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JEE • PHYSICS • LAWS OF MOTION

Laws of motion practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 361-390 of 426 questions

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361 Medium
361 of 426
Understanding +4 | -1
The one which does not represent a force in any context is
View answer and explanation
Correct option: B
Impulse
Option B (Impulse) is correct because impulse is the change in momentum, not a force itself, while friction, tension, and weight are all forces.
362 Medium
362 of 426
Understanding +4 | -1
A cyclist bends while taking turn in order to
View answer and explanation
Correct option: B
provide required centripetal force
Option B (provide required centripetal force) is correct because bending allows the cyclist to lean into the turn, using a component of their weight to provide the necessary centripetal force.
363 Medium
363 of 426
Analyzing +4 | -1
Which of the following statement (s) is/are correct?

I. A string has a mass mm. If it is accelerated, tension is non-uniform and if it is not accelerated, tension is uniform.

II. Tension force is an electromagnetic force.
View answer and explanation
Correct option: B
Only II
Only II is correct. Tension force is an electromagnetic force. Statement I is incorrect because tension can be non-uniform even if the string is not accelerated (e.g., hanging vertically under gravity).
364 Medium
364 of 426
Remembering +4 | -1
Which of the following is NOT a fundamental force in nature?
View answer and explanation
Correct option: C
Friction
Option C (Friction) is correct because friction is a contact force arising from electromagnetic interactions between surfaces, not a fundamental force.
365 Medium
365 of 426
Application +4 | -1
A body starts sliding down an inclined plane of inclination 30∘30^{\circ}. The upper part of length 2 m2 {~m} is smooth and lower part of length 4 m4 {~m} is rough. The coefficient of friction between the plane and the body, if the body is brought to rest just when it reaches the bottom
View answer and explanation
Correct option: A
32\frac{\sqrt{3}}{2}
Option A (32\frac{\sqrt{3}}{2}) is correct because the coefficient of friction is calculated by equating the work done by friction to the change in potential energy.
366 Medium
366 of 426
Understanding +4 | -1
On a banked road, which force is essential to provide the necessary centripetal force to a car to take a turn while driving at the optimum speed?
View answer and explanation
Correct option: A
Component of normal reaction
Option A (Component of normal reaction) is correct because at optimum speed, the horizontal component of the normal reaction provides the necessary centripetal force.
367 Easy
367 of 426
Analyzing +4 | -1
Statement I: A car is moving in a horizontal circular plane with varying speed, then the frictional force is neither pointing towards the radial direction nor along the tangential direction.
Statement II: Components of the frictional force are providing the necessary tangential and centripetal acceleration, in the above situation.
View answer and explanation
Correct option: A
Statement I is true, Statement II is true; Statement II is the correct explanation for Statement I
Option A is correct because the frictional force provides both the tangential and centripetal acceleration, resulting in a net force that is neither purely radial nor tangential.
368 Medium
368 of 426
Remembering +4 | -1
Which one of the following is not used to reduce friction
View answer and explanation
Correct option: C
Sand
Option C (Sand) is correct because sand is used to increase friction, not reduce it. The other options are lubricants or methods to reduce friction.
369 Medium
369 of 426
Application +4 | -1
A vehicle of mass 120 kg is moving with a uniform velocity of 108   kmh−1\;\mathrm{km}{\mathrm{h}^{ - 1}}. The force required to step the vehicle in 10 s is
View answer and explanation
Correct option: C
360 N
Option C (360 N) is correct because it is the force calculated from the change in momentum divided by the time interval.
370 Medium
370 of 426
Application +4 | -1
An object of mass 3 kg3 {~kg} is at rest. Now a force of F⃗=6t2i^+4tj^\vec{F}=6 t^2 \hat{i}+4 t \hat{j} is applied on the object then the velocity of the object at t=3 st=3 {~s} is
View answer and explanation
Correct option: B
18i^+6j^18 \hat{i}+6 \hat{j}
Option B (18i^+6j^18 \hat{i}+6 \hat{j}) is correct because it is the result of integrating the force function with respect to time and dividing by the mass.
371 Medium
371 of 426
Application +4 | -1
The object at rest suddenly explodes into three parts with the mass ratio 2:1:1. The parts of equal masses move at right angles to each other with equal speed ‘vv’. The speed of the third part after explosion will be
View answer and explanation
Correct option: D
v2\frac{v}{{\sqrt 2 }}
Option D (v2\frac{v}{{\sqrt 2 }}) is correct because it is derived from the conservation of momentum in two dimensions after the explosion.
372 Medium
372 of 426
Application +4 | -1
Human heart is pumping blood with constant velocity v m s−1v\,m\,{s^{ - 1}} at the rate of M kg s−1.M\,kg\,{s^{ - 1}}. The force required for this is (in NN)
