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JEE • PHYSICS • ELECTRIC POTENTIAL AND CAPACITANCE

Electric potential and capacitance practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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301 Medium
301 of 407
Remembering +4 | -1
A conductor which can be given almost unlimited charge is_____.
View answer and explanation
Correct option: D
Earth
Option D (Earth) is correct because the Earth is a large conductor that can absorb or supply an almost unlimited amount of charge without a significant change in its potential.
302 Medium
302 of 407
Application +4 | -1
Eight identical spherical drops, each carrying a charge 1nC1 \mathrm{nC} are at a potential of 900 V900 \mathrm{~V} each. All these drops combine together to form a single large drop. Calculate the potential of this large drop. (Assume no wastage of any kind and take the capacitance of a sphere of radius rr as proportional to rr ).
View answer and explanation
Correct option: B
3600 V3600 \mathrm{~V}
Option B (3600 V3600 \mathrm{~V}) is correct because the potential of the large drop is calculated based on the conservation of charge and the relationship between capacitance and radius.
303 Medium
303 of 407
Application +4 | -1
A capacitor 4μF4\mu F charged to 50V50V is connected to another capacitor of 2μF2\mu F charged to 100V100V with plates of like charges connected together. The total energy before and after connection in multiples of (10−2J)\left( {{{10}^{ - 2}}J} \right) is
View answer and explanation
Correct option: A
1.5 and 1.33
Option A (1.5 and 1.33) is correct because it accurately calculates the total energy before and after connecting the capacitors, considering the voltage redistribution after connection.
304 Medium
304 of 407
Application +4 | -1
A positive point charge +q+\mathrm{q} is placed at the origin. There is an electric field E(x)=E0(2xd+3x2d2)E_{(x)}=E_0\left(2 \frac{x}{d}+3 \frac{x^2}{d^2}\right), that accelerates the point charge along the x\mathrm{x}-axis. The kinetic energy of the charge when it reaches the position x=2 d\mathrm{x}=2 \mathrm{~d} is XqdE0X q d E_0 then find the value of XX.
View answer and explanation
Correct option: A
12
Option A (12) is correct because it is derived from integrating the electric field to find the potential difference and then calculating the kinetic energy.
305 Medium
305 of 407
Application +4 | -1
A capacitor of capacitance 1μF1 \mu F can with stand the maximum voltage 6kV6 \mathrm{kV} while a capacitor of 2μF2 \mu \mathrm{F} can withstand the maximum voltage 4kV4 \mathrm{kV}. What maximum voltage (in kV)\mathrm{kV}) will the system of these two capacitor can withstand, if they are connected in series?
View answer and explanation
Correct option: A
9
Option A (9 kV) is correct because it calculates the maximum voltage the series combination can withstand based on the charge limit of the capacitor with the lower charge capacity.
306 Medium
306 of 407
Analyzing +4 | -1
A short electric dipole is placed in the electric field due to a point charge. Then

A) The dipole must experience a force

B) The dipole may experience a force

C) The dipole must experience a torque

D) The dipole may experience a torque
View answer and explanation
Correct option: A
A and D are correct
Option A is correct because a dipole in a non-uniform electric field (due to a point charge) may experience a force and may experience a torque depending on its orientation.
307 Medium
307 of 407
Understanding +4 | -1
Polar molecules are the molecules
View answer and explanation
Correct option: B
Having a permanent electric dipole moment
The correct answer is B (Having a permanent electric dipole moment) because polar molecules, by definition, possess a permanent separation of charge, resulting in a dipole moment.
308 Medium
308 of 407
Analyzing +4 | -1
Assertion: Two equipotential surfaces can cut each other.

Reason: Two equipotential surfaces are always parallel to each other.
View answer and explanation
Correct option: D
Both assertion and reason are false
Option D is correct because equipotential surfaces cannot intersect, and they are not always parallel.
309 Medium
309 of 407
Understanding +4 | -1
The force between two short dipoles separated by a distance rr is directly proportional to
View answer and explanation
Correct option: D
r−4r^{-4}
Option D (r−4r^{-4}) is correct because the force between two short dipoles is inversely proportional to the fourth power of the distance between them.
310 Medium
310 of 407
Analyzing +4 | -1
Assertion (A): Two capacitor of same capacity are connected first in parallel and then in series. The ratio of resultant capacities in the two cased will be 4:1.4: 1.

