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JEE • PHYSICS • ELECTRIC FIELDS AND CHARGES

Electric fields and charges practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 385 questions
31 Medium
31 of 385
Understanding +4 | -1
Given below are two statements:
Statement I: A time varying electric field is a source of changing magnetic field and vice-versa. Thus a disturbance in electric or magnetic field creates EM waves.
Statement II: In a material medium, the EM wave travels with speed v=1μ0ε0.v = \frac{1}{{\sqrt {{\mu _0}{\varepsilon _0}} }}.
In the light of the above statements, choose the correct answer from the options given below.
View answer and explanation
Correct option: C
Statement I is correct but statement II is false
Option C (Statement I is correct but statement II is false) is correct because Statement I accurately describes the relationship between time-varying electric and magnetic fields, while Statement II omits the relative permittivity and permeability of the material medium.
32 Medium
32 of 385
Application +4 | -1
A conducting sphere of radius 5 cm5 \mathrm{~cm} has an unknown charge. The electric field at 10 cm10 \mathrm{~cm} from the centre of the sphere is 1.8×103 N/C1.8 \times 10^3 \mathrm{~N} / \mathrm{C} and points radially inward. What is the net charge on the sphere?
View answer and explanation
Correct option: B
2 nC2 \mathrm{~nC}
Option B (2 nC) is correct because the net charge is calculated using the electric field at a given distance from the center of the sphere.
33 Medium
33 of 385
Application +4 | -1
Two infinite plane parallel sheets separated by a distance dd have equal and opposite uniform charge densities σ.\sigma . Electric field at a point between the sheets is
View answer and explanation
Correct option: B
σε0\frac{\sigma }{{{\varepsilon _0}}}
Option B (σε0\frac{\sigma }{{\varepsilon _0}}) is correct because the electric field between two infinite parallel sheets with equal and opposite charge densities is the sum of the fields due to each sheet.
34 Medium
34 of 385
Remembering +4 | -1
Choose the correct relation between polarization 'P\text{P}' and electric susceptibility 'χe\chi_{\mathrm{e}}' of dielectric material. (E=(\text{E}= electric field)
View answer and explanation
Correct option: C
P=χeE\mathrm{P}=\chi_{\mathrm{e}} \mathrm{E}
Option C (P=χeE\mathrm{P}=\chi_{\mathrm{e}} \mathrm{E}) is correct because it represents the direct proportionality between polarization and electric field, mediated by electric susceptibility.
35 Medium
35 of 385
Understanding +4 | -1
A cube of side bb has a charge qq at each of its vertices. The electric field due to this charge distribution at the centre of this cube will be
View answer and explanation
Correct option: D
Zero
Option D is correct because the electric field at the center of the cube due to symmetrically placed charges is zero.
36 Medium
36 of 385
Understanding +4 | -1
According to Gauss’ Theorem, electric field of an infinitely long straight wire is proportional to
View answer and explanation
Correct option: D
1/r1/r
Option D is correct because the electric field due to an infinitely long straight wire is inversely proportional to the distance from the wire.
37 Medium
37 of 385
Understanding +4 | -1
Assertion:- Charge given to a conductor appears on its surface.
Reason:- When charge appears on surface then potential energy of conductor becomes minimum.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because charges on a conductor reside on its surface to minimize potential energy, leading to a stable electrostatic configuration.
38 Medium
38 of 385
Application +4 | -1
A point charge of 1.8μC is at the centre of cubical Gaussian surface 55cm on edge. What is the net electric flux through the surface?
View answer and explanation
Correct option: C
2.0×105N−m2C−12.0 \times {10^5}\mathrm{N} - {\mathrm{m}^2}{\mathrm{C}^{ - 1}}
Option C (2.0×105N−m2C−12.0 \times {10^5}\mathrm{N} - {\mathrm{m}^2}{\mathrm{C}^{ - 1}}) is correct because it is the net electric flux calculated using Gauss's law.
39 Medium
39 of 385
Analyzing +4 | -1
A long, hollow conducting cylinder is kept coaxially inside another long, hollow conducting cylinder of larger radius. Both the cylinders are initially electrically neutral.
View answer and explanation
Correct option: A
A potential difference appears between the two cylinders when a charge density is given to the inner cylinder
The correct answer is A because a charge on the inner cylinder induces a charge on the outer cylinder, creating an electric field and thus a potential difference between them.
40 Medium
40 of 385
Understanding +4 | -1
Equipotential surfaces corresponding to electric field due to an infinitely large uniformly charged sheet are
View answer and explanation
Correct option: C
Planer
Option C is correct. Equipotential surfaces are always perpendicular to electric field lines. For an infinitely large uniformly charged sheet, the electric field lines are straight and parallel, resulting in planar equipotential surfaces.
41 Medium
41 of 385
Application +4 | -1
A golden ornament has a charge of +10−4  coulombs.+ {10^{ - 4}}\,\,{\text{coulombs}}. The number of electrons removed from the ornament is
View answer and explanation
Correct option: B
6.25×10146.25 \times {10^{14}}
Option B (6.25×10146.25 \times {10^{14}}) is correct because it calculates the number of electrons removed using the quantization of charge formula.
42 Medium
42 of 385
Understanding +4 | -1
Which of the following statements is not true about Gauss’ law?
View answer and explanation
Correct option: A
Gauss’ law is not much useful in calculating electrostatic field when the system has some symmetry
Option A (Gauss’ law is not much useful in calculating electrostatic field when the system has some symmetry) is correct because Gauss's law is *most* useful when the system has symmetry, allowing for easier calculation of the electric field.
43 Medium
43 of 385
Application +4 | -1
Two charges, each of 5  μc5\,\,\mu c but opposite in sign, are placed 4cm apart. What is the value of electric field intensity at a point distance 4 cm from the mid-point on the axial line of the dipole?
View answer and explanation
Correct option: B
108  NC{10^8}\,\,\frac{N}{C}
Option B (108 NC{10^8}\,\frac{N}{C}) is correct because the electric field intensity is calculated using the formula for the electric field due to a dipole at a point on its axial line.
44 Medium
44 of 385
Understanding +4 | -1
If σ\sigma is the surface charge density of the conductor then, mechanical force per unit area of a charged conductor is proportional to:
View answer and explanation
Correct option: B
σ2\sigma^2
Option B is correct because the mechanical force per unit area of a charged conductor is proportional to the square of the surface charge density, as derived from electrostatic principles.
45 Medium
45 of 385
Application +4 | -1
Two insulated charged metallic spheres 'PP' and 'QQ' of negligible radii have their centers separated by a distance of 60 cm.60 \mathrm{~cm}. The mutual force of electrostatic repulsion if the charge on each 6×10−7C6 \times 10^{-7} \mathrm{C} is _______
View answer and explanation
Correct option: A
9×10−3 N9 \times 10^{-3} \mathrm{~N}
Option A (9×10−3 N9 \times 10^{-3} \mathrm{~N}) is correct because it is the electrostatic force calculated using Coulomb's law with the given charges and distance.
46 Medium
46 of 385
Analyzing +4 | -1
Assertion: The coulomb force is the dominating force in the universe.

