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JEE • PHYSICS • ELECTRO MAGNETIC INDUCTION

Electro magnetic induction practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 276 questions

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211 Medium
211 of 276
Remembering +4 | -1
Mutual inductance of a pair of coils, depend
on
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because mutual inductance depends on the separation, relative orientation, and geometric dimensions of the coils.
212 Medium
212 of 276
Application +4 | -1
Two cells of emf 1.25 V, 0.75 V and each of internal resistance 1 Ω1\,\Omega are connected in parallel. The effective emf will be
View answer and explanation
Correct option: A
1 Volt
Option A (1 Volt) is correct because it is the effective EMF calculated from the parallel combination of the two cells.
213 Medium
213 of 276
Analyzing +4 | -1
Assertion : The mutual inductance of two coils is doubled if the self inductance of the primary
or secondary coil is doubled.

Reason : Mutual inductance is proportional to the self inductance of primary and secondary
coils.
View answer and explanation
Correct option: C
If Assertion is True but the reason is false
Option C (If Assertion is True but the reason is false) is correct because while doubling self-inductance does double mutual inductance, the reason provided is not entirely accurate.
214 Medium
214 of 276
Application +4 | -1
An emf is 15 V is applied in a circuit coil containing 5 H inductance and 10 Ω resistance. The ratio of currents at time t=∞t = \infty and t=1 s is
View answer and explanation
Correct option: B
e2e2−1\frac{{{e^2}}}{{{e^2} - 1}}
Option B is correct because the ratio of currents is derived from the inductor current equation at t=infinity and t=1s.
215 Medium
215 of 276
Understanding +4 | -1
An infinitely cylinder is kept parallel to an uniform magnetic field BB directed along positive zz axis. This direction of induced current as seen from the zz axis will be
View answer and explanation
Correct option: C
Zero
The correct answer is C (Zero) because in a uniform magnetic field, the change in magnetic flux is zero, resulting in no induced current.
216 Medium
216 of 276
Remembering +4 | -1
The induction coil works on the principle of
View answer and explanation
Correct option: B
Mutual induction
Option B (Mutual induction) is correct because induction coils use two coils to transfer energy through a changing magnetic field.
217 Medium
217 of 276
Understanding +4 | -1
Consider the following statements.

(a) Eddy current loss is minimized by using laminated cores.

(b) Self-inductance is called inertia of electricity.

Choose the correct statements:
View answer and explanation
Correct option: C
Both a and b
Option C (Both a and b) is correct because laminated cores minimize eddy current loss, and self-inductance is analogous to inertia in electricity.
218 Medium
218 of 276
Understanding +4 | -1
Fleming’s left and right hand rule are used in
View answer and explanation
Correct option: C
DC motor and DC generator
Option C (DC motor and DC generator) is correct because Fleming's left-hand rule is used for DC motors, and Fleming's right-hand rule is used for DC generators.
219 Medium
219 of 276
Analyzing +4 | -1
Assertion: When a conducting rod moves in uniform transverse magnetic field with uniform speed which is perpendicular to its length, then potential difference may develop across its ends.