Reason (R): In parallel, capacity increases and in series capacity decreases.
View answer and explanation
Correct option: B
Both A and R are true but R is not a correct
explanation for A
Option B (Both A and R are true but R is not a correct explanation for A) is correct because the ratio of parallel to series capacitance is 4:1, and parallel capacitance increases while series capacitance decreases, but the latter doesn't explain the former.
311 Medium
311 of 407
Analyzing +4 | -1
Assertion (A): Conductors having equal positive charge and volume, must also have same potential.
Reason (R): Potential depends only on charge and volume of conductor.
View answer and explanation
Correct option: D
Both assertion and reason are false
Option D (Both assertion and reason are false) is correct. Electric potential depends on charge, volume, and shape, making both statements incorrect.
312 Medium
312 of 407
Application +4 | -1
The capacitance of two conductors in parallel is four times when they are connected in series. The ratio of the individual capacitance will be
View answer and explanation
Correct option: B
0.042361111
Option B (01:01) is correct because the ratio of capacitances is 1:1 when the capacitance in parallel is four times the capacitance in series, implying equal individual capacitances.
313 Medium
313 of 407
Application +4 | -1
Two conducting spheres of radii R1R_1 and R2R_2 are kept widely separated from each other. What are their individual capacitances? If the spheres are connected by a metal wire, what will be the capacitance of the combination? Think in terms of series-parallel connections.
View answer and explanation
Correct option: B
4πε0(R1+R2)4 \pi \varepsilon_0\left(\mathrm{R}_1+\mathrm{R}_2\right)
Option B (4πε0(R1+R2)4 \pi \varepsilon_0\left(\mathrm{R}_1+\mathrm{R}_2\right)) is correct because the capacitance of a single sphere is 4πε0R4 \pi \varepsilon_0 R and when connected by a wire, they act as parallel capacitors.
314 Medium
314 of 407
Application +4 | -1
An electric field is expressed as E=2i^+3j^E=2 \hat{i}+3 \hat{j}. Find the potential difference (VA−VB)\left(V_A-V_B\right) between two points AA and BB whose position vectors are given by rA=i^+2j^r_A=\hat{i}+2 \hat{j} and rB=2i^+j^+3k^r_B=2 \hat{i}+\hat{j}+3 \hat{k}.
View answer and explanation
Correct option: A
−1V-1 V
Option A (-1 V) is correct because the potential difference is calculated by integrating the electric field along the displacement vector.
315 Easy
315 of 407
Application +4 | -1
Two identical capacitors have same capacitance CC. One of them is charged to the potential VV and other to the potential 2V2 V. The negative ends of both are connected together. When the positive ends are also joined together, the decrease in energy of the combined system is:
View answer and explanation
Correct option: A
14CV2\frac{1}{4} {CV}^2
Option A (14CV2\frac{1}{4} {CV}^2) is correct because it is the difference between the initial and final energies of the capacitor system after connecting them.
316 Medium
316 of 407
Understanding +4 | -1
The intensity of electric field at a point between the plates of a charged capacitor
View answer and explanation
Correct option: D
Does not depend upon the distance between the plates
Option D (Does not depend upon the distance between the plates) is correct because the electric field between the plates of a charged capacitor is uniform and independent of the distance from the plates.
317 Medium
317 of 407
Application +4 | -1
A parallel-plate capacitor of capacitance 100μF100 \mu \mathrm{F} is connected to a power supply of 200 V200 \mathrm{~V}. A dielectric slab of dielectric constant 5 is now inserted into the gap between the plates. (a) Find the extra charge flown through the power supply and the work done by the supply. (b) Find the change in the electrostatic energy of the electric field in the capacitor.
View answer and explanation
Correct option: A
16 J; 8 J
Option A (16 J; 8 J) is correct because the extra charge flown through the power supply and the work done by the supply are 16 J, and the change in the electrostatic energy of the electric field in the capacitor is 8 J.
318 Medium
318 of 407
Understanding +4 | -1
A hollow spherical conductor of radius rr and potential of 100 V100 \mathrm{~V} at its outer surface. The potential inside the hollow at a distance of r/2r / 2 from its centre is
View answer and explanation
Correct option: A
100 V100 \mathrm{~V}
Option A is correct because the electric potential inside a hollow spherical conductor is constant and equal to the potential at the surface.
319 Medium
319 of 407
Application +4 | -1
A parallel plate capacitor has capacitance of 2μF2\mu F in air and 12μF12\mu F when immersed in oil. The dielectric constant of oil
View answer and explanation
Correct option: D
6
Option D (6) is correct because the dielectric constant is the ratio of capacitance in the medium to the capacitance in air.
