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JEE • PHYSICS • GRAVITATION

Gravitation practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 301-330 of 392 questions

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301 Medium
301 of 392
Understanding +4 | -1
In a gravitational field, at a point where the gravitational potential is zero
View answer and explanation
Correct option: A
The gravitational field is necessarily zero
The correct answer is not necessarily zero. Gravitational potential being zero at a point does not imply the gravitational field is also zero at that point. The field is related to the gradient of the potential, not the potential itself.
302 Medium
302 of 392
Understanding +4 | -1
Escape velocity when a body of mass m\mathrm{m} is thrown vertically from the surface of the earth is v\mathrm{v}, what will be the escape velocity of another body of mass 4 m4 \mathrm{~m} is thrown vertically
View answer and explanation
Correct option: A
v\mathrm{v}
Option A is correct because escape velocity is independent of the mass of the object being projected.
303 Medium
303 of 392
Understanding +4 | -1
Assertion: A satellite can not be set on a stable orbit in a plane not passing through the earth's centre.
Reason: For the orbital motion of satellite, the centripetal force is provided by gravitational pull of earth on satellite.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because the gravitational pull of the Earth provides the necessary centripetal force for a satellite's orbital motion, and this force acts towards the Earth's center.
304 Medium
304 of 392
Understanding +4 | -1
Statement I: The weight of a body at the centre of earth is zero

Statement II: The mass of a body decreases with increase in depth below the surface of earth.
View answer and explanation
Correct option: C
If Statement - I is true but Statement - II is false.
Option C (If Statement - I is true but Statement - II is false) is correct because weight at the center of the Earth is zero, but mass remains constant regardless of depth.
305 Medium
305 of 392
Understanding +4 | -1
Which is constant for a satellite in orbit
View answer and explanation
Correct option: B
Angular momentum
Option B is correct because angular momentum is conserved for a satellite in orbit due to the absence of external torques.
306 Medium
306 of 392
Understanding +4 | -1
If the total energy of a satellite is negative. It
means
View answer and explanation
Correct option: D
Satellite is in bound orbit
Option D (Satellite is in bound orbit) is correct because a negative total energy indicates that the satellite is gravitationally bound to the central body and cannot escape.
307 Medium
307 of 392
Understanding +4 | -1
The moon does not fall to Earth because:
View answer and explanation
Correct option: D
The statement is wrong: moon is in a state of free fall
Option D is correct because the moon is indeed in a state of free fall, constantly accelerating towards the Earth due to gravity, but also possessing tangential velocity that keeps it in orbit.
308 Medium
308 of 392
Application +4 | -1
In a certain region of space, the gravitational field is given by −k/r-k/r, where rr is the distance and kk is a constant. If the gravitational potential at r=r0r = {r_0} be V0{V_0}, then what is the expression for the gravitational potential V?
View answer and explanation
Correct option: C
V0+klog⁡(r/r0){V_0} + k\log \left( {r/{r_0}} \right)
Option C (V0+klog⁡(r/r0){V_0} + k\log \left( {r/{r_0}} \right)) is correct because it is derived from integrating the gravitational field to find the gravitational potential.
309 Medium
309 of 392
Analyzing +4 | -1
Two bodies of masses mm and MM are placed a distance dd apart. The gravitational potential at the position where the gravitational field due to them is zero is VV, then
View answer and explanation
Correct option: D
V=−Gd(m+M)2V=-\frac{G}{d}(\sqrt{m}+\sqrt{M})^2
Option D is correct. The gravitational potential at the point where the field is zero is calculated by finding the distances to that point and summing the individual potentials due to each mass.
310 Medium
310 of 392
Application +4 | -1
The period of revolution of planet A around the sun is 8 times that BB. The distance of a from the sun is how many times greater than that of BB from the sun?
View answer and explanation
Correct option: B
3
Option C (4) is incorrect. The distance of A from the sun is 4 times greater than that of B, not 3 times as the question asks for the ratio of distances, not the difference.
311 Medium
311 of 392
Understanding +4 | -1
Which of the following is always positive?
View answer and explanation
Correct option: C
Kinetic energy
Option C (Kinetic energy) is correct because kinetic energy is always positive due to the square of velocity in its formula, while potential and total energy can be negative.
312 Medium
312 of 392
Application +4 | -1
Two satellites S1{S_1} and S2{S_2} revolve around a planet in coplanar circular orbits in the same sense. Their periods of revolution are 4 hr and 6 hr respectively. The radius of the orbit of S1{S_1} is 104 km. The angular speed of S2{S_2} as observed by an astronaut in S1{S_1} (in radius)
View answer and explanation
Correct option: D
π6\frac{\pi }{6}
Option D (π6\frac{\pi }{6}) is correct because the relative angular speed is the difference between the angular speeds of the two satellites.
313 Medium
313 of 392
Application +4 | -1
The mass and diameter of a planet have twice the value of the corresponding parameters of Earth. Acceleration due to gravity on the surface of the planet is:
View answer and explanation
Correct option: B
4.9 m/sec24.9 \mathrm{~m} / \mathrm{sec}^2
Option B (4.9 m/sec24.9 \mathrm{~m} / \mathrm{sec}^2) is correct because the acceleration due to gravity is inversely proportional to the square of the radius and directly proportional to the mass. Since both mass and radius are doubled, the gravity is halved.
314 Medium
314 of 392
Analyzing +4 | -1
Mark the correct statements.

