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JEE • PHYSICS • KINETIC THEORY OF GASES

Kinetic theory of gases practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 290 questions
211 Medium
211 of 290
Understanding +4 | -1
The ratio of Cp\mathrm{C}_{\mathrm{p}} and Cv\mathrm{C}_{\mathrm{v}} depends on temperature T\mathrm{T} according to relation
View answer and explanation
Correct option: A
γ∝T\gamma \propto \mathrm{T}
The correct answer is that γ\gamma does not depend on temperature, so none of the options are correct. The provided answer and explanation are incorrect.
212 Medium
212 of 290
Application +4 | -1
A diatomic gas (γ=1.4)(\gamma=1.4) does 50 J50 {~J} of work when it is expanded isobarically. The heat given to the gas in this process is
View answer and explanation
Correct option: C
175 J175 {~J}
Option D (175 J175 {~J}) is correct because it is the heat given to the gas calculated using the relationship between work and heat in an isobaric process.
213 Easy
213 of 290
Application +4 | -1
If the root mean square velocity of hydrogen molecule at a given temperature and pressure is 2 km/s2 \mathrm{~km} / \mathrm{s}, the root mean square velocity of oxygen at the same condition in km/s\mathrm{km} / \mathrm{s} is:
View answer and explanation
Correct option: C
0.5
Option C (0.5) is correct because the root mean square velocity is inversely proportional to the square root of the molar mass.
214 Medium
214 of 290
Understanding +4 | -1
Mean free path is inversely proportional to
View answer and explanation
Correct option: D
Both 1 and 2
Option D (Both 1 and 2) is correct because the mean free path is inversely proportional to both the number density and the square of the molecular diameter.
215 Medium
215 of 290
Understanding +4 | -1
If the rms velocity of a gas is vv ,then
View answer and explanation
Correct option: B
v2/T=constant{v^2}/T = \mathrm{constant}
Option B (v2/T=constant{v^2}/T = \mathrm{constant}) is correct because the square of the RMS velocity is directly proportional to the temperature.
216 Medium
216 of 290
Application +4 | -1
If mass of gas is double and vrmsv_{r m s} is half then pressure of gas will be.
View answer and explanation
Correct option: A
P′∝12 times P^{\prime} \propto \frac{1}{2} \text { times }
Option A (P′∝12 times P^{\prime} \propto \frac{1}{2} \text { times }) is correct because pressure is proportional to mass and the square of the RMS velocity, and the changes in these variables result in a halving of the pressure.
217 Medium
217 of 290
Understanding +4 | -1
At 00C{0^0}C temperature, root mean square speed of which of the following gas will be maximum?
View answer and explanation
Correct option: A
H2{H_2}
Option A (H2{H_2}) is correct because the root mean square speed is inversely proportional to the square root of the molar mass, and hydrogen has the lowest molar mass.
218 Medium
218 of 290
Understanding +4 | -1
Assertion: For a mixture of non-reactive ideal gases, the total pressure gets contribution from each gas in the mixture.
Reason: In equilibrium, the average kinetic energy of the molecules of different gases will be equal.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of assertion
Option A (If both assertion and reason are true and reason is the correct explanation of assertion) is correct because Dalton's law is based on the equal average kinetic energy of gas molecules at equilibrium.
219 Medium
219 of 290
Understanding +4 | -1
Critical temperature of CO2\mathrm{CO}_2 is 31.2∘C31.2^{\circ} \mathrm{C}. In summer, the room temperature is 40∘C40^{\circ} \mathrm{C}.
View answer and explanation
Correct option: A
CO2\mathrm{CO}_2 cannot be liquefied
Option A is correct because the pressure of an ideal gas is independent of the container's shape and depends on the number of moles, temperature, and volume, as described by the ideal gas law.
220 Medium
220 of 290
Application +4 | -1
1 mole of a gas having γ=75\gamma=\frac{7}{5} is mixed with 1 mole of a gas having γ=43\gamma=\frac{4}{3}. What will be the γ\gamma for the mixture?
View answer and explanation
Correct option: C
1511\frac{15}{11}
Option C (1511\frac{15}{11}) is correct because it correctly calculates the effective gamma for the mixture using the number of moles and the specific heat capacities.
