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JEE • PHYSICS • ELECTROMAGNETIC WAVES

Electromagnetic waves practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 250 questions
61 Easy
61 of 250
Remembering +4 | -1
The S.I. unit of displacement current is:
View answer and explanation
Correct option: C
Ampere
Option C (Ampere) is correct because displacement current, like conventional current, is measured in Amperes, representing the flow of charge per unit time.
62 Medium
62 of 250
Application +4 | -1
You are given a 2μF2 \mu \mathrm{F} parallel plate capacitor. How would you establish an instantaneous displacement current of 1 mA1 \mathrm{~mA} in the space between its plates?
View answer and explanation
Correct option: A
By applying a varying potential difference of 500 V/s500 \mathrm{~V} / \mathrm{s}
Option A (By applying a varying potential difference of 500 V/s500 \mathrm{~V} / \mathrm{s}) is correct because the displacement current is proportional to the rate of change of potential difference across the capacitor.
63 Medium
63 of 250
Application +4 | -1
If electric field in an electromagnetic wave is given by E=6×106sin⁡(2πft−2πλx)VmE=6 \times 10^6 \sin \left(2 \pi f t-\frac{2 \pi}{\lambda} x\right) \frac{\mathrm{V}}{\mathrm{m}}. The peak value of magnetic field in the region is
View answer and explanation
Correct option: D
0.02 T0.02 \mathrm{~T}
Option D (0.02 T0.02 \mathrm{~T}) is correct because it is calculated using the relationship between the electric field and magnetic field in an electromagnetic wave, E0/B0=cE_0/B_0 = c.
64 Medium
64 of 250
Understanding +4 | -1
Assertion: The velocity of electromagnetic waves depends on
electric and magnetic properties of the medium
Reason: Velocity of electromagnetic waves in free space is
constant
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the
correct explanation of assertion
Option B (If both assertion and reason are true but reason is not the correct explanation of assertion) is correct because both statements are true, but the constant speed of light in free space doesn't explain the medium dependence.
65 Medium
65 of 250
Remembering +4 | -1
The electromagnetic wave having the shortest wavelength is
View answer and explanation
Correct option: B
γ\gamma-rays
Option B (γ\gamma-rays) is correct because gamma rays have the shortest wavelength and highest frequency in the electromagnetic spectrum among the given options.
66 Easy
66 of 250
Understanding +4 | -1
Given below are two statements:
Statement I: Electromagnetic waves carry energy
as they travel through space and this energy is
equally shared by the electric and magnetic fields
Statement II: When electromagnetic waves strike
a surface, a pressure is exerted on the surface
In the light of the above statements, choose the
most appropriate answer from the options given
below
View answer and explanation
Correct option: A
Both Statement I and Statement II are correct
Option A is correct because electromagnetic waves transport energy through space, and this energy is equally distributed between the electric and magnetic fields. Also, EMW exerts pressure.
67 Easy
67 of 250
Remembering +4 | -1
The range of frequency allotted for FM radio is
View answer and explanation
Correct option: B
8888 to 108 MHz108 \mathrm{~MHz}
Option B (8888 to 108 MHz108 \mathrm{~MHz}) is correct because it represents the standard frequency range allocated for FM radio broadcasting.
68 Medium
68 of 250
Remembering +4 | -1
Pick out the longest wavelength from the following types of radiations
View answer and explanation
Correct option: D
Red light
Option D (Red light) is correct because red light has the longest wavelength among the given options in the electromagnetic spectrum.
69 Medium
69 of 250
Understanding +4 | -1
Assertion: The gyrating electron can be source of EMW.

