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JEE • PHYSICS • ELECTRIC POTENTIAL AND CAPACITANCE

Electric potential and capacitance practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 407 questions

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91 Medium
91 of 407
Application +4 | -1
Three point charges 1 C,2 C1 \mathrm{~C}, 2 \mathrm{~C} and 3 C3 \mathrm{~C} are placed at the corners of an equilateral triangle of side 1 m.1 \mathrm{~m}. The work done in bringing these charges to the vertices of a smaller similar triangle of side 0.5 m0.5 \mathrm{~m} is:
View answer and explanation
Correct option: B
9.9×1010 J9.9 \times 10^{10} \mathrm{~J}
Option B (9.9×1010 J9.9 \times 10^{10} \mathrm{~J}) is correct because it is calculated from the difference in potential energy between the two configurations.
92 Medium
92 of 407
Understanding +4 | -1
Assertion: If an electric dipole of dipole moment 30×10−5Cm30 \times 10^{-5} \mathrm{Cm} is enclosed by a closed surface, the net flux coming out of the surface will be zero.

Reason: An electric dipole consists of two equal and opposite charges.
View answer and explanation
Correct option: A
Both Assertion and Reason are true, and Reason is the correct explanation for Assertion
Option A (Both Assertion and Reason are true, and Reason is the correct explanation for Assertion) is correct because the net electric flux through a closed surface enclosing an electric dipole is zero due to the equal and opposite charges of the dipole.
93 Medium
93 of 407
Application +4 | -1
A dielectric of thickness 5 cm5 \mathrm{~cm} and dielectric constant 10, is introduced in between the plates of a parallel plate capacitor having plate area 500 cm2500 \mathrm{~cm}^2 and separation between plates 10 cm.10 \mathrm{~cm}. The capacitance of the capacitor is (If ε0=8.8×10−12 SI units):\text{(If }\varepsilon_0=\mathrm{8 . 8} \times 10^{-12} \text{ SI units}):
View answer and explanation
Correct option: A
8 pF8 \mathrm{~pF}
Option A (8 pF8 \mathrm{~pF}) is correct because the equivalent capacitance is calculated considering the dielectric and air gaps as series capacitors.
94 Medium
94 of 407
Application +4 | -1
The capacity of a parallel plate condenser consisting of two plates each 20 cm square and are separated by a distance of 8 mm is (Take air as the medium between the plates).
View answer and explanation
Correct option: B
2.2×10−12F2.2 \times {10^{ - 12}}F
Option B (2.2×10−12F2.2 \times {10^{ - 12}}F) is correct because it is the capacitance calculated using the formula for a parallel plate capacitor with air as the medium.
95 Medium
95 of 407
Application +4 | -1
Capacitance of a parallel plate capacitor becomes 4/34/3 times its original value if a dielectric slab of thickness t=d/2t = d/2 is inserted between the plates (dd is the separation between the plates). The dielectric constant of the slab is
View answer and explanation
Correct option: D
2
Option D (2) is correct because the capacitance increases by a factor of 4/3 when a dielectric slab of thickness d/2 is inserted, which allows us to solve for the dielectric constant K.
96 Medium
96 of 407
Application +4 | -1
Force of attraction between the plates of a parallel plate capacitor is
View answer and explanation
Correct option: A
q22ε0AK\frac{{{q^2}}}{{2{\varepsilon _0}AK}}
Option A (q22ε0AK\frac{{{q^2}}}{{2{\varepsilon _0}AK}}) is correct because it represents the force derived from the electric field created by one plate acting on the charge of the other plate in a parallel plate capacitor.
97 Hard
97 of 407
Analyzing +4 | -1
Statement-1: The heat produced by a resistor in any time tt during the charging of a capacitor in a series circuit is half the energy stored in the capacitor by that time.
Statement-2: Current in the circuit is equal to the rate of increase in charge on the capacitor.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D is correct because Statement-1 is false, and Statement-2 is true. The heat produced is not half the energy stored, and the current is indeed the rate of increase in charge.
98 Medium
98 of 407
Application +4 | -1
A capacitor with stored energy 4.0 J is connected with an identical capacitor with no electric field in between. Find the total energy stored in the two capacitors
View answer and explanation
Correct option: B
2 J
Option B (2 J) is correct because when the capacitors are connected, the charge is shared equally, resulting in half the initial energy stored in each capacitor.
99 Medium
99 of 407
Application +4 | -1
The potential difference between two points x=10 mx = 10\,m and 20 m in the field E=100x2E = \frac{{100}}{{{x^2}}} will be in volt
View answer and explanation
Correct option: A
5
Option A (5) is correct because the potential difference is calculated by integrating the electric field over the given distance, resulting in 5V.
100 Medium
100 of 407
Understanding +4 | -1
A conductor carries a certain charge. When it is connected to another uncharged conductor of finite capacity, then the energy of the combined system is:
View answer and explanation
Correct option: B
Less than that of the first conductor
Option B is correct because energy is lost during the transfer of charge due to the heating effect, resulting in the combined system having less energy than the first conductor.
101 Medium
101 of 407
Application +4 | -1
If a slab of insulating material 4×10−3m4 \times {10^{ - 3}}m thick is introduced between the plates of a parallel plate capacitor, the separation between plates has to be increased by 3.5×10−3m3.5 \times {10^{ - 3}}m to restore the capacity to original value. The dielectric constant of the material will be
View answer and explanation
Correct option: B
8
Option B (8) is correct because the dielectric constant is calculated using the formula relating the thickness of the slab and the increase in separation.
102 Medium
102 of 407
Application +4 | -1
A cylindrical capacitor is constructed using two coaxial cylinders of the same length 10 cm10 \mathrm{~cm} and of radii 2 mm2 \mathrm{~mm} and 4 mm4 \mathrm{~mm}. Calculate the capacitance.
View answer and explanation
Correct option: A
8 PF
Option A (8 PF) is correct because the capacitance is calculated using the formula for a cylindrical capacitor.
103 Medium
103 of 407
Understanding +4 | -1
Assertion: Electrons move away from a low potential to high potential region.

