Skip to main content
Back to KINETIC THEORY OF GASES

JEE PHYSICS MCQ: KINETIC THEORY OF GASES

1 Medium
1 of 1
Application +4 | -1
If Ξ³\gamma be the ratio of specific heats of a perfect gas, the number of degrees of freedom of a molecule of the gas is
View answer and explanation
Correct option: C
2Ξ³βˆ’1\frac{2}{\gamma-1}
Option C (2Ξ³βˆ’1\frac{2}{\gamma-1}) is correct because the number of degrees of freedom is related to the ratio of specific heats by the formula n=2Ξ³βˆ’1n = \frac{2}{\gamma-1}.

More Questions from KINETIC THEORY OF GASES

Practice All Chapter MCQs β†’
Type at least 2 characters or jump directly:
πŸ”“

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.