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JEE • PHYSICS • ELECTRO MAGNETIC INDUCTION

Electro magnetic induction practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 276 questions

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181 Medium
181 of 276
Understanding +4 | -1
Assertion: Acceleration of a magnet falling through a long solenoid decreases.
Reason: The induced current produced in a circuit always flow in such direction that it opposes the change to the cause that produced it.
View answer and explanation
Correct option: A
Assertion is correct, reason is correct; reason is a correct explanation for assertion
Option A (Assertion is correct, reason is correct; reason is a correct explanation for assertion) is correct because Lenz's law explains the deceleration of the magnet.
182 Medium
182 of 276
Analyzing +4 | -1
Assertion (A) : Electric field produced by a variable magnetic field can't exert a force on a charged particle.

Reason (R) : This electric field is non-conservative in nature.
View answer and explanation
Correct option: D
If Assertion is false, but the Reason is true.
Option D is correct. The assertion is false because a variable magnetic field produces an electric field that *can* exert a force on a charged particle. The reason is true because this electric field is non-conservative.
183 Medium
183 of 276
Application +4 | -1
A rod of 10 cm10 \mathrm{~cm} length is moving perpendicular to uniform magnetic field of intensity 5×10−4 Wb/m25 \times {10}^{-4} \mathrm{~Wb} / \mathrm{m}^2. If the acceleration of the rod is 5 m/s25 \mathrm{~m} / \mathrm{s}^2 then rate of increase of induced emf is ____
View answer and explanation
Correct option: D
2.5×10−4 Vs−12.5 \times 10^{-4} \mathrm{~Vs}^{-1}
Option D (2.5×10−4 Vs−12.5 \times 10^{-4} \mathrm{~Vs}^{-1}) is correct because it represents the rate of increase of induced emf, calculated using the acceleration of the rod and the magnetic field.
184 Medium
184 of 276
Application +4 | -1
A wheel with 30 metallic spokes each of 0.7 m0.7 \mathrm{~m} long is rotated with a speed of 120 rev/min120 \mathrm{~rev} / \mathrm{min}, in a plane normal to the horizontal component of earth's magnetic field HE\mathrm{H_E} at a place. If HE=0.8 G\mathrm{H_E}=0.8\,G at the place, what is the induced emf between the axle and the rim of the wheel?
Given 1 G=10−4 T1 \mathrm{~G}=10^{-4} \mathrm{~T}
View answer and explanation
Correct option: A
2.46×10−42.46 \times 10^{-4} volt
Option A (2.46×10−42.46 \times 10^{-4} volt) is correct because the induced emf is calculated using the formula E=BπR2vE = B \pi R^2 v, where BB is the magnetic field, RR is the length of the spoke, and vv is the frequency of rotation.
185 Medium
185 of 276
Remembering +4 | -1
Principle of working of AC generator is
View answer and explanation
Correct option: B
Electromagnetic induction
The correct answer is B (Electromagnetic induction) because AC generators operate based on the principle of electromagnetic induction.
186 Medium
186 of 276
Application +4 | -1
The horizontal component of the earth’s magnetic field at a place is 3×10−4  T3 \times {10^{ - 4}}\,\,T and the dip is θ=tan⁡−1(4/3).\mathrm{\theta } = {\tan ^{ - 1}}\left( {4/3} \right). A metal rod of length 0.25 m placed in the north-south position is moved at a constant speed of 10m/s towards the east. The emf induced in the rod will be…….mv
View answer and explanation
Correct option: C
1
Option C (1) is correct because the induced emf is calculated using the vertical component of Earth's magnetic field and the given velocity and length.
187 Medium
187 of 276
Application +4 | -1
In a transformer, the coefficient of mutual inductance between the primary and the secondary coil is 0.2 henry. When the current changes by 5 ampere/second in the primary, the induced e.m.f. in the secondary will be:
View answer and explanation
Correct option: B
1 V1 \mathrm{~V}
Option B (1 V1 \text{ V}) is correct because the induced emf is calculated using the formula e=Mdidte = M \frac{di}{dt}, where M is the mutual inductance and didt\frac{di}{dt} is the rate of change of current.
188 Medium
188 of 276
Application +4 | -1
An e.m.f. of 5  volt5\,\,volt is produced by a self inductance, when the current changes at a steady rate from 3  A3\,\,A to 2  A2\,\,A in 1 milli second\mathrm{1\, milli\,second}. The value of self inductance is
View answer and explanation
Correct option: D
5  mH5\,\,mH
Option D (5,mH5\\,\text{{mH}}) is correct because it is calculated directly from the formula relating induced EMF to self-inductance and rate of change of current.
