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JEE • PHYSICS • ELECTRO MAGNETIC INDUCTION

Electro magnetic induction practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 151-180 of 276 questions

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151 Medium
151 of 276
Remembering +4 | -1
Lenz’s law is statement of
View answer and explanation
Correct option: C
Law of conservation of energy
Option C (Law of conservation of energy) is correct because Lenz's law is a direct consequence of the conservation of energy in electromagnetic induction.
152 Medium
152 of 276
Understanding +4 | -1
In a dc motor, induced e.m.f. will be maximum
View answer and explanation
Correct option: A
When motor takes maximum speed
Option A (When motor takes maximum speed) is correct because the induced EMF (back EMF) in a DC motor is directly proportional to its speed.
153 Medium
153 of 276
Understanding +4 | -1
The dimensions of self inductance are
View answer and explanation
Correct option: C
[ML2 T−2 A−2]\left[\mathrm{ML}^2 \mathrm{~T}^{-2} \mathrm{~A}^{-2}\right]
Option C (ML2 T−2 A−2\mathrm{ML}^2 \mathrm{~T}^{-2} \mathrm{~A}^{-2}) is correct because the dimensions of self-inductance can be derived from the energy stored in an inductor, U=(1/2)LI2U = (1/2)LI^2, where L is self-inductance and I is current.
154 Medium
154 of 276
Application +4 | -1
A wire of length 2.5 km2.5 \mathrm{~km} and resistance 35Ω35 \Omega has fallen from a height of 10 m10 \mathrm{~m} in earth's horizontal field of 2×10−5 T.2 \times 10^{-5} \mathrm{~T}. The current through the wire is
View answer and explanation
Correct option: C
0.02 A0.02 \mathrm{~A}
Option C (0.02 A) is correct because it is calculated using the induced EMF in the wire as it falls through the Earth's magnetic field.
155 Medium
155 of 276
Understanding +4 | -1
Energy associated with a moving charge is due to
View answer and explanation
Correct option: C
Both (a) and (b)
Option C is correct because a moving charge creates both an electric and a magnetic field, and energy is associated with both fields.
156 Medium
156 of 276
Understanding +4 | -1
Use of eddy currents is done in the following expect
View answer and explanation
Correct option: D
dynamo
The correct answer is D (dynamo) because dynamos primarily rely on Faraday's law of induction and do not intentionally utilize eddy currents.
157 Medium
157 of 276
Understanding +4 | -1
We can reduce eddy currents in the core of the transformer
View answer and explanation
Correct option: D
By taking laminated core
Option D (By taking laminated core) is correct because lamination increases the resistance to eddy current flow.
158 Medium
158 of 276
Application +4 | -1
The inductance of a coil is L=10  HL = 10\,\,\mathrm{H} and resistance R=5  ΩR = 5\,\,\mathrm{\Omega }. If applied voltage of battery is 10V\mathrm{10 V} and it switches off in 1 milli second\mathrm{1 \,milli\,second}, find induced emf of inductor
View answer and explanation
Correct option: A
2×104 V2 \times {10^4}\,\mathrm{V}
Option A (2×104 V2 \times {10^4}\,\mathrm{V}) is correct because the induced emf is calculated using the formula e = L(di/dt).
159 Medium
159 of 276
Understanding +4 | -1
Assertion: Induced emf will always occur when ever there is change in magnetic flux.

Reason: Current always induces whenever there is change in magnetic flux.
View answer and explanation
Correct option: C
Assertion is true but reason is false
Option C (Assertion is true but reason is false) is correct because induced EMF occurs with changing magnetic flux, but current only induces in a closed loop.
160 Medium
160 of 276
Remembering +4 | -1
The coupling coefficient of the perfectly coupled coil is:
View answer and explanation
Correct option: B
One
Option B (One) is correct because the coupling coefficient is unity for perfectly coupled coils.
161 Medium
161 of 276
Understanding +4 | -1
Two different loops are concentric and lie in the same plane. The current in the outer loop is clockwise and increasing with time. The induced current in the inner loop then, is
View answer and explanation
Correct option: C
Counter clockwise
Option C (Counter clockwise) is correct because, according to Lenz's law, the induced current opposes the change in magnetic flux, which means it will create a magnetic field pointing out of the page.
162 Medium
162 of 276
Understanding +4 | -1
The average power dissipated in a pure inductance is
View answer and explanation
Correct option: D
Zero
Option D is correct because the average power dissipated in a pure inductor is zero, as the voltage and current are 90 degrees out of phase.
163 Medium
163 of 276
Understanding +4 | -1
Statement I: A flexible wire loop of irregular shape carrying current when placed in a uniform external magnetic field acquires circular shape.

