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JEE • PHYSICS • KINETIC THEORY OF GASES

Kinetic theory of gases practice · Mixed difficulty

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Showing 31-60 of 290 questions
31 Medium
31 of 290
Understanding +4 | -1
Which of the following statements about kinetic theory of gases is wrong
View answer and explanation
Correct option: B
The molecules continuously undergo inelastic collisions
Option B is correct because the kinetic theory of gases assumes elastic collisions, not inelastic collisions.
32 Medium
32 of 290
Understanding +4 | -1
A sealed container with negligible coefficient of volumetric expansion contains helium (a monoatomic gas). When it is heated from 300  K300\;K to 600  K600\;K the average K.E. of helium atoms is
View answer and explanation
Correct option: C
Doubled
Option C (Doubled) is correct because the average kinetic energy of gas molecules is directly proportional to the absolute temperature.
33 Medium
33 of 290
Remembering +4 | -1
The average velocity of molecules of a gas of molecular weight MM at temperature TT is
View answer and explanation
Correct option: D
zero
Option D (zero) is correct because gas molecules have random motion, and their velocities cancel each other out, resulting in an average velocity of zero.
34 Medium
34 of 290
Application +4 | -1
A diatomic gas molecule has translational, rotational and vibrational degrees of freedom. The CP/CV{C_P}/{C_V} is
View answer and explanation
Correct option: D
1.33
Option D (1.33) is correct because the ratio of specific heats is calculated using the degrees of freedom for a diatomic gas with translational, rotational, and vibrational modes.
35 Medium
35 of 290
Analyzing +4 | -1
Assertion: The change in air pressure effect the speed of sound.
Reason: The speed of sound in a gas is proportional to the square of pressure.
View answer and explanation
Correct option: D
If both Assertion and Reason are false
Option D (If both Assertion and Reason are false) is correct because the speed of sound is independent of pressure changes when temperature is constant, and the speed of sound is proportional to the square root of pressure, not the square.
36 Medium
36 of 290
Application +4 | -1
At what temperature, the rms velocity of gas molecules would be double of its value at NTP, if pressure is remaining constant?
View answer and explanation
Correct option: A
819∘C819^{\circ} \mathrm{C}
Option A (819∘C819^{\circ} \mathrm{C}) is correct because the rms velocity is proportional to the square root of the absolute temperature, and the temperature is calculated accordingly.
37 Medium
37 of 290
Understanding +4 | -1
What is an ideal gas?
View answer and explanation
Correct option: B
A gas satisfying the assumptions of kinetic theory
The correct answer is B (A gas satisfying the assumptions of kinetic theory) because an ideal gas is defined as one that obeys the assumptions of the kinetic theory of gases.
38 Medium
38 of 290
Application +4 | -1
A gas mixture consists of 4 mol4 \mathrm{~mol} of oxygen and 6 mol6 \mathrm{~mol} of argon at temperature TT. Neglecting all vibrational modes, the total internal energy of the system is
View answer and explanation
Correct option: D
19RT19 R T
Option D (19RT) is correct because it sums the internal energies of oxygen (diatomic) and argon (monoatomic) gases, considering their respective degrees of freedom.
39 Medium
39 of 290
Application +4 | -1
Oxygen is filled in a closed metal jar of volume 1.0×10−3 m31.0 \times 10^{-3} \mathrm{~m}^3 at a pressure of 1.5×105 Pa1.5 \times 10^5 \mathrm{~Pa} and temperature 400 K400 \mathrm{~K}. The jar has a small leak in it. The atmospheric pressure is 1.0×105 Pa1.0 \times 10^5 \mathrm{~Pa} and the atmospheric temperature is 300 K300 \mathrm{~K}. Find the mass of the gas that leaks out by the time the pressure and the temperature inside the jar equalise with the surrounding.
View answer and explanation
Correct option: C
0.16 g
Option C (0.16 g) is correct because the mass of gas leaked out is calculated by finding the difference in mass before and after the pressure and temperature equalize.
40 Medium
40 of 290
Application +4 | -1
If the molar specific heat at constant pressure for a polyatomic non-linear
gas is xx and the molar specific heat at constant volume for a diatomic gas
is y,y, find the value of xy.\frac{x}{y}.
View answer and explanation
Correct option: A
1.6
Option A (1.6) is correct because it calculates the ratio of molar specific heats at constant pressure and constant volume for polyatomic non-linear and diatomic gases respectively.
