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JEE • PHYSICS • ELECTRIC POTENTIAL AND CAPACITANCE

Electric potential and capacitance practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 271-300 of 372 questions

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271 Medium
271 of 372
Analyzing +4 | -1
Assertion:- Electric potential energy of any positive charge is always positive.
Reason:-Potential energy is a vector quantity.
View answer and explanation
Correct option: D
If both Assertion & Reason are False
Option D (If both Assertion & Reason are False) is correct because the electric potential energy of a positive charge can be negative, and potential energy is a scalar quantity.
272 Medium
272 of 372
Understanding +4 | -1
Assertion: Electrings always move from a region of lower potential to a region of high potential.

Reason: Electrings carryy a negative charge.
View answer and explanation
Correct option: A
Both Assertion & Reason are true. Reason is the correct explanation for assertion
Option A (Both Assertion & Reason are true. Reason is the correct explanation for assertion) is correct because electrons are negatively charged and move from lower to higher potential.
273 Medium
273 of 372
Understanding +4 | -1
Assertion:- The capacitance of a capacitor depends on the shape, size and geometrical placing of the conductors and the medium between them.
Reason:- When a charge qq passes through a battery of emf E{E} from the negative terminal to the positive terminal, an amount of work qE{qE} is done by the battery.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because both statements are true, but the reason doesn't explain why capacitance depends on geometry and the medium.
274 Medium
274 of 372
Analyzing +4 | -1
A point charge is situated at an axial point of a small electric dipole at a large distance from it. The charge
experiences a force F. If the distance of the charge is doubled, the force acting on the charge will become
View answer and explanation
Correct option: B
F8\frac{F}{8}
Option B (F8\frac{F}{8}) is correct because the electric field due to a dipole varies inversely with the cube of the distance.
275 Medium
275 of 372
Remembering +4 | -1
A conductor which can be given almost unlimited charge is_____.
View answer and explanation
Correct option: D
Earth
Option D (Earth) is correct because the Earth is a large conductor that can absorb or supply an almost unlimited amount of charge without a significant change in its potential.
276 Medium
276 of 372
Application +4 | -1
Eight identical spherical drops, each carrying a charge 1nC1 \mathrm{nC} are at a potential of 900 V900 \mathrm{~V} each. All these drops combine together to form a single large drop. Calculate the potential of this large drop. (Assume no wastage of any kind and take the capacitance of a sphere of radius rr as proportional to rr ).
View answer and explanation
Correct option: B
3600 V3600 \mathrm{~V}
Option B (3600 V3600 \mathrm{~V}) is correct because the potential of the large drop is calculated based on the conservation of charge and the relationship between capacitance and radius.
277 Medium
277 of 372
Application +4 | -1
A capacitor 4μF4\mu F charged to 50V50V is connected to another capacitor of 2μF2\mu F charged to 100V100V with plates of like charges connected together. The total energy before and after connection in multiples of (10−2J)\left( {{{10}^{ - 2}}J} \right) is
View answer and explanation
Correct option: A
1.5 and 1.33
Option A (1.5 and 1.33) is correct because it accurately calculates the total energy before and after connecting the capacitors, considering the voltage redistribution after connection.
278 Medium
278 of 372
Application +4 | -1
A positive point charge +q+\mathrm{q} is placed at the origin. There is an electric field E(x)=E0(2xd+3x2d2)E_{(x)}=E_0\left(2 \frac{x}{d}+3 \frac{x^2}{d^2}\right), that accelerates the point charge along the x\mathrm{x}-axis. The kinetic energy of the charge when it reaches the position x=2 d\mathrm{x}=2 \mathrm{~d} is XqdE0X q d E_0 then find the value of XX.
View answer and explanation
Correct option: A
12
Option A (12) is correct because it is derived from integrating the electric field to find the potential difference and then calculating the kinetic energy.
279 Medium
279 of 372
Application +4 | -1
A capacitor of capacitance 1μF1 \mu F can with stand the maximum voltage 6kV6 \mathrm{kV} while a capacitor of 2μF2 \mu \mathrm{F} can withstand the maximum voltage 4kV4 \mathrm{kV}. What maximum voltage (in kV)\mathrm{kV}) will the system of these two capacitor can withstand, if they are connected in series?
View answer and explanation
Correct option: A
9
Option A (9 kV) is correct because it calculates the maximum voltage the series combination can withstand based on the charge limit of the capacitor with the lower charge capacity.
280 Medium
280 of 372
Analyzing +4 | -1
A short electric dipole is placed in the electric field due to a point charge. Then

