Skip to main content
Back to LAWS OF MOTION

Your Progress

0 / 426 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • PHYSICS • LAWS OF MOTION

Laws of motion practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 271-300 of 426 questions

Preparing practice and saved progress…

271 Medium
271 of 426
Analyzing +4 | -1
A spring balance and a physical balance are kept in a lift. In these balances equal masses are placed. If now the lift starts moving upwards with constant acceleration, then
View answer and explanation
Correct option: D
The reading of spring balance will increase and the physical balance will remain in equilibrium
Option D is correct. The spring balance reading increases due to the pseudo force, while the physical balance remains in equilibrium as the pseudo force acts equally on both masses.
272 Medium
272 of 426
Understanding +4 | -1
A lift is descending with a constant velocity ' v{v} '. A man in the lift drops a coin. The coin experiences an acceleration towards the floor equal to :
View answer and explanation
Correct option: C
gg
Option C (gg) is correct because the acceleration of the coin relative to the floor of the lift is still the acceleration due to gravity, regardless of the lift's constant velocity.
273 Medium
273 of 426
Remembering +4 | -1
Formula for true force is
View answer and explanation
Correct option: A
F=maF = ma
Option A (F=maF = ma) is correct because it represents Newton's second law in its simplest form, where mass is constant.
274 Medium
274 of 426
Understanding +4 | -1
Assertion: Frictional force opposes relative motion and dissipates power in the form of heat.
Reason: Friction is always an undesirable force.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C is correct because frictional force indeed opposes relative motion and dissipates energy as heat, but friction is not always undesirable; it's necessary for many processes like walking or braking.
275 Medium
275 of 426
Understanding +4 | -1
When an elevator cabin falls down, the cabin and all the bodies fixed in the cabin are accelerated with respect to
View answer and explanation
Correct option: C
man standing on earth
Option C (man standing on earth) is correct because the cabin and all bodies within it accelerate downwards relative to an observer on Earth.
276 Medium
276 of 426
Understanding +4 | -1
If a stone is thrown out of an accelerated train, then
acceleration of the stone at any instant depends on
View answer and explanation
Correct option: A
force acting on it at that instant
The correct answer is A (force acting on it at that instant) because the acceleration of the stone at any instant is determined solely by the net force acting on it at that instant according to Newton's Second Law.
277 Medium
277 of 426
Analyzing +4 | -1
Statement I: A cloth covers a table. Some dishes are kept on it. The cloth can be pulled out without dislodging the dishes from the table.
Statement II: For every action there is an equal and opposite reaction.
View answer and explanation
Correct option: B
Statement I is true, statement II is true; statement II is not a correct explanation for statement I
Option B (Statement I is true, statement II is true; statement II is not a correct explanation for statement I) is correct because the cloth can be pulled out due to inertia (Newton's first law), and statement II is Newton's third law, which is true but not relevant.
278 Medium
278 of 426
Application +4 | -1
A platform is moving upwards with an acceleration of 5 ms−25 \mathrm{~ms}^{-2}. At the moment when its velocity is u=3 ms−1u=3 \mathrm{~ms}^{-1}, a ball is thrown from it with a speed of 30 ms−130 \mathrm{~ms}^{-1} w.r.t. platform at an angle of θ=30∘\theta=30^{\circ} with horizontal. The time taken by the ball to return to the platform is
View answer and explanation
Correct option: A
2 s2 \mathrm{~s}
Option A (2 s2 \mathrm{~s}) is correct because the time of flight is calculated using the relative acceleration between the ball and the platform.
279 Easy
279 of 426
Analyzing +4 | -1
Choose the wrong statement
View answer and explanation
Correct option: C
If the speed of a particle is constant, its acceleration must be zero
Option C is correct because constant speed does not necessarily mean zero acceleration; uniform circular motion is an example where speed is constant, but acceleration is non-zero.
280 Medium
280 of 426
Analyzing +4 | -1
Statement I: If bodies slide down an inclined plane without rolling, then all the bodies reach the bottom simultaneously.

