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JEE PHYSICS MCQ: GRAVITATION

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A satellite is orbiting around the earth with orbital radius

R

and time period

T

. The quantity which remain constant is

View answer and explanation

Correct option: D

\frac{{{T^2}}}{{{R^3}}}

Option D (

\frac{{{T^2}}}{{{R^3}}}

) is correct because Kepler's third law states that the square of the orbital period is proportional to the cube of the orbital radius.

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The escape velocity for a body projected vertically upwards from the surface of the earth is

11.2\mathrm{\;\;km}{\mathrm{s}^{ - 1}}

. If the body is projected in a direction making an angle of

{45^0}

with the vertical, the escape velocity will be The escape velocity of a body projected from the surface of earth is

v_e

. If the body is projected at an angle

\theta

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