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JEE • PHYSICS • LAWS OF MOTION

Laws of motion practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 241-270 of 426 questions

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241 Medium
241 of 426
Application +4 | -1
A 500 kg horse pulls a cart of mass 1500 kg along a level road with an acceleration of 1  ms−21\;m{s^{ - 2}}. If the coefficient of sliding friction is 0.2, then the force exerted by the horse in forward direction is
View answer and explanation
Correct option: D
6000 N
Option D (6000 N) is correct because the force exerted by the horse is the sum of the force required to accelerate the cart and horse and the force to overcome friction.
242 Medium
242 of 426
Understanding +4 | -1
Pendulum after some time becomes slow in motion and finally stops due to
View answer and explanation
Correct option: A
Air friction
Option A (Air friction) is correct because air friction opposes the motion of the pendulum, causing it to lose energy and eventually stop.
243 Medium
243 of 426
Understanding +4 | -1
Statement-I: A man in a closed cabin falling freely does not experience gravity
Statement-II: Inertial and gravitational mass have equivalence
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A (Statement-I is true and statement-II is true) is correct because a freely falling observer does not experience gravity, and inertial and gravitational mass are equivalent according to the equivalence principle.
244 Medium
244 of 426
Understanding +4 | -1
When a body is stationary
View answer and explanation
Correct option: C
the combination of forces acting on it balances each other
Option C (the combination of forces acting on it balances each other) is correct because, according to Newton's first law, a stationary body experiences balanced forces resulting in zero net force.
245 Medium
245 of 426
Application +4 | -1
A body is moving with a speed of 1 ms−11 \mathrm{~ms}^{-1} and a force F\mathrm{F} is needed to stop it in a distance xx. If the speed of the body is 3 ms−13 \mathrm{~ms}^{-1}, the force needed to stop it in the same distance x\mathrm{x} will be
View answer and explanation
Correct option: D
9 F9 \mathrm{~F}
Option D (9F) is correct because the force needed to stop the body is proportional to the square of its velocity.
246 Medium
246 of 426
Application +4 | -1
A rocket is fired with a speed u=3gRu=3 \sqrt{g R} from the earth surface. What will be its speed at interstellar space?
View answer and explanation
Correct option: C
7gR\sqrt{7 g R}
Option C (7gR\sqrt{7 g R}) is correct because it is derived from the conservation of mechanical energy, considering the initial kinetic and potential energy and the final kinetic energy at interstellar space.
247 Medium
247 of 426
Understanding +4 | -1
Select the wrong statement(s) from the following.
I. Newton's laws of motion hold good for both inertial and non-inertial frames

II. During explosion, linear momentum is conserved
III. Force of friction is zero when no driving force is applied
View answer and explanation
Correct option: A
I only
Option A (I only) is correct because Newton's laws of motion are only valid in inertial frames of reference.
248 Medium
248 of 426
Application +4 | -1
A lorry starting from rest moving with acceleration 2 m/s22 {~m} / {s}^2, has a trolley 4.5 m4.5 {~m} long. A box is placed at 4.5 m4.5 {~m} from the open end and coefficient of friction between box and lorry is 0.02 . The distance covered by the lorry by the time the box falls off the trolley is (g=10 m/s2)\left({g}=10 {~m} / {s}^2\right)
View answer and explanation
Correct option: A
5 m5 {~m}
Option C (109v\frac{{10}}{9}v) is correct because the apparent frequency is calculated using the Doppler effect formula, considering the velocities of both the source and the observer.
249 Medium
249 of 426
Analyzing +4 | -1
Assertion (A) : Speed of a particle moving in a circle varies with time as, v=(4t−12)v=(4 t-12). Such type of circular motion is not possible.

