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JEE • PHYSICS • ELECTRIC POTENTIAL AND CAPACITANCE

Electric potential and capacitance practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 372 questions

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211 Medium
211 of 372
Understanding +4 | -1
Consider an electric dipole placed in a region of
non-uniform electric field. Choose the correct
statement out of the following options.
View answer and explanation
Correct option: C
The dipole will experience both force and the
torque
Option C (The dipole will experience both force and the torque) is correct because in a non-uniform electric field, a dipole experiences both a net force and a torque.
212 Medium
212 of 372
Understanding +4 | -1
Assertion:- The dipoles in a dielectric are not completely aligned in weak external electric field.
Reason:- Thermal energy tends to de-align them.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because the dipoles in a dielectric material are not perfectly aligned in a weak electric field due to thermal energy, which tends to randomize their orientation.
213 Medium
213 of 372
Understanding +4 | -1
Metallic sphere of radius RR is charged to potential VV. Then charge qq is proportional to:
View answer and explanation
Correct option: C
Both VV and RR
Option C (Both VV and RR) is correct because the charge qq on a metallic sphere is directly proportional to both its potential VV and its radius RR, as given by the formula q=4πϵ0RVq = 4 \pi \epsilon_0 R V.
214 Medium
214 of 372
Understanding +4 | -1
Assertion: A metallic shield in form of a hollow shell may be built to block an electric field.

Reason: In a hollow spherical shield, the electric field inside it is zero at every point.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A is correct because a metallic shield blocks electric fields due to the zero electric field inside a hollow conductor.
215 Medium
215 of 372
Understanding +4 | -1
For a polar molecule, which of the following statements is true?
View answer and explanation
Correct option: B
The centre of gravity of electrons and protons do not coincide
Option B is correct because in a polar molecule, the centers of positive and negative charge do not coincide, resulting in a dipole moment.
216 Medium
216 of 372
Application +4 | -1
In a Vande graff generator a spherical metal shell is to be a 15×105 V15 \times {10^5}\,V electrode. The dielectric strength of a gas surrounding the electrodes is 5×107 Vm−15 \times {10^7}\,V{m^{ - 1}}. The minimum radius of the spherical shell is
View answer and explanation
Correct option: C
3 cm
Option C (3 cm) is correct because the minimum radius is calculated using the formula relating potential, electric field, and radius for a spherical conductor.
217 Medium
217 of 372
Application +4 | -1
A charge of 10−9C{10^{ - 9}}C is placed on each of the 64 identical drops of radius 2  cm.2\;cm. They are then combined to form a bigger drop. Find its potential
View answer and explanation
Correct option: A
7.2×103V7.2 \times {10^3}V
Option A (7.2×103V7.2 \times {10^3}V) is correct because the potential of the larger drop is calculated using the formula V=n2/3vV = {n^{2/3}}v, where n is the number of smaller drops.
218 Medium
218 of 372
Application +4 | -1
1000 small water drops each of radius rr and charge qq coalesce together to form one spherical drop. The potential of the big drop is larger than that of the smaller drop by a factor of
View answer and explanation
Correct option: B
100
Option B (100) is correct because the potential of a larger drop formed by coalescing smaller drops is proportional to n(2/3), where n is the number of smaller drops.
219 Medium
219 of 372
Understanding +4 | -1
Assertion:- A dielectric slab is inserted between the plates of an isolated charged capacitor. The charge on the capacitor will remain the same.
Reason:- Charge on an isolated system is conserved.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because both the Assertion and Reason are true, and the Reason correctly explains why the charge on the capacitor remains the same.
220 Medium
220 of 372
Application +4 | -1
If the circumference of a sphere is 3 m,3 \mathrm{~m}, the capacitance of the sphere in water is (dielectric constant of water = 80)
View answer and explanation
Correct option: A
4250 pF4250 \mathrm{~pF}
Option A (4250 pF4250 \mathrm{~pF}) is correct because it is calculated by using the formula for capacitance of a sphere in a medium with a given dielectric constant.
221 Medium
221 of 372
Understanding +4 | -1
The electric potential at centre of metallic conducting sphere is
View answer and explanation
Correct option: C
Equal from potential at surface of sphere
Option C (Equal from potential at surface of sphere) is correct because the electric potential inside a metallic conducting sphere is constant and equal to the potential at the surface.
222 Medium
222 of 372
Understanding +4 | -1
Electric intensity due to an electric dipole varies with distance (r ) as E∝rn,E \propto {r^n}, where n is
View answer and explanation
Correct option: A
−3- 3
Option A (-3) is correct because the electric field due to a dipole decreases with the cube of the distance.
223 Medium
223 of 372
Application +4 | -1
The work done in placing a charge of 5×10−18C5 \times 10^{-18} \mathrm{C} on a condenser of capacity 100μF100 \mu \mathrm{F} is:
View answer and explanation
Correct option: B
1.25×10−31 J1.25 \times 10^{-31}\mathrm{~J}
Option B (1.25×10−31 J1.25 \times 10^{-31}\,\mathrm{J}) is correct because the work done is calculated using the formula W=12q2CW = \frac{1}{2}\frac{{{q^2}}}{C}.
224 Medium
224 of 372
Application +4 | -1
In parallel plate capacitor, electric field between the plate is 'E\text{E}'. If the charge on the plates is 'Q\text{Q}' then the force on each plate is
View answer and explanation
Correct option: C
QE2\frac{\mathrm{QE}}{2}
Option C (QE2\frac{\mathrm{QE}}{2}) is correct because the force on each plate of a capacitor is due to the electric field created by the other plate, which is E/2.
225 Medium
225 of 372
Understanding +4 | -1
Statement- I: For a charged particle moving from point P{P} to point Q{Q}, the net work done by an electrostatic field on the particle is independent of the path connecting point PP to point Q{Q}.