189 Medium
189 of 276
Understanding +4 | -1
Assertion: Electric force and magnetic force are jointly called electromagnetic force.
Reason: Electric and magnetic effects are inseparable.
View answer and explanation
Correct option: A
Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
Option A (Both Assertion and Reason are correct and Reason is the correct explanation of Assertion) is correct because moving charges create magnetic fields, making electric and magnetic effects inseparable and justifying the term electromagnetic force.
190 Medium
190 of 276
Understanding +4 | -1
If 'N\mathrm{N}' is the number of turns in a circular coil, the value of its self inductance varies as
View answer and explanation
Correct option: C
N2\mathrm{N}^2
Option C (N2\mathrm{N}^2) is correct because the self-inductance of a coil is directly proportional to the square of the number of turns.
191 Medium
191 of 276
Understanding +4 | -1
Electromotive force is the force which is able to maintain a constant
View answer and explanation
Correct option: A
potential difference
Option A (potential difference) is correct because electromotive force (EMF) is the energy per unit charge provided by a source to maintain a potential difference.
192 Medium
192 of 276
Application +4 | -1
An emf of 0.5 V0.5 \mathrm{~V} is developed in the secondary coil, when current in primary coil changes from 5.0 A5.0 \mathrm{~A} to 2.0 A2.0 \mathrm{~A} in 300 millisecond. Calculate the mutual inductance of the two coils.
View answer and explanation
Correct option: A
0.05 H0.05 \mathrm{~H}
Option A (0.05 H) is correct because it is calculated using the formula for induced emf in terms of mutual inductance.
193 Medium
193 of 276
Remembering +4 | -1
The net magnetic flux through any closed surface, kept in a magnetic field is
View answer and explanation
Correct option: A
Zero
Option A (Zero) is correct because Gauss's law for magnetism states that the net magnetic flux through any closed surface is always zero, reflecting the fact that magnetic monopoles do not exist.
194 Medium
194 of 276
Understanding +4 | -1
If coil is open then LL and RR become
View answer and explanation
Correct option: B
0,∞0,\infty
Option B (0,∞0,\infty) is correct because an open coil has no inductance (L=0) and infinite resistance (R=∞\infty).
195 Medium
195 of 276
Application +4 | -1
When the number of turns and the length of the solenoid are doubled keeping the area of cross-section same, the inductance
View answer and explanation
Correct option: C
Is doubled
Option C (Is doubled) is correct because the inductance is proportional to the square of the number of turns and inversely proportional to the length.
196 Medium
196 of 276
Understanding +4 | -1
Whenever a magnet is moved either towards or away from a conducting coil, an emf is induced, the magnitude of which is independent of
View answer and explanation
Correct option: D
The resistance of the coil
Option D (The resistance of the coil) is correct because the induced EMF depends on the rate of change of magnetic flux, the number of turns, and the strength/speed of the magnet, but not the coil's resistance.
197 Medium
197 of 276
Understanding +4 | -1
When a wire loop is rotated in a magnetic field, the direction of induced e.m.f. changes one in each
View answer and explanation
Correct option: B
1/2\mathrm{1/2} revolution
Option B is correct because the induced emf changes direction every half revolution in a rotating loop within a magnetic field.
198 Medium
198 of 276
Remembering +4 | -1
Induction furnace uses ……… to produce heat.
View answer and explanation
Correct option: A
Eddy current
Option A (Eddy current) is correct because induction furnaces use eddy currents generated within the metal to produce heat through resistive losses.
199 Medium
199 of 276
Remembering +4 | -1
The electromagnetic force induced in coil is given by
View answer and explanation
Correct option: B
Faraday’s law
Option B (Faraday’s law) is correct because Faraday's law describes the relationship between a changing magnetic field and the induced electromagnetic force (EMF) in a coil.
200 Medium
200 of 276
Remembering +4 | -1
The direction of induced current in a conductor when moved in a magnetic field can be determined by
View answer and explanation
Correct option: C
Fleming’s right hand rule
Option C (Fleming’s right hand rule) is correct because Fleming's right-hand rule is used to determine the direction of induced current in a conductor moving in a magnetic field.
201 Medium
201 of 276
Understanding +4 | -1
A bar magnet is released from rest along the axis of a very long vertical copper tube. After some time the magnet will
View answer and explanation
Correct option: C
move down with almost constant speed
Option C is correct because as the magnet falls, it induces eddy currents in the copper tube, which oppose the magnet's motion, eventually leading to a nearly constant terminal speed.
202 Medium
202 of 276
Application +4 | -1
Self-inductance of two coils is 2H&8H2 \mathrm{H} \& 8 \mathrm{H}. If 50%50 \% flux of primary coil is linked with secondary coil, then find coefficient of mutual inductance.