Statement II: Acceleration of all bodies are equal and independent of shape.
View answer and explanation
Correct option: A
If both Statement - I and Statement - II are true, and Statement - II is the correct explanation of Statement - I
Option A (If both Statement - I and Statement - II are true, and Statement - II is the correct explanation of Statement - I) is correct because the acceleration is independent of shape, leading to simultaneous arrival.
281 Medium
281 of 426
Application +4 | -1
A body of mass 10 kg10 {~kg} is acted upon by a force given by equation F=(3t2−30)F=\left(3 t^2-30\right) Newton's, The initial velocity of the body is 10 m/s10 {~m} / {s}. The velocity of the body after 5sec5 {sec} is
View answer and explanation
Correct option: C
7.5 m/s7.5 {~m} / {s}
Option C (7.5 m/s7.5 {~m} / {s}) is correct because it is the result of integrating the force equation to find the velocity at t=5s, considering the initial velocity.
282 Medium
282 of 426
Application +4 | -1
A spacecraft of mass M is moving with velocity v in free space when it explodes and breaks in two. After the explosion, a mass m of the spacecraft is left stationary. What is the velocity of other part?
View answer and explanation
Correct option: A
Mv(M−m)\frac{{Mv}}{{\left( {M - m} \right)}}
Option A (Mv(M−m)\frac{{Mv}}{{\left( {M - m} \right)}}) is correct because it is derived from the conservation of momentum principle.
283 Medium
283 of 426
Understanding +4 | -1
External agencies like gravitational and magnetic forces ...X...
exerts force on a body from a distance.
Here, X refers to
View answer and explanation
Correct option: A
can
Option A (can) is correct because gravitational and magnetic forces are examples of external agencies that can exert force on a body from a distance.
284 Medium
284 of 426
Understanding +4 | -1
The net force acting is not zero on
View answer and explanation
Correct option: A
A retarding train
Option A (A retarding train) is correct because a retarding train has a non-zero net force due to its deceleration.
285 Hard
285 of 426
Application +4 | -1
The velocity of a body of mass 20 kg20\,kg decreases from 20 m/s20\,m/s to 5 m/s5\,m/s in a distance of 100   m100\,\,\,m Force on the body is
View answer and explanation
Correct option: C
−37.5 N- 37.5\,N
Option C (-37.5 N) is correct because it is the force calculated using the work-energy theorem or kinematic equations to find the acceleration and then applying Newton's second law.
286 Medium
286 of 426
Understanding +4 | -1
An athlete does not come to rest immediately after crossing the winning line due to the
View answer and explanation
Correct option: B
Inertia of motion
Option B (Inertia of motion) is correct because the athlete continues moving due to inertia, resisting a change in their state of motion.
287 Easy
287 of 426
Understanding +4 | -1
Which of the following statement (s) is/are incorrect?
View answer and explanation
Correct option: B
Friction always opposes the motion of two bodies.
Option B is correct because friction opposes the *relative* motion between two surfaces in contact, not necessarily the motion of the bodies themselves. Static friction can even help initiate motion (e.g., walking).
288 Medium
288 of 426
Application +4 | -1
Two equals forces are acting at a point with an angle of 60∘60^{\circ} between them. If the resultant force is equal to 403 N40 \sqrt{3} \mathrm{~N}, the magnitude of each force is
View answer and explanation
Correct option: A
40 N40 \mathrm{~N}
Option D (6 m) is correct because it is the height the ball will reach after one impact, considering the 40% energy loss.
289 Medium
289 of 426
Application +4 | -1
A body of mass mm is launched up on a rough inclined plane making an angle 45∘45^{\circ} with horizontal. If the time of ascent is half of the time of descent, the frictional coefficient between plane and body is
View answer and explanation
Correct option: B
35\frac{3}{5}
Option B (3/5) is correct because it is derived from equating the distances traveled during ascent and descent, considering the different accelerations due to friction.
290 Medium
290 of 426
Understanding +4 | -1
Statement-I: Newton's third law of motion is applicable only when bodies are in motion or rest.
Statement-II: Newton's third law applies to all types of force, e.g. gravitational, electric or magnetic forces etc.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A (Statement-I is true and statement-II is true) is correct because Newton's third law applies to bodies at rest or in motion and to all types of forces.
291 Medium
291 of 426
Understanding +4 | -1
Assertion: When a force F⃗\vec{F} attempts to slide a body along a surface, a frictional force parallel to the surface and directed so as to oppose the sliding, is exerted on the body by the surface.
Reason: It is due to the bonding between the body and the surface.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because the frictional force arises due to bonding between the body and the surface.
