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JEE • PHYSICS • ELECTRO MAGNETIC INDUCTION

Electro magnetic induction practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 295 questions

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181 Medium
181 of 295
Understanding +4 | -1
Assertion : The coils in the resistance boxes are made by doubling the wire.
Reason :When two coils are wound on each other, the mutual inductance is zero.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because doubling the wire cancels magnetic field effects.
182 Medium
182 of 295
Analyzing +4 | -1
A rectangular, a square, a circular and an elliptical loop, all in the (x−y)\left( {x - y} \right) plane, are moving out of a uniform magnetic field with a constant velocity V⃗=vi⃗\vec V = v\vec i . The magnetic field is directed along the negative zz-axis direction. The induced emfemf, during the passage of these loops, out of the field region, will not remain constant for
View answer and explanation
Correct option: B
The circular and the elliptical loops
Option B is correct because the induced emf will not remain constant for the circular and elliptical loops due to the changing rate of area leaving the magnetic field.
183 Medium
183 of 295
Understanding +4 | -1
Lenz’s law is a corollary of the law of conservation of
View answer and explanation
Correct option: D
Energy
Option D (Energy) is correct because Lenz's law is a direct consequence of the conservation of energy, ensuring that induced currents oppose the change that produced them.
184 Medium
184 of 295
Understanding +4 | -1
Two pure inductors each of self inductance L\text{L} are connected in series, the net inductance is
View answer and explanation
Correct option: B
2 L\text{2 L}
Option B (2 L) is correct because inductors in series add directly, similar to resistors in series.
185 Medium
185 of 295
Understanding +4 | -1
Three solenoid coils of same dimension, same number of turns and same number of layers of winding are taken. Coil 1\mathrm{1} with inductance L1{L_1} was wound using a Mn\mathrm{Mn} wire of resistance 11  Ωm−1\mathrm{11}\,\,\mathrm{\Omega }{m^{ - 1}};Coil 2\mathrm{2} with inductance L2{L_2} was wound using the similar wire but the direction of winding was reversed in each layer; Coil 3\mathrm{3} with inductance L3{L_3} was wound using a superconducting wire. The self-inductance of the Coils L1,L2,L3{L_1},{L_2},{L_3} are
View answer and explanation
Correct option: C
L1,=L3;L2=0{L_1}, = {L_3};{L_2} = 0
Option C (L1,=L3;L2=0{L_1}, = {L_3};{L_2} = 0) is correct because reversing the winding direction in coil 2 results in zero net flux, and coils 1 and 3 have the same inductance.
186 Medium
186 of 295
Understanding +4 | -1
A square current carrying loop is changed to a circular loop in time t1t_1. Then
View answer and explanation
Correct option: A
emf is induced in loop for time t<t1t < t_1
Option A is correct because an emf is induced only when the area of the loop is changing, which occurs during the time interval t<t1t < t_1.
187 Medium
187 of 295
Understanding +4 | -1
S-I: Induced e.m.f. tries to keep the energy conserved.

S-II: An e.m.f can be induced between the two ends of a straight copper wire when it is moved through a uniform magnetic field.
View answer and explanation
Correct option: A
Both S-I and S-II are correct
Option A (Both S-I and S-II are correct) is correct because induced EMF tries to conserve energy (Lenz's Law), and an EMF is indeed induced in a wire moving through a magnetic field.
188 Medium
188 of 295
Application +4 | -1
A small coil is introduced between the poles of an electromagnet so that its axis coincides with the magnetic field direction. The number of turns is n and the cross sectional area of the coil is AA. When the coil turns through 1800{180^0} about its diameter, the charge flowing through the coil is QQ. The total resistance of the circuit is RR. What is the magnitude of the magnetic induction
View answer and explanation
Correct option: D
QR2nA\frac{{QR}}{{2nA}}
Option A (QRnA\frac{{QR}}{{nA}}) is incorrect. Option B (2QRnA\frac{{2QR}}{{nA}}) is the correct answer because the magnetic induction is derived from Faraday's law of induction and the charge flowing through the coil.
189 Medium
189 of 295
Application +4 | -1
A coil having 500 square loop each of side 10 cm is placed normal to a magnetic flux which increases at the rate of 1.0 tesla/second. The induced e.m.f in volts is
View answer and explanation
Correct option: D
5
Option A (45.59 cal s−145.59 \mathrm{~cal} \mathrm{~s}^{-1}) is correct because it is calculated using Stefan-Boltzmann law considering emissivity and the temperature difference between the ball and the enclosure.
190 Medium
190 of 295
Application +4 | -1
A coil having an inductance of 0.5  H0.5\,\,H carries a current which is uniformly varying from zero to 10  ampere\mathrm{10}\,\,\mathrm{ampere} in 2  second\mathrm{2}\,\,\mathrm{second}. The e.m.f. (in volts) generated in the coil is
View answer and explanation
Correct option: C
2.5
Option C (2.5) is correct because it is calculated using the formula for induced EMF in an inductor.