221 Medium
221 of 290
Remembering +4 | -1
The ratio of two specific heats CPCV\frac{{{C_P}}}{{{C_V}}} of COCO is
View answer and explanation
Correct option: B
1.4
Option B (1.4) is correct because carbon monoxide (CO) is a diatomic gas, and the ratio of specific heats for diatomic gases is approximately 1.4.
222 Medium
222 of 290
Understanding +4 | -1
For a gas γ=7/5.\gamma = 7/5. The gas may probably be
View answer and explanation
Correct option: B
Hydrogen
Option B (Hydrogen) is correct because diatomic gases like Hydrogen have a γ\gamma value of approximately 7/5 (1.4).
223 Medium
223 of 290
Application +4 | -1
Average K.E. of one single molecule of monoatomic gas is 0.414eV0.414 \mathrm{eV} (of ⊥\perp molecule). What will be is temp == ?
View answer and explanation
Correct option: B
3200 K
Option B (3200 K) is correct because the temperature is calculated using the average kinetic energy formula for a monoatomic gas, KE=32kTKE = \frac{3}{2}kT.
224 Medium
224 of 290
Understanding +4 | -1
Three vessels of equal capacity have gases at
the same temperature and pressure. The first
vessel contains helium (monoatomic), the
second contains fluorine (diatomic) and the
third contains sulfur hexafluoride (polyatomic).
The correct statement, among the following is:
View answer and explanation
Correct option: D
The root mean square speed of helium is
the largest
Option D (The root mean square speed of helium is the largest) is correct because RMS speed is inversely proportional to the square root of the molar mass, and helium has the smallest molar mass.
225 Medium
225 of 290
Understanding +4 | -1
In a dilute gas at pressure pp and temperature T,T, the mean time between successive collisions of a molecule varies with TT as
View answer and explanation
Correct option: B
1T\frac{1}{{\sqrt T }}
Option B is correct because the mean time between collisions is inversely proportional to the square root of the temperature.
226 Medium
226 of 290
Understanding +4 | -1
Assertion: In case of collision of gas molecules in a given amount of gas, total kinetic energy is conserved.
Reason: All collisions of the gas molecules in a given amount of gas are elastic.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of assertion
Option A is correct because in an elastic collision, both momentum and kinetic energy are conserved, and the conservation of kinetic energy directly implies that the total kinetic energy remains constant.
227 Medium
227 of 290
Remembering +4 | -1
The number of translatioaonal degrees of freedom of a diatomic gas is
View answer and explanation
Correct option: A
3
Option A (3) is correct because a diatomic gas can move along the x, y, and z axes, giving it 3 translational degrees of freedom.
228 Medium
228 of 290
Application +4 | -1
A vessel has 6 g6 \mathrm{~g} of hydrogen at pressure PP and temperature 500 K500 \mathrm{~K}. A small hole is made in it so that hydrogen leaks out. How much hydrogen leaks out if the final pressure is P3\frac{P}{3} and temperature falls to 300 K?
View answer and explanation
Correct option: C
2.66 g
Option C (2.66 g) is correct because the mass of gas remaining is calculated using the ideal gas law, and the difference between the initial and final mass gives the mass leaked out.
229 Medium
229 of 290
Analyzing +4 | -1
Read the given statements and decide which is/are correct on the basis of kinetic theory of gases
(I) Energy of one molecule at absolute temperature is zero
(II) r.m.s.r.m.s.speeds of different gases are same at same temperature
(III) For one gram of all ideal gas kinetic energy is same at same temperature
(IV) For one mole of all ideal gases mean kinetic energy is same at same temperature
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because all the given statements are incorrect based on the kinetic theory of gases.
230 Medium
230 of 290
Remembering +4 | -1
At a given temperature the r.m.s.r.m.s. velocity of molecules of the gas is
View answer and explanation
Correct option: D
Inversely proportional to square root of molecular weight
Option D is correct because the root-mean-square velocity of gas molecules is inversely proportional to the square root of the molecular weight.
231 Medium
231 of 290
Analyzing +4 | -1
A certain ideal gas undergoes a polytropic process pVn=p V^n= constant such that the molar specific heat during the process is negative. If the ratio of the specific heat of the gas be γ\gamma, then the range of values of nn will be
View answer and explanation
Correct option: B
1<n<γ1 < n < \gamma
Option B is correct because the molar specific heat is negative when 1 < n < gamma, as derived from the polytropic process equation.
