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JEE • PHYSICS • LAWS OF MOTION

Laws of motion practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 391-420 of 426 questions

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391 Medium
391 of 426
Understanding +4 | -1
Assertion: Pseudo force is an imaginary force which is recognised only by a non-inertial observer to explain the physical situation according to Newton's laws.
Reason: Pseudo force has no physical origin, that is, it is not caused by one of the basic interactions in nature. It does not exist as on action reaction pair.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because pseudo forces are imaginary forces arising in non-inertial frames and lack a physical origin.
392 Medium
392 of 426
Application +4 | -1
If impulse II varies with time tt as F(kg−ms−1)=20t2−40tF\left(\mathrm{kg}-\mathrm{ms}^{-1}\right)=20 t^2-40 t. The change in momentum is minimum at
View answer and explanation
Correct option: B
t=1 st=1 \mathrm{~s}
Option B (t=1 st=1 \mathrm{~s}) is correct because the change in momentum is minimum when the rate of change of impulse with respect to time is zero.
393 Easy
393 of 426
Application +4 | -1
An object is placed on the surface of a smooth inclined plane of inclination θ\theta. It takes time tt to reach the bottom of the inclined plane. If the same object is allowed to slide down rough inclined plane of same inclination θ\theta, it takes time nt to reach the bottom where n\mathrm{n} is a number greater than 1 . The coefficient of friction μ\mu is given by
View answer and explanation
Correct option: A
μ=tan⁡θ(1−1n2)\mu=\tan \theta\left(1-\frac{1}{\mathrm{n}^2}\right)
Option A (μ=tan⁡θ(1−1n2)\mu=\tan \theta\left(1-\frac{1}{\mathrm{n}^2}\right)) is correct because it is derived from comparing the distances traveled on smooth and rough inclined planes using kinematic equations.
394 Medium
394 of 426
Understanding +4 | -1
Select the incorrect statement(s) about static friction.
I. Static friction exists on its own
II. In the absence of applied force static friction is maximum
III. Static friction is equal and opposite to the applied force upto a certain limit
View answer and explanation
Correct option: D
I and II
Option D (I and II) is correct because static friction does not exist on its own and is zero in the absence of an applied force.
395 Easy
395 of 426
Understanding +4 | -1
A rider on horse falls backward when horse starts running all of a sudden because of
View answer and explanation
Correct option: C
Inertia of rest
Option C (Inertia of rest) is correct because the rider's upper body tends to remain at rest while the horse moves forward.
396 Medium
396 of 426
Understanding +4 | -1
Statement I: Limiting friction depends on surface area.
Statement II: Kinetic friction depends on surface area.
View answer and explanation
Correct option: D
Both statements are false
Option D (Both statements are false) is correct because neither limiting friction nor kinetic friction depends on the surface area of contact.
397 Medium
397 of 426
Understanding +4 | -1
Why does a man getting down from a running bus fall forward?
View answer and explanation
Correct option: B
Due to inertia of motion upper part of body continues to be in motion in forward direction while feet come to rest as soon as they touch the road
Option B (Due to inertia of motion upper part of body continues to be in motion in forward direction while feet come to rest as soon as they touch the road) is correct because the upper body continues moving forward due to inertia while the feet stop upon contact with the ground.
398 Medium
398 of 426
Application +4 | -1
The force of 6 N acts on a body at rest and of mass 1 kg. During this time the body attains a velocity of 30 m/s. The time for which the force acts on the body is
View answer and explanation
Correct option: C
5 seconds
Option C (5 seconds) is correct because it is the time calculated using the formula relating force, mass, acceleration, and velocity.
399 Medium
399 of 426
Understanding +4 | -1
Which of the following is NOT an illustration of Newton's third law?
View answer and explanation
Correct option: B
A cricket player lowering his hands while catching a cricket ball
Option B (A cricket player lowering his hands while catching a cricket ball) is correct because this action is an example of impulse and momentum, not Newton's third law.
400 Medium
400 of 426
Application +4 | -1
The rate of mass of the gas emitted from rear of a rocket is initially 0.1 kg/sec0.1 \mathrm{~kg} / \mathrm{sec}. If the speed of the gas relative to the rocket is 50 m/sec50 \mathrm{~m} / \mathrm{sec} and mass of the rocket is 2 kg2 \mathrm{~kg}, then the acceleration of the rocket in m/sec2\mathrm{m} / \mathrm{sec}^2 is
View answer and explanation
Correct option: C
2.5
Option C (2.5) is correct because the acceleration of the rocket is calculated using the formula a=vMdMdta = \frac{v}{M} \frac{dM}{dt}.