I. Gravitational potential at the centre of curvature of a thin hemispherical shell of radius RR and mass MM is equal to GM/RG M / R

II. Gravitation field strength at a point lying on the axis at a distance of ' aa ' on a thin, uniform circular ring of radius R\mathrm{R} and mass M\mathrm{M} is equal GMR(a2+R2)3/2\frac{G M R}{\left(a^2+R^2\right)^{3 / 2}}

III. Newton's law of gravitation for gravitational force between two bodies is applicable only when bodies have sphrical symmetric distribution of mass
View answer and explanation
Correct option: B
II and III
Option B (II and III) is correct because the gravitational field strength formula is correct and Newton's law applies only to spherically symmetric mass distributions.
315 Medium
315 of 392
Analyzing +4 | -1
Average density of the earth
View answer and explanation
Correct option: B
is a complex function of gg
Option B is correct because the average density of the earth is a complex function of g, involving the gravitational constant, radius of the earth, and pi.
316 Medium
316 of 392
Application +4 | -1
The escape velocity of a body from the earth's surface is vev_e. If the same body is projected from the surface of the earth with the velocity 2ve2 v_e, then the velocity of the body when it reaches to infinity, i.e., beyond the earth's gravitational field is
View answer and explanation
Correct option: D
3ve\sqrt{3 v_e}
Option D (3ve\sqrt{3 v_e}) is correct because it is derived from the conservation of energy principle, considering the initial kinetic energy and the escape velocity.
317 Medium
317 of 392
Application +4 | -1
The value of g on the earth’s surface is 980  cms−2980\mathrm{\;cm}{\mathrm{s}^{ - 2}}. Its value at a height of 64 km from the earth’s surface is
View answer and explanation
Correct option: A
960.40  cms−2960.40\mathrm{\;cm}{\mathrm{s}^{ - 2}}
Option A (960.40;cms−2960.40\\;\mathrm{cm}{\mathrm{s}^{ - 2}}) is correct because it is calculated using the formula for the variation of g with height.
318 Medium
318 of 392
Application +4 | -1
A geostationary satellite is orbiting around an arbitrary planet PP at a height of 11R11R above the surface of PP, RR being the radius of PP. The time period of another satellite in hours at a height of 2R2R from the surface of PP is……
PP has the time period of 24 h.
View answer and explanation
Correct option: C
3
Option C (3) is correct because it accurately calculates the time period of the second satellite using Kepler's third law.
319 Medium
319 of 392
Application +4 | -1
A body is moving in a low circular orbit about a planet of mass MM and radiusRR. The radius of the orbit can be taken to be RR itself. Then, the ratio of the speed of this body in the orbit to the escape velocity from the planet is
View answer and explanation
Correct option: B
12\frac{1}{{\sqrt 2 }}
Option B (12\frac{1}{{\sqrt 2 }}) is correct because the ratio of orbital speed to escape velocity is always 12\frac{1}{{\sqrt 2 }} for a circular orbit at the planet's surface.
320 Medium
320 of 392
Understanding +4 | -1
When a satellite going round the earth in a circular orbit of radius rr and speed vv loses some of its energy, then rr and vv change as
View answer and explanation
Correct option: C
rr will decrease and vv will increase
Option C (rr will decrease and vv will increase) is correct because as a satellite loses energy, its orbital radius decreases, and its orbital speed increases to maintain equilibrium.
321 Medium
321 of 392
Understanding +4 | -1
What effect occurs on the frequency of a pendulum of it is taken from the earth surface to deep into a mine?
View answer and explanation
Correct option: B
decreases
The correct answer is B (decreases) because the effective value of g decreases as you go deeper into a mine, and frequency is proportional to the square root of g.
322 Medium
322 of 392
Application +4 | -1
The radius of earth is R. Height of a point vertically above the earth's surface at which acceleration due to gravity becomes 1% of its value of the surface is
View answer and explanation
Correct option: B
9R
Option B (9R) is correct because it is the height at which the acceleration due to gravity is 1% of its surface value, calculated using the inverse square law.