Reason: The electron in circular motion is accelerated motion.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because a gyrating (accelerating) electron emits electromagnetic waves, and circular motion implies acceleration.
70 Medium
70 of 250
Understanding +4 | -1
In an electromagnetic wave, the direction of the magnetic field induction B⃗\vec{B} is
View answer and explanation
Correct option: B
Perpendicular to electric field E⃗\vec{E}
Option B (Perpendicular to electric field E⃗\vec{E}) is correct because in an electromagnetic wave, the electric and magnetic fields are perpendicular to each other and to the direction of propagation.
71 Medium
71 of 250
Remembering +4 | -1
The electromagnetic waves generally used in the purification of water are
View answer and explanation
Correct option: C
Ultra violet rays
Option C (Ultra violet rays) is correct because ultraviolet (UV) rays are commonly used for water purification due to their ability to kill bacteria and viruses.
72 Medium
72 of 250
Understanding +4 | -1
Which of the following electromagnetic wave play an important role in maintaining the earth’s warmth or average temperature through the greenhouse effect?
View answer and explanation
Correct option: B
Infrared waves
Option B (Infrared waves) is correct because infrared radiation is responsible for the greenhouse effect, trapping heat and maintaining Earth's temperature.
73 Medium
73 of 250
Application +4 | -1
Find the displacement current developed in the space between the plates of parallel plate capacitor of capacity 2μF2 \mu \mathrm{F} when voltage is changing at a rate of 106Vs−1.10^6 \mathrm{Vs}^{-1}.
View answer and explanation
Correct option: A
0.083333333
Option C (2 mA) is correct because the displacement current is calculated using the formula id=CdVdti_d = C \frac{dV}{dt}.
74 Medium
74 of 250
Remembering +4 | -1
Which rays are not part of electromagnetic spectrum?
View answer and explanation
Correct option: B
α−rays\alpha - {\text{rays}}
Option B (α−rays\alpha - {\text{rays}}) is correct because alpha rays are not part of the electromagnetic spectrum; they are particles.
75 Medium
75 of 250
Remembering +4 | -1
The part of the spectrum of the electromagnetic radiation used to cook food is
View answer and explanation
Correct option: D
Microwaves
Option D (Microwaves) is correct because microwaves are used in microwave ovens to cook food.
76 Medium
76 of 250
Application +4 | -1
The wave function (in S.I units) for an electromagnetic wave is given as −ψ(X,t)=103sin⁡π(3×106X−9×1014t)- \psi \left( {X,t} \right) = {10^3}\sin \pi \left( {3 \times {{10}^6}X - 9 \times {{10}^{14}}t} \right). The speed of wave is :
View answer and explanation
Correct option: B
3×108 m/s3 \times {10^8}\,m/s
Option B (3×108 m/s3 \times {10^8}\,m/s) is correct because the speed of the wave is calculated by dividing the angular frequency by the wave number, which results in the speed of light.
77 Medium
77 of 250
Application +4 | -1
The charge of a parallel plate capacitor is varying as q=q0sin⁡2πftq = {q_0}\sin 2\pi ft. The plates are very large and close together (area=A= A, separation=d= d). Neglecting edge effects, the displacement current through the capacitor is
View answer and explanation
Correct option: C
2πfq0cos⁡2πft2\pi f{q_0}\cos 2\pi ft
Option C (2πfq0cos⁡2πft2\pi f{q_0}\cos 2\pi ft) is correct because the displacement current is the time derivative of the charge.
78 Medium
78 of 250
Remembering +4 | -1
The electromagnetic waves travel with a velocity
View answer and explanation
Correct option: B
Equal to velocity of light
Option B (Equal to velocity of light) is correct because electromagnetic waves, by definition, travel at the speed of light in a vacuum.
79 Medium
79 of 250
Application +4 | -1
Find the values of magnetic field between plates of capacitor at distance 1 m1 \mathrm{~m} from centre where electric field varies by 101010^{10} volt /m/s/ \mathrm{m} / \mathrm{s}.
View answer and explanation
Correct option: A
5.56×10−8 T5.56 \times 10^{-8} \mathrm{~T}
Option A (5.56×10−8 T5.56 \times 10^{-8} \mathrm{~T}) is correct because it is calculated using the formula for the magnetic field between the plates of a capacitor due to the changing electric field.
80 Medium
80 of 250
Understanding +4 | -1
Assertion: During discharging there is magneticfield between plates of capacitor.

Reason : Time varying electric field produces magnetic field.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because a time-varying electric field between the capacitor plates during discharging produces a magnetic field, as described by Maxwell's equations.
81 Medium
81 of 250
Understanding +4 | -1
Which of the following statements about electromagnetic waves is/are correct?

(1) X-rays in vacuum travel faster than light waves in vacuum.

