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JEE • PHYSICS • KINETIC THEORY OF GASES

Kinetic theory of gases practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 290 questions

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181 Medium
181 of 290
Remembering +4 | -1
The absolute zero is the temperature at which
View answer and explanation
Correct option: C
Molecular motion ceases
Option C (Molecular motion ceases) is correct because absolute zero (0 K or -273.15 °C) is theoretically the temperature at which all molecular motion stops.
182 Easy
182 of 290
Understanding +4 | -1
Assertion: Specific heat of a gas at constant pressure CPC_P is greater than its specific heat at constant volume CVC_V.
Reason: At constant pressure, some heat is spent in expansion of the gas.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion) is correct because at constant pressure, some heat is used for expansion, requiring more heat input than at constant volume.
183 Medium
183 of 290
Application +4 | -1
Calculate the total number of degrees of freedom possessed by the molecules in 1 cm31 \mathrm{~cm}^3 of H2\mathrm{H}_2 gas at N.T.P.
View answer and explanation
Correct option: C
1.34375×1020{1.34375} \times 10^{20}
Option A (4.34375×1020{4.34375} \times 10^{20}) is correct because it represents the total degrees of freedom calculated using Avogadro's number, the volume, and the degrees of freedom for a diatomic molecule.
184 Medium
184 of 290
Understanding +4 | -1
The velocities of ten particles (in ms−1\mathrm{ms}^{-1}) are 0,2,3,4,4,4,5,5,6,90,2,3,4,4,4,5,5,6,9. The most probable speed is
View answer and explanation
Correct option: B
4 ms−14 \mathrm{~ms}^{-1}
Option B (4 ms⁻¹) is correct because the most probable speed is the speed that occurs most frequently in the given data set.
185 Medium
185 of 290
Understanding +4 | -1
The kinetic energy per g  molg\;mol for a diatomic gas at room temperature is
View answer and explanation
Correct option: B
52RT\frac{5}{2}RT
Option B (52RT\frac{5}{2}RT) is correct because a diatomic gas has 5 degrees of freedom at room temperature.
186 Easy
186 of 290
Analyzing +4 | -1
Assertion: Maxwell speed distribution graph is symmetric about most probable speed.
Reason: rms speed of ideal gas, depends upon its type (monoatomic, diatomic and polyatomic).
View answer and explanation
Correct option: D
If both assertion and reason are false
Option D is correct because both assertion and reason are false. The Maxwell speed distribution graph is asymmetric, and the rms speed of an ideal gas depends on temperature and molar mass, not the type of gas (monoatomic, diatomic, etc.).
187 Medium
187 of 290
Application +4 | -1
A vessel contains two non-reactive gases neon (monatomic) and oxygen (diatomic). The ratio of their partial pressures is 1:21: 2. The ratio of number of molecules is:
View answer and explanation
Correct option: C
12\frac{1}{2}
Option C (12\frac{1}{2}) is correct because the ratio of the number of molecules is equal to the ratio of their partial pressures at the same volume and temperature.
188 Medium
188 of 290
Understanding +4 | -1
The degrees of freedom of a triatomic gas is
View answer and explanation
Correct option: A
6
Option A (6) is correct because a triatomic gas molecule has 3 translational and 3 rotational degrees of freedom, totaling 6.
189 Medium
189 of 290
Understanding +4 | -1
Which one of the following is a wrong statement in kinetic theory of gases?
View answer and explanation
Correct option: B
The collision between molecules is inelastic.
Option B (The collision between molecules is inelastic) is correct because the kinetic theory of gases assumes perfectly elastic collisions between gas molecules.
190 Medium
190 of 290
Understanding +4 | -1
Which of the following is correct for the molecules of an ideal gas at a given temperature?
View answer and explanation
Correct option: B
Molecules have different speed distribution of which average remain constant
Option B (Molecules have different speed distribution of which average remain constant) is correct because, according to Maxwell's distribution, gas molecules at a given temperature have a range of speeds, but the average speed remains constant.
191 Medium
191 of 290
Understanding +4 | -1
At NTP, sample of equal volume of chlorine and oxygen is taken. Now ratio of no. of molecules is
View answer and explanation
Correct option: A
1  :11\;:1
Option A (1  :  11\;:\;1) is correct because, according to Avogadro's hypothesis, equal volumes of gases at the same temperature and pressure contain the same number of molecules.