191 Medium
191 of 295
Application +4 | -1
A coil having an area 2   m22{\mkern 1mu} \,{\mkern 1mu} {m^2} is placed in a magnetic field which changes from 1  wb/m21\,\,wb/{m^2} to 4  wb/m24\,\,wb/{m^2} in an interval of 2 second. The average e.m.f. induced in the coil will be
View answer and explanation
Correct option: B
3 V
Option B (3 V) is correct because the average induced emf is calculated using Faraday's law of induction.
192 Medium
192 of 295
Application +4 | -1
If the current through a coil changes from 1 A1 \mathrm{~A} to 3 A3 \mathrm{~A} in 0.02 s0.02 \mathrm{~s} to produce an emf of 6 V6 \mathrm{~V}, then the self-inductance of the coil is
View answer and explanation
Correct option: B
0.06 H0.06 \mathrm{~H}
Option B (0.06 H) is correct because it is calculated using the formula for self-inductance, E=LdIdtE = L \frac{dI}{dt}.
193 Medium
193 of 295
Application +4 | -1
A boat is moving due east in a region where the earth’s magnetic field is 5.0×10−5  NA−1m−15.0 \times {10^{ - 5}}\,\,\mathrm{N}{\mathrm{A}^{ - 1}}{\mathrm{m}^{ - 1}} due north and horizontal. The boat carries a vertical aerial 1 2 m1{\mkern 1mu} \mathrm{2}\,\mathrm{m} long. If the speed of the boat is 1.50  ms−1\mathrm{1}\mathrm{.50}\,\,\mathrm{m}{\mathrm{s}^{ - 1}}, the magnitude of the induced emf in the wire of aerial is
View answer and explanation
Correct option: C
0.15  mV\mathrm{0}.\mathrm{15}\,\,\mathrm{mV}
Option C (0.15 mV\mathrm{0}.\mathrm{15}\,\mathrm{mV}) is correct because it uses the formula for induced emf in a moving conductor in a magnetic field.
194 Medium
194 of 295
Understanding +4 | -1
As a result of change in the magnetic flux linked to the closed loop shown in the fig, an e.m.f. V volt is induced in the loop. The work done (joule) in taking a charge Q\mathrm{Q} coulomb once along the loop is
View answer and explanation
Correct option: A
QV\mathrm{QV}
Option A (QV) is correct because the work done in moving a charge Q around a closed loop is equal to the charge multiplied by the induced emf.
195 Medium
195 of 295
Analyzing +4 | -1
Two identical coaxial circular loops carry a current ii each circulating in the same direction. As the loops are moved away from each other
View answer and explanation
Correct option: B
The current in each will increase
Option B (The current in each will increase) is correct because as the loops move apart, the decreasing magnetic flux induces an increased current to oppose the change.
196 Medium
196 of 295
Analyzing +4 | -1
An inductor is connected to a battery through a switch induced emf is e1\mathrm{e}_1 when the switch is pressed and e2\mathrm{e}_2 when the switch is opened. Then
View answer and explanation
Correct option: C
e1<e2\mathrm{e}_1 < \mathrm{e}_2
Option C (e1<e2e_1 < e_2) is correct because the induced emf is greater when the switch is opened due to the rapid change in current.
197 Medium
197 of 295
Understanding +4 | -1
Assertion: Acceleration of a magnet falling through a long solenoid decreases.
Reason: The induced current produced in a circuit always flow in such direction that it opposes the change to the cause that produced it.
View answer and explanation
Correct option: A
Assertion is correct, reason is correct; reason is a correct explanation for assertion
Option A (Assertion is correct, reason is correct; reason is a correct explanation for assertion) is correct because Lenz's law explains the deceleration of the magnet.
198 Medium
198 of 295
Analyzing +4 | -1
Assertion (A) : Electric field produced by a variable magnetic field can't exert a force on a charged particle.

Reason (R) : This electric field is non-conservative in nature.
View answer and explanation
Correct option: D
If Assertion is false, but the Reason is true.
Option D is correct. The assertion is false because a variable magnetic field produces an electric field that *can* exert a force on a charged particle. The reason is true because this electric field is non-conservative.
199 Medium
199 of 295
Application +4 | -1
A rod of 10 cm10 \mathrm{~cm} length is moving perpendicular to uniform magnetic field of intensity 5×10−4 Wb/m25 \times {10}^{-4} \mathrm{~Wb} / \mathrm{m}^2. If the acceleration of the rod is 5 m/s25 \mathrm{~m} / \mathrm{s}^2 then rate of increase of induced emf is ____
View answer and explanation
Correct option: D
2.5×10−4 Vs−12.5 \times 10^{-4} \mathrm{~Vs}^{-1}
Option D (2.5×10−4 Vs−12.5 \times 10^{-4} \mathrm{~Vs}^{-1}) is correct because it represents the rate of increase of induced emf, calculated using the acceleration of the rod and the magnetic field.
