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JEE • PHYSICS • ELECTRO MAGNETIC INDUCTION

Electro magnetic induction practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 295 questions

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211 Medium
211 of 295
Understanding +4 | -1
If coil is open then LL and RR become
View answer and explanation
Correct option: B
0,∞0,\infty
Option B (0,∞0,\infty) is correct because an open coil has no inductance (L=0) and infinite resistance (R=∞\infty).
212 Medium
212 of 295
Application +4 | -1
When the number of turns and the length of the solenoid are doubled keeping the area of cross-section same, the inductance
View answer and explanation
Correct option: C
Is doubled
Option C (Is doubled) is correct because the inductance is proportional to the square of the number of turns and inversely proportional to the length.
213 Medium
213 of 295
Understanding +4 | -1
Whenever a magnet is moved either towards or away from a conducting coil, an emf is induced, the magnitude of which is independent of
View answer and explanation
Correct option: D
The resistance of the coil
Option D (The resistance of the coil) is correct because the induced EMF depends on the rate of change of magnetic flux, the number of turns, and the strength/speed of the magnet, but not the coil's resistance.
214 Medium
214 of 295
Understanding +4 | -1
When a wire loop is rotated in a magnetic field, the direction of induced e.m.f. changes one in each
View answer and explanation
Correct option: B
1/2\mathrm{1/2} revolution
Option B is correct because the induced emf changes direction every half revolution in a rotating loop within a magnetic field.
215 Medium
215 of 295
Remembering +4 | -1
Induction furnace uses ……… to produce heat.
View answer and explanation
Correct option: A
Eddy current
Option A (Eddy current) is correct because induction furnaces use eddy currents generated within the metal to produce heat through resistive losses.
216 Medium
216 of 295
Remembering +4 | -1
The electromagnetic force induced in coil is given by
View answer and explanation
Correct option: B
Faraday’s law
Option B (Faraday’s law) is correct because Faraday's law describes the relationship between a changing magnetic field and the induced electromagnetic force (EMF) in a coil.
217 Medium
217 of 295
Remembering +4 | -1
The direction of induced current in a conductor when moved in a magnetic field can be determined by
View answer and explanation
Correct option: C
Fleming’s right hand rule
Option C (Fleming’s right hand rule) is correct because Fleming's right-hand rule is used to determine the direction of induced current in a conductor moving in a magnetic field.
218 Medium
218 of 295
Understanding +4 | -1
A bar magnet is released from rest along the axis of a very long vertical copper tube. After some time the magnet will
View answer and explanation
Correct option: C
move down with almost constant speed
Option C is correct because as the magnet falls, it induces eddy currents in the copper tube, which oppose the magnet's motion, eventually leading to a nearly constant terminal speed.
219 Medium
219 of 295
Application +4 | -1
Self-inductance of two coils is 2H&8H2 \mathrm{H} \& 8 \mathrm{H}. If 50%50 \% flux of primary coil is linked with secondary coil, then find coefficient of mutual inductance.
View answer and explanation
Correct option: A
2 H2 \mathrm{~H}
Option A (2 H) is correct because the mutual inductance is calculated using the formula M = k*sqrt(L1*L2), where k is the coupling coefficient.
220 Medium
220 of 295
Application +4 | -1
If the current 3.0 A3.0 \mathrm{~A} flowing in the primary coil is made zero in 0.1 sec0.1 \mathrm{~sec}, the emf induced in the secondary coil is 1.51.5 volt. The mutual inductance between the coils is
View answer and explanation
Correct option: A
0.05 H0.05 \mathrm{~H}
Option A (0.05 H0.05 \mathrm{~H}) is correct because it is calculated using the formula for induced emf in terms of mutual inductance.
221 Medium
221 of 295
Application +4 | -1
The magnetic flux ϕ\phi (in weber) linked with a coil of resistance 10Ω10 \Omega varies with time tt (in second) as ϕ=8t2−4t+1\phi=8 {t}^2-4 t+1. The current induced in the coil at t=0.1 sect=0.1 \mathrm{~sec} is
View answer and explanation
Correct option: B
0.24 A0.24 \mathrm{~A}
Option B (0.24 A0.24 \mathrm{~A}) is correct because it is the induced current calculated using Faraday's law and Ohm's law at t=0.1 sect=0.1 \mathrm{~sec}.
222 Medium
222 of 295
Application +4 | -1
In a region at a distance rr from zz-axis, magnetic field B⃗=B0rtk^\vec{B}=B_0 r t \hat{k} is present where B0B_0 is constant and tt is time. Then the magnitude of induced electric field at a distance rr from zz-axis is given by
View answer and explanation
Correct option: C
r23B0\frac{r^2}{3} B_0
Option D (None) is correct because the magnitude of the induced electric field is B0r23\frac{{B_0 r^2}}{3}.
223 Medium
223 of 295
Application +4 | -1
The magnetic flux linked with a coil of resistance 2   Ω2\,\,\,\Omega at any instant is given by ϕ=5t2−10t+50   weber.\phi = 5{t^2} - 10t + 50\,\,\,{\text{weber}}. The emf in the coil at t=2   secondst = 2\,\,\,{\text{seconds}} is
View answer and explanation
Correct option: A
–10 volt
Option A (–10 volt) is correct because it is the value of the induced emf calculated by differentiating the magnetic flux with respect to time and evaluating at t = 2 seconds.
224 Medium
224 of 295
Application +4 | -1
A square loop of wire, side length 10  cm\mathrm{10}\,\,\mathrm{cm} is placed at angle of 45∘\mathrm{45}^\circ with a magnetic field that changes uniformly from 0.1T\mathrm{0}\mathrm{.1 T} to zero in 0.7s\mathrm{0}\mathrm{.7 s}. The induced current in the loop (its resistance is 1  Ω)\mathrm{1}\,\,\mathrm{\Omega }) is
View answer and explanation
Correct option: A
1.0  mA\mathrm{1}.\mathrm{0}\,\,\mathrm{mA}
Option A (1.0  mA\mathrm{1}.\mathrm{0}\,\,\mathrm{mA}) is correct because the induced current is calculated using Faraday's law and Ohm's law, considering the change in magnetic flux.
225 Medium
225 of 295
Application +4 | -1
For a current carrying inductor, emf associated is 20 mV20 \mathrm{~m} \mathrm{V}. Now, current through it changes from 6 A6 \mathrm{~A} to 2 A2 \mathrm{~A} in 2 s2 \mathrm{~s}. The coefficient of mutual inductance is
View answer and explanation
Correct option: B
10 mH10 \mathrm{~mH}
Option B (10 mH10 \mathrm{~mH}) is correct because the mutual inductance is calculated using the formula ε=MΔIΔt\varepsilon = M \frac{\Delta I}{\Delta t}.
226 Medium
226 of 295
Understanding +4 | -1
Assertion: Eddy currents are produced in any metallic conductor when magnetic flux is changed around it.

