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JEE • PHYSICS • GRAVITATION

Gravitation practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 331-360 of 392 questions

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331 Medium
331 of 392
Analyzing +4 | -1
If a planet of given density were made larger (keeping its density unchanged) its force of attraction for an object on its surface would increase because of increased mass of the planet but would decrease because of larger separation between the centre of the planet and its surface. Which effect would dominate?
View answer and explanation
Correct option: B
Increase in radius
The correct answer is B (Increase in radius) because the acceleration due to gravity is directly proportional to the radius of the planet when density is constant.
332 Medium
332 of 392
Analyzing +4 | -1
Assertion: The time period of revolution of a satellite around a planet is directly proportional to the radius of the orbit of the satellite.

Reason: Artificial satellite do not follow Kepler's laws of planetary motion.
View answer and explanation
Correct option: C
If assertion is true, but reason is false.
Option C (If assertion is true, but reason is false) is correct because the time period is proportional to r(3/2) and artificial satellites do follow Kepler's laws.
333 Medium
333 of 392
Understanding +4 | -1
Consider a binary star system of star AA and star BB with masses mA{m_A} and mB{m_B} revolving in a circular orbit of radii rA{r_A} and rB{r_B} respectively. If TA{T_A} and TB{T_B} are the time period of star AA and star BB respectively, then
View answer and explanation
Correct option: B
TA=TB{T_A} = {T_B}
Option B (TA=TB{T_A} = {T_B}) is correct because both stars in a binary system orbit their common center of mass with the same angular velocity, hence the same period.
334 Medium
334 of 392
Application +4 | -1
Find the distance of a point from the earth's centre where the resultant gravitational field due to the earth and the moon is zero. The mass of the earth is 6.0×1024 kg6.0 \times 10^{24} \mathrm{~kg} and that of the moon is 7.4×1022 kg7.4 \times 10^{22} \mathrm{~kg}. The distance between the earth and the moon is 4.0×105 km4.0 \times 10^5 \mathrm{~km}.
View answer and explanation
Correct option: A
3.6×105 km3.6 \times 10^5 \mathrm{~km}
Option A (3.6×105 km3.6 \times 10^5 \mathrm{~km}) is correct because it is the distance where the gravitational fields of the Earth and Moon cancel each other out.
335 Medium
335 of 392
Application +4 | -1
If a body of mass mm has to be taken from the surface of the earth to a height h=4Rh=4 R, then the amount of energy required is (R=R= radius of the earth)
View answer and explanation
Correct option: C
4mgR5\frac{4 m g R}{5}
Option C (4mgR5\frac{{4 m g R}}{{5}}) is correct because it represents the difference in gravitational potential energy between the surface and the height h=4R.
336 Medium
336 of 392
Analyzing +4 | -1
A spherical uniform planet is rotating about its axis. The velocity of a point on its equator is V.V. Due to the rotation of the planet about its axis the acceleration due to gravity g{g} at equator is 1/2 of gg at poles. The escape velocity of a particle on the planet in terms of V{V} from the pole of the planet is
View answer and explanation
Correct option: A
Ve=2V{V_e}=2{V}
Option A (Ve=2V{V_e}=2{V}) is correct because by relating the acceleration due to gravity at the equator and poles with the planet's rotation, we can derive the escape velocity in terms of the equatorial velocity V.
337 Medium
337 of 392
Understanding +4 | -1
The weight of an astronaut, in an artificial satellite revolving around the earth, is
View answer and explanation
Correct option: A
Zero
Option A is correct because in an artificial satellite, the astronaut experiences weightlessness due to freefall, making their apparent weight zero.
338 Medium
338 of 392
Application +4 | -1
An earth's satellite makes a circle around the earth in 90 minutes. Calculate the height of the satellite above the earth's surface. Given radius of the earth is 6400 km6400 \mathrm{~km} and g=980 cms−2g=980 \mathrm{~cms}^{-2}.
View answer and explanation
Correct option: A
268 km268 \mathrm{~km}
Option A (268 km268 \mathrm{~km}) is correct because it is the height calculated using the time period of the satellite's orbit and the given values of g and R.
