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JEE • PHYSICS • KINETIC THEORY OF GASES

Kinetic theory of gases practice · Mixed difficulty

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Showing 91-120 of 290 questions

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91 Medium
91 of 290
Understanding +4 | -1
At 0∘ K0^\circ \,K which of the following properties of a gas will be zero?
View answer and explanation
Correct option: A
Kinetic energy
Option A is correct because at 0°K, also known as absolute zero, the kinetic energy of the gas molecules is theoretically zero.
92 Medium
92 of 290
Understanding +4 | -1
When an ideal gas is compressed adiabatically, its temperature rises the molecules on the average have more kinetic energy than before. The kinetic energy increases
View answer and explanation
Correct option: A
Because of collisions with moving parts of the wall only
Option A is correct because during adiabatic compression, the gas molecules gain kinetic energy through collisions with the moving parts of the wall (e.g., piston).
93 Medium
93 of 290
Application +4 | -1
One mole of an ideal diatomic gas undergoes a process P=P0(1+VV0)3P=\frac{P_0}{\left(1+\frac{V}{V_0}\right)^3}, where P0P_0 and V0V_0 are positive constants. The translational kinetic energy of the gas when V=V0V=V_0 is given by
View answer and explanation
Correct option: B
3P0V016\frac{3 P_0 V_0}{16}
Option B (3 P₀ V₀ / 16) is correct because it is derived from the ideal gas law and the given process equation to find the translational kinetic energy.
94 Medium
94 of 290
Understanding +4 | -1
If an ideal flask containing hot coffee is shaken, the temperature of the coffee will
View answer and explanation
Correct option: B
Increase
Option B (Increase) is correct because shaking the coffee introduces mechanical energy, which is converted into thermal energy due to the viscosity of the coffee, thus increasing its temperature.
95 Medium
95 of 290
Remembering +4 | -1
The ratio of the molar heat capacities of a diatomic gas at constant pressure to that at constant volume is
View answer and explanation
Correct option: D
75\frac{7}{5}
Option D (7/5) is correct because for a diatomic gas, Cp = (7/2)R and Cv = (5/2)R, so Cp/Cv = 7/5.
96 Medium
96 of 290
Application +4 | -1
The ratio of rms speed of an ideal gas molecules at pressure pp to that at pressure 2p2 p is
View answer and explanation
Correct option: C
1:21: \sqrt{2}
Option C (1:21: \sqrt{2}) is correct because the rms speed is inversely proportional to the square root of the density, and density is proportional to pressure at constant temperature.
97 Medium
97 of 290
Application +4 | -1
If mass of HeHe atom is 4 times that of hydrogen atom then mean velocity of HeHe is
View answer and explanation
Correct option: B
1/2 times of HH-mean value
Option B (1/2 times of HH-mean value) is correct because the mean velocity is inversely proportional to the square root of the mass.
98 Medium
98 of 290
Understanding +4 | -1
Some gas at 300 K is enclosed in a container. Now, the container is placed on a fast moving train. While the train is in motion, the temperature of the gas
View answer and explanation
Correct option: A
Rises above 300 K
Option C (Remains unchanged) is correct because the temperature of a gas depends on the average kinetic energy of its molecules, which is not affected by the train's motion.
99 Medium
99 of 290
Understanding +4 | -1
If VH,VN{V_H},{V_N} and V0{V_0} denote the root –mean square velocities of molecules of hydrogen, nitrogen and oxygen respectively at a given temperature, then
View answer and explanation
Correct option: B
VH>VN>VO{V_H} > {V_N} > {V_O}
Option B (VH>VN>VO{V_H} > {V_N} > {V_O}) is correct because the root-mean-square velocity is inversely proportional to the square root of the molar mass.
100 Medium
100 of 290
Remembering +4 | -1
In van der Waals’ equation, the critical pressure Pc\mathrm{P_c} is given by
View answer and explanation
Correct option: B
a/27b2\mathrm{a/27b}^2
Option B (a/27b2\mathrm{a/27b}^2) is correct because the critical pressure in van der Waals' equation is given by this expression.
101 Medium
101 of 290
Application +4 | -1
The ratio of the molecular masses of two gases is 7/8. What is the ratio of the number of moles of two gases, if they are in two different containers and have same mass for each gas?
View answer and explanation
Correct option: A
8/78 / 7
Option A (8/78 / 7) is correct because the ratio of moles is inversely proportional to the ratio of molecular masses when the mass is the same.
102 Medium
102 of 290
Understanding +4 | -1
The rms speed of a large number of molecules of a gas in a vessel is 600 m s−1600 \mathrm{~m} \mathrm{~s}^{-1}. If 25%25 \% of the gas leaks out at constant temperature, then rms speed of the remaining molecules will be
View answer and explanation
Correct option: D
600 m s−1600 \mathrm{~m} \mathrm{~s}^{-1}
Option D (600 m s−1600 \mathrm{~m} \mathrm{~s}^{-1}) is correct because the RMS speed depends only on temperature and molar mass, not the amount of gas.
103 Medium
103 of 290
Application +4 | -1
Let AA and BB the two gases and given TBMA=4.TBMB;\frac{{{T_B}}}{{{M_A}}} = 4.\frac{{{T_B}}}{{{M_B}}}; where TT is the temperature and MM is molecular mass. If CA{C_A} and CB{C_B} are the r.m.s.r.m.s. speed, then the ratio CACB\frac{{{C_A}}}{{{C_B}}} will be equal to
View answer and explanation
Correct option: A
2
Option A (2) is correct because the ratio of RMS speeds is proportional to the square root of the ratio of (T/M).
104 Medium
104 of 290
Understanding +4 | -1
Cooking gas containers are kept in a lorry moving with uniform speed. The temperature of the gas molecules inside will
View answer and explanation
Correct option: C
Remain same
Option C (Remain same) is correct because the temperature of the gas molecules depends on their average kinetic energy, which is not affected by the uniform motion of the lorry.
105 Easy
105 of 290
Understanding +4 | -1
The temperature of gas is produced by
View answer and explanation
Correct option: B
The kinetic energy of its molecules
Option B is correct because the temperature of a gas is directly related to the average kinetic energy of its molecules.
106 Medium
106 of 290
Understanding +4 | -1
Vapour is injected at a uniform rate in a closed vessel which was initially evacuated. The pressure in the vessel
View answer and explanation
Correct option: C
First increases and then decreases
Option D (First increases and then becomes constant) is the correct answer. Initially, the pressure increases as vapor is injected. Once the saturation vapor pressure is reached, the vapor starts to condense, and the pressure remains constant.
107 Medium
107 of 290
Understanding +4 | -1
Given below are two statements:

Statement (I): The mean free path of gas molecules is inversely proportional to square of molecular diameter.

Statement (II): Average kinetic energy of gas molecules is directly proportional to absolute temperature of gas.

In the light of the above statements, choose the correct answer from the option given below:
View answer and explanation
Correct option: D
Both Statement I and Statement II are true
Option D is correct because the mean free path is inversely proportional to the square of the molecular diameter, and the average kinetic energy is directly proportional to the absolute temperature.
108 Medium
108 of 290
Understanding +4 | -1
For a gas at a temperature TT the root-mean-square velocity vrms,{v_{rms}}, the most probable speed vmp,{v_{mp}}, and the average speed vav{v_{av}} obey the relationship
View answer and explanation
Correct option: B
vrms>vav>vmp{v_{rms}} > {v_{av}} > {v_{mp}}
Option B (vrms>vav>vmp{v_{rms}} > {v_{av}} > {v_{mp}}) is correct because the root-mean-square velocity is always greater than the average velocity, which is greater than the most probable speed.
109 Medium
109 of 290
Application +4 | -1
If γ\gamma be the ratio of specific heats of a perfect gas, the number of degrees of freedom of a molecule of the gas is
View answer and explanation
Correct option: C
2γ−1\frac{2}{\gamma-1}
Option C (2γ−1\frac{2}{\gamma-1}) is correct because the number of degrees of freedom is related to the ratio of specific heats by the formula n=2γ−1n = \frac{2}{\gamma-1}.
110 Medium
110 of 290
Understanding +4 | -1
The average kinetic energy of a gas molecules is
View answer and explanation
Correct option: D
Directly proportional to absolute temperature of gas
Option D (Directly proportional to absolute temperature of gas) is correct because the average kinetic energy of a gas molecule is directly proportional to the absolute temperature, as described by the equation E = (3/2)kT.
111 Medium
111 of 290
Application +4 | -1
A gas cylinder of 50 litres capacity contained helium at 80 atmospheric pressure. Due to slow leakage it was found after a while that the pressure had dropped to 40 atmosphere. Find the proportion of the gas that has escaped and also the volume the escaped gas would occupy at atmospheric pressure.
View answer and explanation
Correct option: A
2000 litre
Option A (2000 litre) is correct because it is calculated using Boyle's law to determine the volume of the escaped gas at atmospheric pressure.
112 Medium
112 of 290
Understanding +4 | -1
Root mean square velocity of a particle is vv at pressure P.P. If pressure is increased two times, then the r.m.s.r.m.s. velocity becomes
View answer and explanation
Correct option: D
vv
Option D (v) is correct because the root mean square velocity depends on temperature and molar mass, not pressure.
113 Medium
113 of 290
Analyzing +4 | -1
Imagine a planet whose diameter and mass are both one half of those of Earth. The day's temperature of this planet's surface reaches up to 800 K800 \mathrm{~K}. Find whether oxygen molecules are possible in the atmosphere of this planet.
View answer and explanation
Correct option: A
vrms⁡v_{\operatorname{rms}} is very small compared to escape velocity on the planet, molecules cannot escape from the surface of the planet's atmosphere
Option A (vrms⁡v_{\operatorname{rms}} is very small compared to escape velocity on the planet, molecules cannot escape from the surface of the planet's atmosphere) is correct because the calculated RMS velocity is much less than the escape velocity.