Reason (R) : Speed cannot change linearly with time.
View answer and explanation
Correct option: C
If Assertion is true, but the Reason is false.
Option C is correct because the assertion is true; negative speed is not possible, but the reason is false; speed can change linearly with time (constant acceleration).
250 Medium
250 of 426
Application +4 | -1
An initially stationary device lying on a frictionless floor explodes into two pieces and slides across the floor. One piece is moving in positive xx-direction, then other piece is moving in
View answer and explanation
Correct option: C
Negative xx-direction
Option C (Negative xx-direction) is correct because, according to the law of conservation of momentum, if one piece moves in the positive x-direction, the other must move in the negative x-direction to maintain zero total momentum.
251 Medium
251 of 426
Application +4 | -1
Inside a horizontally moving box, an experimenter finds that when an object is placed on a smooth horizontal table and is released, it moves with an acceleration of 10 ms−210 \mathrm{~ms}^{-2}. In this box, if 1-kg body is suspended with a light string, the tension in the string in equilibrium position. (w.r.t. experimenter) will be (take g=10 ms−2g=10 \mathrm{~ms}^{-2} )
View answer and explanation
Correct option: B
102 N10 \sqrt{2} \mathrm{~N}
Option B (102 N10 \sqrt{2} \mathrm{~N}) is correct because the tension in the string is the resultant of the gravitational force and the pseudo force due to the box's acceleration.
252 Medium
252 of 426
Application +4 | -1
A disc revolves in a horizontal plane at a steady rate of 3 rad/s. A coin will remain on the disc if kept at a distance of 20 cm from the axis of rotation. The coefficient of friction ( g=10 m/s2g = 10\,m/{s^2}) is:
View answer and explanation
Correct option: D
0.18
Option D (0.18) is correct because it is calculated by equating the centripetal force to the frictional force and solving for the coefficient of friction.
253 Hard
253 of 426
Application +4 | -1
Two guns A and B can fire bullets at speeds 1 km/s and 2 km/s, respectively. From a point on a horizontal ground, they are fired in all possible directions. The ratio of maximum areas covered by the bullets on the ground fired by the two guns is
View answer and explanation
Correct option: B
0.052777778
Option B (01:16) is correct because the ratio of areas is proportional to the fourth power of the ratio of their velocities.
254 Medium
254 of 426
Understanding +4 | -1
Rocket engines lift a rocket from the earth surface because hot gas with high velocity
View answer and explanation
Correct option: C
react against the rocket and push it up
Option C is correct because the rocket is propelled upwards due to the reaction force from the high-velocity exhaust gases.
255 Medium
255 of 426
Application +4 | -1
A nucleus of mass MM breaks into 3 nuclei with a mass defect of Δm\Delta m. Find the speed of each daughter nuclei if they have equal mass.
View answer and explanation
Correct option: B
c2Δm(M−Δm)c \sqrt{\frac{2 \Delta m}{(M-\Delta m)}}
Option B (c2Δm(M−Δm)c \sqrt{\frac{{2 \Delta m}}{{(M-\Delta m)}}}) is correct because it is derived from equating the total kinetic energy of the fragments to the energy released from the mass defect.
256 Medium
256 of 426
Application +4 | -1
A body of mass mm moving with a constant velocity VV hits another body of the mass mm moving with same velocity VV but in the opposite direction, and sticks to it. The velocity of the compound body after collision is :
View answer and explanation
Correct option: C
Zero
Option C (Zero) is correct because, according to the conservation of momentum, the total momentum after the collision is zero, resulting in zero velocity.
257 Medium
257 of 426
Application +4 | -1
A machine gun fires a bullet of mass 40 grams with a velocity 1200  ms−11200\,\,m{s^{ - 1}} . The man holding it can
exert a maximum force of 144 N on the gun. The number of bullets he can fire per second at the most is
View answer and explanation
Correct option: A
3
Option A (3) is correct because it's the maximum number of bullets that can be fired per second based on the force the man can exert.
258 Medium
258 of 426
Understanding +4 | -1
In case of uniform circular motion which of the following physical quantity do not remain constant
View answer and explanation
Correct option: B
Momentum
Option B is correct because in uniform circular motion, speed and kinetic energy are constant, but momentum changes direction.
259 Medium
259 of 426
Analyzing +4 | -1
Assertion: A rocket in flight is an illustration of the application of the principle of conservation of linear momentum of a system of varying mass.

Reason: The linear momentum of the exhaust gases becomes irrelevant, as these gases no longer remain a part of the rocket.
View answer and explanation
Correct option: C
If assertion is true, but reason is false.
The assertion is true, but the reason is false. The linear momentum of the exhaust gases is relevant and must be considered for the conservation of linear momentum.
260 Medium
260 of 426
Understanding +4 | -1
Which motion does not require force to maintain it?
View answer and explanation
Correct option: C
Uniform straight line motion
Option C is correct because, according to Newton's first law, an object in uniform straight-line motion requires no net force to maintain its motion.
261 Medium
261 of 426
Analyzing +4 | -1
Assertion (A) A particle of mass MM at rest decay into two particles of masses m1m_1 and m2m_2, having non-zero velocities will have ratio of de-Broglie wavelengths unity.

