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JEE PHYSICS MCQ: KINETIC THEORY OF GASES
1
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Application
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Find the loss in the mass of 1 mole of an ideal monatomic gas kept in a rigid container as it cools down by . The gas constant .
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Correct option: A
Option A () is correct because it represents the mass loss calculated from the energy change due to cooling, using .
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Assertion: The pressure exerted by an enclosed ideal gas does not depend on the shape of the container.
Reason: The pressure of an ideal gas depends on the number moles, temperature and volume of the enclosed If is the velocity of sound in air and is the rms velocity, then Four particles have velocities . The root mean square of the particles is (in ) The translational degrees of freedom and rotational degrees of freedom of molecule are: On any planet, the presence of atmosphere implies (= root mean square velocity of molecules and escape velocity) At a given temperature, the pressure of an ideal gas of density is proportional to
Reason: The pressure of an ideal gas depends on the number moles, temperature and volume of the enclosed If is the velocity of sound in air and is the rms velocity, then Four particles have velocities . The root mean square of the particles is (in ) The translational degrees of freedom and rotational degrees of freedom of molecule are: On any planet, the presence of atmosphere implies (= root mean square velocity of molecules and escape velocity) At a given temperature, the pressure of an ideal gas of density is proportional to