320 Medium
320 of 407
Understanding +4 | -1
A hollow metallic sphere of radius RR is given a charge QQ. Then, the potential at the centre is
View answer and explanation
Correct option: B
14πε0.QR\frac{1}{{4\pi {\varepsilon _0}}}.\frac{Q}{R}
Option B is correct because the electric potential inside a hollow metallic sphere is constant and equal to the potential at the surface, which is given by 14πε0.QR\frac{1}{{4\pi \varepsilon _0}}.\frac{Q}{R}.
321 Medium
321 of 407
Application +4 | -1
An electric dipole having dipole moment 4×4 \times 10−9Cm10^{-9} \mathrm{Cm} makes an angle 30∘30^{\circ} with the direction of a uniform electric field of magnitude 5 ×104NC−1\times 10^4 \mathrm{NC}^{-1}. Calculate the magnitude of the torque acting on the dipole. Also find out work required to rotate the dipole to make angle 90∘90^{\circ} with the direction of the electric field.
View answer and explanation
Correct option: B
3×10−4 J\sqrt{3} \times 10^{-4} \mathrm{~J}
Option B (3×10−4 J\sqrt{3} \times 10^{-4} \mathrm{~J}) is correct because it is the work required to rotate the dipole, calculated using the potential energy difference at the given angles.
322 Medium
322 of 407
Analyzing +4 | -1
Assertion: A parallel plate capacitor is connected across battery through a key. A dielectric slab of dielectric constant k{k} is introduced between the plates. The energy stored becomes k{k} times.
Reason: The surface density of charge on the plate remains constant.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C (If assertion is true but reason is false) is correct because while the energy stored does increase by a factor of k, the surface charge density also increases, not remains constant.
323 Medium
323 of 407
Application +4 | -1
The ratio of charge densities on the surface of two conducting spheres is 3 : 2 If the radii of the spheres are 4 cm and 8 cm. the ratio of electric potential on the surfaces of the spheres is
View answer and explanation
Correct option: A
03:04
Option A (03:04) is correct because the ratio of electric potentials is directly proportional to the ratio of charge densities and the ratio of radii.
324 Medium
324 of 407
Application +4 | -1
There is an electric field EE in X−X -direction. If the work done on moving a charge 0.2  C0.2\;C through a distance of 2  m2\;m along a line making an angle 60∘60^\circ with the X−X -axis is 4.04.0, what is the value of EE
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the calculated electric field is 20 N/C, which is not among the provided options.
325 Easy
325 of 407
Application +4 | -1
An electric dipole is made up of two equal and opposite charges of 2×10−6C2 \times 10^{-6} {C} at a distance of 3 cm3 {~cm}. If this is kept in an electric field of 2×1052 \times 10^5 N/C{N} / {C}, then the maximum torque acting on the dipole is
View answer and explanation
Correct option: A
0.012
Option A (0.012) is correct because it is the maximum torque calculated using the formula τ=pE\tau = pE, where p is the dipole moment and E is the electric field.
326 Medium
326 of 407
Remembering +4 | -1
The energy stored in a capacitor of capacitance C\text{C} having a charge Q\text{Q} under a potential V\text{V} is
View answer and explanation
Correct option: D
12QV\frac{1}{2} \mathrm{QV}
Option D (12QV\frac{1}{2} \mathrm{QV}) is correct because the energy stored in a capacitor is given by half the product of the charge and the potential difference.
327 Medium
327 of 407
Understanding +4 | -1
Electron and proton is moving away from each other then potential energy of system
View answer and explanation
Correct option: B
Increasing
Option B (Increasing) is correct because as the electron moves away from the proton, positive work is done, increasing the potential energy of the system.
328 Medium
328 of 407
Understanding +4 | -1
The electric potential due to a small electric dipole at a large distance rr from the centre of the dipole is proportional to
View answer and explanation
Correct option: B
1/r1/r
Option D (1/r21/{r^2}) is correct because the electric potential due to a small electric dipole at a large distance rr is inversely proportional to r2r^2.
329 Medium
329 of 407
Understanding +4 | -1
The angle between the dipole moment and electric field at any point on the equatorial plane is:
View answer and explanation
Correct option: C
180∘180^{\circ}
Option C (180∘180^{\circ}) is correct because the electric field direction is opposite to the dipole moment direction on the equatorial plane.
330 Medium
330 of 407
Understanding +4 | -1
It becomes possible to define potential at a point in an electric field because electric field:
View answer and explanation
Correct option: A
Is a conservative field
Option A (Is a conservative field) is correct because the electric field is conservative, allowing for the definition of electric potential.
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