Reason: Electric potential determines the flow of charge.
View answer and explanation
Correct option: B
Both Assertion and Reason are true and Reason is not the correct explanation of Assertion
Option B is correct because both the assertion and the reason are true, but the reason does not explain why eddy currents are produced.
227 Medium
227 of 295
Understanding +4 | -1
If magnetic monopoles exists then Gauss's law in magnetism can be written as
View answer and explanation
Correct option: B
∮B⃗⋅ds‾=μ0⋅mnet\oint \vec{B} \cdot \overline{d s}=\mu_0 \cdot m_{ {net }}
Option B is correct because Gauss's law for magnetism would include a term for the net magnetic monopole charge if monopoles existed.
228 Medium
228 of 295
Remembering +4 | -1
Mutual inductance of a pair of coils, depend
on
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because mutual inductance depends on the separation, relative orientation, and geometric dimensions of the coils.
229 Medium
229 of 295
Application +4 | -1
Two cells of emf 1.25 V, 0.75 V and each of internal resistance 1 Ω1\,\Omega are connected in parallel. The effective emf will be
View answer and explanation
Correct option: A
1 Volt
Option A (1 Volt) is correct because it is the effective EMF calculated from the parallel combination of the two cells.
230 Medium
230 of 295
Analyzing +4 | -1
Assertion : The mutual inductance of two coils is doubled if the self inductance of the primary
or secondary coil is doubled.