323 Medium
323 of 392
Application +4 | -1
Four particles of masses m,2m,3mm, 2 m, 3 m and 4m4 m are kept in sequence at the corners of a square of side aa. The magnitude of gravitational force acting on a particle of mass m\mathrm{m} placed at the centre of the square will be
View answer and explanation
Correct option: C
42Gm2a2\frac{4 \sqrt{2} G m^2}{a^2}
Option C (42Gm2a2\frac{{4 \sqrt{{2}} G m^2}}{{a^2}}) is correct because it represents the net gravitational force calculated by vectorially summing the forces from each mass at the corners of the square.
324 Medium
324 of 392
Application +4 | -1
A satellite of mass m is moving around the earth in a circular orbit of radius r. If the mass of the earth is M, the energy required to take the satellite to an orbit of radius 3r is
View answer and explanation
Correct option: C
GMm3r\frac{{GMm}}{{3r}}
Option C (GMm3r\frac{{GMm}}{{3r}}) is correct because the energy required is the difference in the total mechanical energy of the satellite in the two orbits.
325 Medium
325 of 392
Understanding +4 | -1
A man weighs 80kg80 \mathrm{kg} on the surface of the earth. His weight on a geostationary satellite is
View answer and explanation
Correct option: C
Zero
Option C (Zero) is correct because objects in geostationary orbit experience weightlessness due to the absence of a supporting normal force.
326 Medium
326 of 392
Understanding +4 | -1
Gravitational field due to a solid sphere
View answer and explanation
Correct option: B
Increases inside the sphere and decreases outside the
sphere
Option D (Increases inside the sphere and decreases outside the sphere) is correct because the gravitational field increases linearly inside and decreases inversely with the square of the distance outside.
327 Medium
327 of 392
Analyzing +4 | -1
A particle of mass mm is dropped from a great height hh above the hole in the earth dug along its diameter. Then, which of the following statement is correct?
View answer and explanation
Correct option: D
The speed of the particle at the centre of earth equals GM(R+3h)R(R+h)\sqrt{\frac{G M(R+3 h)}{R(R+h)}}, where RR and MM are the radius and mass of the earth, respectively.
Option D is correct because it accurately calculates the particle's speed at the Earth's center considering its initial height and the varying gravitational force inside the Earth.
328 Medium
328 of 392
Understanding +4 | -1
The orbit of geostationary satellite is circular, the time period of satellite depends on
(i) mass of the satellite
(ii) mass of the earth
(iii) radius of the orbit
(iv) height of the satellite from the surface of earth
Which of the following correct?
View answer and explanation
Correct option: D
(ii), (iii) and (iv)
Option D ((ii), (iii) and (iv)) is correct because the time period of a geostationary satellite depends on the mass of the Earth, the radius of the orbit, and the height of the satellite.
329 Medium
329 of 392
Understanding +4 | -1
When a satellite is shifted from a nearer orbit to a farther orbit, its

(a) Gravitational potential energy increases

(b) Kinetic energy increases

(c) Gravitational potential energy decreases

(d) Kinetic energy decreases

Choose the correct option.
View answer and explanation
Correct option: B
(a) and (d) are correct
Option B ((a) and (d) are correct) is correct because as a satellite moves to a farther orbit, its potential energy increases while its kinetic energy decreases due to a reduction in orbital speed.
330 Medium
330 of 392
Analyzing +4 | -1
Statement I: If ice on the pole melts, length of the day will shorten.

Statement II: Ice will flow towards equator and will result in the decrease in moment of inertia of earth resulting in decrease in frequency of rotation of earth.
View answer and explanation
Correct option: C
If Statement - I is true but Statement - II is false.
Option C (If Statement - I is true but Statement - II is false) is correct because melting ice at the poles increases the moment of inertia, slowing down Earth's rotation and lengthening the day.
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