Reason: The coulomb force is stronger than the gravitational force.
View answer and explanation
Correct option: D
Assertion is false and Reason is true
The correct answer is D. The assertion is false because gravitational force dominates on a cosmic scale, while the reason is true because the Coulomb force is significantly stronger than the gravitational force at the atomic level.
47 Medium
47 of 385
Application +4 | -1
A 100 eV100 \mathrm{~eV} electron is fired directly towards a large metal plate having surface charge density −2×106 C m−2-2 \times 10^6 \mathrm{~C} \mathrm{~m}^{-2}. The distance from where the electron is projected so that just fails to strike the plate is
View answer and explanation
Correct option: A
0.44 mm0.44 \mathrm{~mm}
Option A (0.44 mm0.44 \text{{ mm}}) is correct because it calculates the distance at which the electron's kinetic energy is completely converted to potential energy due to the electric field.
48 Medium
48 of 385
Understanding +4 | -1
Two charged spheres of radii 10cm10cm and 15cm15cm are connected by a thin wire. No charge will flow, if they have
View answer and explanation
Correct option: B
The same potential
Option B (The same potential) is correct because charge flows from higher potential to lower potential; if the potentials are the same, there will be no charge flow.
49 Medium
49 of 385
Analyzing +4 | -1
Two positive charges Q1Q_1 and Q2Q_2 are fixed at AA and BB. A unit positive charge is taken from AA to BB along the line joining ABA B. The force experienced by unit charge
View answer and explanation
Correct option: D
Decreases first and then increases
Option D (Decreases first and then increases) is correct because the force due to Q1 decreases as the unit charge moves away, while the force due to Q2 increases as the unit charge moves closer.
50 Medium
50 of 385
Analyzing +4 | -1
Statement-I: Acceleration of charged particle in non uniform electric field does not depend on veloicty of charged particle

