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JEE • PHYSICS • ELECTRIC POTENTIAL AND CAPACITANCE

Electric potential and capacitance practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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1 Easy

1 of 23

Analyzing +4 | -1

Assertion (A) : In series combination, charges on two capacitors are always equal.

Reason (R) : If charges are same, the total potential difference applied across two capacitors will be distributed in inverse ratio of capacities.

View answer and explanation

Correct option: D

If Assertion is false but the Reason is true.

Option D (If Assertion is false but the Reason is true) is correct because in a series combination, charges are the same only if initially uncharged, and the potential difference is indeed inversely proportional to capacitance.

2 Easy

2 of 23

Understanding +4 | -1

A positively charged particle is released from rest in an uniform electric field. The electric potential energy of the charge

View answer and explanation

Correct option: C

Decreases because the charge moves along the electric field

Option C (Decreases because the charge moves along the electric field) is correct because a positive charge moves in the direction of the electric field, decreasing its potential energy.

3 Easy

3 of 23

Remembering +4 | -1

To store electric charge, we use

View answer and explanation

Correct option: D

A capacitor.

Option D (A capacitor) is correct because capacitors are specifically designed to store electric charge.

4 Easy

4 of 23

Understanding +4 | -1

Two charged conducting spheres of radii

\mathrm{a}

and

\mathrm{b}

are connected to each other by a conducting wire. The ratio of charges of the two spheres respectively is:

View answer and explanation

Correct option: C

\frac{\mathrm{a}}{\mathrm{b}}

Option C (

\frac{\mathrm{a}}{\mathrm{b}}

) is correct because when conducting spheres are connected, they have the same potential, and the ratio of charges is proportional to the ratio of their radii.

5 Easy

5 of 23

Application +4 | -1

A sphere P of radius 6 cm is charged to a potential of 12 V and is connected to an uncharged sphere Q of radius 3 cm. Determine the loss energy during the process.

View answer and explanation

Correct option: B

16 \times {10^{ - 11}}J

Option B (

16 \times {10^{ - 11}}J

) is correct because it calculates the loss of energy when two charged spheres are connected.

6 Easy

6 of 23

Remembering +4 | -1

One micro microfarad is equal to

View answer and explanation

Correct option: B

1 \,{pF}

Option B (

1 \,{pF}

) is correct because micro microfarad is equivalent to picofarad.

7 Easy

7 of 23

Application +4 | -1

The capacity of a parallel plate capacitor is

8.85 \times {10^{ - 12}}\,\,F

and area of each plate is

4\,\,c{m^2}

then the distance between two plates is

View answer and explanation

Correct option: B

4 cm

Option B (4 cm) is correct because the distance between the plates is calculated using the formula for the capacitance of a parallel plate capacitor.

8 Easy

8 of 23

Analyzing +4 | -1

Assertion (A) : When an uncharged capacitor is charged by a battery, only

50 \%

of the energy supplied by a battery is stored in the capacitor.

Reason (R): Rest

50 \%

is lost.

View answer and explanation

Correct option: B

If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.

Option B is correct because both the assertion and the reason are true, but the reason does not fully explain the assertion. The energy loss is due to resistance in the connecting wires.

9 Easy

9 of 23

Understanding +4 | -1

If the plates of a charged capacitor are brought closer, then the

p

d

) between the plates will

View answer and explanation

Correct option: A

Decrease.

Option A (Decrease) is correct because as the distance between the plates decreases, the capacitance increases, leading to a decrease in potential difference.

10 Easy

10 of 23

Application +4 | -1

The energy stored in a capacitor of capacitance

100 \mu F

50 J

. Its potential difference is

View answer and explanation

Correct option: C

1000 V

Option C (1000 V) is correct because it is calculated using the formula for energy stored in a capacitor,

U = \frac{1}{2}CV^2

, solving for V.

11 Easy

11 of 23

Application +4 | -1

A capacitor of capacitance

C_1

is charged to a potential

V

and then connected in parallel to an uncharged capacitor of capacitance

C_2

. The final potential difference across each capacitor will be

View answer and explanation

Correct option: A

\frac{C_1 V}{C_1+C_2}

Option A (

\frac{{C_1 V}}{{C_1+C_2}}

) is correct because the final potential difference is determined by the charge conservation and the total capacitance of the parallel combination.

