JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Application +4 | -1

Two charges, each of

5\,\,\mu c

but opposite in sign, are placed 4cm apart. What is the value of electric field intensity at a point distance 4 cm from the mid-point on the axial line of the dipole?

View answer and explanation

Correct option: B

{10^8}\,\,\frac{N}{C}

Option B (

{10^8}\,\frac{N}{C}

) is correct because the electric field intensity is calculated using the formula for the electric field due to a dipole at a point on its axial line.

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