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JEE • PHYSICS • ELECTROMAGNETIC WAVES

Electromagnetic waves practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 250 questions
31 Hard
31 of 250
Application +4 | -1
A parallel plate condenser of capacity 100 PF is connected to 230 V of AC supply of 300 rad / sec frequency. The rms value of displacement current [in μA\mu A ]
View answer and explanation
Correct option: A
6.9
Option A (6.9) is correct because the RMS value of displacement current is calculated using the formula Id=VCωI_d = VC\omega.
32 Medium
32 of 250
Remembering +4 | -1
Which of the following electromagnetic waves has minimum frequency?
View answer and explanation
Correct option: B
Audible waves
Option B (Audible waves) is correct because audible waves are mechanical waves, not electromagnetic waves, and generally have lower frequencies than radio waves.
33 Medium
33 of 250
Remembering +4 | -1
The Maxwell ∮B⃗⋅dI⃗=μ0(I+ε0dϕEdt)\oint \vec{B} \cdot d \vec{I}=\mu_0\left(I+\varepsilon_0 \frac{d \phi_E}{d t}\right) is a statement of
View answer and explanation
Correct option: B
Modified Ampere's law
Option B (Modified Ampere's law) is correct because the given equation is the mathematical representation of Ampere-Maxwell's law, which is the modified form of Ampere's law.
34 Easy
34 of 250
Understanding +4 | -1
Let the velocities of light in vacuum and glass are represented by vv and vgv_{\mathrm{g}}. When electrons move through glass with a velocity vev_e, there emitted a visible radiation in glass if
View answer and explanation
Correct option: A
ve>vgv_e > v_g
Option A is correct because visible radiation (Cherenkov radiation) is emitted when a charged particle travels through a dielectric medium faster than the speed of light in that medium.
35 Medium
35 of 250
Understanding +4 | -1
A laser beam is used for locating distant objects because
View answer and explanation
Correct option: B
It is coherent
Option B is correct. Coherence is the key property of laser beams that allows them to maintain a small spot size over long distances, making them suitable for locating distant objects.
36 Hard
36 of 250
Application +4 | -1
Assume that all the energy from a 1000 W1000 \mathrm{~W} lamp is radiated uniformly, then the amplitude of electric field of radiation at a distance of 2 m2 \mathrm{~m} from the lamp is
View answer and explanation
Correct option: A
245.01 V/m245.01 \mathrm{~V} / \mathrm{m}
Option A (245.01 V/m245.01 \mathrm{~V} / \mathrm{m}) is correct because it is the amplitude of the electric field calculated from the power of the lamp and the distance, considering uniform radiation.
37 Medium
37 of 250
Understanding +4 | -1
Select the correct statement from the following.
View answer and explanation
Correct option: D
Electromagnetic waves carry both energy and momentum as they propagate through space
Option D is correct because electromagnetic waves, as they propagate through space, inherently carry both energy and momentum.
38 Medium
38 of 250
Application +4 | -1
The magnetic field in a plane electromagnetic wave is given by By=2×10−7sin⁡(0.5×103x+1.5×1011t)T.B_y=2 \times 10^{-7} \sin \left(0.5 \times 10^3 x+1.5 \times 10^{11} t\right) T . What is the wavelength and frequency of the wave?
View answer and explanation
Correct option: A
1.26 cm,23.9 GHz1.26 \mathrm{~cm}, 23.9 \mathrm{~GHz}
Option A (1.26 cm,23.9 GHz1.26 \mathrm{~cm}, 23.9 \mathrm{~GHz}) is correct because it is derived from comparing the given equation with the standard wave equation and calculating wavelength and frequency.
39 Medium
39 of 250
Remembering +4 | -1
According to Maxwell’s hypothesis, a changing electric field gives rise to
View answer and explanation
Correct option: B
magnetic field
Option B (magnetic field) is correct because Maxwell's hypothesis states that a changing electric field gives rise to a magnetic field.
40 Medium
40 of 250
Application +4 | -1
The eye can detect 5×1045 \times 10^4 photons per square metre per sec of green light (λ=5000Ao)(\lambda=5000 \mathop {\text{A}}\limits^{\text{o}}) while the ear can detect 10−13( W/m2)10^{-13}\left(\mathrm{~W} / \mathrm{m}^2\right). The factor by which the eye is more sensitive as a power detector than the ear is close to
View answer and explanation
Correct option: A
5
The correct answer is A (5) because the eye is approximately 5 times more sensitive than the ear as a power detector, based on the calculated minimum intensity detectable by the eye compared to the ear.
41 Medium
41 of 250
Application +4 | -1
An EM wave is given by

