Skip to main content
Back to KINETIC THEORY OF GASES

Your Progress

0 / 290 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • PHYSICS • KINETIC THEORY OF GASES

Kinetic theory of gases practice · Mixed difficulty

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 61-90 of 290 questions
61 Medium
61 of 290
Application +4 | -1
Find the loss in the mass of 1 mole of an ideal monatomic gas kept in a rigid container as it cools down by 10∘C10^{\circ} \mathrm{C}. The gas constant R=8.3 J K−1 mol−1R=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}.
View answer and explanation
Correct option: A
1.38×10−15 kg1.38 \times 10^{-15} \mathrm{~kg}
Option A (1.38×10−15 kg1.38 \times 10^{-15} \mathrm{~kg}) is correct because it represents the mass loss calculated from the energy change due to cooling, using E=mc2E=mc^2.
62 Medium
62 of 290
Understanding +4 | -1
Mean kinetic energy (or average energy) per gg molecule of a monoatomic gas is given by
View answer and explanation
Correct option: A
32RT\frac{3}{2}RT
Option A (32RT\frac{{3}}{{2}}RT) is correct because it represents the average kinetic energy per mole of a monoatomic gas.
63 Medium
63 of 290
Understanding +4 | -1
At the same temperature and pressure and volume of two gases, which of the following quantities is constant
View answer and explanation
Correct option: B
Average kinetic energy
Option B (Average kinetic energy) is correct because at the same temperature, the average kinetic energy of gas molecules is the same, regardless of the type of gas.
64 Medium
64 of 290
Understanding +4 | -1
If the volume of the gas containing nn number of molecules is V,V, then the pressure will decrease due to force of intermolecular attraction in the proportion
View answer and explanation
Correct option: C
(n/V)2{\left( {n/V} \right)^2}
Option C ((n/V)2{\left( {n/V} \right)^2}) is correct because the pressure decrease due to intermolecular attraction is proportional to the square of the number density of the gas molecules.
65 Easy
65 of 290
Understanding +4 | -1
The root mean square speeds of molecules of ideal gases at the same temperature are:
View answer and explanation
Correct option: B
Inversely proportional to the square root of the molecular weight
Option B is correct because the root mean square speed of molecules is inversely proportional to the square root of the molecular weight.
66 Medium
66 of 290
Remembering +4 | -1
In Vander Wal's equation the critical pressure PcP_c is given by
View answer and explanation
Correct option: B
a27 b2\frac{\mathrm{a}}{27 \mathrm{~b}^2}
Option B (a27 b2\frac{\mathrm{a}}{27 \mathrm{~b}^2}) is correct because it is the formula for critical pressure derived from Vander Wal's equation of state.
67 Medium
67 of 290
Understanding +4 | -1
According to kinetic theory of gases,
A. The motion of the gas molecules freezes at 0∘C0^\circ C
B. The mean free path of gas molecules decreases if the density of molecules is increased.
C. The mean free path of gas molecules increases if temperature is increased keeping pressure constant.
D. Average kinetic energy per molecule per degree of freedom is 32 kBT\frac{3}{2}\,{k_B}T (for monoatomic gases).
Choose the most appropriate answer from the options given below:
View answer and explanation
Correct option: B
B and C only
Option B (B and C only) is correct because the mean free path decreases with increasing density and increases with increasing temperature at constant pressure.
68 Medium
68 of 290
Understanding +4 | -1
Assertion: Each vibrational mode gives two degrees of freedom
Reason: By law of equipartition of energy, the energy for each degree of freedom in thermal equilibrium is 2kBT2 k_B T
View answer and explanation
Correct option: C
If Assertion is true and Reason is false
Option C is correct because each vibrational mode contributes two degrees of freedom (kinetic and potential energy), but the energy for each degree of freedom is 12kBT\frac{1}{2}k_BT, not 2kBT2k_BT.
69 Medium
69 of 290
Application +4 | -1
At what temperature the rms velocity of helium molecules will be equal to that of hydrogen molecules at NTP?