View answer and explanation
Correct option: B
MvMv
Option B (MvMv) is correct because force is the rate of change of momentum, and in this case, it's the product of the mass flow rate and the velocity.
373 Medium
373 of 426
Analyzing +4 | -1
Assertion: The weighing machine measures the weight of a body.
Reason: Weightlessness means the absence of weight.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because a weighing machine measures apparent weight, not true weight, and weightlessness means the absence of apparent weight, not true weight.
374 Medium
374 of 426
Understanding +4 | -1
In a non-inertial frame, the second law of motion is written as
where, Fp\mathbf{F}_p is pseudo force while a\mathbf{a} is the acceleration of the body relative to the non-inertial frame.
View answer and explanation
Correct option: C
F=ma−Fp\mathbf{F}=m \mathbf{a}-\mathbf{F}_p
Option C (F=ma−Fp\mathbf{F}=m \mathbf{a}-\mathbf{F}_p) is correct because in a non-inertial frame, Newton's second law includes a pseudo force term subtracted from the net force.
375 Medium
375 of 426
Application +4 | -1
A machine gun fires a bullet of 10 g with a speed of 100 ms−1.100\,m{s^{ - 1}}. A person holding the gun can exert a maximum force of 100 N on it. The number of bullets that can be fired from the gun per second is
View answer and explanation
Correct option: B
100
Option B (100) is correct because the number of bullets fired per second is determined by the maximum force the person can exert and the momentum change of each bullet.
376 Hard
376 of 426
Understanding +4 | -1
A metre scale is moving with uniform velocity. This implies
View answer and explanation
Correct option: B
the force acting on the scale is zero and the torque acting about centre of mass of the scale is also zero
Option B is correct because uniform velocity implies zero net force and zero net torque acting on the meter scale.
377 Medium
377 of 426
Application +4 | -1
A force vector applied on a mass is represented as F⃗=(6i^−8j^+10k^)N\vec{F}=(6 \hat{i}-8 \hat{j}+10 \hat{k}) \mathrm{N} and accelerates with 1 m/sec21 \mathrm{~m} / \mathrm{sec}^2. What will be the mass of the body?
View answer and explanation
Correct option: A
102 kg10 \sqrt{2} \mathrm{~kg}
Option A (102 kg10 \sqrt{2} \mathrm{~kg}) is correct because mass is calculated by dividing the magnitude of the force by the acceleration.
378 Medium
378 of 426
Analyzing +4 | -1
If a person with a spring balance and a body hanging from it goes up and up in an aeroplane, then the reading of the weight of the body as indicated by the spring balance will
View answer and explanation
Correct option: C
First increase and then decrease
Option D (First increase and then decrease) is correct because the apparent weight increases due to upward acceleration initially, and then decreases due to decreasing gravity at higher altitudes.
379 Medium
379 of 426
Application +4 | -1
A rocket of initial mass 6,000 kg6,000 \mathrm{~kg} ejects mass at a constant rate of 16 kg s−116 \mathrm{~kg} \mathrm{~s}^{-1} with constant relative speed of 11kms−111 \mathrm{kms}^{-1}. What is acceleration of the rocket a minute after the blast? Neglect gravity.
View answer and explanation
Correct option: A
34.92 ms−234.92 \mathrm{~ms}^{-2}
Option A (34.92 ms−234.92 \mathrm{~ms}^{-2}) is correct because the acceleration of the rocket is calculated using the Tsiolkovsky rocket equation, considering the rate of mass ejection and relative speed.
380 Medium
380 of 426
Application +4 | -1
At a certain instant of time the mass of rocket going up vertically is 100 kg. If it is ejecting 5 kg of gas per second at a speed of 400 m/s, the acceleration of the rocket would be (Taking g=10  m/s2)g = 10\;\mathrm{m}/{\mathrm{s}^2})
View answer and explanation
Correct option: B
10 m/s2m/{s^2}
Option B (10 m/s2m/{s^2}) is correct because the acceleration is calculated by subtracting gravitational acceleration from the upward acceleration due to the rocket's thrust.
381 Medium
381 of 426
Application +4 | -1
A minimum force FF is applied to a block of mass 102 kg102 \mathrm{~kg} to prevent it from sliding on a plane with an inclination angle 30∘30^{\circ} with the horizontal. If the coefficients of static and kinetic friction between the block and the plane are 0.40.4 and 0.30.3 respectively, then the force FF is
View answer and explanation
Correct option: A
157 N157 \mathrm{~N}
Option A (157 N) is correct because the minimum force required to prevent sliding is the difference between the component of weight along the plane and the maximum static friction force.
382 Medium
382 of 426
Application +4 | -1
An object of mass 15 kg15 {~kg} moves at a constant speed of 15 ms−115 {~ms}^{-1}. A constant force, which acts for 5 seconds on the object gives it a speed 5 ms−1{ms}^{-1} in opposite direction. The force acting on the object is?
View answer and explanation
Correct option: D
−60 N-60 {~N}
Option D (-60 N) is correct because it is the force calculated from the rate of change of momentum, considering the change in direction.
383 Medium
383 of 426
Understanding +4 | -1
Assertion: Rocket in flight is not an illustration of projectile.