Statement II: Any current carrying loop when placed in external magnetic field tries to acquires minimum energy and hence maximum magnetic flux and for a given perimeter circular shape is having greatest area.
View answer and explanation
Correct option: A
Statement I is true, Statement II is true; Statement II is
the correct explanation for Statement I
Option A is correct because a current loop in a magnetic field tries to minimize energy by maximizing flux, leading to a circular shape for maximum area.
164 Medium
164 of 276
Application +4 | -1
A uniformly wound solenoidal coil of self inductance 1.8×10−41.8 \times {10^{ - 4}} H and resistance 6 Ω is broken up into two identical coils. These identical coils are then connected in parallel across a 12 V battery of negligible resistance. The time constant of the current in the circuit 
View answer and explanation
Correct option: A
3  ×10−5 s 3\; \times {10^{ - 5}}\,s\,
Option A (3×10−5 s 3 \times {10^{ - 5}}\,s\,) is correct because it is the time constant calculated using the parallel combination of the halved inductance and resistance values.
165 Medium
165 of 276
Understanding +4 | -1
Assertion : The coils in the resistance boxes are made by doubling the wire.
Reason :When two coils are wound on each other, the mutual inductance is zero.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because doubling the wire cancels magnetic field effects.
166 Medium
166 of 276
Analyzing +4 | -1
A rectangular, a square, a circular and an elliptical loop, all in the (x−y)\left( {x - y} \right) plane, are moving out of a uniform magnetic field with a constant velocity V⃗=vi⃗\vec V = v\vec i . The magnetic field is directed along the negative zz-axis direction. The induced emfemf, during the passage of these loops, out of the field region, will not remain constant for
View answer and explanation
Correct option: B
The circular and the elliptical loops
Option B is correct because the induced emf will not remain constant for the circular and elliptical loops due to the changing rate of area leaving the magnetic field.
167 Medium
167 of 276
Understanding +4 | -1
Lenz’s law is a corollary of the law of conservation of
View answer and explanation
Correct option: D
Energy
Option D (Energy) is correct because Lenz's law is a direct consequence of the conservation of energy, ensuring that induced currents oppose the change that produced them.
168 Medium
168 of 276
Understanding +4 | -1
Two pure inductors each of self inductance L\text{L} are connected in series, the net inductance is
View answer and explanation
Correct option: B
2 L\text{2 L}
Option B (2 L) is correct because inductors in series add directly, similar to resistors in series.
169 Medium
169 of 276
Understanding +4 | -1
Three solenoid coils of same dimension, same number of turns and same number of layers of winding are taken. Coil 1\mathrm{1} with inductance L1{L_1} was wound using a Mn\mathrm{Mn} wire of resistance 11  Ωm−1\mathrm{11}\,\,\mathrm{\Omega }{m^{ - 1}};Coil 2\mathrm{2} with inductance L2{L_2} was wound using the similar wire but the direction of winding was reversed in each layer; Coil 3\mathrm{3} with inductance L3{L_3} was wound using a superconducting wire. The self-inductance of the Coils L1,L2,L3{L_1},{L_2},{L_3} are
View answer and explanation
Correct option: C
L1,=L3;L2=0{L_1}, = {L_3};{L_2} = 0
Option C (L1,=L3;L2=0{L_1}, = {L_3};{L_2} = 0) is correct because reversing the winding direction in coil 2 results in zero net flux, and coils 1 and 3 have the same inductance.
170 Medium
170 of 276
Understanding +4 | -1
A square current carrying loop is changed to a circular loop in time t1t_1. Then
View answer and explanation
Correct option: A
emf is induced in loop for time t<t1t < t_1
Option A is correct because an emf is induced only when the area of the loop is changing, which occurs during the time interval t<t1t < t_1.
171 Medium
171 of 276
Understanding +4 | -1
S-I: Induced e.m.f. tries to keep the energy conserved.

