JEE PHYSICS MCQ: KINETIC THEORY OF GASES

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Analyzing +4 | -1

An experiment is being performed by a student in laboratory on ideal gas. He found the value of

C_P-C_V

equal to

1.00 \mathrm{~R}

for a gas sample in state
A. Now he performed the experiment on the same gas and found

C_P-C_V

1.03 \mathrm{~R}

in state
B. Let

P_A, P_B

denote the pressures and

T_A, T_B

denote the temperatures of states

A

and

B

respectively. Which of the following will be correct?

View answer and explanation

Correct option: A

P_A < P_B

and

T_A > T_B

Option A (

P_A < P_B

and

T_A > T_B

) is correct because the gas deviates from ideal behavior in state B, implying higher pressure and lower temperature than predicted by the ideal gas law.

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Assertion: The pressure exerted by an enclosed ideal gas does not depend on the shape of the container.
Reason: The pressure of an ideal gas depends on the number moles, temperature and volume of the enclosed If

c_s

is the velocity of sound in air and

c

is the rms velocity, then Four particles have velocities

1,0,2,3 \mathrm{~m} / \mathrm{s}

. The root mean square of the particles is (in

\mathrm{m} / \mathrm{s}

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(f_t)

and rotational degrees of freedom

(f_r)

{CH}_4

molecule are: On any planet, the presence of atmosphere implies (

{C_{rms}} =

= root mean square velocity of molecules and

{V_e} =

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\rho

is proportional to