114 Medium
114 of 290
Understanding +4 | -1
Kinetic theory of gases provide a base for
View answer and explanation
Correct option: C
Charle’s law and Boyle’s law
Option C (Charle’s law and Boyle’s law) is correct because the kinetic theory of gases provides the theoretical foundation for both Boyle's and Charles's laws.
115 Medium
115 of 290
Understanding +4 | -1
Mean free path of O2{O}_2 gas molecules in rigid container is λ\lambda. The temperature of gas is doubled, then new mean free path of O2{O}_2 gas molecules is
View answer and explanation
Correct option: A
λ\lambda
Option A is correct. The mean free path of a gas molecule in a rigid container is independent of temperature because the number density remains constant.
116 Medium
116 of 290
Application +4 | -1
Let AA and BB the two gases and given TBMA=4.TBMB;\frac{{{T_B}}}{{{M_A}}} = 4.\frac{{{T_B}}}{{{M_B}}}; where TT is the temperature and MM is molecular mass. If CA{C_A} and CB{C_B} are the r.m.s.r.m.s. speed, then the ratio CACB\frac{{{C_A}}}{{{C_B}}} will be equal to
View answer and explanation
Correct option: A
2
Option A (2) is correct because the ratio of RMS speeds is proportional to the square root of the ratio of (T/M).
117 Medium
117 of 290
Understanding +4 | -1
The temperature of argon, kept in a vessel, is raised by 1∘C{1^ \circ }C at a constant volume. The total heat supplied to the gas is a combination of translation and rotational energies. Their respective shares are
View answer and explanation
Correct option: D
100% and 0%
Option D (100% and 0%) is correct because argon is a monoatomic gas and only possesses translational kinetic energy.
118 Medium
118 of 290
Analyzing +4 | -1
Let V\mathrm{V} denote the root mean square speed of the molecules in an ideal diatomic gas at absolute temperature T\mathrm{T}. The mass of a molecule is ' mm '. Neglecting vibrational energy terms, which is false?
View answer and explanation
Correct option: C
The average rotational kinetic energy of a molecule is mv2/4\mathrm{mv}^2 / 4
Option D is correct because in an elastic collision the relative velocity is unchanged in magnitude but gets reversed in direction.
119 Medium
119 of 290
Analyzing +4 | -1
Two identical containers A\mathrm{A} and B\mathrm{B} have frictionless pistons. They contain the same volume of a ideal gas at the same temperature. The mass of the gas in A\mathrm{A} is mA\mathrm{m}_{\mathrm{A}} and that in B\mathrm{B} is mB\mathrm{mB}. The gas in each cylinder is now allowed to expand isothermally to double the initial volume. The changes in the pressure in A and B are found to be Δp\Delta p and 1.5Δp1.5 \Delta p respectively.
View answer and explanation
Correct option: C
3 mAA=2mB3 \mathrm{~mA}_{\mathrm{A}}=2 \mathrm{mB}
Option C is correct because the ratio of masses is inversely proportional to the ratio of pressure changes, leading to the relationship 3mA = 2mB.
120 Medium
120 of 290
Analyzing +4 | -1
The equation of state of a gas is given by (P+aT2V)Vc=(RT+b),\left( {P + \frac{{a{T^2}}}{V}} \right){V^c} = \left( {RT + b} \right), where a,b,ca,b,c and RR are constants. The isotherms can be represented by P=AVm−BVn,P = A{V^m} - B{V^n}, where AA and BB depend only on temperature and
View answer and explanation
Correct option: A
m=−cm = - c and n=−1n = - 1
Option A is correct because by rearranging the given equation of state and comparing it with the target form, we find that m = -c and n = -1.
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