E=200sin⁡[1.5×107t−0.05x]N/C\mathrm{E}=200 \sin \left[1.5 \times 10^7 \mathrm{t}-0.05 \mathrm{x}\right] \mathrm{N} / \mathrm{C}

Find the intensity of wave. [ε0=8.85×10−12\left[\varepsilon_0=8.85 \times 10^{-12}\right. SI units ]]
View answer and explanation
Correct option: A
53.1
Option A (53.1) is correct because the intensity of the wave is calculated using I=12ε0E02cI = \frac{1}{2} \varepsilon_0 E_0^2 c.
42 Medium
42 of 250
Application +4 | -1
The magnetic field in a plane electromagnetic wave is given by

B=(200μT)sin⁡[(4.0×1015 s−1)(t−x/c)].B=(200 \mu \mathrm{T}) \sin \left[\left(4.0 \times 10^{15} \mathrm{~s}^{-1}\right)(t-x / c)\right] .

Find the maximum electric field and the average energy density corresponding to the electric field.
View answer and explanation
Correct option: A
6×104 N C−1,0.016 J m−36 \times 10^4 \mathrm{~N} \mathrm{~C}^{-1}, 0.016 \mathrm{~J} \mathrm{~m}^{-3}
Option A (6×104 N C−1,0.016 J m−36 \times 10^4 \mathrm{~N} \mathrm{~C}^{-1}, 0.016 \mathrm{~J} \mathrm{~m}^{-3}) is correct because it's the maximum electric field and average energy density calculated from the given magnetic field.
43 Medium
43 of 250
Remembering +4 | -1
Laser light has the following property
View answer and explanation
Correct option: D
Laser light is highly coherent
Option D (Laser light is highly coherent) is correct because coherence is a defining characteristic of laser light.
44 Medium
44 of 250
Remembering +4 | -1
Solar radiation is
View answer and explanation
Correct option: A
Transverse Electromagnetic wave
Option A is correct. Solar radiation consists of transverse electromagnetic waves, including visible light, ultraviolet, and infrared radiation.
45 Medium
45 of 250
Remembering +4 | -1
In an Electromagnetic Wave, direction of propagation is in the direction of
View answer and explanation
Correct option: C
E  ×  B\mathbf{E}\; \times \;\mathbf{B}
Option C is correct. The direction of propagation of an electromagnetic wave is given by the Poynting vector, which is in the direction of E×B\mathbf{E} \times \mathbf{B}.
46 Medium
46 of 250
Understanding +4 | -1
Pick out the wrong statement.
View answer and explanation
Correct option: B
An EM wave is a wave radiated by a charge at rest and propagates through electric field only
Option B (An EM wave is a wave radiated by a charge at rest and propagates through electric field only) is the wrong statement because EM waves are radiated by accelerating charges and propagate through both electric and magnetic fields.
47 Medium
47 of 250
Understanding +4 | -1
If a long hollow copper pipe carries a direct current, the magnetic field associated with the current will be
View answer and explanation
Correct option: B
Only outside the pipe
Option B (Only outside the pipe) is correct because, according to Ampere's Law, the magnetic field inside a hollow conductor carrying a direct current is zero.
48 Medium
48 of 250
Application +4 | -1
The electric field in an electromagnetic wave is given by E=56.5sin⁡ω(t−x/c)NC−1. E = 56.5\sin \omega (t - x/c)N{C^{ - 1}}.\, Find the intensity of the wave if it is propagating along x – axis in the free space.
(Given ∈0=8.85×10−12C2N−1m−2){ \in _0} = 8.85 \times {10^{ - 12}}{C^2}{N^{ - 1}}{m^{ - 2}})
View answer and explanation
Correct option: B
4.24   Wm−24.24\,\,\,W{m^{ - 2}}
Option B (4.24 W/m²) is correct because the intensity of an electromagnetic wave is proportional to the square of the electric field amplitude.
49 Easy
49 of 250
Application +4 | -1
The frequency of a plane electromagnetic wave traveling in vacuum in X-direction is
30 MHz, its wavelength is
View answer and explanation
Correct option: C
10 m
Option C (10 m) is correct because the wavelength is calculated using the formula λ=c/f\lambda = c/f, where c is the speed of light and f is the frequency.
50 Medium
50 of 250
Understanding +4 | -1
Assertion: A pulsar is a source of radio waves that varies intensity at regular intervals.