Reason : Mutual inductance is proportional to the self inductance of primary and secondary
coils.
View answer and explanation
Correct option: C
If Assertion is True but the reason is false
Option C (If Assertion is True but the reason is false) is correct because while doubling self-inductance does double mutual inductance, the reason provided is not entirely accurate.
231 Easy
231 of 295
Analyzing +4 | -1
Statement I: No current is induced in a metal loop if it is rotated in an electric field.

Statement II: The electric flux through the loop does not change with time.
View answer and explanation
Correct option: C
Statement I is true; Statement II is false
Option C (Statement I is true; Statement II is false) is correct because no current is induced in a metal loop rotated in an electric field, but the electric flux does change with time.
232 Medium
232 of 295
Application +4 | -1
An emf is 15 V is applied in a circuit coil containing 5 H inductance and 10 Ω resistance. The ratio of currents at time t=∞t = \infty and t=1 s is
View answer and explanation
Correct option: B
e2e2−1\frac{{{e^2}}}{{{e^2} - 1}}
Option B is correct because the ratio of currents is derived from the inductor current equation at t=infinity and t=1s.
233 Medium
233 of 295
Understanding +4 | -1
An infinitely cylinder is kept parallel to an uniform magnetic field BB directed along positive zz axis. This direction of induced current as seen from the zz axis will be
View answer and explanation
Correct option: C
Zero
The correct answer is C (Zero) because in a uniform magnetic field, the change in magnetic flux is zero, resulting in no induced current.
234 Medium
234 of 295
Remembering +4 | -1
The induction coil works on the principle of
View answer and explanation
Correct option: B
Mutual induction
Option B (Mutual induction) is correct because induction coils use two coils to transfer energy through a changing magnetic field.
235 Medium
235 of 295
Understanding +4 | -1
Consider the following statements.

(a) Eddy current loss is minimized by using laminated cores.

(b) Self-inductance is called inertia of electricity.

Choose the correct statements:
View answer and explanation
Correct option: C
Both a and b
Option C (Both a and b) is correct because laminated cores minimize eddy current loss, and self-inductance is analogous to inertia in electricity.
236 Medium
236 of 295
Understanding +4 | -1
Fleming’s left and right hand rule are used in
View answer and explanation
Correct option: C
DC motor and DC generator
Option C (DC motor and DC generator) is correct because Fleming's left-hand rule is used for DC motors, and Fleming's right-hand rule is used for DC generators.
237 Medium
237 of 295
Analyzing +4 | -1
Assertion: When a conducting rod moves in uniform transverse magnetic field with uniform speed which is perpendicular to its length, then potential difference may develop across its ends.

Reason: In any conductor, free electrons and free positive ions are available.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
The correct answer is C because while the assertion about potential difference developing is true, the reason provided is false; the presence of free electrons is relevant, but free positive ions are not.
238 Medium
238 of 295
Understanding +4 | -1
A particle mass m, charge Q and kinetic
energy T enters a transverse uniform
magnetic field of induction B after 3s the
kinetic energy of the particle will be
View answer and explanation
Correct option: C
T
Option C (T) is correct because the magnetic force does no work on the charged particle, so its kinetic energy remains constant.
239 Medium
239 of 295
Application +4 | -1
In a magnetic field of 0.05  T0.05\,\,T, area of a coil changes from 101  cm2101\,\,c{m^2} to 100  cm2100\,\,c{m^2} without changing the resistance which is 2  Ω2\,\,\mathrm{\Omega }. The amount of charge that flow during this period is
View answer and explanation
Correct option: A
2.5  ×10−6 coulomb2.5\,\, \times {10^{ - 6}}\,coulomb
Option A (2.5×10−6 coulomb2.5 \times {10^{ - 6}}\,coulomb) is correct because it is calculated using the change in magnetic flux and the resistance of the coil.
240 Medium
240 of 295
Application +4 | -1
Current in a circuit falls from 5.0 A to 0 A in 0.1 s. If an average emf of 200 V is induced, estimate the self-inductance of the circuit
View answer and explanation
Correct option: C
4H
Option C (4H) is correct because the self-inductance is calculated using the induced emf and the rate of change of current.
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