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JEE • PHYSICS • MAGNETIC EFFECT OF CURRENT
Magnetic effect of current practice · Mixed difficulty
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Practice format and chapter quiz
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Showing 121-150 of 418 questions
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121
Medium
121 of 418
Understanding
+4 | -1
Similar or same magnetic fields can be
produced by
produced by
View answer and explanation
Correct option: A
a solenoid and a bar magnet
Option A (a solenoid and a bar magnet) is correct because both produce similar magnetic field patterns, with strong and uniform fields inside and stronger fields at the poles.
122
Medium
122 of 418
Application
+4 | -1
If we double the radius of a coil keeping the current through it unchanged, then the magnetic field at any point at a large distance from the centre becomes approximately
View answer and explanation
Correct option: C
four times
Option C (four times) is correct because the magnetic field at a large distance is proportional to the square of the radius.
123
Medium
123 of 418
Understanding
+4 | -1
The current sensitivity of a moving coil galvanometer depends on
View answer and explanation
Correct option: A
the number of turns in the coil
Option A is correct because the current sensitivity of a moving coil galvanometer is directly proportional to the number of turns in the coil.
124
Medium
124 of 418
Understanding
+4 | -1
A particle of mass , charge and kinetic energy is enters a transverse uniform magnetic field . After 5 seconds the kinetic energy of the particle will be :-
View answer and explanation
Correct option: B
10 J
Option B is correct because a magnetic field only changes the direction of a moving charge, not its speed, so the kinetic energy remains constant.
125
Medium
125 of 418
Application
+4 | -1
Proton (charge , mass ) are being accelerated in a cyclotron where a magnetic field is applied perpendicular to the dees and a battery of volts in connected across the dees to accelerate the protons. The number of revolutions per second (frequency in ) by the protons is
View answer and explanation
Correct option: B
Option B () is correct because it represents the cyclotron frequency, which depends on the charge, magnetic field, and mass of the proton.
126
Medium
126 of 418
Application
+4 | -1
A current carrying loop of radius carries a current in clock wise direction. It is placed in a uniform magnetic field such that plane of the coil is parallel to field. The net torque on the coil is
View answer and explanation
Correct option: A
Option A () is correct because the torque on a current loop in a magnetic field is given by , where M is the magnetic moment.
127
Medium
127 of 418
Application
+4 | -1
A conducting rod of length and mass is suspended by two vertical wires through its ends. An external magnetic field of is applied normal to the rod. Now the current to be passed through the rod so as to make the tension in the wires zero is [Take ]
View answer and explanation
Correct option: C
Option C () is correct because the current is calculated by equating the magnetic force to the weight of the rod.
128
Medium
128 of 418
Application
+4 | -1
A solenoid having area and length is filled with a material having relative permeability 2. The magnetic energy stored in the solenoid is:
View answer and explanation
Correct option: D
Option D () is correct because the magnetic energy density is inversely proportional to the relative permeability, leading to a reduced energy storage.
129
Medium
129 of 418
Remembering
+4 | -1
Current is flowing in a coil of area and number of turns , then magnetic moment of the coil, is equal to
View answer and explanation
Correct option: A
Option A () is correct because the magnetic moment of a current loop is given by the product of the number of turns, the current, and the area of the loop.
130
Medium
130 of 418
Analyzing
+4 | -1
Assertion: Magnetic moment of toroid is zero.
Reason: Magnetic field outside the volume of current carrying toroid is zero.
Reason: Magnetic field outside the volume of current carrying toroid is zero.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because while both the magnetic moment of a toroid is zero and the magnetic field outside the toroid is zero, the zero magnetic field is not the primary reason for the zero magnetic moment.
131
Medium
131 of 418
Understanding
+4 | -1
A force , acting on an electric charge , in presence of an electromagnetic field, moves the charge parallel to the magnetic field with velocity . Then is equal to (where and are electric field and magnetic field respectively)
View answer and explanation
Correct option: A
Option A () is correct because if the charge moves parallel to the magnetic field, the magnetic force is zero, and the net force is only due to the electric field.