(2) The energy of X-ray photon is greater than that of a light photon

(3) Light can be polarised but X-ray cannot.
View answer and explanation
Correct option: D
2 only
Option D (2 only) is correct because X-rays and light waves travel at the same speed in a vacuum, and both can be polarized, but X-ray photons have higher energy than light photons.
82 Medium
82 of 250
Remembering +4 | -1
A radar sends the waves towards a distant object and receives the signal reflected by object. These waves are
View answer and explanation
Correct option: D
Micro waves
Option D (Micro waves) is correct because radar systems typically use microwaves to detect distant objects due to their ability to penetrate atmospheric conditions and reflect off targets.
83 Medium
83 of 250
Application +4 | -1
The maximum electric field in a plane electromagnetic wave is 600 NC−1600 \mathrm{~NC}^{-1}. The wave is going in the xx-direction and the electric field is in the yy-direction. Find the maximum magnetic field in the wave and its direction.
View answer and explanation
Correct option: A
2×10−6 T,z2 \times 10^{-6} \mathrm{~T}, z-direction
Option A (2×10−6 T,z2 \times 10^{-6} \mathrm{~T}, z-direction) is correct because it's calculated using the relationship between electric and magnetic field amplitudes in an electromagnetic wave, and the direction is determined by the wave's propagation and electric field directions.
84 Medium
84 of 250
Understanding +4 | -1
What physical quantity is the same for X\mathrm{X}-rays of wavelength 10−10 m{10^{-10}} \mathrm{~m}, red light of wavelength 6800 A∘6800 ~\mathop {\text{A}}\limits^ \circ, and radiowaves of wavelength 500 m500 \mathrm{~m}?
View answer and explanation
Correct option: A
3×108 m s−13 \times 10^8 \mathrm{~m} \mathrm{~s}^{-1}
Option A (3×108 m s−13 \times 10^8 \mathrm{~m} \mathrm{~s}^{-1}) is correct because the speed of all electromagnetic waves in a vacuum is constant and equal to the speed of light.
85 Medium
85 of 250
Understanding +4 | -1
An electromagnetic wave is propagating along Y\mathrm{Y}-axis. Then
View answer and explanation
Correct option: B
Oscillating electric field is along Z\mathrm{Z}-axis and oscillating magnetic field is along X\mathrm{X}-axis.
Option B is correct because in an electromagnetic wave, the electric and magnetic fields are perpendicular to each other and to the direction of propagation.
86 Medium
86 of 250
Application +4 | -1
50W/m250\mathrm{ W/}{\mathrm{m}^2} energy density of sunlight is normally incident on the surface of a solar panel. Some part of incident energy (25%) is reflected from the surface and the rest is absorbed. The force exerted on 1m2\mathrm{1 }{\mathrm{m}^\mathrm{2}} surface area will be close to (c=3×108  m/s)(c = 3 \times {10^8}{\rm\,\,{m/s)}}
View answer and explanation
Correct option: A
20×10−8N20 \times {10^{ - 8}}\mathrm{N}
Option A (20×10−8N20 \times {10^{ - 8}}\mathrm{N}) is correct because it calculates the force exerted by the sunlight considering both the absorbed and reflected portions of the incident energy.
87 Medium
87 of 250
Remembering +4 | -1
For an electromagnetic wave traveling in free space
View answer and explanation
Correct option: A
E0=cB0E_0=c B_0
Option A (E0=cB0E_0=c B_0) is correct because it represents the relationship between the electric field amplitude (E0E_0) and magnetic field amplitude (B0B_0) in an electromagnetic wave traveling in free space, where c is the speed of light.
88 Medium
88 of 250
Understanding +4 | -1
An EM wave radiates outwards from a dipole antenna with E0E_0 as the amplitude of its electric field vector. The electric field E0E_0 which transports significant energy from the source falls off as
View answer and explanation
Correct option: C
1/r1 / r
Option C (1/r1 / r) is correct because the electric field amplitude from a dipole antenna falls off inversely with distance.
89 Medium
89 of 250
Understanding +4 | -1
Assertion: A changing electric-field produces a magnetic field.

Reason: A changing magnetic field produces an electric field.
View answer and explanation
Correct option: B
Both Assertion and reason are true, but reason is not the correct explanation of Assertion.
Option B is correct because both a changing electric field produces a magnetic field, and a changing magnetic field produces an electric field, but the latter doesn't explain the former.
90 Easy
90 of 250
Application +4 | -1
A new system of units is evolved in which the values of μ0{\mu _0} and ε0{\varepsilon _0} are 2 and 8 respectively. Then the speed of light in this system will be
View answer and explanation
Correct option: A
0.25
Option A (0.25) is correct because the speed of light is inversely proportional to the square root of the product of permeability and permittivity.
Revision notes and key takeaways

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