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JEE • PHYSICS • ELECTRO MAGNETIC INDUCTION

Electro magnetic induction practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 241-270 of 276 questions
241 Medium
241 of 276
Remembering +4 | -1
The working of a dynamo is based on the principle of
View answer and explanation
Correct option: A
Electromagnetic induction
Option A (Electromagnetic induction) is correct because a dynamo (generator) works by converting mechanical energy into electrical energy through the principle of electromagnetic induction.
242 Medium
242 of 276
Application +4 | -1
A uniform magnetic field BB exists in a direction perpendicular to the plane of a square loop made of a metal wire. The wire has a diameter of 4 mm and a total length of 30 cm. The magnetic field changes with time at a steady rate dB/dt=0.032  Ts−1.\mathrm{d}B/dt = \mathrm{0}\mathrm{.032 \,\,T}{\mathrm{s}^{ - 1}}\mathrm{.} The induced current in the loop is close to (Take, resistivity of the metal wire =1.23×10−8Ωm)= 1.\mathrm{23} \times \mathrm{1}{\mathrm{0}^{ - 8}}\Omega \mathrm{m)}
View answer and explanation
Correct option: A
0.61 A
Option A (0.61 A) is correct because it is the induced current calculated using Faraday's law and Ohm's law, considering the geometry and resistivity of the wire.
243 Medium
243 of 276
Application +4 | -1
Two parallel rails of a railway track insulated from each other and with the ground are connected to a millivoltmeter. The distance between the rails is one metre. A train is travelling with a velocity of 72  kmh−172\,\,km{\mathrm{h}^{ - 1}} along the track. The reading of the millivotmeter (in mV\mathrm{mV}) is : (Vertical component of the earth’s magnetic induction is 2  ×10−5 T)2\,\, \times {10^{ - 5}}\,\mathrm{T})
View answer and explanation
Correct option: C
0.4
Option C (0.4) is correct because the induced emf is calculated using the formula e = Bvl, where B is the vertical component of the Earth's magnetic field, v is the velocity of the train, and l is the distance between the rails.
244 Medium
244 of 276
Understanding +4 | -1
If a coil of metal wire is kept stationary in a non-uniform magnetic field, then
View answer and explanation
Correct option: C
Neither e.m.f. nor current is induced
Option C is correct because a stationary coil in a non-uniform magnetic field experiences no change in magnetic flux, so no emf or current is induced.
245 Medium
245 of 276
Remembering +4 | -1
A conductor of length ll is kept in a magnetic field of strength B\mathrm{B}. A current I\mathrm{I} passes through the conductor. The force experienced by the conductor is proportional to
View answer and explanation
Correct option: D
I\mathrm{I}
Option D (I) is correct because the force experienced by a current-carrying conductor in a magnetic field is directly proportional to the current (F = BILsinθ).
246 Medium
246 of 276
Understanding +4 | -1
Assertion: Faraday's copper disc generator is based on dynamic electromagnetic induction.

Reason: Alternating current generator is based on periodic electromagnetic induction.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C (If Assertion is True but the Reason is False) is correct. Faraday's disc generator is based on dynamic electromagnetic induction, but an AC generator is based on *time-varying* electromagnetic induction, not periodic.
247 Medium
247 of 276
Understanding +4 | -1
A horizontal straight conductor when placed along south-north direction falls under gravity; there is
View answer and explanation
Correct option: C
no induced emf along the length of the conductor
Option C (no induced emf along the length of the conductor) is correct because the conductor is falling vertically, and the Earth's magnetic field lines are primarily horizontal. Therefore, the conductor is not cutting through the magnetic field lines, resulting in no induced emf.
248 Medium
248 of 276
Understanding +4 | -1
Two coils are placed close to each other. The mutual inductance of the pair of coils depends upon
View answer and explanation
Correct option: C
The materials of the wires of the coils
Option B (Relative position and orientation of the two coils) is correct because mutual inductance depends on the geometry and relative placement of the coils, influencing the magnetic flux linkage.
249 Medium
249 of 276
Understanding +4 | -1
Assertion (A) : If some ferromagnetic substance is filled inside a solenoid, its coefficient of self induction LL will increase.

Reason (R) : By increasing the current in a coil, its coefficient of self induction LL can be increased.
View answer and explanation
Correct option: C
If Assertion is true, but the Reason is false.
Option C (If Assertion is true, but the Reason is false) is correct because inserting a ferromagnetic substance increases inductance, but increasing current does not.
250 Medium
250 of 276
Analyzing +4 | -1
Assertion : An emf is induced in long solenoid by a small bar magnet that moves while totally inside it along the solenoid axis.

