magnetic force and centripetal force.
189 Hard
189 of 418
Analyzing +4 | -1
A charged particle of unit mass and unit charge moves with velocity of v⃗=(8i^+6j^)m/s\vec{v}=(8 \hat{i}+6 \hat{j}) \mathrm{m} / \mathrm{s} in a magnetic field of B⃗=2k^T.\vec{B}=2 \hat{k} T.
Then choose wrong statement.
View answer and explanation
Correct option: C
The path of the particle may be y2+z2=25y^2+z^2=25
Option C is the wrong statement. The path of the particle may be y2+z2=25y^2+z^2=25 is incorrect because the initial velocity is in the x-y plane and the magnetic field is along the z-axis, so the motion will be confined to the x-y plane.
190 Medium
190 of 418
Understanding +4 | -1
Statement-A: When a charge particle of charge 'qq' moves with a velocity vv in magnetic field of induction B⃗\vec{B} then force acting on it F⃗=q(V⃗×B⃗)\vec{F}=q(\vec{V} \times \vec{B})

Statement-B: An electron is projected in a magnetic field along the lines of force then their will be no effect on the motion of electron.
View answer and explanation
Correct option: D
Both A and B are true
Option D (Both A and B are true) is correct because Statement A correctly states the Lorentz force, and Statement B is true since the magnetic force is zero when the electron moves parallel to the magnetic field.
191 Easy
191 of 418
Understanding +4 | -1
The following statement is false for Helmholtz coils:
View answer and explanation
Correct option: B
Planes of Helmholtz coils are perpendicular to each other.
Option B is correct because the planes of Helmholtz coils are parallel, not perpendicular, to each other.
192 Medium
192 of 418
Application +4 | -1
A wire 28 m28 \mathrm{~m} long is bent into NN turns of circular coil of diameter 14 cm14 \mathrm{~cm} forming a solenoid of length 60 cm60 \mathrm{~cm}. Calculate the flux density inside it when a current of 5 amp5\,\mathrm{amp} passed through it. (μ0=12.57×10−7 m−1)\left(\mu_0=12.57 \times 10^{-7} \mathrm{~m}^{-1}\right)
View answer and explanation
Correct option: A
6.67×10−4 T6.67 \times 10^{-4} \mathrm{~T}
Option A (6.67×10−4 T6.67 \times 10^{-4} \mathrm{~T}) is correct because it is calculated using the formula for magnetic flux density inside a solenoid, B=μ0nIB = \mu_0 n I, where n is the number of turns per unit length.
193 Medium
193 of 418
Application +4 | -1
An electron of mass 9×10−31 kg9 \times 10^{-31} \mathrm{~kg} and charge 1.6 ×10−19C\times 10^{-19} \mathrm{C} moving with a velocity of 106 ms−110^6 \mathrm{~ms}^{-1} entered a magnetic field normally and described a circle of radius 10 cm10 \mathrm{~cm}. Then the intensity of the magnetic field is
View answer and explanation
Correct option: A
5.625×10−5 T5.625 \times 10^{-5} \mathrm{~T}
Option A (5.625×10−5 T5.625 \times 10^{-5} \mathrm{~T}) is correct because it is calculated using the formula for the magnetic force on a moving charge.
194 Medium
194 of 418
Application +4 | -1
When a proton has a velocity v⃗=(2i^+3j^)×106 ms−1\vec{v}=(2 \hat{i}+3 \hat{j}) \times 10^6 \mathrm{~ms}^{-1}, it experiences a force F⃗=−(1.28×10−13k^)N\vec{F}=-\left(1.28 \times 10^{-13} \hat{k}\right) \mathrm{N}. When its velocity is along the zz-axis, it experiences a force along the xx-axis. What is the magnetic field?
View answer and explanation
Correct option: A
−(0.4j^)T-(0.4 \hat{j}) \mathrm{T}
Option A (−(0.4j^)T-(0.4 \hat{j}) \mathrm{T}) is correct because it is found by applying the Lorentz force equation and analyzing the force directions for the given velocities.
195 Hard
195 of 418
Application +4 | -1
An insulating rod of length ll carries a charge qq distributed uniformly on it. The rod is pivoted at an end and is rotated at a frequency ff about a fixed perpendicular axis. The magnetic moment of the system is :
View answer and explanation
Correct option: D
13πqfl2\frac{1}{3} \pi q f l^2
Option D (240 years) is correct because after 4 half-lives, the ratio of the radioactive isotope to the stable element will be 1:15.
196 Medium
196 of 418
Analyzing +4 | -1
Statement I - A bar magnet can exert torque on itself due to it's own field.