A) The dipole must experience a force

B) The dipole may experience a force

C) The dipole must experience a torque

D) The dipole may experience a torque
View answer and explanation
Correct option: A
A and D are correct
Option A is correct because a dipole in a non-uniform electric field (due to a point charge) may experience a force and may experience a torque depending on its orientation.
281 Medium
281 of 372
Understanding +4 | -1
Polar molecules are the molecules
View answer and explanation
Correct option: B
Having a permanent electric dipole moment
The correct answer is B (Having a permanent electric dipole moment) because polar molecules, by definition, possess a permanent separation of charge, resulting in a dipole moment.
282 Medium
282 of 372
Analyzing +4 | -1
Assertion: Two equipotential surfaces can cut each other.

Reason: Two equipotential surfaces are always parallel to each other.
View answer and explanation
Correct option: D
Both assertion and reason are false
Option D is correct because equipotential surfaces cannot intersect, and they are not always parallel.
283 Medium
283 of 372
Understanding +4 | -1
The force between two short dipoles separated by a distance rr is directly proportional to
View answer and explanation
Correct option: D
r−4r^{-4}
Option D (r−4r^{-4}) is correct because the force between two short dipoles is inversely proportional to the fourth power of the distance between them.
284 Medium
284 of 372
Analyzing +4 | -1
Assertion (A): Two capacitor of same capacity are connected first in parallel and then in series. The ratio of resultant capacities in the two cased will be 4:1.4: 1.

