Skip to main content
Back to KINETIC THEORY OF GASES

JEE PHYSICS MCQ: KINETIC THEORY OF GASES

1 Medium
1 of 1
Application +4 | -1
The molecules of a given mass of gas have a root mean square velocity of 200 m s−1200 \mathrm{~m} \mathrm{~s}^{-1} at 27∘C27^{\circ} \mathrm{C} and 1.0×105 N m−21.0 \times 10^5 \mathrm{~N} \mathrm{~m}^{-2} pressure. When the temperature is 127∘C127^{\circ} \mathrm{C} and the pressure 0.5×105Nm−20.5 \times 10^5 \mathrm{Nm}^{-2}, the root mean square velocity in ms−1\mathrm{ms}^{-1}, is
View answer and explanation
Correct option: A
4003\frac{400}{\sqrt{3}}
Option A (4003\frac{{400}}{{\sqrt{{3}}}}) is correct because it is calculated using the relationship between RMS velocity and temperature.

More Questions from KINETIC THEORY OF GASES

Practice All Chapter MCQs →
Assertion: The pressure exerted by an enclosed ideal gas does not depend on the shape of the container.
Reason: The pressure of an ideal gas depends on the number moles, temperature and volume of the enclosed If csc_s is the velocity of sound in air and cc is the rms velocity, then Four particles have velocities 1,0,2,3 m/s1,0,2,3 \mathrm{~m} / \mathrm{s}. The root mean square of the particles is (in m/s\mathrm{m} / \mathrm{s} ) The translational degrees of freedom (ft)(f_t) and rotational degrees of freedom (fr)(f_r) of CH4{CH}_4 molecule are: On any planet, the presence of atmosphere implies (Crms={C_{rms}} == root mean square velocity of molecules and Ve={V_e} = escape velocity) At a given temperature, the pressure of an ideal gas of density ρ\rho is proportional to
Type at least 2 characters or jump directly:
🩺 NEET MCQs 🔬 JEE MCQs 🎯 JEE College Predictor Study guides 📊 Dashboard
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.

Continue with Free Account →