Statement- II: The net work done by a conservative force on an object moving along a closed loop is zero.
View answer and explanation
Correct option: A
Statement-I is True, statement-II is True
Option A (Statement-I is True, statement-II is True) is correct because electrostatic fields are conservative, and work done by conservative forces in a closed loop is zero.
226 Medium
226 of 372
Analyzing +4 | -1
In a certain two-dimensional field of force, the potential energy of the particle has the form U=ax2+by2,U={a} {x}^2+{b} {y}^2, where a,b(a≠b){a},{b}({a} \neq {b}) are positive constants with different magnitudes. What is the shape of the equipotential surface for which the magnitude of force vector is constant?
View answer and explanation
Correct option: B
Ellipse
Option B (Ellipse) is correct. The equipotential surface is defined by U = constant, which results in the equation of an ellipse.
227 Medium
227 of 372
Analyzing +4 | -1
A parallel plate capacitor is charged by
connecting a 2 V battery across it. It is then
disconnected from the battery and a glass slab
is introduced between plates. Which of the
following pairs of quantities decrease?
View answer and explanation
Correct option: D
Potential difference and energy stored
Option D (Potential difference and energy stored) is correct because when the battery is disconnected, the charge remains constant, and introducing a glass slab increases capacitance, thus decreasing potential difference and energy stored.
228 Medium
228 of 372
Understanding +4 | -1
An equipotential surface and an electric line of force:
View answer and explanation
Correct option: D
Intersect at 90∘90^{\circ}
Option D (Intersect at 90∘90^{\circ}) is correct because equipotential surfaces are always perpendicular to electric field lines.
229 Medium
229 of 372
Analyzing +4 | -1
Considering a group of positive charges, which of the following statements is correct?
View answer and explanation
Correct option: A
Net potential of the system cannot be zero at a point but net electric field can be zero at that point.
Option A is correct. The net potential of a system of positive charges cannot be zero at any point, but the net electric field can be zero at some point due to vector cancellation.
230 Medium
230 of 372
Understanding +4 | -1
The electric field and the potential of an electric dipole vary with distance r{r} as
View answer and explanation
Correct option: D
1r3\frac{1}{{r}^3} and 1r2\frac{1}{{r}^2}
Option D is correct because the electric field due to an electric dipole varies with distance as 1r3\frac{{1}}{{r^3}}, and the electric potential varies as 1r2\frac{{1}}{{r^2}}.
231 Medium
231 of 372
Analyzing +4 | -1
You have a parallel plate capacitor, a spherical capacitor and cylindrical capacitor. Each capacitor is charged by and then removed from the same battery. Consider the following situations
(i) separation between the plates of parallel plate capacitor is reduced
(ii) radius of the outer spherical shell of the spherical capacitor is increased
(iii) radius of the outer cylinder of cylindrical capacitor is increased
Which of the following is correct ?
View answer and explanation
Correct option: C
In each of these situations (i), (ii) and (iii), charge on the given capacitor remains the same but potential difference, in situations (i), decreases, and in situations (ii) and (iii), increases
Option C is correct because the charge remains constant after disconnecting from the battery, but the potential difference changes based on the capacitance change in each scenario.
232 Medium
232 of 372
Analyzing +4 | -1
Statement-I: In bringing an electron towards a proton electrostatic potential energy of the system increases.