132
Easy
132 of 418
Understanding
+4 | -1
Magnetic field dB to a current element at any
point on its axis is
point on its axis is
View answer and explanation
Correct option: B
zero
The correct answer is B (zero) because the magnetic field due to a current element is zero at any point on its axis due to the cross product in the Biot-Savart law.
133
Medium
133 of 418
Application
+4 | -1
Two similar moments and each magnetic moment are taken. If is cut alor its axial line and is cut along its equator line all the four pieces obtained have each of
View answer and explanation
Correct option: C
magnetic moment
Option C (magnetic moment ) is correct because cutting the magnets along either the axial or equatorial line halves the magnetic moment.
134
Medium
134 of 418
Application
+4 | -1
If the current in the toroidal solenoid increase uniformly from zero to in . Self inductance of the toroidal solenoid is . The magnitude of self induced emf is
View answer and explanation
Correct option: A
Option B (12.5 N) is correct because the reaction at the hinge is calculated by considering the torque due to the weight of the rod and the resulting angular acceleration when the string is cut.
135
Medium
135 of 418
Application
+4 | -1
When a high resistance R is connected in series with a voltmeter of resistance G, the range of the voltmeter increases 10 times then G:R will be
View answer and explanation
Correct option: C
Option C (1:9) is correct because the series resistance required to increase the voltmeter range by a factor of 10 is 9 times the voltmeter's resistance.
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136
Medium
136 of 418
Application
+4 | -1
A uniform magnetic field and electric field exist along and negative axis respectively. Under the influence of these fields a charge particle moves along undeflected. If electric field is swithed off, find the pitch of helical trajectory in which the particle will move.
View answer and explanation
Correct option: D
Option D () is correct because it's the pitch of the helical trajectory, derived from equating electric and magnetic forces and using the time period.
137
Medium
137 of 418
Understanding
+4 | -1
A wire of length L is placed parallel to the lines
of force in a uniform magnetic field B. If I is
the current in the wire, then it will experience:
of force in a uniform magnetic field B. If I is
the current in the wire, then it will experience:
View answer and explanation
Correct option: D
no force
Option D (no force) is correct because the force on a current-carrying wire in a magnetic field is given by , and when the wire is parallel to the field (), the force is zero.
138
Medium
138 of 418
Analyzing
+4 | -1
Assertion (A): If a proton and an -particle enter a uniform magnetic field perpendicularly, with the same speed, the time period of revolution of -particle is double that of proton.
Reason (R): In a magnetic field, the time period of revolution of a charged particle is inversely proportional its specific charge.
Reason (R): In a magnetic field, the time period of revolution of a charged particle is inversely proportional its specific charge.
View answer and explanation
Correct option: A
(A) and (R) are true and (R) is the correct explanation of (A)
Option A ((A) and (R) are true and (R) is the correct explanation of (A)) is correct because the time period is directly proportional to mass and inversely proportional to charge.
139
Medium
139 of 418
Application
+4 | -1
A narrow vertical rectangular coil is suspended from the middle of its upper side with its plane parallel to a uniform horizontal magnetic field of . The coil has 10 turns and the lengths of its vertical and horizontal sides are and respectively. Calculate the torque on the coil when a current of is passed into it. What would be the new value of the torque if the plane of the vertical coil was initially at to the magnetic field and a current of was passed into the coil.
View answer and explanation
Correct option: A
Option A () is correct because it correctly calculates the torque using the formula and .
140
Hard
140 of 418
Understanding
+4 | -1
Assertion: The kinetic energy does not change when a particle moves in uniform magnetic field.
Reason: The speed of the particle is not affected by magnetic field.