401 Hard
401 of 426
Analyzing +4 | -1
A body of mass M is kept on a rough horizontal surface (friction coefficient μ\mu). A person is trying to pull the body by applying a horizontal force but the body is not moving. The force by the surface on the body is F, where
View answer and explanation
Correct option: C
Mg≤F≤Mg1+μ2Mg \le F \le Mg\sqrt {1 + {\mu ^2}}
Option C (Mg≤F≤Mg1+μ2Mg \le F \le Mg\sqrt {1 + {\mu ^2}}) is correct because the force by the surface ranges from the weight to the maximum force including friction.
402 Medium
402 of 426
Analyzing +4 | -1
Assertion(A): A glass ball is dropped on concrete floor can easily get broken compared, if it is dropped on wooden floor.

Reason(R): On concrete floor, glass ball will take less time to come to rest.
View answer and explanation
Correct option: A
Both Assertion and Reason are true and Reason is the correct explanation of Assertion.
Option A (Both Assertion and Reason are true and Reason is the correct explanation of Assertion) is correct because the glass ball experiences a greater force on the concrete floor due to the shorter time interval, leading to breakage.
403 Medium
403 of 426
Application +4 | -1
A lift is moving upwards with an acceleration aa. The force exerted by a person of mass MM on the floor of the lift will be
View answer and explanation
Correct option: B
Mg+MaMg + Ma
Option B (Mg+MaMg + Ma) is correct because the force exerted by the person on the floor is the normal reaction, which is equal to the apparent weight in an accelerating lift.
404 Medium
404 of 426
Application +4 | -1
Five persons A,B,C,D\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D} and E\mathrm{E} are pulling a cart of mass 100 kg100 \mathrm{~kg} on a smooth surface and the cart is moving with an acceleration of 3 m s−23 \mathrm{~m} \mathrm{~s}^{-2} in the east direction. If another person F\mathrm{F} comes and starts pulling the cart with a force of 100 N100 \mathrm{~N} due west, then the acceleration of the cart will be
View answer and explanation
Correct option: C
2 m s−22 \mathrm{~m} \mathrm{~s}^{-2}
Option C (2 m s−22 \mathrm{~m} \mathrm{~s}^{-2}) is correct because the net force is reduced by the force applied by person F, resulting in a lower acceleration.
405 Medium
405 of 426
Analyzing +4 | -1
A light spring balance hangs from the hook of the other light spring balance and a block of mass M kg hangs from the former one. Then the true statement about the scale reading is
View answer and explanation
Correct option: B
Both the scales read M Kg each
Option B is correct because each spring balance will read the weight of the block, which is M kg.
406 Medium
406 of 426
Application +4 | -1
One end of a long string of linear mass density 8.0×10−3 kg m−18.0 \times 10^{-3} \mathrm{~kg} \mathrm{~m}^{-1} is connected to an electrically driven tuning fork of frequency 256 Hz256 \mathrm{~Hz}, such that the frequency of tuning fork is equal to that of the string. The other end passes over a pulley and is tied to a pan containing a mass of 90 kg90 \mathrm{~kg}. The pulley end absorbs all the incoming energy so that reflected waves at this end have negligible amplitude. At t=0t=0, the left end (fork end) of the string x=0x=0 has zero transverse displacement (y=0)(y=0) and is moving along positive yy direction. The amplitude of the wave is 5.0 cm5.0 \mathrm{~cm}. Then the transverse displacement yy (in m) as function of xx and tt that describes the wave on the string. (Take g=9.8 m/s2g=9.8 \mathrm{~m} / \mathrm{s}^2 )
View answer and explanation
Correct option: A
0.05sin⁡(1.61×103t−4.84x)0.05 \sin \left(1.61 \times 10^3 \mathrm{t}-4.84 \mathrm{x}\right)
Option A (0.05sin⁡(1.61×103t−4.84x)0.05 \sin \left(1.61 \times 10^3 \mathrm{t}-4.84 \mathrm{x}\right)) is correct because it represents the transverse displacement of the wave with the correct amplitude, angular frequency, and wave number.
407 Medium
407 of 426
Application +4 | -1
A man of mass 60 kg60 {~kg} climbed down using an elevator. The elevator had an acceleration of 4 ms−24 {~ms}^{-2}. If the acceleration due to gravity is 10 ms−210 {~ms}^{-2}, the man's apparent weight on his way down is
View answer and explanation
Correct option: C
360 N360 {~N}
Option A (q22ε0AK\frac{{{q^2}}}{{2{\varepsilon _0}AK}}) is correct because it represents the force of attraction between the plates of a parallel plate capacitor considering the electric field due to one plate acting on the other.