Reason: In any conductor, free electrons and free positive ions are available.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
The correct answer is C because while the assertion about potential difference developing is true, the reason provided is false; the presence of free electrons is relevant, but free positive ions are not.
220 Medium
220 of 276
Understanding +4 | -1
A particle mass m, charge Q and kinetic
energy T enters a transverse uniform
magnetic field of induction B after 3s the
kinetic energy of the particle will be
View answer and explanation
Correct option: C
T
Option C (T) is correct because the magnetic force does no work on the charged particle, so its kinetic energy remains constant.
221 Medium
221 of 276
Application +4 | -1
In a magnetic field of 0.05  T0.05\,\,T, area of a coil changes from 101  cm2101\,\,c{m^2} to 100  cm2100\,\,c{m^2} without changing the resistance which is 2  Ω2\,\,\mathrm{\Omega }. The amount of charge that flow during this period is
View answer and explanation
Correct option: A
2.5  ×10−6 coulomb2.5\,\, \times {10^{ - 6}}\,coulomb
Option A (2.5×10−6 coulomb2.5 \times {10^{ - 6}}\,coulomb) is correct because it is calculated using the change in magnetic flux and the resistance of the coil.
222 Medium
222 of 276
Application +4 | -1
Current in a circuit falls from 5.0 A to 0 A in 0.1 s. If an average emf of 200 V is induced, estimate the self-inductance of the circuit
View answer and explanation
Correct option: C
4H
Option C (4H) is correct because the self-inductance is calculated using the induced emf and the rate of change of current.
223 Medium
223 of 276
Remembering +4 | -1
The unit of magnetic flux density is
View answer and explanation
Correct option: D
All of these
The correct answer is D (All of these) because Tesla (T), Weber/m² (Wb/m²), and N/A-m are all equivalent units for magnetic flux density.
224 Medium
224 of 276
Understanding +4 | -1
Identify the incorrect statement. Induced electric field
View answer and explanation
Correct option: C
cannot exist in a region not occupied by magnetic field
Option C (cannot exist in a region not occupied by magnetic field) is correct because induced electric fields can exist even outside the region where the magnetic field is changing.
225 Medium
225 of 276
Application +4 | -1
If 10  A\mathrm{10}\,\,\mathrm{A} deposits 10.8  g\mathrm{10}\mathrm{.8 \,\,g} of silver in 25  min\mathrm{25}\,\,\mathrm{min}, how much copper would deposit when 9  A\mathrm{9}\,\,\mathrm{A} current flows for 20  min\mathrm{20}\,\,\mathrm{min}.?
View answer and explanation
Correct option: A
3.81  g\begin{array}{llllllllllllllllllll} {\mathrm{3}\mathrm{.81}\,\,\mathrm{g}} \end{array}
Option A (3.81  g\begin{array}{llllllllllllllllllll} {\mathrm{3}\mathrm{.81}\,\,\mathrm{g}} \end{array}) is correct because it correctly applies Faraday's laws of electrolysis to find the mass of copper deposited.
226 Medium
226 of 276
Remembering +4 | -1
Magnetic energy density in an inductor is given by
View answer and explanation
Correct option: A
UB=B2/2μ0\mathrm{U}_{\mathrm{B}}=\mathrm{B}^2 / 2 \mu_0
Option A (UB=B2/2μ0\mathrm{U}_{\mathrm{B}}=\mathrm{B}^2 / 2 \mu_0) is correct because this is the formula for magnetic energy density in an inductor.
227 Medium
227 of 276
Remembering +4 | -1
Lenz's law gives
View answer and explanation
Correct option: B
the direction of the induced current
Option B (the direction of the induced current) is correct because Lenz's law specifies the direction of the induced current.
228 Medium
228 of 276
Remembering +4 | -1
Average energy stored in a pure inductance LL when a current ii flows through it, is
View answer and explanation
Correct option: D
Li22\frac{{L{i^2}}}{2}
Option D (Li22\frac{{L{i^2}}}{2}) is correct because the energy stored in an inductor is given by the formula U=12Li2U = \frac{1}{2}Li^2.
229 Medium
229 of 276
Remembering +4 | -1
The particle accelerator that uses the phenomenon of electromagnetic induction is the
View answer and explanation
Correct option: B
Betatron
Option B (Betatron) is correct because a betatron accelerates electrons using the principle of electromagnetic induction.
230 Medium
230 of 276
Understanding +4 | -1
If the magnetic flux is expressed in weberweber, then magnetic induction can be expressed in
View answer and explanation
Correct option: A
WeberWeber/m2{m^2}
Option A (WeberWeber/m2{m^2}) is correct because magnetic induction (B) is defined as magnetic flux per unit area.
231 Medium
231 of 276
Analyzing +4 | -1
A square conducting loop of side LL is situated in gravity-free space. A small conducting circular loop of radius r(r≪L)r(r \ll L) is placed at the center of the square loop, with its plane perpendicular to the plane of the square loop. The mutual inductance of the two coils is
View answer and explanation
Correct option: C
0
Option C (0) is correct because the magnetic field produced by the square loop is parallel to the plane of the circular loop, resulting in zero flux through the circular loop and thus zero mutual inductance.
232 Medium
232 of 276
Understanding +4 | -1