292 Medium
292 of 426
Analyzing +4 | -1
Assertion : The two bodies of masses M and m (M > m) are allowed to fall from the same height if the air resistance for each be the same then both the bodies will reach the earth simultaneously.
Reason : For same air resistance, acceleration of both the bodies will be same.
View answer and explanation
Correct option: A
Assertion is correct, reason is correct; reason is a correct explanation for assertion.
Option A (Assertion is correct, reason is correct; reason is a correct explanation for assertion) is correct because the acceleration difference due to air resistance is smaller for the heavier object, causing them to fall at nearly the same rate.
293 Medium
293 of 426
Application +4 | -1
A body of mass 10 kg is projected from the ground with a velocity 30 m/s at an angle 60∘60^\circ with the vertical. If t1{t_1} is the time in seconds at which the body is projected and t2{t_2} is the time in seconds at which reaches the ground. The change in momentum in kgms−1kgm{s^{ - 1}} during the time (t2−t1)\left( {{t_2} - {t_1}} \right) is
View answer and explanation
Correct option: C
300 m
Option C (300 m) is correct because the change in momentum is equal to the impulse, which is the force of gravity multiplied by the time of flight.
294 Medium
294 of 426
Understanding +4 | -1
Statement-I: A concept of pseudo forces is valid both for inertial as well as non-inertial frame of reference
Statement-II: A frame accelerated with respect to an inertial frame is a non-inertial frame.
View answer and explanation
Correct option: C
Statement-I is false and statement-II is true
Statement-I is false because pseudo forces are only valid in non-inertial frames. Statement-II is true because a frame accelerating with respect to an inertial frame is, by definition, a non-inertial frame.
295 Medium
295 of 426
Application +4 | -1
A lift of mass 2000 kg2000 \mathrm{~kg} is supported by thick steel ropes. If maximum upward acceleration of the lift be 1.2 ms−21.2 \mathrm{~ms}^{-2}, and the breaking stress for the ropes be 2.8×108 Nm−22.8 \times 10^8 \mathrm{~Nm}^{-2}, what should be the minimum diameter of rope?
View answer and explanation
Correct option: A
1 cm1 \mathrm{~cm}
Option A (1 cm1 \mathrm{~cm}) is correct because it is the minimum diameter calculated based on the breaking stress and the maximum tension in the rope.
296 Medium
296 of 426
Analyzing +4 | -1
Statement-I: If the force varies with time in a complicated way then the net force is measured by the total change in momentum of the body.
Statement-II: Change in momentum and impulsive force are numerically equal.
View answer and explanation
Correct option: C
Statement-I is false and statement-II is true
Statement-I is false and statement-II is true. Statement I should refer to the impulse, not the net force, and Statement II correctly states the impulse-momentum theorem.
297 Medium
297 of 426
Understanding +4 | -1
A passenger in a moving bus is thrown forwards when the bus is suddenly stopped. This is explained by
View answer and explanation
Correct option: A
Newton’s first law
Option A (π\pi) is correct because A×B=−(B×A)\mathbf{A} \times \mathbf{B} = -(\mathbf{B} \times \mathbf{A}), so for A×B=B×A\mathbf{A} \times \mathbf{B}=\mathbf{B} \times \mathbf{A} to hold, the angle must be π\pi.
298 Medium
298 of 426
Application +4 | -1
A car of mass MM is moving with a uniform velocity vv on a horizontal road when the hero of a Hindi film drops himself on it from above. Taking the mass of the hero to be mm, what will be the velocity of the car after the event?
View answer and explanation
Correct option: A
MvM+m\frac{M v}{M+m}
Option A (MvM+m\frac{{Mv}}{{M+m}}) is correct because it applies the principle of conservation of momentum in the horizontal direction during the inelastic collision.
299 Easy
299 of 426
Remembering +4 | -1
In the above ques., the height to which the lift takes the passenger is
View answer and explanation
Correct option: D
36 meters
The correct answer is D (36 meters) because the distance traveled is the area under the velocity-time graph, which calculates to 36 meters.
300 Easy
300 of 426
Understanding +4 | -1
A particle of mass mm is moving with a uniform velocity v1v_1. It is given an impulse such that its velocity becomes v2v_2. The impulse is equal to
View answer and explanation
Correct option: D
m(v2−v1){m}\left({v}_2-{v}_1\right)
Option D m(v2−v1){m}\left({v}_2-{v}_1\right) is correct because impulse is defined as the change in momentum, which is mass times the change in velocity.
Revision notes and key takeaways

Review LAWS OF MOTION in your textbook or class notes, then use this set to check your understanding.

Showing 271-300 of 426 questions

Your practice

0 / 426 answered · 426 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.