232 Medium
232 of 290
Analyzing +4 | -1
The specific heats, Cp  and  CV{C_p}\mathrm{ \,\,and }\,\,{C_V} of a gas of diatomic molecules, A are given (in units of Jmol−1K−1\mathrm{J mo}{\mathrm{l}^{ - 1}}{K^{ - 1}}) by 29 and 22, respectively. Another gas of diatomic molecules B, has the corresponding values 30 and 21. If they are treated as ideal gases, then
View answer and explanation
Correct option: A
A has a vibrational mode but B has none
Option A (A has a vibrational mode but B has none) is correct because the calculated degrees of freedom for gas A is approximately 7, indicating a vibrational mode, while for gas B it is 5, indicating no vibrational mode.
233 Medium
233 of 290
Remembering +4 | -1
The rate of diffusion is
View answer and explanation
Correct option: D
Faster in gases than in liquids and solids
Option D (Faster in gases than in liquids and solids) is correct because gas molecules have greater kinetic energy and weaker intermolecular forces, allowing for faster diffusion.
234 Medium
234 of 290
Understanding +4 | -1
Pressure of an ideal gas is increased by keeping temperature constant. What is the effect on kinetic energy of molecules?
View answer and explanation
Correct option: C
No change
Option C is correct because the kinetic energy of an ideal gas depends only on temperature, which is kept constant in this scenario.
235 Medium
235 of 290
Analyzing +4 | -1
Given below are two statements :
Statement I : The average momentum of a molecule in a sample of an ideal gas depends on temperature.
Statement II : The rms speed of oxygen molecules in a gas is v. If the temperature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will become 2v.2v.
In the light of the above statements, choose the correct answer from the options given below:
View answer and explanation
Correct option: D
Statement I is false but Statement II is true
Option D (Statement I is false but Statement II is true) is correct because the average momentum of an ideal gas molecule is zero, while the rms speed calculation is accurate.
236 Medium
236 of 290
Remembering +4 | -1
The r.m.s.r.m.s. speed of gas molecules is given by
View answer and explanation
Correct option: B
1.73RTM1.73\sqrt {\frac{{RT}}{M}}
Option B (1.73RTM1.73\sqrt {\frac{{RT}}{M}}) is correct because the root-mean-square speed of gas molecules is given by 3RTM\sqrt{\frac{{3RT}}{M}}, and 3≈1.73\sqrt{3} \approx 1.73.
237 Medium
237 of 290
Understanding +4 | -1
At O K which of the following properties of a gas will be zero
View answer and explanation
Correct option: A
Kinetic energy
Option A (Kinetic energy) is correct because at 0 K, all molecular motion ceases, resulting in zero kinetic energy.
238 Medium
238 of 290
Application +4 | -1
The equation of state for 3 g3 \mathrm{~g} of oxygen at a pressure PP and temperature TT, when occupying a volume VV, will be:
View answer and explanation
Correct option: B
PV=332RTP V=\frac{3}{32} {RT}
Option B (PV=332RTP V=\frac{3}{32} {RT}) is correct because it uses the ideal gas law with the correct number of moles calculated from the given mass and molecular mass of oxygen.
239 Medium
239 of 290
Analyzing +4 | -1
An ideal gas in a closed container is slowly heated. As its temperature increases, which of the following statements are true?
A. The mean free path of the molecules decreases.
B. The mean collision time between the molecules decreases.
C. The mean free path remains unchanged.
D. The mean collision time remains unchanged.
View answer and explanation
Correct option: A
B and C
Option A (B and C) is correct because in a closed container, the mean free path remains constant, and as temperature increases, the mean collision time decreases.
240 Medium
240 of 290
Remembering +4 | -1
The ideal gas equation connecting Pressure (P) Volume (V) and absolute temperature (T) is (Where KB{K_B} is the Blotzmann Constant and N is the number of molecules)
View answer and explanation
Correct option: C
  PV=KBNT\;PV = {K_B}NT
Option C (  PV=KBNT\;PV = {K_B}NT) is correct because this is the ideal gas equation using Boltzmann's constant and the number of molecules.
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