Statement (A): The alternating current lags behind the e.m.f. by a phase angle of π2,\frac{\pi }{2}, when ac flows through an inductor.
Statement (B): A bulb connected in series with a solenoid is connected to ac source. If a soft iron core is introduced in the solenoid, the bulb will glow brighter.
Statement (C): The dc and ac both can be measured by a hot wire instrument.
View answer and explanation
Correct option: C
only A and C are true
Option C (only A and C are true) is correct because in an inductor, current lags the voltage by π2\frac{\pi}{2}, and a hot wire instrument measures both AC and DC.
233 Medium
233 of 276
Analyzing +4 | -1
A diamagnetic rod is placed vertically between the poles of an electromagnet when the current in the
electromagnet is switched on, then the diamagnetic rod is pushed up, out of the horizontal magnetic field, Hence the
rod gains gravitational potential energy. The work required to do this comes from.
View answer and explanation
Correct option: A
the induced electric field due to the changing magnetic field
The correct answer is the induced electric field due to the changing magnetic field because the work done comes from the energy associated with the induced electric field.
234 Medium
234 of 276
Analyzing +4 | -1
A flat rectangular coil is placed in a uniform magnetic field and rotated about an axis passing through its centre, parallel to its shorter edges and perpendicular to the field. The maximum flux linked and maximum induced emf are ϕ\phi and E\mathrm{E} respectively. If the axis is shifted to coincide with one of the shorter edges, then
View answer and explanation
Correct option: D
Maximum flux and induced emf remain ϕ/2\phi / 2 and E\mathrm{E}
The correct answer is D because the maximum flux depends on the area and magnetic field, and the maximum induced emf depends on the rate of change of flux, both of which are halved when the axis shifts.
235 Medium
235 of 276
Application +4 | -1
A circular coil of area 300 cm2300 \mathrm{~cm}^2 and 25 turns rotates about its vertical diameter with an angular speed of 40 s−140 \mathrm{~s}^{-1} in a uniform horizontal magnetic field of magnitude 0.05 T0.05 \mathrm{~T}. Obtain the maximum voltage induced in the coil.
View answer and explanation
Correct option: C
1.5 V1.5 \mathrm{~V}
Option C (1.5 V1.5 \mathrm{~V}) is correct because the maximum induced voltage is given by ε0=NBAω\varepsilon_0 = NBA\omega, where NN is the number of turns, BB is the magnetic field, AA is the area, and ω\omega is the angular speed.
236 Medium
236 of 276
Application +4 | -1
If a coil of 40\mathrm{40} turns and area 4.0  cm2\mathrm{4}\mathrm{.0}\,\,\mathrm{c}{\mathrm{m}^\mathrm{2}} is suddenly removed from a magnetic field, it is observed that a charge of 2.0  ×10−4  C2.0\,\, \times {10^{ - 4}}\,\,\mathrm{C} flows into the coil. If the resistance of the coil is 80  Ω\mathrm{80}\,\,\mathrm{\Omega }, the magnetic flux density in Wbm−2\mathrm{Wb}{\mathrm{m}^{ - 2}} is
View answer and explanation
Correct option: B
1
Option B (1) is correct because the magnetic flux density is calculated using the formula relating induced charge, number of turns, resistance, and area.
237 Medium
237 of 276
Application +4 | -1
An inductor coil stores 32 J32 \mathrm{~J} of magnetic field energy and dissipates energy as heat at the rate 320 W320 \mathrm{~W} when a current of 4 A4 \mathrm{~A} is passed through it. The time constant of the circuit when this coil is joined across an ideal battery will be
View answer and explanation
Correct option: A
0.2 s0.2 \mathrm{~s}
Option A (0.2 s) is correct because the time constant is calculated using the inductance and resistance of the coil.
238 Medium
238 of 276
Understanding +4 | -1
The pointer of a dead-beat galvanometer gives a steady deflection because
View answer and explanation
Correct option: A
eddy currents are produced in the conducting frame over which the coil is wound.
Option A (eddy currents are produced in the conducting frame over which the coil is wound) is correct because eddy currents provide electromagnetic damping, causing the pointer to come to rest quickly.
239 Medium
239 of 276
Remembering +4 | -1
Van De graff generator is used to
View answer and explanation
Correct option: A
Create a high potential of range of few million volts
Option A (Create a high potential of range of few million volts) is correct because the Van de Graaff generator is designed to produce very high electrostatic potentials.
240 Medium
240 of 276
Application +4 | -1
A magnetic field is directed into the page and changes with time according to the expression B=(0.03t2+1.4)TB=\left(0.03 t^2+1.4\right) T, where tt is in seconds. The field has a circular cross section of radius RR when t=3.0 s\mathrm{t}=3.0 \mathrm{~s} and r=0.02 m\mathrm{r}=0.02 \mathrm{~m}.
View answer and explanation
Correct option: A
18×10−4N/C18 \times 10^{-4} N / C
Option A (18×10−4N/C18 \times 10^{-4} N / C) is correct because it's the induced electric field at r = 0.02 m when t = 3.0 s, calculated using Faraday's law of induction.
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