View answer and explanation
Correct option: C
273∘C^ \circ C
Option C (273∘C^ \circ C) is correct because it is the temperature at which the rms velocity of helium molecules equals that of hydrogen molecules at NTP, calculated using the rms velocity formula.
70 Medium
70 of 290
Understanding +4 | -1
KE per unit volume is EE. The pressure exerted by the gas is given by
View answer and explanation
Correct option: B
2E3\frac{{2E}}{3}
Option B (2E3\frac{{2E}}{3}) is correct because the pressure exerted by a gas is related to the kinetic energy per unit volume by the equation P=23EP = \frac{2}{3}E.
71 Medium
71 of 290
Remembering +4 | -1
The average thermal energy for a mono-atomic gas is: (kB{\mathrm{k}_\mathrm{B}} is Boltzmann constant and T\mathrm{T}, absolute temperature)
View answer and explanation
Correct option: B
32 kBT\frac{3}{2}\,{\mathrm{k}_\mathrm{B}}\mathrm{T}
Option B is correct. A monoatomic gas has 3 degrees of freedom, so the average thermal energy is (3/2) * k_B * T.
72 Medium
72 of 290
Application +4 | -1
The temperature at which the average translational kinetic energy of a molecule is equal to the energy gained by an electron in accelerating from rest through a potential difference of 1  volt1\;volt is
View answer and explanation
Correct option: D
7.7×103K7.7 \times {10^3}K
Option D (7.7×103K7.7 \times {10^3}K) is correct because it is calculated by equating the average translational kinetic energy of a molecule to the energy gained by an electron accelerated through a potential difference of 1 volt.
73 Medium
73 of 290
Understanding +4 | -1
If a Vander-Waal’s gas expands freely, then final temperature is
View answer and explanation
Correct option: A
Less than the initial temperature
Option A (Less than the initial temperature) is correct because a van der Waals gas cools during free expansion due to overcoming intermolecular forces.
74 Medium
74 of 290
Application +4 | -1
For a gas molecule with 6 degrees of freedom the law of equipartition of energy gives the following relation between the molecular specific heat (CV)\left( {{C_V}} \right) and gas constant (R)\left( R \right)
View answer and explanation
Correct option: D
CV=3R{C_V} = 3R
Option D (CV=3R{C_V} = 3R) is correct because the molecular specific heat is calculated using the equipartition theorem, where each degree of freedom contributes R/2 to the specific heat.
75 Medium
75 of 290
Understanding +4 | -1
Which of the following is incorrect regarding the assumptions of kinetic theory of gases?
View answer and explanation
Correct option: C
Gas molecules have some intermolecular forces of attraction
Option C is correct because the kinetic theory of gases assumes negligible intermolecular forces, not the presence of some attractive forces.
76 Medium
76 of 290
Remembering +4 | -1
According to the kinetic theory of gases the r.m.sr.m.s velocity of gas molecules is directly proportional to
View answer and explanation
Correct option: B
T\sqrt T
Option B (T\sqrt T) is correct because the root-mean-square (rms) velocity of gas molecules is directly proportional to the square root of the absolute temperature.
77 Medium
77 of 290
Understanding +4 | -1
According to the kinetic theory of gases, the pressure exerted by a gas on the walls is measured as
View answer and explanation
Correct option: A
rate of change of momentum imparted to the walls per second per unit area.
Option A is correct. According to the kinetic theory of gases, the pressure exerted by a gas is due to the rate of change of momentum imparted to the walls per second per unit area.
78 Medium
78 of 290
Understanding +4 | -1
The ratio of mean kinetic energy of hydrogen and oxygen at a given temperature is
View answer and explanation
Correct option: D
1  :11\;:1
Option D (1 : 1) is correct because the average kinetic energy of a molecule depends only on the temperature and is independent of the type of gas.
79 Medium
79 of 290
Understanding +4 | -1
Assertion (A) : In equation p=13αvrms 2p=\frac{1}{3} \alpha v_{\text {rms }}^2, the term α\alpha represents density of gas.