Reason (R): In parallel, capacity increases and in series capacity decreases.
View answer and explanation
Correct option: B
Both A and R are true but R is not a correct
explanation for A
Option B (Both A and R are true but R is not a correct explanation for A) is correct because the ratio of parallel to series capacitance is 4:1, and parallel capacitance increases while series capacitance decreases, but the latter doesn't explain the former.
285 Medium
285 of 372
Analyzing +4 | -1
Assertion (A): Conductors having equal positive charge and volume, must also have same potential.
Reason (R): Potential depends only on charge and volume of conductor.
View answer and explanation
Correct option: D
Both assertion and reason are false
Option D (Both assertion and reason are false) is correct. Electric potential depends on charge, volume, and shape, making both statements incorrect.
286 Medium
286 of 372
Application +4 | -1
The capacitance of two conductors in parallel is four times when they are connected in series. The ratio of the individual capacitance will be
View answer and explanation
Correct option: B
0.042361111
Option B (01:01) is correct because the ratio of capacitances is 1:1 when the capacitance in parallel is four times the capacitance in series, implying equal individual capacitances.
287 Medium
287 of 372
Application +4 | -1
Two conducting spheres of radii R1R_1 and R2R_2 are kept widely separated from each other. What are their individual capacitances? If the spheres are connected by a metal wire, what will be the capacitance of the combination? Think in terms of series-parallel connections.
View answer and explanation
Correct option: B
4πε0(R1+R2)4 \pi \varepsilon_0\left(\mathrm{R}_1+\mathrm{R}_2\right)
Option B (4πε0(R1+R2)4 \pi \varepsilon_0\left(\mathrm{R}_1+\mathrm{R}_2\right)) is correct because the capacitance of a single sphere is 4πε0R4 \pi \varepsilon_0 R and when connected by a wire, they act as parallel capacitors.
288 Medium
288 of 372
Application +4 | -1
An electric field is expressed as E=2i^+3j^E=2 \hat{i}+3 \hat{j}. Find the potential difference (VA−VB)\left(V_A-V_B\right) between two points AA and BB whose position vectors are given by rA=i^+2j^r_A=\hat{i}+2 \hat{j} and rB=2i^+j^+3k^r_B=2 \hat{i}+\hat{j}+3 \hat{k}.
View answer and explanation
Correct option: A
−1V-1 V
Option A (-1 V) is correct because the potential difference is calculated by integrating the electric field along the displacement vector.
289 Medium
289 of 372
Understanding +4 | -1
The intensity of electric field at a point between the plates of a charged capacitor
View answer and explanation
Correct option: D
Does not depend upon the distance between the plates
Option D (Does not depend upon the distance between the plates) is correct because the electric field between the plates of a charged capacitor is uniform and independent of the distance from the plates.
290 Medium
290 of 372
Application +4 | -1
A parallel-plate capacitor of capacitance 100μF100 \mu \mathrm{F} is connected to a power supply of 200 V200 \mathrm{~V}. A dielectric slab of dielectric constant 5 is now inserted into the gap between the plates. (a) Find the extra charge flown through the power supply and the work done by the supply. (b) Find the change in the electrostatic energy of the electric field in the capacitor.
View answer and explanation
Correct option: A
16 J; 8 J
Option A (16 J; 8 J) is correct because the extra charge flown through the power supply and the work done by the supply are 16 J, and the change in the electrostatic energy of the electric field in the capacitor is 8 J.
291 Medium
291 of 372
Understanding +4 | -1
A hollow spherical conductor of radius rr and potential of 100 V100 \mathrm{~V} at its outer surface. The potential inside the hollow at a distance of r/2r / 2 from its centre is
View answer and explanation
Correct option: A
100 V100 \mathrm{~V}
Option A is correct because the electric potential inside a hollow spherical conductor is constant and equal to the potential at the surface.
292 Medium
292 of 372
Application +4 | -1
A parallel plate capacitor has capacitance of 2μF2\mu F in air and 12μF12\mu F when immersed in oil. The dielectric constant of oil
View answer and explanation
Correct option: D
6
Option D (6) is correct because the dielectric constant is the ratio of capacitance in the medium to the capacitance in air.
293 Medium
293 of 372
Understanding +4 | -1
A hollow metallic sphere of radius RR is given a charge QQ. Then, the potential at the centre is
View answer and explanation
Correct option: B
14πε0.QR\frac{1}{{4\pi {\varepsilon _0}}}.\frac{Q}{R}
Option B is correct because the electric potential inside a hollow metallic sphere is constant and equal to the potential at the surface, which is given by 14πε0.QR\frac{1}{{4\pi \varepsilon _0}}.\frac{Q}{R}.
294 Medium
294 of 372
Application +4 | -1
An electric dipole having dipole moment 4×4 \times 10−9Cm10^{-9} \mathrm{Cm} makes an angle 30∘30^{\circ} with the direction of a uniform electric field of magnitude 5 ×104NC−1\times 10^4 \mathrm{NC}^{-1}. Calculate the magnitude of the torque acting on the dipole. Also find out work required to rotate the dipole to make angle 90∘90^{\circ} with the direction of the electric field.
View answer and explanation
Correct option: B
3×10−4 J\sqrt{3} \times 10^{-4} \mathrm{~J}
Option B (3×10−4 J\sqrt{3} \times 10^{-4} \mathrm{~J}) is correct because it is the work required to rotate the dipole, calculated using the potential energy difference at the given angles.
295 Medium
295 of 372
Analyzing +4 | -1
Assertion: A parallel plate capacitor is connected across battery through a key. A dielectric slab of dielectric constant k{k} is introduced between the plates. The energy stored becomes k{k} times.
Reason: The surface density of charge on the plate remains constant.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C (If assertion is true but reason is false) is correct because while the energy stored does increase by a factor of k, the surface charge density also increases, not remains constant.
296 Medium
296 of 372
Application +4 | -1
The ratio of charge densities on the surface of two conducting spheres is 3 : 2 If the radii of the spheres are 4 cm and 8 cm. the ratio of electric potential on the surfaces of the spheres is
View answer and explanation
Correct option: A
03:04
Option A (03:04) is correct because the ratio of electric potentials is directly proportional to the ratio of charge densities and the ratio of radii.
297 Medium
297 of 372
Application +4 | -1
There is an electric field EE in X−X -direction. If the work done on moving a charge 0.2  C0.2\;C through a distance of 2  m2\;m along a line making an angle 60∘60^\circ with the X−X -axis is 4.04.0, what is the value of EE
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the calculated electric field is 20 N/C, which is not among the provided options.
298 Medium
298 of 372
Remembering +4 | -1
The energy stored in a capacitor of capacitance C\text{C} having a charge Q\text{Q} under a potential V\text{V} is
View answer and explanation
Correct option: D
12QV\frac{1}{2} \mathrm{QV}
Option D (12QV\frac{1}{2} \mathrm{QV}) is correct because the energy stored in a capacitor is given by half the product of the charge and the potential difference.
299 Medium
299 of 372
Understanding +4 | -1
Electron and proton is moving away from each other then potential energy of system
View answer and explanation
Correct option: B
Increasing
Option B (Increasing) is correct because as the electron moves away from the proton, positive work is done, increasing the potential energy of the system.
300 Medium
300 of 372
Understanding +4 | -1
The electric potential due to a small electric dipole at a large distance rr from the centre of the dipole is proportional to
View answer and explanation
Correct option: B
1/r1/r
Option D (1/r21/{r^2}) is correct because the electric potential due to a small electric dipole at a large distance rr is inversely proportional to r2r^2.
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