41 Medium
41 of 290
Understanding +4 | -1
The temperature of Argon, kept in a vessel, is raised by 1∘C1^{\circ} \mathrm{C} at a constant volume. The total heat supplied to the gas is a combination of translational and rotational energies. Their respective shares are:-
View answer and explanation
Correct option: D
100%100 \% and 0%0 \%
Option D is correct because Argon is a monoatomic gas, possessing only translational kinetic energy. Therefore, all the heat supplied increases translational energy, and none increases rotational energy.
42 Medium
42 of 290
Application +4 | -1
At 11∘c11^{\circ} c, the rms speed of a gas molecule is found to be 1000 m/s1000 \mathrm{~m} / \mathrm{s}. Take R=253SIR=\frac{25}{3} \mathrm{SI} units. The molecular mass (ingrams), of the gas molecule (in nearest integer) is
View answer and explanation
Correct option: A
7
Option A (7) is correct because by using the RMS speed formula and substituting the given values, the molecular mass is calculated to be approximately 7 grams.
43 Medium
43 of 290
Understanding +4 | -1
A box contains n molecules of a gas. How will the pressure of the gas be effected, if the number of molecules is made 2n2n
View answer and explanation
Correct option: C
Pressure will be doubled
Option C (Pressure will be doubled) is correct because the pressure of a gas is directly proportional to the number of molecules when volume and temperature are constant.
44 Medium
44 of 290
Understanding +4 | -1
A gas is allowed to expand isothermally. The root mean square velocity of the molecules
View answer and explanation
Correct option: C
Will remain unchanged
Option C (Will remain unchanged) is correct because the root mean square velocity depends only on temperature, which is constant in an isothermal process.
45 Medium
45 of 290
Application +4 | -1
A cubical box with porous walls containing an equal number of O2{O_2} and H2{H_2} molecules is placed in a large evacuated chamber. The entire system is maintained at constant temperature T.T. The ratio of vrms{v_{rms}} of O2{O_2} molecules to that of the vrms{v_{rms}} of H2{H_2} molecules, found in the chamber outside the box after a short interval is
View answer and explanation
Correct option: B
14\frac{1}{4}
Option B (14\frac{1}{4}) is correct because the ratio of RMS velocities is inversely proportional to the square root of the molar masses of the gases.
46 Medium
46 of 290
Understanding +4 | -1
Degree of freedom for polyatomic gas
View answer and explanation
Correct option: C
≥6\geq 6
Option C is correct because a polyatomic gas has at least 6 degrees of freedom (3 translational and 3 rotational).
47 Medium
47 of 290
Remembering +4 | -1
Which of the following options may be the correct estimate of the mean free path of gas particles?

[n:[n: Number of gas particle per unit volume, d:d: diameter]
View answer and explanation
Correct option: D
λ=12nd2\lambda=\frac{1}{\sqrt{2} n d^2}
Option D (λ=12nd2\lambda=\frac{1}{\sqrt{2} n d^2}) is correct because it represents the correct formula for the mean free path of gas particles, where n is the number of particles per unit volume and d is the diameter.
48 Medium
48 of 290
Application +4 | -1
An ideal gas filled in closed vessel at 27∘C27^{\circ} \mathrm{C} temperature if gas is heated then its pressure is made 2 times. Then find out the final temperature of gas.
View answer and explanation
Correct option: A
600 K600 \mathrm{~K}
Option A (600 K600 \mathrm{~K}) is correct because using Gay-Lussac's Law (P1T1=P2T2\frac{P_1}{T_1} = \frac{P_2}{T_2}) with constant volume, the final temperature is twice the initial temperature in Kelvin.
49 Medium
49 of 290
Application +4 | -1
The average translational kinetic energy of air molecules is 0.040eV  (1eV=1.6×10−19 J)0.040 \mathrm{eV}\,\, \left(1 \mathrm{eV}=1.6 \times 10^{-19} \mathrm{~J}\right). Calculate the temperature of the air. Boltzmann constant k=1.38×10−23 J K−1k=1.38 \times 10^{-23} \mathrm{~J} \mathrm{~K}^{-1}.
View answer and explanation
Correct option: C
310 K
Option C (310 K) is correct because the average translational kinetic energy is directly proportional to the temperature, and the calculation yields approximately 310 K.