Reason: Rocket takes flight due to combustion of fuel and does not move under the gravity effect alone
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A is correct because the rocket's flight is not solely due to projectile motion under gravity; it's propelled by fuel combustion, making the reason a correct explanation of the assertion.
384 Medium
384 of 426
Understanding +4 | -1
When a train takes a turn, the passengers are thrown outwards because of-
View answer and explanation
Correct option: C
Inertia of direction
Option C is correct because passengers experience inertia of direction, which causes them to resist the change in direction when the train turns.
385 Medium
385 of 426
Understanding +4 | -1
Units of impulse is
View answer and explanation
Correct option: C
kg−m/skg - m/s
Option C is correct because impulse is defined as the change in momentum, which has units of kg-m/s.
386 Easy
386 of 426
Understanding +4 | -1
If the coefficient of friction is 1, the angle of friction is
View answer and explanation
Correct option: B
45∘45^\circ
Option B (45∘45^\circ) is correct because the angle of friction is the arctangent of the coefficient of friction, and when the coefficient of friction is 1, the angle is 45 degrees.
387 Easy
387 of 426
Understanding +4 | -1
Assertion: To conserve linear momentum of a system, no force should act on the system.

Reason: If net force on a system is zero, its linear momentum should remain constant.
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true
Option D is correct because the reason accurately describes the condition for linear momentum conservation, while the assertion is too restrictive.
388 Easy
388 of 426
Application +4 | -1
A force is applied for a duration of 10 seconds on a body of mass 5 kg that is at rest. As a result the body acquires a velocity of 2 ms−12\,m{s^{ - 1}}. Find the magnitude of the force applied
View answer and explanation
Correct option: A
1 N
Option A (1 N) is correct because the force is calculated using Newton's second law and the given values of mass, velocity, and time.
389 Medium
389 of 426
Application +4 | -1
A body under the action of a force Fˉ=9i−6j+8k\bar F = 9i - 6j + 8k acquires an acceleration of 2  m/s2.2\,\,m/{s^2}. The mass of this body be
View answer and explanation
Correct option: A
6.7
Option A (6.7) is correct because the mass is calculated by dividing the magnitude of the force by the acceleration.
390 Medium
390 of 426
Application +4 | -1
A book of weight 20 N is pressed between two hands and each hand exerts a force of 40 N. If the book just starts to slide down. Coefficient of friction is
View answer and explanation
Correct option: A
0.25
Option A (0.25) is correct because the coefficient of friction is calculated by balancing the weight of the book with the frictional forces from both hands.
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