Reason (R) : vrms=3RTMv_{\mathrm{rms}}=\sqrt{\frac{3 R T}{M}}.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are true but Reason is not the correct explanation of Assertion) is correct because both the assertion and the reason are true statements, but the reason does not explain the assertion.
80 Medium
80 of 290
Understanding +4 | -1
Assertion (A) Assertion The total translational kinetic energy of all the molecules of a given mass of an ideal gas is 1.5 times the product of its pressure and volume.

Reason (R) The molecules of gas collide with each other and the velocities of the molecules change due to the collision.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.
Option B is correct because both the assertion and reason are true, but the reason does not explain the assertion.
81 Medium
81 of 290
Understanding +4 | -1
The root mean square speed of the molecules of a gas is
View answer and explanation
Correct option: C
Independent of its pressure but directly proportional to the square root of its Kelvin temperature
Option C (Independent of its pressure but directly proportional to the square root of its Kelvin temperature) is correct because the RMS speed is proportional to the square root of temperature and independent of pressure.
82 Medium
82 of 290
Analyzing +4 | -1
Assertion: The ratio Cp/CvC_p / C_v is more for helium gas than for hydrogen gas.
Reason: All metals acts as black bodies.
View answer and explanation
Correct option: D
If both assertion and reason are false
Option D is correct because both the assertion and the reason are false statements regarding the ratio of specific heats and the properties of metals as black bodies.
83 Medium
83 of 290
Understanding +4 | -1
If Maxwell distribution is valid and vpv_p denotes the most probable speed, vavv_{av} is the average speed and vrmsv_{rms} is the root-mean-square speed, then
View answer and explanation
Correct option: C
vp<vav<vrmsv_p < v_{av} < v_{rms}
Option C (vp<vav<vrmsv_p < v_{av} < v_{rms}) is correct because the most probable speed is the lowest, followed by the average speed, and the root-mean-square speed is the highest.
84 Medium
84 of 290
Understanding +4 | -1
Relation between the ratio of specific heats (γ)\left( \gamma \right) of gas and degree of freedom &#39;f&#39; will be
View answer and explanation
Correct option: C
f=2/(γ−1)f = 2/\left( {\gamma - 1} \right)
Option C (f=2/(γ−1)f = 2/(\gamma - 1)) is correct because it represents the relationship between the ratio of specific heats and the degree of freedom of a gas.
85 Easy
85 of 290
Application +4 | -1
A sample contains mixture of helium and oxygen gas. The ratio of root mean square speed of helium and oxygen in the sample, is :
View answer and explanation
Correct option: B
221\frac{2 \sqrt{2}}{1}
Option B (221\frac{2 \sqrt{2}}{1}) is correct because it correctly applies the formula for RMS speed and calculates the ratio.
86 Medium
86 of 290
Remembering +4 | -1
The specific heat of an ideal gas is
View answer and explanation
Correct option: D
Independent of TT
Option D is correct. For an ideal gas, the specific heat is independent of temperature, assuming constant degrees of freedom.
87 Medium
87 of 290
Understanding +4 | -1
The average translational kinetic energy of O2{O}_2 (molar mass 32) at a particular temperature is 0.048 eV0.048 \mathrm{~eV}. The average translational kinetic energy of N2{N}_2 (molar mass 28) molecules (in eV\mathrm{eV}) at the same temperature is
View answer and explanation
Correct option: C
0.0480.048
Option C (0.048) is correct because the average translational kinetic energy depends only on temperature, which is the same for both gases.
88 Medium
88 of 290
Application +4 | -1
Find the ratio of specific heat at constant pressure to the specific heat constant volume for NH3N{H_3}
View answer and explanation
Correct option: C
1.28
Option C (1.28) is correct because the ratio of specific heats for a polyatomic gas like NH3 is less than 1.33, and 1.28 is the closest value.
89 Hard
89 of 290
Understanding +4 | -1
Assertion: Vibrational degree of freedom of a di-atomic gas molecule appears at very high temperature
Reason: Di-atomic gas has two vibrational degree of freedom in one direction.
View answer and explanation
Correct option: B
If both Assertion and Reason are true, but Reason is not the correct explanation of Assertion
Option C is correct because the resistance of copper decreases with decreasing temperature, while the resistance of germanium increases with decreasing temperature.
90 Medium
90 of 290
Application +4 | -1
The R.M.S. speed of oxygen molecules at temperature T{T} (in kelvin) is v ms−1{v} \,{ms}^{-1}. As the temperature becomes 4 T4 {~T} and the oxygen gas dissociated into atomic oxygen, then the speed of atomic oxygen
View answer and explanation
Correct option: D
Becomes 22 v2 \sqrt{2} \,v
Option D (Becomes 22,v2 \sqrt{2} \\,v) is correct because the RMS speed is proportional to the square root of temperature and inversely proportional to the square root of the molar mass.
Revision notes and key takeaways

Review KINETIC THEORY OF GASES in your textbook or class notes, then use this set to check your understanding.

Showing 61-90 of 290 questions
0 /290
0✓ 0✗
0% Accuracy
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.