Skip to main content
Back to KINETIC THEORY OF GASES

Your Progress

0 / 290 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • PHYSICS • KINETIC THEORY OF GASES

Kinetic theory of gases practice · Mixed difficulty

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 271-290 of 290 questions
271 Medium
271 of 290
Understanding +4 | -1
If at the same temperature and pressure, the densities of two diatomic gases are d1d_1 and d2d_2, respectively. The ratio of mean kinetic energy per molecule of gases will be
View answer and explanation
Correct option: A
1:11: 1
Option A (1:1) is correct because the mean kinetic energy per molecule depends only on temperature, which is the same for both gases.
272 Medium
272 of 290
Application +4 | -1
The absolute temperature of a gas is increases 3 times. The root mean square velocity of the moelcules will be
View answer and explanation
Correct option: D
3\sqrt{3} times
Option D (3\sqrt{3} times) is correct because the root mean square velocity is proportional to the square root of the absolute temperature.
273 Medium
273 of 290
Understanding +4 | -1
Assertion: The root mean square and most probable speeds of the molecules in a gas are the same
Reason: The Maxwell's distribution for the speed of molecules in a gas is symmetrical.
View answer and explanation
Correct option: D
If both Assertion and Reason are false
Option D is correct because the root mean square and most probable speeds are different, and Maxwell's distribution is asymmetrical.
274 Medium
274 of 290
Understanding +4 | -1
For a gas at a temperature T\mathrm{T} the root mean square velocity Vrms\mathrm{V}_{\mathrm{rms}} and the most probable speed VmpV_{m p}, and the average speed VavV_{a v} obey the relationship -
View answer and explanation
Correct option: D
Vmp>Vrms >VavV_{\mathrm{mp}}>V_{\text {rms }}>V_{a v}
Option B (Vrms >Vav >VmpV_{\text {rms }}>V_{\text {av }}>V_{m p }) is correct because the root mean square velocity is always greater than the average velocity, which is greater than the most probable speed.
275 Medium
275 of 290
Application +4 | -1
In a vertical open vessel an ideal gas is filled and it is enclosed by a piston of mass 4 kg4 \mathrm{~kg} and cross-section area is 2 cm22 \mathrm{~cm}^2 then find out pressure applied by gas on piston in equilibrium.
View answer and explanation
Correct option: B
3P03 P_0
Option B (3P03 P_0) is correct because the gas pressure equals atmospheric pressure plus the pressure due to the piston's weight.
276 Medium
276 of 290
Application +4 | -1
An ideal gas is allowed to expands from volume VV to 2V2 V according to the law VP2=V P^2= Constant. If initial temperature of the gas is TT then its final temperature will be
View answer and explanation
Correct option: B
T2T \sqrt{2}
Option B (T2T \sqrt{2}) is correct because the final temperature is derived from the given relation VP2=constantVP^2 = constant and the ideal gas law.
277 Medium
277 of 290
Application +4 | -1
The volume of vessel AA is twice the volume of another vessel BB, and both of them are filled with the same gas. If the gas in AA is at twice the temperature and twice the pressure in comparison to the gas in BB, then the ratio of the gas molecules in AA to that of BB
View answer and explanation
Correct option: A
21\frac{2}{1}
Option C (Equal to or greater than sin⁡−1(34){\sin ^{ - 1}}\left( {\frac{3}{4}} \right)) is correct because for total internal reflection to occur, the angle of incidence must be greater than or equal to the critical angle.
278 Easy
278 of 290
Analyzing +4 | -1
Assertion: Equal masses of helium and oxygen gases are given equal quantities of heat. There will be a greater rise in the temperature of helium compared to that of oxygen.
Reason: The molecular weight of oxygen is more than the molecular weight of helium.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not correct explanation of the assertion
The correct answer is C (x<z<yx < z < y) because the percentage error in x is 1%, in y is 7%, and in z is 2%, so the order is x < z < y.
279 Easy
279 of 290
Understanding +4 | -1
If the molecular weight of two gases are M1{M_1} and M2{M_2}, then at a temperature the ratio of root mean square velocity v1{v_1} and v2{v_2} will be
View answer and explanation
Correct option: B
M2M1\sqrt {\frac{{{M_2}}}{{{M_1}}}}
Option B is correct because the root mean square velocity is inversely proportional to the square root of the molecular weight.
280 Medium
280 of 290
Understanding +4 | -1
Which statements are correct about degrees of freedom?
(A) A molecule with nn degrees of freedom has n2n^2 different ways of storing energy.
(B) Each degree of freedom is associated with 12RT\frac{1}{2} R T average energy per mole.
(C) A monatomic gas molecule has 1 rotational degree of freedom whereas diatomic molecule has 2 rotational degrees of freedom.
(D) CH4\mathrm{CH}_4 has a total of 6 degrees of freedom.
Choose the correct answer from the option given below:
View answer and explanation
Correct option: B
(B) and (D) only
Option B is correct because, according to Einstein's photoelectric equation, the kinetic energy of emitted electrons depends on the frequency of the incident light.
281 Easy
281 of 290
Understanding +4 | -1
A gas is taken through a number of thermodynamic states. What happens to its specific heat?
View answer and explanation
Correct option: D
It can have any value depending upon process of heat absorbed or evolved
Option D is correct because the specific heat of a gas depends on the thermodynamic process it undergoes.
282 Medium
282 of 290
Analyzing +4 | -1
Assertion(A): If initial and final volumes are equal, then work done by gas is zero.