Statement II - One element of a current carrying wire can exert a force on another element of same wire.
View answer and explanation
Correct option: A
Statement II is true; Statement II is true
Option A is correct because a bar magnet cannot exert a torque on itself due to its own field, and one element of a current-carrying wire can exert a force on another element of the same wire.
197 Medium
197 of 418
Application +4 | -1
A current of 4 A4 \mathrm{~A} produces a deflection of 30∘30^{\circ} in the galvanometer. The figure of merit is
View answer and explanation
Correct option: B
7.6 A/rad7.6 \mathrm{~A} / \mathrm{rad}
Option B (7.6 A/rad) is correct because the figure of merit is correctly calculated using the given current and deflection.
198 Medium
198 of 418
Understanding +4 | -1
A magnetic field can be produced by :-
View answer and explanation
Correct option: D
Both (1) &\& (2)
Option D (Both (1) & (2)) is correct because both a moving charge and a changing electric field can produce a magnetic field.
199 Medium
199 of 418
Application +4 | -1
A proton carrying 1 MeV kinetic energy is moving
in a circular path of radius RR in uniform magnetic
field. What should be the energy of an a-particle
to describe a circle of the same radius in the same
field?
View answer and explanation
Correct option: B
1 MeV
Option B (1 MeV) is correct because the energy of the alpha particle is equal to the energy of the proton when they have the same radius in the same magnetic field.
200 Easy
200 of 418
Understanding +4 | -1
Assertion: Electron moving perpendicular to BI\mathop B\limits^I will perform circular motion
Reason: Force by magnetic field is perpendicular to velocity
View answer and explanation
Correct option: B
If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion
Option B (If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion) is correct because both statements are true, but the reason doesn't fully explain why the motion is circular; the force must be *always* perpendicular.
201 Medium
201 of 418
Analyzing +4 | -1
Assertion (A) : A charged particle moves along positive yy-axis with constant velocity in uniform electric and magnetic fields. If magnetic field is acting along positive xx-axis, then electric field should act along positive zz-axis.

Reason (R) : To keep the charged particle undeviated the relation E=B×v\mathbf{E}=\mathbf{B} \times \mathbf{v} must hold good.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.
Option A (If both Assertion and Reason are true and the Reason is correct explanation of the Assertion) is correct because the electric and magnetic forces must balance to keep the charged particle undeviated, and the given relation ensures this.
202 Medium
202 of 418
Understanding +4 | -1
In a moving coil galvanometer, we use a radial magnetic feild so that the galvanometer scale is
View answer and explanation
Correct option: C
Linear
The correct answer is Linear because a radial magnetic field ensures that the torque on the coil is directly proportional to the current, resulting in a linear scale.
203 Medium
203 of 418
Understanding +4 | -1
To which of the following quantities, the radius
of the circular path of a charged particle
moving at right angles to a uniform magnetic
field is directly proportional?
View answer and explanation
Correct option: D
momentum of the particle
Option D is correct because the radius of the circular path of a charged particle in a magnetic field is directly proportional to the momentum of the particle.
204 Medium
204 of 418
Understanding +4 | -1
Two galvanometers ' G1G_1 ' and ' G2G_2 ' require 2 mA2 \mathrm{~mA} and 3 mA3 \mathrm{~mA} respectively to produce the same deflection. Then
View answer and explanation
Correct option: D
G1G_1 is more sensitive than G2G_2
Option D (G1G_1 is more sensitive than G2G_2) is correct because sensitivity is inversely proportional to the current required for the same deflection. Since G1G_1 requires less current, it is more sensitive.
205 Medium
205 of 418
Understanding +4 | -1
A charged particle moves through a magnetic field perpendicular to its direction, then
View answer and explanation
Correct option: C
Momentum changes but kinetic energy constant
Option C (Momentum changes but kinetic energy constant) is correct because the magnetic force only changes the direction of the velocity, not its magnitude.
206 Medium
206 of 418
Application +4 | -1
A magnetic dipole is placed under the effect of two magnetic fields inclined at 75∘75^{\circ} to each other. One of the field has a magnetic induction of 1.5×10−2 T1.5 \times 10^{-2} \mathrm{~T}. The magnet comes to rest at an angle of 30∘30^{\circ} with the direction of this field. The magnitude of the other field is
View answer and explanation
Correct option: C
1.52×10−2 T\frac{1.5}{\sqrt{2}} \times 10^{-2} \mathrm{~T}
The correct answer is C (1.52×10−2 T\frac{1.5}{\sqrt{2}} \times 10^{-2} \text{{ T}}) because the magnetic dipole aligns where the torques due to both fields balance each other.
207 Medium
207 of 418
Understanding +4 | -1
A charge particle moving in magnetic field BB, has the components of velocity along BB as well as perpendicular to BB. The path of the charge particle will be
View answer and explanation
Correct option: B
Helical path with the axis along magnetic field BB
Option B (Helical path with the axis along magnetic field BB) is correct because the component of velocity along the magnetic field causes linear motion, while the perpendicular component causes circular motion, resulting in a helical path.
208 Medium
208 of 418
Understanding +4 | -1
Identify the correct statement from the following
View answer and explanation
Correct option: C
Cyclotron frequency is independent of speed of charged particle
Option C (Cyclotron frequency is independent of speed of charged particle) is correct because the cyclotron frequency depends only on the magnetic field and the charge-to-mass ratio.
209 Medium
209 of 418
Understanding +4 | -1
A long solenoid of length L has a mean
diameter D. It has n layers of windings of N
turns each. If it carries a current I, the
magnetic field at its centre will be
View answer and explanation
Correct option: C
independent of D
Option C (independent of D) is correct because the magnetic field at the center of a long solenoid depends on the number of turns per unit length (n) and the current (I), but not on the diameter (D).
210 Medium
210 of 418
Remembering +4 | -1
Cyclotron is a device which is used to:
View answer and explanation
Correct option: C
Accelerate protons
Option C (Accelerate protons) is correct because a cyclotron is designed to accelerate heavy charged particles like protons.
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