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JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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Application +4 | -1
The wavelength of the oscillatory magnetic field in a plane electromagnetic wave given by By=0.6×10−5sin⁡(4000πx−5×1010πt)TB_y=0.6 \times 10^{-5} \sin \left(4000 \pi x-5 \times 10^{10} \pi t\right) T is (where xx is meter and tt is in second)
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Correct option: C
0.5××10−3 m0.5 \times \times 10^{-3} \mathrm{~m}
Option C (0.5×10−3 m0.5 \times 10^{-3} \mathrm{~m}) is correct because the wavelength is calculated from the wave number in the given equation of the magnetic field.

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