192 Medium
192 of 290
Remembering +4 | -1
The number of degrees of freedom for each atom of a monoatomic gas is
View answer and explanation
Correct option: A
3
Option A (3) is correct because a monoatomic gas atom can move independently in three spatial dimensions (x, y, and z), giving it three translational degrees of freedom.
193 Medium
193 of 290
Understanding +4 | -1
A gas enclosed in a closed pot is kept in a train moving with high speed, the temperature of the gas
View answer and explanation
Correct option: C
Will remain the same
Option C is correct because the temperature of the gas depends on the average kinetic energy of its molecules, which is independent of the train's motion.
194 Medium
194 of 290
Understanding +4 | -1
Assertion: Molecules of monoatomic gas has three degrees of freedom.

Reason: Molecules of diatomic gas has five degrees of freedom.
View answer and explanation
Correct option: B
If both assertion and reason are true and reason is not correct explanation of assertion.
Option B is correct because both statements are true, but the reason does not explain the assertion.
195 Medium
195 of 290
Application +4 | -1
The temperature of an ideal gas is increased from 37∘C37^{\circ} \mathrm{C} to 137∘C137^{\circ} \mathrm{C}, then percentage increase in vrms v_\text{rms } is:
View answer and explanation
Correct option: B
14.9%14.9 \%
Option B (14.9%14.9 \%) is correct because it is the calculated percentage increase in vrms v_\text{rms } using the formula vrms=3RTMv_{\text{rms}} = \sqrt{\frac{3RT}{M}} and converting Celsius to Kelvin.
196 Medium
196 of 290
Understanding +4 | -1
What is the value of RCP\frac{R}{{{C_P}}} for diatomic gas
View answer and explanation
Correct option: C
2/72/7
Option C is correct because for a diatomic gas, Cp = (7/2)R, so R/Cp = 2/7.
197 Medium
197 of 290
Application +4 | -1
Three moles of nitrogen is mixed with six moles of helium. The effective molar specific heat of the mixture at constant volume is
View answer and explanation
Correct option: C
1.83 R
Option C (1.83 R) is correct because it accurately calculates the effective molar specific heat of the mixture using the formula Cvmixture=n1Cv1+n2Cv2n1+n2Cv_{mixture} = \frac{{n_1Cv_1 + n_2Cv_2}}{{n_1 + n_2}}.
198 Medium
198 of 290
Understanding +4 | -1
The absolute temperature of a gas is determined by
View answer and explanation
Correct option: D
The mean square velocity of the molecules
Option D is correct because the absolute temperature of a gas is directly proportional to the mean square velocity of its molecules, as described by the kinetic theory of gases.
199 Medium
199 of 290
Understanding +4 | -1
The ratio of specific heats of an ideal gas is
View answer and explanation
Correct option: B
1+RCv1+\frac{R}{C_v}
Option B (1+RCv1+\frac{R}{C_v}) is correct because it represents the ratio of specific heats (γ=CPCV\gamma = \frac{C_P}{C_V}) derived from the relationship CP−CV=RC_P - C_V = R.
200 Medium
200 of 290
Application +4 | -1
The kinetic energy of one g-mole of a gas at normal temperature and pressure is (R=8.31  J/mol−KR = 8.31\;J/mol - K)
View answer and explanation
Correct option: D
3.4×103J3.4 \times {10^3}J
Option D (3.4×103J3.4 \times {10^3}J) is correct because it is the kinetic energy calculated using the formula E=32RTE = \frac{3}{2}RT with the given values.
201 Medium
201 of 290
Application +4 | -1
What is the ratio of rms speed of oxygen and hydrogen molecules at the same temperature?
View answer and explanation
Correct option: C
1:41:4
The correct answer is C (1:4) because the rms speed is inversely proportional to the square root of the molar mass.
202 Medium
202 of 290
Understanding +4 | -1
At constant pressure, which of the following is true?
View answer and explanation
Correct option: D
v∝1ρv \propto \frac{1}{{\sqrt \rho }}
Option D (v∝1ρv \propto \frac{1}{{\sqrt \rho }}) is correct because at constant pressure, the speed of sound is inversely proportional to the square root of the density.