Reason: The speed of the particle is not affected by magnetic field.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and Reason is the correct explanation of Assertion
Option A (If both Assertion and Reason are true and Reason is the correct explanation of Assertion) is correct because the magnetic force is perpendicular to the velocity, so it does no work, keeping kinetic energy constant.
141
Medium
141 of 418
Remembering
+4 | -1
The law which states that ‘a variation in an
electric field causes magnetic field, is
electric field causes magnetic field, is
View answer and explanation
Correct option: C
Modified Ampere’s Law
Option C (Modified Ampere’s Law) is correct because it incorporates the concept of displacement current due to changing electric fields.
142
Medium
142 of 418
Application
+4 | -1
Find the current density as a function of distance from the axis of a radially symmetrical parallel stream of electrons if the magnetic induction inside the stream varies as , where and are positive constants.
View answer and explanation
Correct option: A
Option A () is correct because it is derived from Ampere's law, relating the magnetic field to the current density in a radially symmetrical stream of electrons.
143
Hard
143 of 418
Application
+4 | -1
A solenoid of 1000 turns per meter has a core with relative permeability 500. Insulated windings of the solenoid carry an electric current of 5A. The magnetic flux density produced by the solenoid is (permeability of free space )
View answer and explanation
Correct option: A
Option A () is correct. The magnetic flux density is calculated using the formula B = μ_r μ_0 n I, where μ_r is the relative permeability, μ_0 is the permeability of free space, n is the number of turns per meter, and I is the current.
144
Medium
144 of 418
Application
+4 | -1
A current of is flowing east to west in a long wire kept horizontally in the east-west direction. Find magnetic field in a horizontal plane at a distance of (i) north (ii) south from the wire
View answer and explanation
Correct option: A
Option A () is correct because it is calculated by using the formula for the magnetic field around a long straight wire at the specified distances.
145
Medium
145 of 418
Remembering
+4 | -1
Field inside a solenoid is
View answer and explanation
Correct option: B
directly proportional to current
Option B (directly proportional to current) is correct because the magnetic field inside a solenoid is directly proportional to the current flowing through it.
146
Medium
146 of 418
Understanding
+4 | -1
The magnetic moment is NOT associated with
View answer and explanation
Correct option: A
stationary charge
Option A is correct because a stationary charge does not produce a magnetic field or magnetic moment.
147
Medium
147 of 418
Remembering
+4 | -1
The magnetic induction at a point near end of a current carrying solenoid is current, number of turns per unit length, permeability
View answer and explanation
Correct option: A
Option A () is correct because the magnetic field at the end of a solenoid is half the value at the center.
148
Medium
148 of 418
Understanding
+4 | -1
Assertion (A) : Power of a magnetic force on a charged particle is always zero.
Reason (R) : Power of electric force on charged particle cannot be zero.
Reason (R) : Power of electric force on charged particle cannot be zero.
View answer and explanation
Correct option: C
If Assertion is true, but the Reason is false.
Option C (If Assertion is true, but the Reason is false) is correct because the power of a magnetic force is always zero, but the power of an electric force can be zero if the force is perpendicular to the velocity.
149
Medium
149 of 418
Understanding
+4 | -1
A small conducting circular loop is placed inside a long solenoid carrying a current. The plane of the loop contains the axis of the solenoid. If the current in the solenoid is varied, the current induced in the loop is
View answer and explanation
Correct option: C
Zero
Option C is correct because the magnetic flux through the loop remains zero regardless of the current variation in the solenoid, resulting in no induced current.
150
Easy
150 of 418
Remembering
+4 | -1
The magnetic field at a point on one end of a solenoid having turns per metre length and carrying a current of ampere is given by
View answer and explanation
Correct option: B
Option B () is correct because it represents the magnetic field at one end of a solenoid.
Revision notes and key takeaways
Review MAGNETIC EFFECT OF CURRENT in your textbook or class notes, then use this set to check your understanding.
Showing 121-150 of 418 questions