View answer and explanation
Correct option: A
2 H2 \mathrm{~H}
Option A (2 H) is correct because the mutual inductance is calculated using the formula M = k*sqrt(L1*L2), where k is the coupling coefficient.
203 Medium
203 of 276
Application +4 | -1
If the current 3.0 A3.0 \mathrm{~A} flowing in the primary coil is made zero in 0.1 sec0.1 \mathrm{~sec}, the emf induced in the secondary coil is 1.51.5 volt. The mutual inductance between the coils is
View answer and explanation
Correct option: A
0.05 H0.05 \mathrm{~H}
Option A (0.05 H0.05 \mathrm{~H}) is correct because it is calculated using the formula for induced emf in terms of mutual inductance.
204 Medium
204 of 276
Application +4 | -1
The magnetic flux ϕ\phi (in weber) linked with a coil of resistance 10Ω10 \Omega varies with time tt (in second) as ϕ=8t2−4t+1\phi=8 {t}^2-4 t+1. The current induced in the coil at t=0.1 sect=0.1 \mathrm{~sec} is
View answer and explanation
Correct option: B
0.24 A0.24 \mathrm{~A}
Option B (0.24 A0.24 \mathrm{~A}) is correct because it is the induced current calculated using Faraday's law and Ohm's law at t=0.1 sect=0.1 \mathrm{~sec}.
205 Medium
205 of 276
Application +4 | -1
In a region at a distance rr from zz-axis, magnetic field B⃗=B0rtk^\vec{B}=B_0 r t \hat{k} is present where B0B_0 is constant and tt is time. Then the magnitude of induced electric field at a distance rr from zz-axis is given by
View answer and explanation
Correct option: C
r23B0\frac{r^2}{3} B_0
Option D (None) is correct because the magnitude of the induced electric field is B0r23\frac{{B_0 r^2}}{3}.
206 Medium
206 of 276
Application +4 | -1
The magnetic flux linked with a coil of resistance 2   Ω2\,\,\,\Omega at any instant is given by ϕ=5t2−10t+50   weber.\phi = 5{t^2} - 10t + 50\,\,\,{\text{weber}}. The emf in the coil at t=2   secondst = 2\,\,\,{\text{seconds}} is
View answer and explanation
Correct option: A
–10 volt
Option A (–10 volt) is correct because it is the value of the induced emf calculated by differentiating the magnetic flux with respect to time and evaluating at t = 2 seconds.
207 Medium
207 of 276
Application +4 | -1
A square loop of wire, side length 10  cm\mathrm{10}\,\,\mathrm{cm} is placed at angle of 45∘\mathrm{45}^\circ with a magnetic field that changes uniformly from 0.1T\mathrm{0}\mathrm{.1 T} to zero in 0.7s\mathrm{0}\mathrm{.7 s}. The induced current in the loop (its resistance is 1  Ω)\mathrm{1}\,\,\mathrm{\Omega }) is
View answer and explanation
Correct option: A
1.0  mA\mathrm{1}.\mathrm{0}\,\,\mathrm{mA}
Option A (1.0  mA\mathrm{1}.\mathrm{0}\,\,\mathrm{mA}) is correct because the induced current is calculated using Faraday's law and Ohm's law, considering the change in magnetic flux.
208 Medium
208 of 276
Application +4 | -1
For a current carrying inductor, emf associated is 20 mV20 \mathrm{~m} \mathrm{V}. Now, current through it changes from 6 A6 \mathrm{~A} to 2 A2 \mathrm{~A} in 2 s2 \mathrm{~s}. The coefficient of mutual inductance is
View answer and explanation
Correct option: B
10 mH10 \mathrm{~mH}
Option B (10 mH10 \mathrm{~mH}) is correct because the mutual inductance is calculated using the formula ε=MΔIΔt\varepsilon = M \frac{\Delta I}{\Delta t}.
209 Medium
209 of 276
Understanding +4 | -1
Assertion: Eddy currents are produced in any metallic conductor when magnetic flux is changed around it.

Reason: Electric potential determines the flow of charge.
View answer and explanation
Correct option: B
Both Assertion and Reason are true and Reason is not the correct explanation of Assertion
Option B is correct because both the assertion and the reason are true, but the reason does not explain why eddy currents are produced.
210 Medium
210 of 276
Understanding +4 | -1
If magnetic monopoles exists then Gauss's law in magnetism can be written as
View answer and explanation
Correct option: B
∮B⃗⋅ds‾=μ0⋅mnet\oint \vec{B} \cdot \overline{d s}=\mu_0 \cdot m_{ {net }}
Option B is correct because Gauss's law for magnetism would include a term for the net magnetic monopole charge if monopoles existed.
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