203 Medium
203 of 290
Application +4 | -1
The ratio of velocity of sound in hydrogen gas to that in helium gas at the same temperature -
View answer and explanation
Correct option: B
4225\sqrt{\frac{42}{25}}
Option D (n2R{n^2}R) is correct because the new resistance is calculated by considering the change in length and area when the wire is stretched.
204 Medium
204 of 290
Application +4 | -1
The speeds of 5 molecules of a gas (in arbitrary units) are as follows: 2,3,4,5,6.2,3,4,5,6. The root mean square speed for these molecules is
View answer and explanation
Correct option: D
4.24
Option D (4.24) is correct because it is the root mean square speed calculated using the given speeds of the molecules.
205 Medium
205 of 290
Understanding +4 | -1
Three vessels of equal volume contain gases at the same temperature and pressure. The first vessel contains neon (monoatomic), the second contains chlorine (diatomic) and third contains uranium hexafluoride (polyatomic). Arrange these on the basis of their root mean square speed (vms)\left(v_{\mathrm{ms}}\right) and choose the correct answer from the options given below:
View answer and explanation
Correct option: A
vrms v_{\text {rms }} (mono) >vms>v_{\mathrm{ms}} (dia) >vrms>v_{\mathrm{rms}} (poly)
Option A (vrms v_{\text {rms }} (mono) >vms>v_{\mathrm{ms}} (dia) >vrms>v_{\mathrm{rms}} (poly)) is correct because the root mean square speed is inversely proportional to the square root of the molar mass.
206 Medium
206 of 290
Analyzing +4 | -1
Same gas is filled in two vessels of the same volume at the same temperature. If the ratio of the number of molecules is 1:41: 4, then
A. The r.m.s. velocity of gas molecules in two vessels will be the same.
B. The ratio of pressure in these vessels will be 1:41 : 4.
C. The ratio of pressure will be 1:11 : 1.
D. The r.m.s. velocity of gas molecules in two vessels will be in the ratio of 1:41 : 4.
Choose the correct answer from the options given
below
View answer and explanation
Correct option: C
A and B only
Option C (A and B only) is correct because the r.m.s. velocity is the same due to the same temperature, and the pressure ratio is 1:4 due to the number of molecules ratio.
207 Easy
207 of 290
Analyzing +4 | -1
If the Avogadro’s number was to tend to infinity; the phenomenon of Brownian motion would:
View answer and explanation
Correct option: A
Remain completely unaffected
Option A is correct because Brownian motion depends on the temperature and viscosity of the fluid, and the size of the particles, not on Avogadro's number.
208 Medium
208 of 290
Application +4 | -1
A vessel contains 1.60 g1.60 \mathrm{~g} of oxygen and 2.80 g2.80 \mathrm{~g} of nitrogen. The temperature is maintained at 300 K300 \mathrm{~K} and the volume of the vessel is 0.166 m30.166 \mathrm{~m}^3. Find the pressure of the mixture.
View answer and explanation
Correct option: B
2250 N/m22250 \mathrm{~N/m^2}
The correct answer is 2250 N/m² because the pressure of the mixture is calculated using the ideal gas law and Dalton's law of partial pressures.
209 Medium
209 of 290
Application +4 | -1
Assume that the temperature remains essentially constant in the upper part of the atmosphere. Obtain an expression for the variation in pressure in the upper atmosphere with height. The mean molecular weight of air is MM.
View answer and explanation
Correct option: D
p=p0e−MghRTp=p_0 e^{-\frac{M g h}{R T}}
Option D (p=p0e−MghRTp=p_0 e^{-\frac{M g h}{R T}}) is correct because it accurately describes the exponential decrease of pressure with height in the upper atmosphere, considering constant temperature.
210 Medium
210 of 290
Application +4 | -1
At room temperature (27∘C)  ^ \circ C)\; the rms speed of the molecules of a certain diatomic gas is found to be 1920 ms−1{s^{ - 1}}. The gas is
View answer and explanation
Correct option: D
H2{\mathrm{H}_2}
Option D (H2{\mathrm{H}_2}) is correct because the calculated molar mass from the given rms speed matches that of hydrogen gas.
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