Reason: A pulsar is a rotating neutron star.
View answer and explanation
Correct option: A
Both Assertion and reason are true and the reason is correct explanation of the Assertion.
Option A is correct because a pulsar is indeed a source of radio waves with regular intensity variations, and this is due to it being a rotating neutron star.
51 Medium
51 of 250
Understanding +4 | -1
Displacement current goes through the gap between the plates of a capacitor when the charge on the capacitor
View answer and explanation
Correct option: A
Is changing with time
Option C (Shear modulii << Young's modulii << bulk modulii) is correct because for most materials, the bulk modulus is the highest, followed by Young's modulus, and then the shear modulus.
52 Easy
52 of 250
Application +4 | -1
A new system of units is evolved in which the values of μ0{\mu _0} and ε0{\varepsilon _0} are 2 and 8 respectively. Then the speed of light in this system will be
View answer and explanation
Correct option: A
0.25
Option A (0.25) is correct because the speed of light is inversely proportional to the square root of the product of permeability and permittivity.
53 Medium
53 of 250
Application +4 | -1
The magnetic field in a travelling electromagnetic wave has a peak value of 20 nT. The peak value of electric field strength is
View answer and explanation
Correct option: B
6 V/m
Option B (6 V/m) is correct because the peak electric field strength is the product of the peak magnetic field and the speed of light.
54 Medium
54 of 250
Understanding +4 | -1
These rays lie in upper frequency range of
electromagnetic spectrum. The rays are produced
in nuclear reactions and used in medicine to
destroy cancer cells. The rays are:
View answer and explanation
Correct option: B
Gamma-rays
Option B (Gamma-rays) is correct because gamma rays have the highest frequency in the electromagnetic spectrum, are produced in nuclear reactions, and are used in medicine to destroy cancer cells.
55 Medium
55 of 250
Understanding +4 | -1
Electromagnetic waves propagate in the direction parallel to the vector (E‾\overline E is electric field and B‾\overline B is magnetic field)
View answer and explanation
Correct option: C
E×BE \times B
The correct answer is C (E×BE \times B) because electromagnetic waves propagate in the direction of the Poynting vector, which is parallel to E×BE \times B.
56 Medium
56 of 250
Understanding +4 | -1
An electromagnetic wave travels in vacuum along zz-direction

E=(E1i^+E2ȷ^)cos⁡(kz−ωt)\mathbf{E}=\left(E_1 \hat{\mathfrak{i}}+E_2 \hat{\jmath}\right) \cos (k z-\omega t). Choose the correct option from the following
View answer and explanation
Correct option: D
The given electromagnetic wave is plane polarised
Option D (The given electromagnetic wave is plane polarised) is correct because the electric field vector is confined to a plane.
57 Medium
57 of 250
Understanding +4 | -1
The electric and the magnetic field, associated with an e.m. wave, propagating along the + z− axis,\mathrm{ + }\,\mathrm{z - }\,\mathrm{axis,} can be represented by
View answer and explanation
Correct option: A
[E→=E0i^,  B→=B0j^]\left[ {\overrightarrow E = {E_0}\hat i,\,\,\overrightarrow B = {B_0}\hat j} \right]
Option A ([E→=E0i^,,B→=B0j^]\left[ {\overrightarrow E = {E_0}\hat i,\\,\overrightarrow B = {B_0}\hat j} \right]) is correct because the direction of propagation of an electromagnetic wave is given by the direction of E→×B→\overrightarrow E \times \overrightarrow B.
58 Medium
58 of 250
Understanding +4 | -1
If μ0\mu_0 be the peremeability and ε0\varepsilon_0 be the permittivity of a medium, then its refractive index is given by
View answer and explanation
Correct option: C
μ0ε0\sqrt{\mu_0 \varepsilon_0}
μ0ε0\sqrt{\mu_0 \varepsilon_0} is the correct answer because the refractive index is the square root of the product of permeability and permittivity.
59 Medium
59 of 250
Application +4 | -1
A Laser beam is sent to the moon and reflected back to earth by ay mirror placed on the moon by an astronaut. If the moon is 384000 km from earth, how long does it take the light to make the round trip?
View answer and explanation
Correct option: C
2.5 s
Option C (2.5 s) is correct because it is calculated by dividing the total distance (twice the distance to the moon) by the speed of light.
60 Medium
60 of 250
Understanding +4 | -1
The conduction current is the same as displacement current when source is :-
View answer and explanation
Correct option: C
both ac and dc
Option C (both ac and dc) is correct because the conduction and displacement currents are equal regardless of whether the source is AC or DC.
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