Statement-II: charge is an invariant quantity, that is, amount of charge on particle doesn't depend on frame of referenced
View answer and explanation
Correct option: A
Statement-I is True, statement-II is True
Option A (Statement-I is True, statement-II is True) is correct because the acceleration of a charged particle in a non-uniform electric field depends on the electric field and charge, not velocity, and charge is an invariant quantity.
51 Medium
51 of 385
Application +4 | -1
The inward and outward electric flux for a closed surface in units of N−m2/CN - {m^2}/C are respectively 8×1038 \times {10^3} and 4×1034 \times {10^3}. Then the total charge inside the surface in S.I. units is (Where ε0{\varepsilon _0} = permittivity constant)
View answer and explanation
Correct option: D
−4×103E0- 4 \times {10^3}{E_0}
Option D is correct because the net electric flux is related to the enclosed charge by Gauss's law, and inward flux is negative.
52 Medium
52 of 385
Understanding +4 | -1
The ratio of the forces between two small spheres with constant charge (a)\left( a \right) in air (b)\left( b \right) in a medium of dielectric constant KK is
View answer and explanation
Correct option: B
K  :1K\;:1
Option B (K:1K:1) is correct because the force between two charges decreases by a factor of K when placed in a medium with dielectric constant K.
53 Medium
53 of 385
Analyzing +4 | -1
A body has a charge of 9.6×10−209.6 \times {10^{ - 20}} coulomb. It is
View answer and explanation
Correct option: B
Not possible
Option B is correct because charge is quantized and must be an integer multiple of the elementary charge (1.6 × 10-19 C).
54 Medium
54 of 385
Remembering +4 | -1
Top of the stratosphere has an electric field EE (in units of V/mV/m) nearly equal to
View answer and explanation
Correct option: C
100
Option C (100) is correct because the electric field at the top of the stratosphere is approximately 100 V/m.
55 Medium
55 of 385
Understanding +4 | -1
If a proton is moved against the coulomb force
of an electric field, then
View answer and explanation
Correct option: B
Energy is used from some outside source
Option B (Energy is used from some outside source) is correct because work must be done against the electric field to move the proton.
56 Medium
56 of 385
Remembering +4 | -1
The scientist whose major contribution is
towards the measurement of electronic charge
View answer and explanation
Correct option: B
R.A. Millikan
Option B (R.A. Millikan) is correct because R.A. Millikan is famous for his oil drop experiment, which accurately measured the elementary electric charge.
57 Medium
57 of 385
Application +4 | -1
Two charges placed in air repel each other by a force of 10−4N.{10^{ - 4}}N. When oil is introduced between the charges, the force becomes 2.5×10−5N.2.5 \times {10^{ - 5}}N. The dielectric constant of oil is
View answer and explanation
Correct option: D
4.04.0
Option D (4.04.0) is correct because the dielectric constant is the ratio of the force in air to the force in the medium.
58 Medium
58 of 385
Understanding +4 | -1
While taking off synthetic clothes, seeing a spark or
hearing a crackle, are due to
View answer and explanation
Correct option: C
Electric discharge
Option C is correct because the spark and crackle are due to the electric discharge caused by accumulated static electricity.
59 Medium
59 of 385
Analyzing +4 | -1
Assertion: Two identicalballs are charged by qq. They are suspended from a common point by two insulating threads ll each. In equilibrium the angle between the threads is 180∘180^{\circ}. (Ignore gravity)

Reason: In equllibrium tension in the springs is T=14πε0×q⋅ql2T=\frac{1}{4 \pi \varepsilon_0} \times \frac{q \cdot q}{l^2}
View answer and explanation
Correct option: C
Assertion is true & Reason is false
Option D (Assertion is false and Reason is true) is incorrect. The assertion is true, but the reason is false because the tension is calculated with the distance between the balls as 2l.
60 Medium
60 of 385
Analyzing +4 | -1
Assertion:- An electric charge is fixed in free space which produces an electric field around it. No work is done in displacing another charge from its position to any other position.
Reason:- Electrostatic field is non conservative.
View answer and explanation
Correct option: D
If both Assertion & Reason are False
Option D is correct because the assertion is false as work done is zero in moving a charge in an electrostatic field, and the reason is also false as the electrostatic field is conservative.
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Review ELECTRIC FIELDS AND CHARGES in your textbook or class notes, then use this set to check your understanding.

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