408 Medium
408 of 426
Understanding +4 | -1
Law that proves that different masses accelerate to the earth at the same rate, but with different forces is
View answer and explanation
Correct option: B
Newton's second law
Option B (Newton's second law) is correct because Newton's second law (F=maF=ma) explains that the force required to accelerate different masses at the same rate varies with the mass.
409 Medium
409 of 426
Understanding +4 | -1
Swimming is possible on account of
View answer and explanation
Correct option: C
Newton’s Third law of motion
Option C (Newton’s Third law of motion) is correct because swimming involves pushing water backward, and the water pushes the swimmer forward.
410 Easy
410 of 426
Analyzing +4 | -1
Assertion : For the motion of electron around nucleus, Newton's second law is used.
Reason : Newton's second law can be used for motion of any object.
View answer and explanation
Correct option: C
Assertion is correct, reason is incorrect.
Option D (Assertion is incorrect, reason is correct) is correct because Newton's second law is not directly applicable to the motion of electrons around the nucleus due to quantum mechanical effects, but Newton's second law is generally applicable to macroscopic objects.
411 Medium
411 of 426
Remembering +4 | -1
In an ideal string tension at all points of all string will be
View answer and explanation
Correct option: A
Same
Option A (Same) is correct because in an ideal string, the tension is assumed to be uniform throughout the string.
412 Medium
412 of 426
Understanding +4 | -1
Conservation of momentum in a collision between particles can be understood from
View answer and explanation
Correct option: D
Both Newton's second and third law
Option D (Both Newton's second and third law) is correct because conservation of momentum arises from Newton's second law (F=dp/dtF = dp/dt) and the fact that internal forces between colliding particles are equal and opposite (Newton's third law).
413 Medium
413 of 426
Analyzing +4 | -1
Which of the following sets of forces can not have resultant force equal to zero. (All forces are in newton).
View answer and explanation
Correct option: D
10, 20, 40
Option D (10, 20, 40) is correct because the sum of the two smallest forces (10 + 20 = 30) is less than the largest force (40), so they cannot form a closed triangle and have a zero resultant.
414 Medium
414 of 426
Understanding +4 | -1
The frictional force on a block of weight 10 N10 \mathrm{~N} of area 0.1 m20.1 \mathrm{~m}^2 is 5 N5 \mathrm{~N}. If area of block is increased to 0.2 m20.2 \mathrm{~m}^2, keeping weight and material same; the frictional force on new block would be (assume all other conditions to be same)
View answer and explanation
Correct option: A
5 N5 \mathrm{~N}
Option A is correct because frictional force depends on the normal force and the coefficient of friction, not the area of contact.
415 Medium
415 of 426
Application +4 | -1
A bullet of mass 28 grams is fired from a rifle of mass 11 kg with a velocity of 100 m/s. The recoil of the rifle is
View answer and explanation
Correct option: B
-0.25
Option B (-0.25) is correct because it is the recoil velocity calculated using the conservation of momentum.
416 Medium
416 of 426
Remembering +4 | -1
The impulse on a particle due to a force acting on it during a given time interval is equal to the change in its
View answer and explanation
Correct option: B
Momentum
Option B (Momentum) is correct because the impulse on a particle equals the change in its momentum, according to the impulse-momentum theorem.
417 Medium
417 of 426
Understanding +4 | -1
Statement-I: Angle of repose is equal to angle of limiting friction.
Statement-II: When the body is just at the point of motion, the force of friction in this stage is called as limiting friction.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option C is correct because electric field lines do not form closed loops; they originate from positive charges and terminate on negative charges.
418 Medium
418 of 426
Application +4 | -1
A body of mass 60 kg is pushed with just enough force to start it moving on a rough surface with μs=0.5{\mu _s} = 0.5 and μk=0.4{\mu _k} = 0.4 and the force continues to act afterwards. The acceleration of the body is (in m/sec⁡2)\left( {\mathrm{in}\,m/{{\sec }^2}} \right)
View answer and explanation
Correct option: A
0.98
Option A (0.98) is correct because the acceleration is calculated as the difference between the static and dynamic friction coefficients multiplied by the acceleration due to gravity.
419 Medium
419 of 426
Application +4 | -1
A body of mass 10 kg is moving on a horizontal surface by applying a force of 10 N in forward direction. If body moves with constant velocity, the work done by force of fiction for a displacement of 2m is
View answer and explanation
Correct option: A
−20 J- 20\,J
Option A (−20 J-20\,J) is correct because the work done by friction is negative and equal to the force of friction times the displacement.
420 Medium
420 of 426
Understanding +4 | -1
The laws of Newton's are applicable
View answer and explanation
Correct option: B
In inertial frame
Option B is correct because Newton's laws of motion are only directly applicable in inertial frames of reference, where there is no acceleration.
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