Statement-II: Potential due to proton is positive.
View answer and explanation
Correct option: D
Statement-I is false, Statement-II is false
Option C is correct because bringing an electron closer to a proton decreases the potential energy (more negative), and the potential due to a proton is positive.
233 Medium
233 of 372
Application +4 | -1
The potentials of the two plates of capacitor are +10V+ 10V and −10  V.- 10\;V. The charge on one of the plates is 40  C.40\;C. The capacitance of the capacitor is
View answer and explanation
Correct option: A
2  F2\;F
Option A (2 F) is correct because capacitance is calculated as charge divided by the potential difference, which is 20V in this case.
234 Medium
234 of 372
Application +4 | -1
Electric potential at any point is V=−5x+3y+15z,V = - 5x + 3y + \sqrt {15z} , then the magnitude of the electric field is
View answer and explanation
Correct option: D
7
Option D (7) is correct because the magnitude of the electric field is calculated by finding the partial derivatives of the potential with respect to x, y, and z, and then taking the square root of the sum of their squares.
235 Medium
235 of 372
Application +4 | -1
A parallel plate capacitor with air as dielectric is charged to potential VV using a battery. Removing the battery, the charged capacitor is then connected across an identical uncharged parallel plate capacitor filled with wax of dielectric constant ′K′'K'. The common potential of both the capacitor is
View answer and explanation
Correct option: D
VK+1Volts\frac{V}{{K + 1}}Volts
Option D (VK+1Volts\frac{V}{{K + 1}}Volts) is correct because the common potential is found by dividing the initial charge by the total capacitance after connecting the capacitors.
236 Medium
236 of 372
Application +4 | -1
The work done in bringing a 20 coulomb charge from point AA to point BB for distance 0.2 m is 2 joule. The potential difference between the two points will be (in volt)
View answer and explanation
Correct option: C
0.1
Option C (0.1) is correct because the potential difference is calculated by dividing the work done by the charge.
237 Medium
237 of 372
Remembering +4 | -1
The capacity of a parallel plate capacitor increases with the
View answer and explanation
Correct option: C
Increase of its area
Option C (Increase of its area) is correct because the capacitance of a parallel plate capacitor is directly proportional to its area.
238 Medium
238 of 372
Understanding +4 | -1
If we move opposite direction of electric field then electric potential
View answer and explanation
Correct option: A
Increases
Increases is the correct answer because electric potential increases when moving opposite to the direction of the electric field.
239 Medium
239 of 372
Application +4 | -1
Two concentric hollow spherical shells have radii r\text{r} and R(≫r).\text{R} (\gg \text{r}). A charge Q\text{Q} is distributed on them such that the surface charge densities are equal. The electric potential at the centre is
View answer and explanation
Correct option: A
Q(R+r)4πε0(R2+r2)\frac{\mathrm{Q}(\mathrm{R}+\mathrm{r})}{4 \pi \varepsilon_0\left(\mathrm{R}^2+\mathrm{r}^2\right)}
Option A is correct because the electric potential at the center is calculated by summing the potentials due to each spherical shell, considering their respective charges and radii, and using the condition of equal surface charge densities.
240 Medium
240 of 372
Understanding +4 | -1
Which of the following statements about dipole moment is not true?
View answer and explanation
Correct option: D
Dipole moment is a scalar quantity and has magnitude charge equal to the potential of separation between charges
Option D (Dipole moment is a scalar quantity and has magnitude charge equal to the potential of separation between charges) is correct because dipole moment is a vector quantity, not a scalar, and its magnitude is the product of charge and separation, not potential.
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