S-II: An e.m.f can be induced between the two ends of a straight copper wire when it is moved through a uniform magnetic field.
View answer and explanation
Correct option: A
Both S-I and S-II are correct
Option A (Both S-I and S-II are correct) is correct because induced EMF tries to conserve energy (Lenz's Law), and an EMF is indeed induced in a wire moving through a magnetic field.
172 Medium
172 of 276
Application +4 | -1
A small coil is introduced between the poles of an electromagnet so that its axis coincides with the magnetic field direction. The number of turns is n and the cross sectional area of the coil is AA. When the coil turns through 1800{180^0} about its diameter, the charge flowing through the coil is QQ. The total resistance of the circuit is RR. What is the magnitude of the magnetic induction
View answer and explanation
Correct option: D
QR2nA\frac{{QR}}{{2nA}}
Option A (QRnA\frac{{QR}}{{nA}}) is incorrect. Option B (2QRnA\frac{{2QR}}{{nA}}) is the correct answer because the magnetic induction is derived from Faraday's law of induction and the charge flowing through the coil.
173 Medium
173 of 276
Application +4 | -1
A coil having 500 square loop each of side 10 cm is placed normal to a magnetic flux which increases at the rate of 1.0 tesla/second. The induced e.m.f in volts is
View answer and explanation
Correct option: D
5
Option A (45.59 cal s−145.59 \mathrm{~cal} \mathrm{~s}^{-1}) is correct because it is calculated using Stefan-Boltzmann law considering emissivity and the temperature difference between the ball and the enclosure.
174 Medium
174 of 276
Application +4 | -1
A coil having an inductance of 0.5  H0.5\,\,H carries a current which is uniformly varying from zero to 10  ampere\mathrm{10}\,\,\mathrm{ampere} in 2  second\mathrm{2}\,\,\mathrm{second}. The e.m.f. (in volts) generated in the coil is
View answer and explanation
Correct option: C
2.5
Option C (2.5) is correct because it is calculated using the formula for induced EMF in an inductor.
175 Medium
175 of 276
Application +4 | -1
A coil having an area 2   m22{\mkern 1mu} \,{\mkern 1mu} {m^2} is placed in a magnetic field which changes from 1  wb/m21\,\,wb/{m^2} to 4  wb/m24\,\,wb/{m^2} in an interval of 2 second. The average e.m.f. induced in the coil will be
View answer and explanation
Correct option: B
3 V
Option B (3 V) is correct because the average induced emf is calculated using Faraday's law of induction.
176 Medium
176 of 276
Application +4 | -1
If the current through a coil changes from 1 A1 \mathrm{~A} to 3 A3 \mathrm{~A} in 0.02 s0.02 \mathrm{~s} to produce an emf of 6 V6 \mathrm{~V}, then the self-inductance of the coil is
View answer and explanation
Correct option: B
0.06 H0.06 \mathrm{~H}
Option B (0.06 H) is correct because it is calculated using the formula for self-inductance, E=LdIdtE = L \frac{dI}{dt}.
177 Medium
177 of 276
Application +4 | -1
A boat is moving due east in a region where the earth’s magnetic field is 5.0×10−5  NA−1m−15.0 \times {10^{ - 5}}\,\,\mathrm{N}{\mathrm{A}^{ - 1}}{\mathrm{m}^{ - 1}} due north and horizontal. The boat carries a vertical aerial 1 2 m1{\mkern 1mu} \mathrm{2}\,\mathrm{m} long. If the speed of the boat is 1.50  ms−1\mathrm{1}\mathrm{.50}\,\,\mathrm{m}{\mathrm{s}^{ - 1}}, the magnitude of the induced emf in the wire of aerial is
View answer and explanation
Correct option: C
0.15  mV\mathrm{0}.\mathrm{15}\,\,\mathrm{mV}
Option C (0.15 mV\mathrm{0}.\mathrm{15}\,\mathrm{mV}) is correct because it uses the formula for induced emf in a moving conductor in a magnetic field.
178 Medium
178 of 276
Understanding +4 | -1
As a result of change in the magnetic flux linked to the closed loop shown in the fig, an e.m.f. V volt is induced in the loop. The work done (joule) in taking a charge Q\mathrm{Q} coulomb once along the loop is
View answer and explanation
Correct option: A
QV\mathrm{QV}
Option A (QV) is correct because the work done in moving a charge Q around a closed loop is equal to the charge multiplied by the induced emf.
179 Medium
179 of 276
Analyzing +4 | -1
Two identical coaxial circular loops carry a current ii each circulating in the same direction. As the loops are moved away from each other
View answer and explanation
Correct option: B
The current in each will increase
Option B (The current in each will increase) is correct because as the loops move apart, the decreasing magnetic flux induces an increased current to oppose the change.
180 Medium
180 of 276
Analyzing +4 | -1
An inductor is connected to a battery through a switch induced emf is e1\mathrm{e}_1 when the switch is pressed and e2\mathrm{e}_2 when the switch is opened. Then
View answer and explanation
Correct option: C
e1<e2\mathrm{e}_1 < \mathrm{e}_2
Option C (e1<e2e_1 < e_2) is correct because the induced emf is greater when the switch is opened due to the rapid change in current.
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