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JEE • PHYSICS • ELECTRIC FIELDS AND CHARGES
Electric fields and charges practice · Medium
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 61-90 of 385 questions
61
Medium
61 of 385
Application
+4 | -1
Two charges of and are separated by a distance of 42 cm. Electrostatic field strength from the smaller charge is zero at a distance of
View answer and explanation
Correct option: B
21 cm
Option B (21 cm) is correct because the point where the electric field is zero lies closer to the smaller charge and can be calculated using the formula for the electric field due to point charges.
62
Medium
62 of 385
Application
+4 | -1
Estimate the number of electrons in of water. How much is the total negative charge on these electrons?
View answer and explanation
Correct option: B
Option B () is correct because it calculates the total negative charge by finding the number of electrons and multiplying by the charge of an electron.
63
Medium
63 of 385
Application
+4 | -1
A dipole has two charges and and each have mass . The separation between the charges is . An electric field is applied on the dipole. If the dipole is deflected through from the equilibrium position, time taken by it to come to the equilibrium position again is
View answer and explanation
Correct option: A
Option A () is correct because it's calculated using the formula for the time period of a torsional pendulum.
64
Medium
64 of 385
Analyzing
+4 | -1
Assertion:- Electrostatic energy does not follow superposition principle.
Reason:-Electrostatic energy density is a quadratic function.
Reason:-Electrostatic energy density is a quadratic function.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because electrostatic energy does not follow the superposition principle, and this is because electrostatic energy density is a quadratic function.
65
Medium
65 of 385
Analyzing
+4 | -1
Assertion:- When a positive point charge is placed near a neutral conductor then the Latter becomes negatively charged.
Reason:- Induction is possible in conductors only.
Reason:- Induction is possible in conductors only.
View answer and explanation
Correct option: D
If both Assertion & Reason are False
Option D (If both Assertion & Reason are False) is correct because both the assertion and the reason are incorrect statements about induction.
66
Medium
66 of 385
Analyzing
+4 | -1
Assertion(A): If a bob of a simple pendulum is kept in a horizontal electric field, its period of oscillation will remain same.
Reason(R): If bob is charged and kept in horizontal electric field, then the time period will be decreased.
Reason(R): If bob is charged and kept in horizontal electric field, then the time period will be decreased.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
Option B is correct because both the assertion and reason are correct statements, but the reason doesn't explain why the period remains the same when the bob is uncharged.
67
Medium
67 of 385
Understanding
+4 | -1
Assertion: Electric lines of force cross each other.
Reason: Electric field at a point superimposes to give one resultant electric field.
Reason: Electric field at a point superimposes to give one resultant electric field.
View answer and explanation
Correct option: D
If Assertion is false but Reason is true.
Option D (If Assertion is false but Reason is true) is correct because electric field lines never cross, but the electric field at a point is the superposition of individual fields.
68
Medium
68 of 385
Understanding
+4 | -1
Two equal and opposite charges are placed at points and The null point on the line joining them is
View answer and explanation
Correct option: D
Outside the line joining and
Option D (Outside the line joining and ) is correct because the null point due to two equal and opposite charges lies outside the line joining them, closer to the charge with smaller magnitude (in this case, at infinity if the charges are equal).
69
Medium
69 of 385
Application
+4 | -1
An infinite line charge produces a field of at . The linear charge density is
View answer and explanation
Correct option: A
Option A () is correct because it is calculated using the formula for the electric field due to an infinite line charge, .
70
Medium
70 of 385
Analyzing
+4 | -1
The bob of simple pendulum is hanging vertically down from a fixed identical bob by means of string of length . If both bobs are charged with a charge with a charge each, time period of the pendulum is (ignore the radii of the bobs)
View answer and explanation
Correct option: C
Option C is correct because the electrostatic repulsion between the charged bobs does not affect the time period of the pendulum, which remains the same as for a simple pendulum.
71
Medium
71 of 385
Understanding
+4 | -1
Gauss’s law of electrostatics would be invalid if
View answer and explanation
Correct option: C
The inverse square law was not exactly true
Option C (The inverse square law was not exactly true) is correct because Gauss's law is a direct consequence of the inverse square law in electrostatics.
72
Medium
72 of 385
Application
+4 | -1
A force of is acting between two charges in air if the space between them is completely filled with glass , then the new force will be ……
View answer and explanation
Correct option: B
0.5
Option B (0.5) is correct because the force between two charges is inversely proportional to the dielectric constant of the medium.
73
Medium
73 of 385
Application
+4 | -1
In a region, the intensity of an electric field is given by in The electric flux through a surface in the region is
View answer and explanation
Correct option: B
Option B () is correct because electric flux is the dot product of the electric field and the area vector.
74
Medium
74 of 385
Remembering
+4 | -1
Electric charges under action of electric forces is called
View answer and explanation
Correct option: A
electrostatic
The correct answer is A (electrostatic) because electrostatics deals with electric charges at rest or in slow motion under the influence of electric forces.
75
Medium
75 of 385
Understanding
+4 | -1
A hollow metallic sphere of radius is given a charge of .The electric intensity at a point from the centre is
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the electric field inside a hollow metallic sphere is always zero, regardless of the charge on the sphere.