50 Medium
50 of 290
Application +4 | -1
An oxygen cylinder of volume 30 L30 {~L} has an initial gauge pressure of 15 atm15 {~atm} and a temperature of 27∘C27^{\circ} {C}. After some oxygen is withdrawn from the cylinder, the gauge pressure drops to 11 atm11 {~atm} and its temperature drops to 17∘C17^{\circ} {C}. Estimate the mass of oxygen taken out of the cylinder.
(Take, R=8.31 Jmol−1 K−1R=8.31 \,{Jmol}^{-1} {~K}^{-1} and molecular mass of O2=32u)\left.{O}_2=32 {u}\right)
View answer and explanation
Correct option: C
0.14 kg0.14 {~kg}
Option C (0.14 kg) is correct because it is the mass of oxygen calculated using the ideal gas law.
51 Easy
51 of 290
Understanding +4 | -1
Which of the following gases possesses maximum rms velocity, all being at the same temperature?
View answer and explanation
Correct option: D
Hydrogen
Option D is correct because rms velocity is inversely proportional to the square root of the molar mass, making it highest for Hydrogen.
52 Medium
52 of 290
Understanding +4 | -1
In kinetic theory of gases, which of the following statements regarding elastic collisions of the molecules is wrong
View answer and explanation
Correct option: A
Kinetic energy is lost in collisions
Option A is correct because in the kinetic theory of gases, collisions are assumed to be perfectly elastic, meaning no kinetic energy is lost.
53 Medium
53 of 290
Understanding +4 | -1
For a gas, if the ratio of specific heats at constant pressure and constant volume is γ\gamma, then the value of degrees of freedom is
View answer and explanation
Correct option: D
2γ−1\frac{2}{\gamma-1}
Option D (2γ−1\frac{2}{\gamma-1}) is correct because the degrees of freedom nn are related to the ratio of specific heats γ\gamma by the formula γ=1+2n\gamma = 1 + \frac{2}{n}, which can be rearranged to n=2γ−1n = \frac{2}{\gamma-1}.
54 Medium
54 of 290
Remembering +4 | -1
The translational kinetic energy of gas molecule for one mole of the gas is equal to
View answer and explanation
Correct option: A
32RT\frac{3}{2}RT
Option A (32RT\frac{3}{2}RT) is correct because the translational kinetic energy of a gas molecule for one mole of the gas is equal to 32RT\frac{3}{2}RT, where R is the gas constant and T is the temperature.
55 Medium
55 of 290
Application +4 | -1
The velocities of three molecules are 3v,4v3{v}, 4 {v} and 5v5 {v}, respectively. Their rms speed will be
View answer and explanation
Correct option: A
503v\sqrt{\frac{50}{3}} v
Option A (503v\sqrt{\frac{50}{3}} v) is correct because it is the root mean square speed calculated using the given velocities of the molecules.
56 Medium
56 of 290
Understanding +4 | -1
Assertion(A): Translational kinetic energy of any gas at temperature TT would be 12mvrms2\frac{1}{2} m v_{\mathrm{rms}}^2.
Reason(R): Translational kinetic energy of any type of gas at temperature TT would be 32RT\frac{3}{2} R T for one mole.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion) is correct because both statements are true, but the reason doesn't explain the assertion.
57 Medium
57 of 290
Understanding +4 | -1
The vapour of a substance behaves as a gas
View answer and explanation
Correct option: B
Above critical temperature
Option B is correct because a vapor behaves as a gas above its critical temperature.
58 Medium
58 of 290
Application +4 | -1
What is the ratio of specific heats of constant pressure and constant volume of NH3N{H_3} is
View answer and explanation
Correct option: A
1.33
Option A (1.33) is correct because it calculates the ratio of specific heats using the degrees of freedom for NH3NH_3.
59 Medium
59 of 290
Remembering +4 | -1
Mean kinetic energy per degree of freedom of gas molecules is
View answer and explanation
Correct option: C
12kT\frac{1}{2}kT
Option C (12kT\frac{1}{2}kT) is correct because, according to the law of equipartition of energy, the mean kinetic energy per degree of freedom is 12kT\frac{1}{2}kT.
60 Medium
60 of 290
Analyzing +4 | -1
Assertion (A) : According to the law of equipartition of energy, internal energy of an ideal gas at a given temperature, is equally distributed in translational and rotational kinetic energies.

Reason (R) : Rotational kinetic energy of a monoatomic gas is zero
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true.
Option D is correct because the assertion is false, as equipartition of energy distributes energy equally among all degrees of freedom, not just translational and rotational, and the reason is true, as monoatomic gases have no rotational kinetic energy.
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