Reason (R) Here we cannot apply conservation of linear momentum.
View answer and explanation
Correct option: C
If Assertion is true but Reason is false.
Option C is correct. The assertion is true because the ratio of de Broglie wavelengths is unity due to conservation of momentum. The reason is false because conservation of linear momentum *can* be applied.
262 Medium
262 of 426
Understanding +4 | -1
Assertion: The words 'action' and 'reaction' in the third law of motion stand for simultaneous mutual forces between a pair of objects.
Reason: In this context action always precede or cause reaction.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Assertion is true because action and reaction are simultaneous mutual forces. Reason is false because action does not precede or cause reaction; they occur simultaneously.
263 Medium
263 of 426
Understanding +4 | -1
A thief stole a box full of valuable articles of weight w and while carrying it on his head jumped down from a wall of height hh from the ground. Before he reaches the ground, he experienced a load
View answer and explanation
Correct option: A
Zero
Option A (Zero) is correct because both the thief and the box are in free fall, experiencing weightlessness.
264 Medium
264 of 426
Application +4 | -1
A hammer of mass 10 kg10 \mathrm{~kg} moving with a speed of 5 m/s5 \mathrm{~m} / \mathrm{s} strikes the head of a nail driving it 30 cm30 \mathrm{~cm} into the wall. Find the impulse imparted to the nail.
View answer and explanation
Correct option: D
50 N s50 \mathrm{~N~s}
Option D (50 N s50 \mathrm{~N~s}) is correct because the impulse is calculated as the change in momentum of the hammer.
265 Medium
265 of 426
Application +4 | -1
A body of mass 60 kg is pushed with just enough force to start it moving on a rough surface with μs=0.5{\mu _s} = 0.5 and μk=0.4{\mu _k} = 0.4 and the force continues to act afterwards. The acceleration of the body is (in m/sec⁡2)\left( {\mathrm{in}\,m/{{\sec }^2}} \right)
View answer and explanation
Correct option: A
0.98
Option A (0.98) is correct because the acceleration is calculated using the difference between static and kinetic friction coefficients.
266 Medium
266 of 426
Application +4 | -1
A rocket motor consumes 100 kg100 \mathrm{~kg} of fuel per second, exhausting it with a speed of 5×103 ms−15 \times 10^3 \mathrm{~ms}^{-1}. What force is exerted on the rocket?
View answer and explanation
Correct option: A
5×105 N5 \times 10^5 \mathrm{~N}
Option A (5×105 N5 \times 10^5 \mathrm{~N}) is correct because the force exerted on the rocket is calculated using the formula Thrust = udmdtu \frac{d m}{d t}.
267 Medium
267 of 426
Analyzing +4 | -1
Assertion: A table cloth can be pulled from a table without dislodging the table.
Reason: For a moving object, if its speed changes, its velocity must change and it must have some acceleration.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because both statements are true, but the reason doesn't explain why the tablecloth can be pulled without disturbing the table.
268 Medium
268 of 426
Understanding +4 | -1
Three weights W,2 W\mathrm{W}, 2 \mathrm{~W} and 3 W3 \mathrm{~W} are connected to identical springs suspended from rigid horizontal rod. The assembly of the rod and the weights fall freely. The positions of the weights from the rod are such that
View answer and explanation
Correct option: C
All will be at the same distance
Option C (All will be at the same distance) is correct because during free fall, the apparent weight of all objects becomes zero, so the springs will not be stretched.
269 Medium
269 of 426
Understanding +4 | -1
Select the incorrect statement(s) from the following.
I. Limiting friction is always greater than the kinetic friction
II. Limiting friction is always less than the static friction
III. Coefficient of static fiction is always greater than the coefficient of kinetic fiction
View answer and explanation
Correct option: C
II and III
Option D (I and II) is correct because limiting friction is the maximum static friction, and kinetic friction is generally less than static friction.
270 Medium
270 of 426
Application +4 | -1
A bullet of mass 20 g20 {~g} moving with a speed of 100 m s−1100 {~m} {~s}^{-1} enters a heavy wooden block and stops after a distance of 50 cm50 {~cm}. The average resistive force exerted by the block on the bullet is
View answer and explanation
Correct option: C
200 N200 {~N}
Option C (200 N) is correct because it is calculated by using the kinematic equation to find the deceleration of the bullet and then applying Newton's second law to find the average resistive force.
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