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76
Medium
76 of 385
Application
+4 | -1
An electron is moving round the nucleus of a hydrogen atom in a circular orbit of radius The coulomb force between the two is
View answer and explanation
Correct option: C
Option C () is correct because the Coulomb force is attractive (negative sign) and inversely proportional to the square of the distance, expressed in vector form.
77
Medium
77 of 385
Application
+4 | -1
The repulsive force between two equal charges is To reduce force by 25% how much charge is transferred from first to second:-
View answer and explanation
Correct option: C
Option C () is correct because transferring Q/2 charge results in a 25% reduction in the repulsive force between the charges.
78
Medium
78 of 385
Understanding
+4 | -1
Two charges and are situated at a distance in air. The ratio of the forces acting on them is
View answer and explanation
Correct option: C
The correct answer is 1: 1 because, according to Newton's third law, the forces between two charges are equal and opposite.
79
Medium
79 of 385
Understanding
+4 | -1
Assertion:- Net charge density inside a conductor is zero.
Reason:- Equal and opposite charges are present in conductor.
Reason:- Equal and opposite charges are present in conductor.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because net charge density inside a conductor is zero due to the presence of equal and opposite charges that cancel each other out.
80
Medium
80 of 385
Remembering
+4 | -1
Which of the following is the correct statement of Gauss law for electrostatics in a region of charge distribution in free space?
View answer and explanation
Correct option: B
Option B () is the correct statement of Gauss's law, relating the electric flux through a closed surface to the enclosed charge density.
81
Medium
81 of 385
Analyzing
+4 | -1
Two masses and carry positive charges and , respectively. They are dropped to the floor in a laboratory setup from the same height where there is a constant electric field vertically upwards. hits the floor before . Then,
View answer and explanation
Correct option: D
Option D is correct because the condition for M1 hitting the floor before M2 leads to the inequality M1Q2 > M2Q1.
82
Medium
82 of 385
Understanding
+4 | -1
Assertion: All the charges in a conductor get
distributed on whole of its outer surface.
Reason: In a dynamic system, charges try to
keep their potential energy minimum.
distributed on whole of its outer surface.
Reason: In a dynamic system, charges try to
keep their potential energy minimum.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and
reason is the correct explanation of Assertion
reason is the correct explanation of Assertion
Option A is correct because charges distribute on the outer surface to minimize potential energy, leading to a stable dynamic system.
83
Medium
83 of 385
Remembering
+4 | -1
The surface charge density of the earth is about
View answer and explanation
Correct option: D
Option D () is correct because the surface charge density is calculated by dividing the total charge by the surface area of the Earth.
84
Medium
84 of 385
Application
+4 | -1
If the electric field near the earth's surface be directed downwards, then the surface density of charge on earth's surface is
View answer and explanation
Correct option: C
Option C () is correct because it's calculated using the formula relating electric field and surface charge density: .
85
Medium
85 of 385
Application
+4 | -1
A charge is to be distributed on two conducting spheres. Find out values of charges on spheres so, that the repulsive force between them is maximum at fixed distance.
View answer and explanation
Correct option: A
Option A () is correct because the repulsive force is maximized when the charge is equally distributed between the two spheres.
86
Medium
86 of 385
Remembering
+4 | -1
The force per unit charge is known as_____.
View answer and explanation
Correct option: B
Electric field
Option B (Electric field) is correct because the electric field is defined as the force per unit charge.
87
Medium
87 of 385
Application
+4 | -1
What is the magnitude of a point charge due to which the electric field 30cm away has the magnitude
View answer and explanation
Correct option: A
Option A () is correct because it is calculated directly from the formula for the electric field due to a point charge.
88
Medium
88 of 385
Understanding
+4 | -1
Which of the following is false for electric lines
of force?
of force?
View answer and explanation
Correct option: C
They always form closed loops
Option C is correct because total internal reflection is not directly involved in the formation of a rainbow; the process involves refraction, dispersion, and internal reflection.
89
Medium
89 of 385
Understanding
+4 | -1
Assertion: The coulomb force is the dominating force in the universe.
Reason: The coulomb force is weaker than the gravitational force.
Reason: The coulomb force is weaker than the gravitational force.
View answer and explanation
Correct option: D
If the assertion and reason both are false.
Option D is correct because the Coulomb force is actually much stronger than the gravitational force, and it is not the dominating force in the universe.
90
Medium
90 of 385
Analyzing
+4 | -1
A charged bead is capable of sliding freely
through a string held vertically in tension. An
electric field is applied parallel to the string, so
that the bead stays at rest at middle of the
string. If the electric field is switched off
momentarily and switched on
through a string held vertically in tension. An
electric field is applied parallel to the string, so
that the bead stays at rest at middle of the
string. If the electric field is switched off
momentarily and switched on
View answer and explanation
Correct option: D
The bead moves downwards with constant
velocity till it reaches the bottom of the string
velocity till it reaches the bottom of the string
Option D is correct. After the field is switched off and then on again, the forces balance, resulting in constant velocity.
Revision notes and key takeaways
Review ELECTRIC FIELDS AND CHARGES in your textbook or class notes, then use this set to check your understanding.
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