Skip to main content
Back to KINETIC THEORY OF GASES

JEE PHYSICS MCQ: KINETIC THEORY OF GASES

1 Medium
1 of 1
Application +4 | -1
Calculate the r.m.s. velocity of air molecules at S.T.P. Given density of air at S.T.P. is 1.296 kg m−31.296 \mathrm{~kg} \mathrm{~m}^{-3}.
View answer and explanation
Correct option: D
482.24 ms−1482.24 \mathrm{~ms}^{-1}
Option D (482.24 ms−1482.24 \mathrm{~ms}^{-1}) is correct because it is the result of applying the formula for root mean square velocity using the given pressure and density.

More Questions from KINETIC THEORY OF GASES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.