200 Medium
200 of 295
Application +4 | -1
A wheel with 30 metallic spokes each of 0.7 m0.7 \mathrm{~m} long is rotated with a speed of 120 rev/min120 \mathrm{~rev} / \mathrm{min}, in a plane normal to the horizontal component of earth's magnetic field HE\mathrm{H_E} at a place. If HE=0.8 G\mathrm{H_E}=0.8\,G at the place, what is the induced emf between the axle and the rim of the wheel?
Given 1 G=10−4 T1 \mathrm{~G}=10^{-4} \mathrm{~T}
View answer and explanation
Correct option: A
2.46×10−42.46 \times 10^{-4} volt
Option A (2.46×10−42.46 \times 10^{-4} volt) is correct because the induced emf is calculated using the formula E=BπR2vE = B \pi R^2 v, where BB is the magnetic field, RR is the length of the spoke, and vv is the frequency of rotation.
201 Medium
201 of 295
Remembering +4 | -1
Principle of working of AC generator is
View answer and explanation
Correct option: B
Electromagnetic induction
The correct answer is B (Electromagnetic induction) because AC generators operate based on the principle of electromagnetic induction.
202 Medium
202 of 295
Application +4 | -1
The horizontal component of the earth&rsquo;s magnetic field at a place is&nbsp;3×10−4  T3 \times {10^{ - 4}}\,\,T and the dip is θ=tan⁡−1(4/3).\mathrm{\theta } = {\tan ^{ - 1}}\left( {4/3} \right). A metal rod of length 0.25 m placed in the north-south position is moved at a constant speed of 10m/s towards the east. The emf induced in the rod will be&hellip;&hellip;.mv
View answer and explanation
Correct option: C
1
Option C (1) is correct because the induced emf is calculated using the vertical component of Earth's magnetic field and the given velocity and length.
203 Medium
203 of 295
Application +4 | -1
In a transformer, the coefficient of mutual inductance between the primary and the secondary coil is 0.2 henry. When the current changes by 5 ampere/second in the primary, the induced e.m.f. in the secondary will be:
View answer and explanation
Correct option: B
1 V1 \mathrm{~V}
Option B (1 V1 \text{ V}) is correct because the induced emf is calculated using the formula e=Mdidte = M \frac{di}{dt}, where M is the mutual inductance and didt\frac{di}{dt} is the rate of change of current.
204 Medium
204 of 295
Application +4 | -1
An e.m.f. of 5  volt5\,\,volt is produced by a self inductance, when the current changes at a steady rate from 3  A3\,\,A to 2  A2\,\,A in 1 milli second\mathrm{1\, milli\,second}. The value of self inductance is
View answer and explanation
Correct option: D
5  mH5\,\,mH
Option D (5,mH5\\,\text{{mH}}) is correct because it is calculated directly from the formula relating induced EMF to self-inductance and rate of change of current.
205 Medium
205 of 295
Understanding +4 | -1
Assertion: Electric force and magnetic force are jointly called electromagnetic force.
Reason: Electric and magnetic effects are inseparable.
View answer and explanation
Correct option: A
Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
Option A (Both Assertion and Reason are correct and Reason is the correct explanation of Assertion) is correct because moving charges create magnetic fields, making electric and magnetic effects inseparable and justifying the term electromagnetic force.
206 Medium
206 of 295
Understanding +4 | -1
If 'N\mathrm{N}' is the number of turns in a circular coil, the value of its self inductance varies as
View answer and explanation
Correct option: C
N2\mathrm{N}^2
Option C (N2\mathrm{N}^2) is correct because the self-inductance of a coil is directly proportional to the square of the number of turns.
207 Medium
207 of 295
Understanding +4 | -1
Electromotive force is the force which is able to maintain a constant
View answer and explanation
Correct option: A
potential difference
Option A (potential difference) is correct because electromotive force (EMF) is the energy per unit charge provided by a source to maintain a potential difference.
208 Medium
208 of 295
Application +4 | -1
An emf of 0.5 V0.5 \mathrm{~V} is developed in the secondary coil, when current in primary coil changes from 5.0 A5.0 \mathrm{~A} to 2.0 A2.0 \mathrm{~A} in 300 millisecond. Calculate the mutual inductance of the two coils.
View answer and explanation
Correct option: A
0.05 H0.05 \mathrm{~H}
Option A (0.05 H) is correct because it is calculated using the formula for induced emf in terms of mutual inductance.
209 Easy
209 of 295
Understanding +4 | -1
When you walk through a metal detector carrying a metal object in your pocket, it raises an alarm. This phenomenon works on:
View answer and explanation
Correct option: B
Resonance in ac circuits
Option B (Resonance in ac circuits) is correct because metal detectors utilize the principle of resonance in AC circuits to detect the presence of metal objects.
210 Medium
210 of 295
Remembering +4 | -1
The net magnetic flux through any closed surface, kept in a magnetic field is
View answer and explanation
Correct option: A
Zero
Option A (Zero) is correct because Gauss's law for magnetism states that the net magnetic flux through any closed surface is always zero, reflecting the fact that magnetic monopoles do not exist.
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