12 Easy

12 of 23

Analyzing +4 | -1

Assertion (A) : From the relation

C=\frac{q}{V}

. We can say that, if more charge

q

is given to a conductor, its capacitance should increase.

Reason (R) : Ratio

\frac{q}{V}

will remain constant for a given conductor.

View answer and explanation

Correct option: D

If Assertion is false but the Reason is true.

Option D (If Assertion is false but the Reason is true) is correct because capacitance depends on the geometry of the conductor, not the charge, and the ratio of charge to voltage remains constant.

13 Easy

13 of 23

Remembering +4 | -1

The electric potential at a point distant

\text{r}

from an electric dipole is proportional to

View answer and explanation

Correct option: B

\frac{1}{\mathrm{r}^2}

Option B (

\frac{{1}}{{\mathrm{{r}}^2}}

) is correct because the electric potential due to an electric dipole is inversely proportional to the square of the distance from the dipole.

14 Easy

14 of 23

Remembering +4 | -1

A powerful machine used for producing high positive potentials is

View answer and explanation

Correct option: D

Van de graaff generator.

Option D (Van de graaff generator) is correct because it is specifically designed to generate high positive potentials.

15 Easy

15 of 23

Application +4 | -1

A point

A

is at potential

+500 \mathrm{~Volt}

and

B

is a point of potential

-500 \mathrm{~Volt}.

The work done by an external agent to take a unit positive charge from

A

B

View answer and explanation

Correct option: B

-1000J

Option B (-1000J) is correct because the work done by an external agent is the negative of the potential difference multiplied by the charge.

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16 Easy

16 of 23

Application +4 | -1

Two identical capacitors have same capacitance

C

. One of them is charged to the potential

V

and other to the potential

2 V

. The negative ends of both are connected together. When the positive ends are also joined together, the decrease in energy of the combined system is:

View answer and explanation

Correct option: A

\frac{1}{4} {CV}^2

Option A (

\frac{1}{4} {CV}^2

) is correct because it is the difference between the initial and final energies of the capacitor system after connecting them.

17 Easy

17 of 23

Application +4 | -1

An electric dipole is made up of two equal and opposite charges of

2 \times 10^{-6} {C}

at a distance of

3 {~cm}

. If this is kept in an electric field of

2 \times 10^5

{N} / {C}

, then the maximum torque acting on the dipole is

View answer and explanation

Correct option: A

0.012

Option A (0.012) is correct because it is the maximum torque calculated using the formula

\tau = pE

, where p is the dipole moment and E is the electric field.

18 Easy

18 of 23

Analyzing +4 | -1

Assertion (A) : Two capacitors are connected in series with a battery. Energy stored across them is in inverse ratio of their capacity.

Reason (R):

U=\frac{1}{2} q V

U \propto q V

View answer and explanation

Correct option: B

If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.

Option B is correct because both Assertion and Reason are true, but the Reason is not the correct explanation of the Assertion. The energy stored is inversely proportional to capacitance because charge is the same in series.

19 Easy

19 of 23

Understanding +4 | -1

A spherical equipotential surface is not possible

View answer and explanation

Correct option: B

For a dipole

Option B (For a dipole) is correct because the electric field lines of a dipole do not form spherical equipotential surfaces.

20 Easy

20 of 23

Remembering +4 | -1

The electrostatic potential due to an electric dipole at a distance

r

varies as:

View answer and explanation

Correct option: B

\frac{1}{r^2}

Option B (

\frac{1}{r^2}

) is correct because the electrostatic potential due to an electric dipole decreases with the square of the distance.

21 Easy

21 of 23

Application +4 | -1

The ratio of the resultant capacities when three capacitors of

2\,\,\mu F,\,\,4\,\,\mu F

and

6\,\,\mu F

are connected first in series and then in parallel is

View answer and explanation

Correct option: D

1: 11

Option D (1: 11) is correct because it is the ratio of the equivalent capacitance in series to the equivalent capacitance in parallel for the given capacitors.

22 Easy

22 of 23

Understanding +4 | -1

Two hollow conducting spheres of radii

{R_1}

and

{R_2}({R_1} > > {R_2})

have equal charges. The potential would be:

View answer and explanation

Correct option: C

Key Takeaways

✓ This set contains 23 single-correct-answer MCQs on ELECTRIC POTENTIAL AND CAPACITANCE.
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

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