339 Medium
339 of 392
Application +4 | -1
A diametrical tunnel is dug across the earth. A ball is dropped into the tunnel from one earth. A ball is dropped into the tunnel from one side. The velocity of the ball when it reached the centre of the earth is (Given: gravitational potential at the centre of earth =−32 (GMR)= - \frac{3}{2}\,\left( {\frac{{GM}}{R}} \right))
View answer and explanation
Correct option: B
gR\sqrt {gR}
Option B (gR\sqrt {gR}) is correct because it is derived from equating the loss in potential energy to the gain in kinetic energy as the ball moves to the center of the Earth.
340 Medium
340 of 392
Analyzing +4 | -1
A satellite is revolving around the earth at a height hh. The satellite explodes into two equal parts, one part has zero velocity after the explosion, and the other moves in the same direction with double the orbital speed of the original satellite. The maximum height reached by the part with double the velocity is (Neglect the gravitational effects between the fragments)
View answer and explanation
Correct option: D
None of these
Option D is correct. The velocity after the collision becomes greater than the escape velocity, so the fragment will escape to infinity.
341 Medium
341 of 392
Application +4 | -1
Two satellites A and B have masses m and 2m respectively. A is in a circular orbit of radius R and B is in a circular orbit of radius 2R around the earth. The ratio of their kinetic energies, TA/TB{T_A}/{T_B} is
View answer and explanation
Correct option: D
1
Option D (1) is correct because the ratio of kinetic energies is 1, as both satellites have the same kinetic energy calculated using their orbital speeds and masses.
342 Medium
342 of 392
Application +4 | -1
A satellite is orbiting just above the surface of the earth with period TT. If dd is the density of the earth and GG is the universal constant of gravitation, the quantity 3πGd\frac{3 \pi}{G d} represents
View answer and explanation
Correct option: D
T2T^2
Option D (T2T^2) is correct because the quantity 3πGd\frac{{3 \pi}}{{G d}} is equal to the square of the orbital period TT of a satellite orbiting just above the Earth's surface.
343 Medium
343 of 392
Remembering +4 | -1
Hubble's law is related with
View answer and explanation
Correct option: B
speed of galaxy
Option B (speed of galaxy) is correct because Hubble's law states that the recessional velocity of a galaxy is proportional to its distance from the observer.
344 Medium
344 of 392
Application +4 | -1
An artificial satellite is moving in a circular orbit (of radius rr) around the earth and its orbital speed is equal to 13rd\frac{1}{3}{\text{rd}} of the escape speed from the earth’s surface. The value of rr in terms of radius of earth RR is
View answer and explanation
Correct option: B
9R2\frac{{9R}}{2}
Option B (9R2\frac{{9R}}{2}) is correct because it is derived from equating the orbital speed to one-third of the escape speed and solving for the orbital radius.
345 Medium
345 of 392
Analyzing +4 | -1
Which pair of PE and KE is possible for a polar satellite? [Assume PE=0 at infinity]
View answer and explanation
Correct option: B
KE = 500 J, PE = -1000 J
Option B is correct because for a satellite in orbit, the kinetic energy is half the magnitude of the potential energy, and the potential energy is negative.
346 Medium
346 of 392
Analyzing +4 | -1
Consider Earth to be a homogeneous sphere. Scientist AA goes deep down in a mine and scientist BB goes high up in a balloon. The gravitational field measured by:
View answer and explanation
Correct option: D
Each decreases at different rates
Option D (Each decreases at different rates) is correct because the gravitational field decreases differently inside and outside the Earth.
347 Medium
347 of 392
Understanding +4 | -1
If satellite is shifted towards the earth. Then time period of satellite will be
View answer and explanation
Correct option: B
Decrease
Option B (Decrease) is correct because the time period of a satellite is directly related to its orbital radius, so decreasing the radius decreases the time period.
348 Medium
348 of 392
Understanding +4 | -1
For a satellite escape velocity is 11 km/s11 \mathrm{~km} / \mathrm{s}. If the satellite is launched at angle of 60∘60^{\circ} with the vertical, then escape velocity will be
View answer and explanation
Correct option: A
11 km/s11 \mathrm{~km} / \mathrm{s}
Option A is correct because escape velocity is independent of the angle of projection.
349 Medium
349 of 392
Application +4 | -1
If the distance between the sun and the earth is increased by three times, then attraction between two will
View answer and explanation
Correct option: D
Decrease by 89%89 \%
Option D (Decrease by 89%) is correct because the gravitational force decreases inversely with the square of the distance, resulting in an 89% decrease when the distance triples.