Reason(R): In isochoric process, initial and final volumes are equal and work done by gas is zero.
View answer and explanation
Correct option: D
If Assertion is incorrect but Reason is correct.
Option D is correct. The assertion is incorrect because work done is zero only if the volume remains constant *throughout* the process, not just at the initial and final states. The reason is correct because it accurately describes an isochoric process.
283 Medium
283 of 290
Understanding +4 | -1
In the absence of intermolecular forces of attraction, the observed pressure pp will be
View answer and explanation
Correct option: C
>p> p
Option C (>p> p) is correct because in the absence of intermolecular forces, the molecules exert more pressure due to the lack of attractive forces reducing the impact.
284 Medium
284 of 290
Application +4 | -1
The rms speed of an ideal diatomic gas at temperature TT is VV. When gas dissociates into atoms then its new rms speed becomes double. The temperature at which the gas dissociated into atoms are:
View answer and explanation
Correct option: D
2T2 T
Option D (2 T) is correct because when the diatomic gas dissociates, the molar mass halves, and the rms speed doubles, leading to a doubling of the temperature.
285 Medium
285 of 290
Understanding +4 | -1
According to the kinetic theory of gases, the temperature of a gas is a measure of average
View answer and explanation
Correct option: C
Kinetic energies of its molecules
Option C (Kinetic energies of its molecules) is correct because temperature is directly proportional to the average kinetic energy of the gas molecules.
286 Medium
286 of 290
Application +4 | -1
Two moles of an ideal gas with CpCV=53\frac{{{C_p}}}{{{C_V}}} = \frac{5}{3} are mixed with 3 mol of another ideal gas with CpCV=43.\frac{{{C_p}}}{{{C_V}}} = \frac{4}{3}. The value of CpCV\frac{{{C_p}}}{{{C_V}}} for the mixture is
View answer and explanation
Correct option: A
1.42
Option A (1.42) is correct because it accurately calculates the specific heat ratio for the mixture of ideal gases.
287 Easy
287 of 290
Remembering +4 | -1
The relation between rms velocity, vrmsv_{\text {rms}} and the most probable velocity, vmpv_{{mp}} of a gas is
View answer and explanation
Correct option: B
vrms=32vmpv_{\mathrm{rms}}=\sqrt{\frac{3}{2}} v_{{mp}}
Option B (vrms=32vmpv_{\mathrm{rms}}=\sqrt{\frac{3}{2}} v_{{mp}}) is correct because it represents the correct relationship between the root-mean-square velocity and the most probable velocity of gas molecules.
288 Medium
288 of 290
Understanding +4 | -1
Statement-I: Moon has no atmosphere
Statement-II: The root mean square velocity of air molecules on moon is greater than the escape velocity of air molecules on moon.
View answer and explanation
Correct option: A
Statement-I and statement-II are true
Option A (Statement-I and statement-II are true) is correct because the Moon lacks an atmosphere due to the high RMS velocity of gas molecules exceeding the escape velocity.
289 Medium
289 of 290
Analyzing +4 | -1
Assertion: Absolute zero temperature is not the temperature of zero energy
Reason: Only the translational kinetic energy of the molecules is represented by temperature.
View answer and explanation
Correct option: A
If both Assertion and reason are true and the Reason is the correct explanation of the Assertion
Option B (If both Assertion and reason are true and the Reason is not a correct explanation of the Assertion) is correct because absolute zero doesn't mean zero energy, and temperature only represents translational kinetic energy.
290 Medium
290 of 290
Understanding +4 | -1
If the degree of freedom of a gas are f,f, then the ratio of two specific heats CP/CV{C_P}/{C_V} is given by
View answer and explanation
Correct option: A
2f+1\frac{2}{f} + 1
Option C (Acceleration) is correct because a body in equilibrium has a net force of zero, implying zero acceleration.
Revision notes and key takeaways

Review KINETIC THEORY OF GASES in your textbook or class notes, then use this set to check your understanding.

Showing 271-290 of 290 questions
0 /290
0✓ 0✗
0% Accuracy
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.