Reason : As the magnet moves inside the solenoid, the flux through individual turns of the solenoid does not change.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C is correct. An emf is induced, but the flux through individual turns changes as the magnet's field strength varies along the solenoid's axis.
251 Medium
251 of 276
Remembering +4 | -1
Magnetic flux is
View answer and explanation
Correct option: C
Total number of magnetic field lines passing normally through given area
Option C (Total number of magnetic field lines passing normally through given area) is correct because magnetic flux is defined as the measure of the total magnetic field passing through a given area.
252 Medium
252 of 276
Application +4 | -1
A wire of length 50  cm\mathrm{50}\,\,\mathrm{cm} moves with a velocity of 300  m−min−1\mathrm{300}\,\,\mathrm{m - mi}{\mathrm{n}^{\mathrm{ - 1}}}, perpendicular to a magnetic field. If the emf induced in the wire is 2 V\mathrm{2}\,\mathrm{V}, the magnitude of the field in telsa is
View answer and explanation
Correct option: D
0.8
Option D (0.8) is correct because the magnetic field is calculated using the formula for induced EMF in a moving conductor.
253 Medium
253 of 276
Understanding +4 | -1
Choke coil works on the principle of
View answer and explanation
Correct option: B
self induction
Option B is correct because a choke coil works based on the principle of self-induction, which opposes changes in current.
254 Medium
254 of 276
Analyzing +4 | -1
A short magnet is allowed to fall from rest along the axis of a horizontal conducting ring. The distance fallen by the magnet in one second may be
View answer and explanation
Correct option: C
4 m4 \mathrm{~m}
Option C (4 m) is correct. Due to the repulsion from induced effects, the acceleration will be less than g, so the distance fallen will be less than 5m.
255 Medium
255 of 276
Application +4 | -1
A thin circular ring of area A\mathrm{A} is held perpendicular to a uniform magnetic field of induction B. A small cut is made in the ring and a galvanometer is connected across the ends such that the total resistance of the circuit is R\mathrm{R}. When the ring is suddenly squeezed to zero area, the charge flowing through the galvanometer is
View answer and explanation
Correct option: B
ABR\frac{\mathrm{AB}}{\mathrm{R}}
Option B (ABR\frac{\mathrm{AB}}{\mathrm{R}}) is correct because the charge flowing through the galvanometer is equal to the change in magnetic flux divided by the resistance.
256 Medium
256 of 276
Application +4 | -1
The number of turns of primary and secondary coils of a transformer are 5  and 10\mathrm{5}\,\,\mathrm{and}\,\mathrm{10} respectively and the mutual inductance of the transformer is 25  henry25\,\,henry. Now the number of turns in the primary and secondary of the transformer are made 10  and 5\mathrm{10}\,\,\mathrm{and}\,\mathrm{5} respectively. The mutual inductance of the transformer in henryhenry will be
View answer and explanation
Correct option: C
25
Option C (25) is correct because the mutual inductance is proportional to the product of the number of turns in the primary and secondary coils, and the ratio remains constant.
257 Medium
257 of 276
Application +4 | -1
The mutual inductance between two coils is 2.5 H.2.5 \mathrm{~H}. If the current in one coil is changed at the rate of 1 As−1,1 \mathrm{~As}^{-1}, what will be the emf induced in the other coil?
View answer and explanation
Correct option: A
2.5 V2. 5 \mathrm{~V}
Option A (2.5 V2. 5 \mathrm{~V}) is correct because the induced emf is calculated directly using the formula E=MdIdtE = M \frac{dI}{dt}.
258 Medium
258 of 276
Understanding +4 | -1
The mutual inductance between two coils depends upon
View answer and explanation
Correct option: C
Both the medium and the separation
Option C is correct because mutual inductance depends on the geometry of the coils, their separation, and the permeability of the medium between them.
259 Medium
259 of 276
Analyzing +4 | -1
Assertion: At any instant, if the current through an inductor is zero, then the induced emf may not be zero

Reason: An inductor tends to keep the flux (i.e. current) constant
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
Option A is correct because the induced emf depends on the rate of change of current, not the instantaneous current value, and an inductor opposes changes in flux.
260 Medium
260 of 276
Understanding +4 | -1
An induced e.m.f. is produced when a magnet is plunged into a coil. The strength of the induced e.m.f. is independent of
View answer and explanation
Correct option: C
The resistivity of the wire of the coil
Option C (The resistivity of the wire of the coil) is correct because the induced EMF depends on the rate of change of magnetic flux, which is independent of the coil's resistivity.
261 Medium
261 of 276
Understanding +4 | -1
Assertion : The quantity L/R possesses dimension of time.