Reason: Because electrons has negative charge
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A (If both assertion and reason are true and the reason is the correct explanation of the assertion) is correct because electrons are negatively charged and move from low to high potential.
104 Medium
104 of 407
Understanding +4 | -1
Assertion:- On filling the space between the plates of a parallel plate air capacitor with dielectric, capacity of the capacitor is increased.
Reason:- The same amount of charge can be stored at a reduced potential.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because the dielectric increases capacitance by reducing the potential for the same charge.
105 Medium
105 of 407
Application +4 | -1
Twenty-Seven drops of same size are charged at 220 V each. They combine to form a bigger drop. Calculate the potential of the bigger drop.
View answer and explanation
Correct option: B
1980 V
Option B (1980 V) is correct because the potential of the bigger drop is 9 times the potential of the smaller drops due to the increase in charge and radius.
106 Medium
106 of 407
Understanding +4 | -1
Consider a capacitor - charging circuit. Let Q1Q_1 be the charge given to the capacitor in time interval of 20 ms20 \mathrm{~ms} and Q2Q_2 be the charge given in the next time interval of 20 ms20 \mathrm{~ms}. Let 10μCcharge10 \mu \mathrm{Ccharge} be deposited in a time interval t1t_1 and the next 10μC charge10 \mu \mathrm{C~charge} is deposited in the next time interval t2t_2. Then,
View answer and explanation
Correct option: B
Q1>Q2,t1<t2Q_1 > Q_2, t_1 < t_2
The correct answer is B (Q1 > Q2, t1 < t2) because as the capacitor charges, the charging rate decreases, meaning more charge is deposited initially and it takes longer to deposit the same amount of charge later.
107 Medium
107 of 407
Understanding +4 | -1
A point charge q1=qq_1=q is placed at point PP. Another point charge q2=−qq_2=-q is placed at point QQ. At some point R(R≠P,R≠Q)R(R \neq P, R \neq Q), electric potential due to q1q_1 is V1V_1 and electric potential due to q2q_2 is V2V_2. Which of the following is correct?
View answer and explanation
Correct option: C
For all points V1>V2V_1 > V_2
Option C (For all points V1>V2V_1 > V_2) is correct because the potential due to the positive charge q1q_1 is always positive, and the potential due to the negative charge q2q_2 is always negative.
108 Medium
108 of 407
Understanding +4 | -1
A dielectric introduced between the plates of a parallel plate condenser
View answer and explanation
Correct option: D
Increases the capacity of the condenser
Option D (Increases the capacity of the condenser) is correct because introducing a dielectric between the plates of a capacitor increases its capacitance by a factor equal to the dielectric constant.
109 Medium
109 of 407
Understanding +4 | -1
A dipole of electric dipole moment p is placed in a uniform electric field of strength E. If θ\mathrm{\theta } is the angle between positive directions of p and E, then the potential energy of the electric dipole is largest when θ\mathrm{\theta } is
View answer and explanation
Correct option: C
π\pi
Option C (π\pi) is correct because the potential energy is largest when the cosine of the angle between p and E is -1, which occurs at 180 degrees.
110 Medium
110 of 407
Remembering +4 | -1
The potential due to the electric dipole at a distance rr from the dipole on the axial line is
View answer and explanation
Correct option: A
14π∈02qar2\frac{1}{{4\pi { \in _0}}}\frac{{2qa}}{{{r^2}}}
Option A (14π∈02qar2\frac{1}{{4\pi { \in _0}}}\frac{{2qa}}{{{r^2}}}) is correct because the electric potential due to a dipole on the axial line is given by this formula.
111 Medium
111 of 407
Application +4 | -1
nn small drops of same size are charged to potential VV volt each. If they coalesce to form a single large drop, then its potential will be
View answer and explanation
Correct option: A
n23 Vn^{\frac{2}{3}} \mathrm{~V}
Option A (n23 Vn^{\frac{2}{3}} \mathrm{~V}) is correct because it represents the potential of the larger drop formed by coalescing n smaller drops, derived from the conservation of charge and the relationship between potential and radius.
112 Medium
112 of 407
Understanding +4 | -1
A conductor with a positive charge:
View answer and explanation
Correct option: D
May be at positive, zero or negative potential
Option D is correct because the potential of a charged conductor depends on the reference point (zero potential) and the presence of other charges, so it can be positive, zero, or negative.
113 Medium
113 of 407
Understanding +4 | -1
Ten electrons are equally spaced and fixed around a circle of radius R.R. Relative to V=0V = 0 at infinity, the electrostatic potential VV and the electric field EE at the centre CC are
View answer and explanation
Correct option: B
V≠0  and  E⃗=0V \ne 0\;\mathrm{and\;}\vec E = 0
Option B (V≠0;and;E⃗=0V \ne 0 \\;\mathrm{and\\;}\vec E = 0) is correct because the potential due to multiple charges is a scalar sum and doesn't necessarily cancel out, while the electric field, being a vector, cancels out at the center due to symmetry.
114 Medium
114 of 407
Understanding +4 | -1
Equal charges are given to two spheres of different radii. The potential will
View answer and explanation
Correct option: A
Be more on the smaller sphere
Option A (Be more on the smaller sphere) is correct because the electric potential is inversely proportional to the radius of the sphere, given equal charges.
115 Medium
115 of 407
Understanding +4 | -1
A uniform electric field pointing in positive x-direction exists in a region let AA be the origin BB be the point on x-axis at x=+1 cmx = + 1\,cm and CC be the point on y-axis at y=+1 cmy = + 1\,cm. Then the potentials at points A,B, and C satisfy.
View answer and explanation
Correct option: B
VA>VB{V_A} > {V_B}
Option B (VA>VB{V_A} > {V_B}) is correct because electric potential decreases in the direction of the electric field, and point B is at a higher x-coordinate than A.
116 Medium
116 of 407
Application +4 | -1
Three identical charges are placed at corners of an equilateral triangle of side ll. If force between any two charges is FF, the work required to double the dimensions of triangle is
View answer and explanation
Correct option: C
(−3/2)Fl(-3 / 2) \mathrm{Fl}
Option C ((−3/2)Fl(-3 / 2) \mathrm{Fl}) is correct because it is the work required to double the dimensions of the triangle, calculated as the change in potential energy of the system.
117 Medium
117 of 407
Remembering +4 | -1
One volt is equivalent to:
View answer and explanation
Correct option: C
Joule/coulomb
Option C (Joule/coulomb) is correct because one volt is defined as one joule of energy per coulomb of charge (V = J/C).
118 Medium
118 of 407
Understanding +4 | -1
The work done in bringing a unit positive charge from infinite distance to a point at distance xx from a positive charge QQ is W.W. Then the potential ϕ\phi at that point is
View answer and explanation
Correct option: B
WW
Option B (WW) is correct because the electric potential at a point is defined as the work done in bringing a unit positive charge from infinity to that point.
119 Medium
119 of 407
Analyzing +4 | -1
Assertion: When a proton with certain energy moves from low potential to high potential then its KE{KE} decreases.

Reason: The direction of electric field is opposite to the potential gradient and work done against it is negative.
View answer and explanation
Correct option: B
Both Assertion & Reason are true. Reason is not the correct explanation for assertion
Option B is correct because both the assertion and the reason are true, but the reason does not explain why the kinetic energy decreases; the decrease is due to the proton doing work against the electric field.
120 Medium
120 of 407
Analyzing +4 | -1
Assertion:- If three capacitors of capacitances C1<C2<C3\mathrm{C}_1 < \mathrm{C}_2 < \mathrm{C}_3 are connected in series and parallel, then Cparallel >Cseries \mathrm{C}_{\text {parallel }} > \mathrm{C}_{\text {series }}.
Reason:- Cseries =C1+C2+C3\mathrm{C}_{\text {series }}=\mathrm{C}_1+\mathrm{C}_2+\mathrm{C}_3 and 1Cparallel =1C1+1C2+1C3\frac{1}{\mathrm{C}_{\text {parallel }}}=\frac{1}{\mathrm{C}_1}+\frac{1}{\mathrm{C}_2}+\frac{1}{\mathrm{C}_3}
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C is correct because the assertion is true (parallel capacitance is always greater than series capacitance), but the reason provides incorrect formulas for series and parallel capacitance.
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