350 Medium
350 of 392
Understanding +4 | -1
If ge,  gh and gd{g_e},\;{g_h}\,and\,{g_d} be the accelerations due to gravity at earth’s surface, a height hh and at depth dd respectively. Then
View answer and explanation
Correct option: B
ge>gh<gd{g_e} > {g_h} < {g_d}
Option A (ge>gh<gd{g_e} > {g_h} < {g_d}) is correct because gravity decreases with height and depth, but the rate of decrease is different, with ghg_h decreasing faster than gdg_d for small h=d.
351 Medium
351 of 392
Analyzing +4 | -1
In case of an orbiting satellite, if the radius of orbit is decreased,
View answer and explanation
Correct option: D
Both (1) and (2) are incorrect
Option D (Both (1) and (2) are incorrect) is correct because when the radius of orbit decreases, kinetic energy increases and potential energy decreases.
352 Medium
352 of 392
Application +4 | -1
If the escape velocity on the earth is 11.2 Km/s, its value for a planet having double the radius and 8 times the mass of the earth is &hellip;&hellip; (in km/s)
View answer and explanation
Correct option: B
22.4
Option B (22.4) is correct because the escape velocity is proportional to the square root of (M/R).
353 Medium
353 of 392
Application +4 | -1
A body weighs 90 kgf90 \mathrm{~kgf} on the surface of the earth. How much will it weigh on the surface of Mars whose mass is 1/91 / 9 and the radius is 1/21 / 2 of that of the earth?
View answer and explanation
Correct option: A
40 kgf40 \mathrm{~kg} \mathrm{f}
Option A (40 kg f) is correct because the weight on Mars is calculated using the ratio of gravitational accelerations on Mars and Earth.
354 Medium
354 of 392
Understanding +4 | -1
A person sitting on a chair in a satellite feels weightless because
View answer and explanation
Correct option: C
The normal force is zero
Option C (The normal force is zero) is correct because the person and the chair are in free fall together, so there is no normal force exerted by the chair on the person.
355 Medium
355 of 392
Understanding +4 | -1
When a satellite moves around the earth in a
certain orbit, then the quantity that remains
constant is
View answer and explanation
Correct option: C
Areal velocity
Option C (Areal velocity) is correct because Kepler's Second Law states that a satellite's areal velocity remains constant in its orbit.
356 Medium
356 of 392
Analyzing +4 | -1
A planet is orbiting the sun in an elliptical orbit. Let UU denote the potential energy and KK denote the kinetic energy of the planet at an arbitrary point on the orbit. Choose the correct statement.
View answer and explanation
Correct option: A
K<∣U∣K < |U| always
Option A (K<∣U∣K < |U|) is correct. For a planet in an elliptical orbit, the magnitude of the potential energy is always greater than the kinetic energy.
357 Medium
357 of 392
Analyzing +4 | -1
Assertion: Average density of the earth depends on the value of gg.

Reason: It is because, the density is the ratio of the mass of the earth to its volume.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not correct explanation of the assertion.
Option B is correct. The average density of the Earth depends on g, but the reason given (density is mass/volume) is a true statement but not the correct explanation.
358 Medium
358 of 392
Application +4 | -1
Two point masses of mass 4m4m and mm respectively separated by distance dd are revolving under mutual force of attraction. Ratio of their kinetic energies will be
View answer and explanation
Correct option: A
1:41:4
Option A (1:41:4) is correct because the ratio of kinetic energies is inversely proportional to the ratio of the masses.
359 Medium
359 of 392
Understanding +4 | -1
If the earth stops rotating about its axis, then the magnitude of gravity
View answer and explanation
Correct option: C
Will not change at the poles
Option C (Will not change at the poles) is correct because the effect of Earth's rotation on gravity is zero at the poles.
360 Medium
360 of 392
Application +4 | -1
A remote sensing satellite of the earth revolves in a circular orbit at a height of 250 km250 \mathrm{~km} above the earth's surface. What is the period of revolution of the satellite? Radius of the earth, R=6.38×106 mR=6.38 \times 10^6 \mathrm{~m}, and acceleration due to gravity on the surface of the earth, g=9.8 ms−2g=9.8 \mathrm{~ms}^{-2}.
View answer and explanation
Correct option: A
5370 s5370 \mathrm{~s}
Option A (5370 s5370 \mathrm{~s}) is correct because it is the calculated period of revolution using the given radius of Earth, height of the satellite, and acceleration due to gravity.
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