Reason : To reduce the rate of growth of current through a solenoid, we should increase the time constant (L/R).
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because L/R has the dimension of time and increasing L/R (the time constant) reduces the rate of current growth.
262 Medium
262 of 276
Application +4 | -1
Current in a coil falls from 5.0 A to 1.0 A in 0.1 s. If an average emf of 200 V is induced, then self-inductance of the coil is
View answer and explanation
Correct option: B
5 H
Option B (5 H) is correct because the self-inductance is calculated using the induced emf and the rate of change of current.
263 Medium
263 of 276
Analyzing +4 | -1
The magnetic flux linked with a coil is ϕ\phi and the emf induced in it is e\mathrm{e}
View answer and explanation
Correct option: D
None of the above is correct
Option D (None of the above is correct) is correct because the induced emf depends on the rate of change of magnetic flux, not just the presence or absence of flux.
264 Medium
264 of 276
Remembering +4 | -1
The emf induced in the secondary coil due to unit rate of change of current in the primary is called _______
View answer and explanation
Correct option: C
Mutual induction of two coils
Option C (Mutual induction of two coils) is correct because mutual inductance describes the emf induced in one coil due to a changing current in another.
265 Medium
265 of 276
Understanding +4 | -1
If rotational velocity of a dynamo armature is doubled, then induced e.m.f. will become
View answer and explanation
Correct option: B
Two times
Option B (Two times) is correct because the induced emf in a dynamo is directly proportional to the rotational velocity of the armature.
266 Medium
266 of 276
Application +4 | -1
A circular ring of diameter 20 cm\mathrm{20}\,\mathrm{cm} has a resistance of 0.01  Ω0.01\,\,\mathrm{\Omega }. The charge that will flow through the ring if it is turned from a position perpendicular to a uniform magnetic field of 2.0 T\mathrm{2}.\mathrm{0}\,\mathrm{T} to a position to the field is about
View answer and explanation
Correct option: C
6.3 C\mathrm{6.3}\,\mathrm{C}
Option C (6.3 C\mathrm{6.3}\,\mathrm{C}) is correct because the charge flow is calculated using q=dϕR=BARq = \frac{{d\phi }}{R} = \frac{{BA}}{R}.
267 Medium
267 of 276
Analyzing +4 | -1
A capacitor (without dielectric) is discharging through a resistor. At some instant a dielectric is inserted between the plates, then
View answer and explanation
Correct option: D
After the insertion of the dielectric, time constant will increase
Option D (After the insertion of the dielectric, time constant will increase) is correct because the time constant is directly proportional to the capacitance, which increases with the insertion of a dielectric.
268 Medium
268 of 276
Application +4 | -1
5  cm5\,\,cm long solenoid having 10  ohm10\,\,ohm resistance and 5  mH5\,\,mH inductance is joined to a 10  volt10\,\,volt battery. At steady state the current through the solenoid in ampere will be
View answer and explanation
Correct option: B
1
Option B (1) is correct because at steady state, the inductor acts as a short circuit, and the current is determined only by the resistance.
269 Medium
269 of 276
Application +4 | -1
The current in a coil changes from 0 to 2 A2 \mathrm{~A} in 0.05 s0.05 \mathrm{~s}. If the induced emf is 80 V80 \mathrm{~V}, the self-inductance of the coil is,
View answer and explanation
Correct option: D
2 H2 \mathrm{~H}
The correct answer is 2 H2 \mathrm{~H} because it is calculated using the formula for self-inductance, L=εdIdtL = \frac{\varepsilon}{\frac{dI}{dt}}.
270 Medium
270 of 276
Analyzing +4 | -1
Assertion (A): Only a change in magnetic flux will maintain an induced current in a closed coil.

Reason (R): The presence of large magnetic flux through a coil maintains a current in the coil if the coil is continuous.
View answer and explanation
Correct option: C
Assertion is true but reason is false
Option C is correct. Only a change in magnetic flux induces a current in a closed coil, while the presence of a large magnetic flux doesn't guarantee a current if it's constant.
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